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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 68601. |
\left. \begin{array} { l } { \text { If } \operatorname { cosec } A + \operatorname { sin } A = 5 \frac { 1 } { 5 } , \text { find the value of } } \\ { \operatorname { cosec } ^ { 2 } A + \operatorname { sin } ^ { 2 } A } \end{array} \right. |
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| 68602. |
12.The value of 5 cot? A -5 cosec? A is : |
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Answer» We know, cot²A - cosec²A = 1 So, 5cot²A - 5cosec²A 5 (cot²A - cosec²A) 5 × 1 5 |
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| 68603. |
7. f(x) = x+- 3x +4P+usivu8. f(x) = x+ -5x + 6 is divided by g(x) = 2 - x2.that p2 - 3 is a factor of 2x4 + 3x3 - 2 |
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| 68604. |
In a bakery, 6 kg 500 g flour, 2500 g sugarand 3.250 kg butter are used as the basicingredients to make cookies. Express thetotal weight of the ingredients in grams. |
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Answer» flour is = 6kg 500gm6x1000= 6000gmso in total = 6000+500=6500 gm flour sugar is 2500gmbutter is 3.250 kg = 3.250x1000 = 3250gm total amount of ingredients in gms = 6500+2500+3250=12250 gms total |
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| 68605. |
(5)In a bakery, 6 kg 500 g flour, 2500 g sugarand 3,250 kg butter are used as the basicingredients to make cookies. Express thetotal weight of the ingredients in grams. |
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Answer» weight of flour = 6500 g weight of sugar = 2500 g weight of butter = 3250 g Total weight = 6500+2500+3250 = 12250 g |
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| 68606. |
6. What conjecture can you make about the product of 13 and 8,888,888?13 8813 88813 888813 88,888114411,544115,5441,155,5441,155,555,544115,555,5441,115,555,44411,155,555,444 |
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Answer» 13*88=114413*888=1154413*8888=11554413*88888=115554413*888888=11555544so 13*8888888=115555544option (A) |
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| 68607. |
\begin{array} { l } { \text { The direction cosines of } \overline { A B } \text { are } } \\ { - 2 , \quad 2 , \quad 1 . \text { If } \quad A = ( 4,1,5 ) \text { and } } \\ { I ( A B ) = 6 \text { units, find the } } \\ { \text { coordinates of B. } } \end{array} |
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| 68608. |
512 \text { (ii) } 2197 \quad \text { (iii) } 3375 \text { (iv) } 5832 |
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Answer» Just observe the last digit estimate the number which cube is last digiti) as last digit is 2 so cube root 8ii) 13iii) 15iv) 18 |
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| 68609. |
cosec*((5*pi)/6) %2B cot(pi/6)^2 %2B 3*tan(pi/6)^2=6 |
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Answer» I will give you a hint-π=180° then π/6=30° |
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| 68610. |
P(E | F)=\frac{P(E \cap F)}{P(F)}=\frac{\frac{1}{6}}{\frac{3}{4}}=\frac{2}{9} |
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Answer» thnq so much |
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| 68611. |
find the number of moleculesin 8 gram of oxygen |
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Answer» molar mass of oxygen molecule = 32gmoles of O2 in 8g = 8/32 = 1/4 moles so, no. of molecules = 1/4*Na = 6/4×10²³ = 1.5×10²³ molecules |
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| 68612. |
(quad*(text*((i*i)*((quad*(text*((i*(i*i))/(-2 %2B sqrt(7)))))/(sqrt(2) %2B sqrt(3))))))/(5 %2B 3*sqrt(7)) |
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Answer» please ask one question |
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| 68613. |
\begin{array}{l}{\text { What will be }} \\ {\text { (i) } \frac{-3}{5} \times 7 ? \quad \text { (ii) } \frac{-6}{5} \times(-2) ?}\end{array} |
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Answer» i) (-3)/5 × 7 = -21/5 ii) (-6)/5 × (-2) = 12/5 |
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| 68614. |
(9*p^(-4))/((6*(3^(-3)*p^(-8)))) |
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Answer» the answer of above question is 6P^4 |
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| 68615. |
