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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 66651. |
Shanti Sweets Stall was placing an order for making cardboard boxes for packingtheir sweets. Two sizes of boxes were required. The bigger of dimensions25 cm × 20 cm × 5 cm and the smaller of dimensions 15 cm × 12 cm × 5 cm. For all theoverlaps, 5% of the total surface area is required extra. If the cost of the cardboard is4 for 1000 cm, find the cost of cardboard required for supplying 250 boxes of eachkind. |
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| 66652. |
A sum of money was divided between Rajeev and Ashish so that Rajeev getsof the whole amount.10If he gets 5600, how much was the total sum. |
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| 66653. |
7. A sum of money was divided between Rajeev and Ashish so that Rajeev gets 19 of the whole amount.If he gets R 5600, how much was the total sum? |
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Answer» Let total money is xGiven, 7x/19=56007x=106400x=106400/7x=15200 Thanks |
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| 66654. |
If the values of (a minus b ) and ab are 6 & 4 respectively find the values of a power 2 plus b power 2and (a plus b ) whole square |
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Answer» a-b=6ab=4(a-b)^2=a^2+b^2-2ab=36so a^2+b^2=36+2(4)=36+8=44(a+b)^2=a^2+b^2+2ab=44+8=52 |
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| 66655. |
1 + 10 square + 1 + 1 by 10 square is equal to 1 by sin square A minus sin to the power 4 A |
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Answer» Please take a photo of the equation and post it. Not able to understand the question ok please answer my question |
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| 66656. |
1. Divide 15 sweets between Manu and Sonu so that they get 20 %and 80 % of them respectively. |
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Answer» 20% of 15 = 20*15/100 = 15/5 = 3 sweets to monu amd hence sonu got 15-3 = 12 sweets |
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| 66657. |
ollencingWU) A rectangular field is 15 m long and 10 m wide. Another rectangular field having theperimeter has its sides in the ratio 4. 1. Find the dimension of the rectangular ligema |
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Answer» perimeter of another field =2(15+10)=50cmlenght:breadth=4:1total ratio=5x=50x=50/5=10 so, length =40cmbreadth=10cm is the best answer perimeter of field=2[15+10=50cmlength:breadth=4:1total ratio=5x=50x=50/5=10 so, length=40breadth=10cm is the solution |
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| 66658. |
Ashish can paint his doll in 20 minutes and his sister Chinki can do so in 25 minutes.They paint together for 5 minutes and then Chinki withdraws from the painting. Inhow many minutes will Ashish finish painting the remaining doll? |
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| 66659. |
A pipe can fll 1/4th of the cistern in 16 minutes. In how many minutes, can it fill 3/4 th of the cistern |
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Answer» 16×3=48 minutes is the answer please answer in long |
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| 66660. |
many minutes are there inthe |
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Answer» in 1 hr = 60 minin half hr 30min In 5/6 of half hr there is 25 min |
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| 66661. |
gettingaredcardFind the probability offrom well shuffled 52 cards. |
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Answer» Total no.of red cards = 26Total cards= 52Probability= 26/52 = 1/2 thank you understand sen |
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| 66662. |
the thickness of two words are 6 into 10 to the power minus 6 metre and 1.5 into 10 to the power minus 7 find the ratio of thickness of the two wires |
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Answer» the ratio of thickness of the two wires will be 40:1 |
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| 66663. |
triangularfielda0with sides 240 m, 2another triangular field with sides 240 m, 320as a200 m, 360 m, where shelewheat. In another trianious field, she tm, 400 mted to grow potatoes and onions (see Fig. 12m adjacent to the2.11). She dividedopposite vertexs by joining the mid-point of the longest side to thedprew patafsed for wheatart and onions in the other part. How much area in hectarses, potatoes and onions? (d hectare 10000 m2) |
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Answer» 1)apply the Pythagorean theorem to verify if there is any rectangular triangletriangle ABC360²=200²+240²-------------> 19600=40000+57600--> is not rectangular triangletriangle BCD400²=320²+240²----> 160000=102400+57600----> 160000=160000----- > okthe triangle BCD is a rectangular trianglethe area of triangle BCD=(1/2)*320*240=38400 m²Area for potatoes--------------- > 38400/2=19200m²and Area for onions=Area forpotatoes=19200m² 2) by theformula of Heronfinds the area of atriangleof which all its sides are knowntriangleABCs-----------> semiperimeter=[360+200+240]/2=400 mA=[s*(s-a)*(s-b)*(s-c)]^(1/2)----->[400*(400-360)*(400-200)*(400-240)]^(1/2)A=[400*(40)*(200)*(160)]^(1/2)=22627.42 m²Area for wheat-------- > 22627.42 m² the total area isArea forpotatoes=19200m²Area foronions=19200m²Area for wheat=22627.42 m² total area=19200+19200+22627.42=61027.42 m² in hectares1 hectares---------------------- >10000 m² X------------------------------- > 61027.42 m² X=61027.42 /10000=6.10 hectares total area------> 6.10 HaArea forpotatoes=1.92 HaArea foronions=1.92 HaArea for wheat=2.26 Ha |
