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70701.

The base and corresponding altitude of a parallelogram are 10 cm and 12 cm respectively.The other altitude is 8 cm. The length of the pair of parallel side is

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yes it is the correct answer it is very correct answer

70702.

(14) Sketch the following graphs:(i) y-3 sin x

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thanks

70703.

Class 6INDIAN TALENT.The teacher wrote the expression given below for 4 students to calculate theage of the given elephant. x2 x 4-15If x represents the number of students,what is the age of given elephant?a. 42 yearsb. 60 years49 yearsd. 36 years

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Given expression:x^2 x 4 - 15

Where x = Number of studentsSo x = 4

Therefore,Age of Elephant= 4*4*4 - 15= 64 - 15 = 49 years

70704.

11. A rectangular room of dimension 8 m x6m × 3 m is to be paulted. I fit costs t 60 per sqiarermetre, find the cost of painting the walis of he room.

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Thank u so much sir/mam

70705.

Calculate the area of the shaded region.122m26m20022m

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70706.

A room measures 8 m long, 6 mwide and 3 m high. Its inner wallsand the floor were painted. Whatwas the area painted?

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Area = 2(8+6)= 28m^2

lateral surface area of a rectangle is 2(lb+bh+hl)subtract roof -lb2(8*6+6*3+3*8)-8*62(48+18+24)-48180-48=132m²

70707.

2. The triangular side walls of a lyover have been used for advertisements. The sides ofthe walls are 122 m, 22 m and 120 m (see Fig. 8.9). The advertisements yield an earningof t 5000 per m' per year. A company hired one of its walls for 3 months. How muchrent did it pay?122m120mFig. 8.9

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70708.

Find the length of the largest pole that can be placed in a hall 10 m long, 10 m wide and5 m high.Hint. Length of the diagonal of the room-v2+b2+h29.

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70709.

The walls and the ceiling of a hall 20 m x 16 m x 10 m are to be painted. From each can of pairnt130 m2 of area is painted. How many cans of paint are required to paint the room?

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70710.

o of an oetagon, lind the side of the o tagois 340 en and length is 125 cmiFind the breadth of a rectangle whose perimeter

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perimeter of rectangle is 3402×(125+b)= 340125+ b = 340÷2 = 170b= 170-125b= 45

70711.

9. The are a of a parallelogram, whose base is b and corresponding altitude h, is(i) bh(ii) 2bh(iii) 10h(iv) none of theseIl)bh

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option 1..area of a parallelogram = base * height =b*h

70712.

Kartik is k year old.Rehaan age r is 6 less than 2 time KartiK age which of the Following equation best Represents Rehaan age

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70713.

ot- find the value of sin a

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70714.

There is a slide in a park. One of its side walls has been painted in some colour with amessage·KEEP THE PARK GREEN AND CLEAN" { see Fig. I 2. İ 0 ). If the sides ofthewall are 15 m, 11 mand 6m, find the area painted in colour.3.KEEP THI E PARKGREEN AND CLEAN15

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70715.

2The triangular side walls of a flyover have been used for advertisements. The sides othe walls are 122 m, 22 m and 120 m (see Fig. 12.9). The advertisements yield aearning of t 5000 per m per year. A company hired one of its walls for 3 months, Homuch rent did it pay?122m22m120mFig. 12.9

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70716.

The floor of the hall is to be tiled fulller size. Find the number of tiles required.7. The dimensions of the floor of a rectangular hall are 4 m x 3 m.8 cm × 6 cm rectangular tiles without breaking tiles

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Dimensions of floor of Reactangular hall are length l = 4m = 400 cmbreadth b = 3m = 300 cm

Dimension of tileslength l1 = 8 cm, breadth b1 = 6 cm

Let number of tiles required = n

Then, n*Area of tile = Area of floor n*(l1*b1) = l*bn = 400*300/8*6n = 50*50n = 2500

Therefore number of tiles required = 2500

70717.

2. The triangular side walls of a flyover have been used for advertisements. Thesides of the walls are 122 m, 22 m and 120 m (see Fig. 11.9). The advertisementsyield an earning of Rs 5000 per m' per year. A company hired one of its walls for3 months. How much rent did it pay?122m22m120m

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70718.

The floor of a rectangular room measures 16 m by 1 1 m. The floor has to be tiled with squaretiles of length 40 cm. Find the number of tiles required.

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perimeterof rectangular room16*11= 176 m^2= 17600cm^2

number of tiles required = 17600/40=440 tiles are required

70719.