1 ^ b \cdot 8 p ^ 4 %2B 11 p ^ 2 %2B 3 |
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Answer» 8p⁴+11p²+38p⁴+8p²+3p²+38p²(p²+1)+3(p²+1)(8p²+3)(p²+1) |
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| 68616. |
13. Chalk contains 10% calcium,3% carbon,and 12% oxygenFind the amount (ingrams) ofthese compounds in 1 kg of chalk. |
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Answer» 1kg=1000gram 1. Calcium(10%)= (10/100)*1000=100 gram 2.carbon (3%)= (3/100)*1000=30 gram 3. oxygen (12%)=(12/100)*1000= 120 gram |
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| 68617. |
8. Chalk contains 10% calcium, 3% carbon and 12% oxygen. Find the amount (in grams) of each of thesecompounds in 1 kg of chalk |
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| 68618. |
Chalk contains 3% of carbon 10% of ealeum and 12% of oxygen. Find the amount in gramsof each of these substances tn 1 kg of chalk |
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| 68619. |
1 गान % &gt = || sy |
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Answer» (1/2) * 1 = Rs. 0.5 = 50 paise PLEASE HIT THE LIKE BUTTON |
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| 68620. |
8 %2B \frac 1 4 p < 2 p |
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Answer» As solvingit 8< 2p-P/4 8<7p/432<7p32/7<p |
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| 68621. |
Find the zeroes of the quadratic polynomial x2+7x+10. |
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Answer» X²+7x+10=0 x²+2x+5x+10=0 x(x+2)+5(x+2)=0 (x+2)(x+5) = 0 x+2 = 0 ; x = -2 x+5 = 0 ; x = -5 Like my answer if you find it useful! |
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| 68622. |
ULTUUSU U SCUOI12. Find the roots of the quadratic polynomial x2 -2X-8 |
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Answer» x^2-2x-8=x^2-4x+2x-8=0; x( x-4)+2( x-4)=0; (x-4)( x+2)=0; x=4, -2 x^2-2x-8=0; x^2-4x+2x-8=0 x( x-4)+2(x-4)=0 ( x+2)( x-4)=0 x=-2, 4 |
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| 68623. |
Find the zeroes of the quadratic polynomial x2 + 7x + 12, and verify therelationship between the zeroes and coefficients. |
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| 68624. |
(quad*(text*((5/8)*(i*i))))/8 %2B 7/9 - 1/2 |
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Answer» first find the lcm of denominator then make the denominator same then subtract or add |
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| 68625. |
Find the zeros of the quadratic polynomial x2 +7x+10 and verify the relationshipbetween the zeros and the coefficients. |
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Answer» x²+7x+10=0 x²+2x+5x+10=0 x(x+2)+5(x+2)=0 (x+2)(x+5) = 0 x+2 = 0 ; x = -2 x+5 = 0 ; x = -5 Relationship between the zeroes and coefficients :- Sum of zeroes = -2+(-5) = -2-5 = -7/1 = -x coefficient /x² coefficient Product of zeroes = (-2)(-5) = 10/1 = constant/x² coefficient Hope it helps |
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| 68626. |
Find the area of the triangle in which(i) a 13 m, b-14 m, c 15 m;(ii) a 52 cm, b 56 cm, c 60 cm;(iii) a 91m,b 98 m , c 105 m |
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| 68627. |
Construct triangle ABC with BC = 7.5 cmAC = 5 cm and angle C = 60 |
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| 68628. |
7. 6) Chalk contains calcium, carbon and oxygen in the ratio 103:12. Find the percentageof carbon in chalk.i) If in a stick of chalk, carbon is 3g, what is the weight of the chalk stick? |
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| 68629. |
7.(i Chalk contains calcium,carton and oxygen in the ratio 10.3:12. Find the percentageof carbon in chalk.(W) If in a stick of chalk, carbon is 3g, what is the weight of the chalk stick? |
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| 68630. |
1-PY7. Ifp = 4-9, prove that p'+48. If a + b = 8 and a2 + b2 = 40 find the value of a3 + b32 nrove that 83-863 - 36ab = 27. |
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Answer» (a+b)^2=a^2 +b^2 +2ab(8)^2= 40+2ab64=40+2ab64-40=2ab24= 2ab24÷2=ab12=ab(a+b)^3= a^3+ b^3+3ab (a+b)(8)^3= a^3+b^3+3*12(a+b)(8)^3= a^3+b^3+ 36(a+b)(8)^3=a^3+b^3+36*8(8)^3=a^3+b^3+288(8)^3-288=a^3+b^3512-288=a^3+b^3224=a^3+b^3 |
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| 68631. |