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| 66664. |
SHORT ANSWER-II TYPE PROBLEMS1 Find the missing frequency of the following data if the mode is 48.6:Class interval 10–25 25-40 40-55 55–70Frequency L 62044?70-853 |
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Answer» 48 48 is the right answer for this question |
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| 66665. |
of x. Using this value of ,dle o6. The numbers 52, 53, 54, 54, (2x + 1),55, 55, 56,57 have been arrangedin an ascending order and their median is 55. Find the value of x andhence find the mode of the given data. |
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| 66666. |
1 15509. ७0७609+ 0019= ७. 24. 2 Sg12. Provethal: टजड८9-००19S0 |
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Answer» hit like if you find it useful |
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| 66667. |
I. How many minutes are there from(a) 8:10 a.m. to 8:30 a.m.(b) 9:30 p.m. to 9:55 p.m.(c) 4:35 p.m. to 4:50 p.m.(d) 1 1:40 a.m. to 12 noon(e) 1 1:55 a.m. to 12:30 p.m. =Il. Fill in the blanks with |
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Answer» 20 min25 min15 min20 min35 min |
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| 66668. |
Calculate the probability of getting a red face from a welshuffled deck of cards. |
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| 66669. |
ORtheThe King, Queen and Jack of clubs are removed from a pack of 52 cards and thenremaining cards are well shuffled. A card is selected from the remaining cards. Findthe probability of getting a card(i) of spade(ii) of black king(iii) of club(iv) of jacks |
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Answer» The remaining cards are 52-3 = 49 i) spade cards = 13 probability = 13/52 = 1/4 ii) as king of club is removed black king = 1 probability = 1/52 iii) club cards = 10 probability = 10/52 = 5/26 iv) Jack cards = 3 probability = 3/52 Like my answer if you find it useful! |
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| 66670. |
20% of 1/5 of 2250(1) 55(4) 4050 + ?(2) 90(5) 45(3) 50 |
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| 66671. |
Find the HCF(i)25,40 (ii) 56, 32 (iii) 40, 60, 75(v)18,32,48 (vi) 105, 154 (vii) 42, 45, 48(ix) 56,57 (0777, 315, 588 |
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Answer» 777 = 7×3×37 315 = 3×3×5×7 588 = 2×2×3×7×7 so HCF = 3×7 = 21 how to solve I don't understand |
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| 66672. |
the LCM of 240 320 400 |
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Answer» Prime factors of240=24.3.5Prime factors of320=26.5Prime factors of400=24.52 LCM= 26.52.31=4800 |
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| 66673. |
480, 480, 240, 80, 20, ?e |
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Answer» As we can see that the sequence is continuousy dividing with 1,2,3,4,5 Then, 20/5=4 |
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| 66674. |
in class of 72 studenter of them wee boys, findthe numbers of Girls in the class. I |
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Answer» 36 is the correct answer of the given question 36 is right answer of this question. please like my answer. |
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| 66675. |
t - sinG i+sine |
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Answer» thanks |
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| 66676. |
Sing in the 4eer-of- |
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| 66677. |
Simhasing cottatulCosly-cos2x |
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| 66678. |
One card is drawn at random from a well-shuffled deck of 52 cards. Find the probabilitthat the card drawn is (i) a king, (ii) a spade, (ili) a red queen, (iv) a black 8. |
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| 66679. |
6. The numbers 52, 53, 54, 54, (2x +1), 55, 55, 56, 57 have been arrangedin an ascending order and their median is 55. Find the value of r andhence find the mode of the given data. |
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Answer» which class this quation numbers are in ascending order so middle number is median2x+1=55 so 2x=54 so x=27so that number is 2x+1=5555 occurred 3 times so mode=55 |
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| 66680. |
many days each will take to complete the work.kings,. queens and aces are removed from a pack of 52 cards. The remaining cardshuffled and then a card is drawn from it. Find the probability that the drawnarewell scard is (i) a black face card(ii) a red card. |
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Answer» thanks |
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| 66681. |
5) Express each fraction in its simplest form.248C) 24032080154315(a) 420(b)(0) |
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| 66682. |