3. There is a slide in a park. One of its side walls has been painted in some colour with a"KEEP THE PARK GREEN AND CLEAN" (see Fig. 8.10). If the sides of themessagewall are 15 m, 11 m and 6 m, find the area painted in colour.KEEP THE PARKGREEN AND CLEAN15 m

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tq

70720.

A hall room 3910 m by 3570 m is to be paved with equalsq. tiles. Find the side of the largest tile which will exactlyfit and number of such tiles required?la 402

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Length of room is: = 3910 cmwidth of the room is: = 3570 cm

Now we can factor the distances (length and width): 3910 = 2 ∙ 5 ∙ 17 ∙ 23 3570 = 2 ∙ 3 ∙ 5 ∙ 7 ∙ 17

GCF of the length and width is: GCF(3910, 3570) = 2 ∙ 5 ∙ 17 = 170 cm Hence, the side of the tile is equal to 170cm, so the area of one tile is Stile = (170cm) 2 = 28900 cm2 .

The area of the room: Sroom = 3910 ∙ 3570 = 13958700 cm2 Number of tiles: N = Sroom Stile = 13958700 28900 = 483 tiles

Answer: side of the tile is 170 cm, number of tiles: 483.

70721.

4A flooring tile has the shape of a parallelogram whose base is 24 cm and thecorresponding height is 10cm. How many such tiles are required to cover a floor of 1080 m^2.(If required you can split the tiles in whatever way you want to fill up)

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Given : base= 24 cm

Height= 20 cm

Area of floor= 1080 m²= 1080×100×100cm²

[1m²= 10000cm²]

Area of the Parallelogram = base xheight

= 24 x 10 = 240 cm²

Area of1 tile = 240 cm²

[Tiles are in the shape of a parallelogram]

Number of tiles required= Area of theFloor/Area of the Tiles

= 1080 X100 X100/240 =45000

Number of tiles required to cover a Floor=45000

70722.

A die235-4040 415650-5565-60.

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When a dice thrown one time we get the following outcomes

S = { 1 , 2 , 3, 4, 5, 6}

n(S) =6

Let A be event of getting number greater than 2

A = {3, 4, 5, 6}

n(A) = 4

Probability of getting a number greater than 2 is = n(A)/n(S)

4/6 = 2/3 [dividing both numerator and denominator by 2]

Ans is 2/3

70723.

Find the dimensions of a rectangle whose perimeter is 28 meters and whose area is 40square meters.

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70724.

A person divided his property among his only son and two daughtersin the ratio 2 :1 :1. If the share of his son's property is worth Rs60000, then what is the total property of the person?

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Let 2:1:1 be 2x , 1x and 1xATQ2x+1x+1x = 600004x = 60000x = 60000/4x = 15000

then 2x = 2*1500030000

and 1x = 1*1500015000

2x/4 = 60000

Total property x = 60000*2 = 120000

70725.

203a slide in a park. One of its side walls has been painted in some colour with a5 m. 11 m and 6 m, find the area painted in colour.ereEEP THE PARK GREEN AND CLEAN" (see Fig. 12.10).If the sides of theKEEP THE PARKGREEN AND CLEAN15 m

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70726.

There is a slide in a park. One of its side walls has been painted in some colour with amessage "KEEPTHE PARK GREEN AND CLEAN" (see Fig. 12.10).If the sides of thewall are 15 m, 11 m and 6 m, find the area painted in colour.11 mKEEP THE PARKGREEN AND CLEAN

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70727.

Bol Wants to cover a room 3 m 50 cm wide and 6 m long by squared tiles. If each square tile isside 0.5 m, find the number of square tiles needed to cover the floor

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Area of floor = length * breadthFloor Length= 3.5 m, Breadth = 6 mArea of floor Af = 3.5*6 = 21 m^2

Area of tile = side*sideTile side length = .5 mArea of tile At = .5*.5 =.25 m^2

Let number of tiles needed be nThen, n*At = Afn*.25 = 21n = 21*4 = 84

Number of tiles needed = 84

70728.

The length and breadth of a floor of a room is 5 m by 8 m. It is to be covered with square tiles. If each square is of 25 cm, find the number of tiles required.

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number of tiles = area of rectangular floor/ area of square tiles= 500*800/625640 tiles are requiredn= 500*800/625n= number of tiles

sir full answerde

70729.

9. The following table gives the heights of plants in centimetre. If the mean height of plants is 6095cm; find the value of 'fHeight (cm) 50 55 5860 65 707No of plants2 4 104

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70730.

The Length of a plot is four times is breadth. A playground measuring 1200 square meters occupies a third of the total area of the plot. What is the length of the plot in meters?

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70731.