के. उ, 4, 10, 33, 136 है |
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Answer» This is following a pattern3*1+1,4*2+2,10*3+3,33*4+4,136*5+5so series will be3,4,10,33,136,685 |
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| 68632. |
B s B PR T7 i i4t Gt 1) Htan” -1 =0T 5y |
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| 68633. |
फिरGt¥ +3x+2 |
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| 68634. |
In the following circuit equivalent resistanceand B is.between the points A3013136Ω1319(A)Ω20Ω90(C) Ω13(D) Ω90. |
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Answer» As middle resistance will be removedso resistance will be in seriesand will be addedso (3+6) and (20+10) now these two will be in parallel conditionso Option- c = 90/13 please like the solution 👍 ✔️👍 |
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| 68635. |
9 - 1 \frac { 2 } { 9 } \text { of } 3 \frac { 3 } { 11 } \div 5 \frac { 1 } { 7 } \text { of } \frac { 7 } { 9 } = ? |
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| 68636. |
7/9 - 4/9 |
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Answer» 7/9 - 4/9(7-4)/93/91/3 when denominators are same and nominators are different in subtraction,we should divide only the nominators .ex:denominator is 9. so answer is 7-4/9 =3/9. simple 😀 sorry different answer give me😒 |
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| 68637. |
Thesum of the zeroes of the quadratic polynomial x2-13 is-1S-(b) 13(c) 13 (d |
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Answer» sum of zero of a polynomial is -b/a = 0/1 = 0 , option (a) is correct |
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| 68638. |
13. Find the area of the triangle in which(i) a 13 m, b-14 m, c-15 m;(ii) a 52 cm, b 56 cm, c 60 cm;(iii) a 91 m,b 98 m, c 105 m |
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Answer» thank you very much Bhai |
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| 68639. |
5.9 Jr. Ligue 2, LAOG and/Bog, forma lindar baire. Determine themeasure of ZAOC and ZBOG6n4B उ |
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| 68640. |
2×7÷9+2-8+6 |
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Answer» according to the bodmas14/9-6+6= 14/9ans 14/9 is the correct answer for this question Thank you 14/9 is the correct answer the answer of this question is 14/9 |
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| 68641. |
1081 000༠(17 g4 ) (o |
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| 68642. |
4 \frac { 7 } { 9 } - 2 \frac { 2 } { 3 } |
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Answer» hope it may help u |
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| 68643. |
-2-7t 979) 19 |
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| 68644. |
7/9+(-2/3)+(-11/8)+1/6 |
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Answer» -79/72 is the right answer please mark me the best answer |
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| 68645. |
G4. If the common difference of the A.P is 3, then find the value of a20-a15 |
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Answer» We know that,an=a+(n-1)dSo,a20=a+(20-1)(3)a20=a+19(3)a20=a+57 Similarly, a15=a+14da15=a+14(3)a15=a+42 Now,a20-a15=(a+57)-(a+42)=a+57-a-42=57-42=15 |
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| 68646. |
3. 10 +3+ (-2) + 1 + (-4)13 462tit C-4)F-141+ G4)FlotG-4)4.-11) + 8 - 11 - (-1) |
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Answer» (-11)+8-11-(-1)=(-11)+8-11+1=-11+8-11+1= 22-9=13 |
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| 68647. |
The simplest form of 12-3 [5 +3{(7 - 9) -2 }] |
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Answer» thanks |
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| 68648. |
Convert the following percents into fractions in simplest form:(i)25%(ii) 150%iii)7 1/2%iv)33 1/2% |
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Answer» thanks |
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| 68649. |
1. Express each of the following ratios in simplest form:(i) 24:40(ii) 13.5 15(iii)6: 792(iv):(v) 4:5:(vi) 2.5 6.5 8 |
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| 68650. |
7.Rewrite the following rational numbers in the simplest form:2545-44İLİ(iv)7210 |
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