6. In a pack of cards, find thenumber of red colour. |
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Answer» There are totally 26 red cards in a deck. There are 12 facecardsin thedeck. 6 of the facecardsarered(diamonds or hearts) and 6 of the facecardsare black (spaces or clubs). let A be the event that you have ared card. Since there are 26Red Cardsin thedeck, then p(A) = 26/52. pagal sorry |
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| 66683. |
How many triangles are there? |
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Answer» there are 14 triangle thanking you ☺☺☺☺ There are a total of 20 triangles. |
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| 66684. |
and 15 cm.The circumference of a given circular p55 m. It is surrounded by a path of unwidth 3-5 m. Find the area of the path. |
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| 66685. |
one card is drawn to from a well shuffled deck of 52 cards .find the probility of getting 1.A king of red colour2.A face card3.A red black card4.A red face card |
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| 66686. |
There are timi a ny shaded trianglesWhite triangle There are 3 white triangleHow many triangles are shaded? |
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Answer» Number of white triangles = 3 Then,As per given condition Number of shaded triangles = 2*(Number of white triangles)= 2*3= 6 6 number is the right answer |
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| 66687. |
How many triangles are there in the following figure? |
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Answer» this question is the correct answer is 16 triangle's There are 16 triangles in the given figure. 16 triangles are in the given figure. there are eleven triangles |
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| 66688. |
3. Identify the error, if any.This is 2This isThis is 44 |
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| 66689. |
22. How many triangles are there in the given figure? |
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Answer» There are 15 triangles in the given figure. there are 15 triangles in the given figure |
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| 66690. |
2 How many triangles are there in thisfigure?4 |
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| 66691. |
How many trianglesare there?(97.67% get this wrong) |
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Answer» 9 9 5 is the answer of this question 12 is the right answer 15 is the correct answer 19 May be the answer Sorry 18 is the correct answer . My apologies. |
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| 66692. |
How many triangles are there in the given figure? |
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Answer» 7 triangles are there in the given figure 4 triangle are there in the given figure |
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| 66693. |
2.How many triangles are formed in the given figure? |
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Answer» total 20 triangles are formed |
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| 66694. |
90 km ubstream inhouss the beoreoim imhe" spee |
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Answer» it's wrong ans is 0 |
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| 66695. |
Directions (4-5): What will come in placeof the question mark (?) in the following numberseries?4.5120 1280 320 80 ?(1) 16(2) 24(3) 20(4) 40(5) 275.8 17 42. 91 ?(1) 170(2) 142(3) 140(4) 172(5) 180 |
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Answer» ANSWER IS 20. The patter is division by 4 1. question answere is 20 2. question answere is 172 4. 3) . 20 5. 4) . 172 is the correct answer 4-(2)245-(2)142😊😊😊😊😊😊😊😊 4. 3)205. 4)172 is the right answer of the following 20 & 172 is correct answer |
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| 66696. |
(V)10. Draw a 4 ABC. Take a point Don BC.Join AD.How many triangles do you get?Name them.Con a triangle have |
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Answer» We will get 2 triangle 1 Triangle ABD2. Triangle ADC 3 triangle1. triangle ABC2. triangle ABD3. triangle ACD we will have 3 triangle now....1.triangle ABC2.triangle ABD3.triangle ADC4.triangle ACD |
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| 66697. |
Q.4.04. What will be the apparent frequency (v') ofthe sound,if the source of sound emits waves of frequencyv and is moving with a speed u_s (i) towards the listener (ii)away from the listener? |
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Answer» thank you and r u on Facebook I want to say that I love u |
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| 66698. |
A well of diameter 4 m is dug 21 m deep. The earth taken out of it has been spread evenlyall around it in the shape of a circular ring of width 3 m to form an embankment. Find theheight of the embankment. |
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| 66699. |
that two of itsand rand all the zeroes of 2t-3r-3x+ár-2, if you know |
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| 66700. |
He 8.392ABCDisatombus and Q,Rand S are Owthe mid points of the stiles Aant DArespetively Show that the quistrilateral Pa reetane |
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