2. Find the area of a circle circumscribing an equilateral triangle of side 15 cm. [Take pi = 3.14]

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thank you

70732.

which of the two has larger area _a rectangle of dimensions 20cm × 12cm or a square of side 15 cm

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length of the rectangle= 20 cmbreadth of the rectangle= 12 cmarea of the rectangle= length×breadth= 240 cm²

side of the square= 15 cmarea of the square= (side)²= (15)²= 225 cm²

therefore, area of the rectangle is having the larger area.

area of rectangle = L×B = 20×12 = 240cm^2and area of square= side^2 =15×15 =225cm^2hance larger area is rectangular area that 240cm^2

70733.

QID: 13 - In a certain code language, '=' represents'+', represents 'x', '+' represents '-' and 'x'represents '-'. Find out the answer to the followingquestion.6 x 20 - 5 - 20 + 4 = ?Options:1) 112) 373) 144) 35

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answer is 1) 11 hoga

answer 1 eleven11

70734.

3. IfA and B commute, then prove that (AB)n A"Bn n, for all nEN.

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70735.

4. Problem : Use mathematical induction to prove that 2.4 (2n +1)3(n) is divisible by 11,マneN.

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70736.

42. If axb = 3 + 6j + 2k, la=4, angle betweena and 6 is 30°, then b is:nen

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70737.

जुी (८-9, (६-20 से विभाज्य $,neN

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70738.

For what value of k will be k+9, 2k-1 and 2k+7 are the consecutive tern of an arithmetic progression.

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70739.

The least number of square tiles that willbe needed to pave a plot 225 m by 30 m is(A) 30 tiles(C) 25 tiles(B) 15 tiles(D) 45 tiles

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The side of the square tile must be a factor of both 225 and 30, so that no tile needs to be cut.

For least no. of tiles, the size of the tiles should be maximum.So, the side of the square tiles must be the HCF of 225 and 30 = 15 m

Area of plot = 225 * 30Area of tile = 15 * 15

No of tiles = area of plot / are of tile = 30

70740.

how many square tiles of side 50 centimetre will be required to cover a floor of 3m X 4m

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area of square50×50=2500 area of floor=3×4=12no of tiles= 2500÷12=28.3

70741.

8 meters length and 6-meter width is a sequence of square tiles in the capital of a room, how many tiles will it see?

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8multiply by 6 48 is the answer

70742.

5. In an Α.Ρ., if pth term. is-and q tern is-, prove that the surn of firstpqterms is(pq +1), where pヂq.

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Given:-pth term = 1/q,that is ap= a + (p-1)d = 1/q=>aq + (pq - q)d = 1 --- (1)Similarly, we get:-ap + (pq - p)d = 1 --- (2)From (1) and (2), we get:-aq + (pq - q)d =ap + (pq - p)d=>aq - ap = d[pq - p - pq + q]=>a(q - p) = d(q - p)Therefore, a = dEquation (1) becomes,dq + pqd - dq = 1 d = 1/pqHence a = 1/pqConsider, Spq= (pq/2)[2a + (pq - 1)d] = (pq/2)[2(1/pq) + (pq - 1)(1/pq)] = (1/2)[2 + pq - 1] = (1/2)[pq + 1]

70743.

3. A room is 10m50cm long and 9m60cm wide. How many square tiles of side 15 cmwill be required to pave it?

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Area of the room is 500×540cm=270000Now,Area oa square tiles =15×15225cm.To find number of tiles required? Area of room ÷Area of tiles =72therefore 72 tiles are required to pave the room

70744.

QUESTION FOR DAY 7Q7. In a certain coded language BAT is coded as 2012, BALL iscoded as 121212. What will be the code of BOWLER?(A) 1851223152(C) 95323152(B) 1815221352(D) 185223152

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The position of each alphabet in the word is written but in the reverse order. Like the position of alphabets in the word BOWLER is 2, 15, 23, 12, 5, 18. So, the code is 1851223152

70745.

In a certain code language, if'PRIME' is coded asRPHEM, then how will 'GIVEN' be coded in thesame language?

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thanks

70746.

(J3.Write the following sets in Tabular form:(1) A={4 nEN, 2 +1 = 34, and a = 2}, a, a, - 1}Vid B = {4, :ne N, a +2 = 4r+l+( C = {3"-2":nEN, I Sns 5).

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70747.

In an AP, if the common difference (d) -4, and the seventh term (ar) is 4, then find the firsttern1.

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70748.

ve-that2rsec.。.cn兮"N

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70749.

its first negative term

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70750.

Find the common difference of the Arithmetic ProgressionA.P.1 3-a 3-2aЗа , 3a , (a=0)

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Common difference is 3-a/3a-1/a=3-a/3a-3/3a=-a/3a=-1/a