Explore topic-wise InterviewSolutions in .

12^2-7^2=(12-7)(12+7)=5*19=95using identity a^2-b^2=(a-b)(a+b)

3x^2+5x+6=0X=-b+-√b^2-4ac/2aX=-5+-√25-4*6*3/6X=-5+-√25-52/6X=-5+-√-27/6hence this equation has imaginary roots

Equating the real and imaginary parts:-

3=9^x. and 2y=7=>x=1/2. and y=7/2

P(B/A)=P(AintersectionB)/P(A)hence P(AintersectionB)=0.4*0.6=0.24

tnx

thnk u sir

the difference between two numbers is 5and the sum of their square is 97 find the numbersthis problem is based on quadratic

1)Given ODE ordinary differential equation of 1st order 1st degree:

y' + 2 y = Sin x

1) Generic solution: First we solve for y' + 2 y = 0 dy/dx = - 2 y dy/y = - 2 dx Ln y = -2 x + K y = e^{-2x + K} where K is some constant. or, y = A e⁻²ˣ , where A is some constant.

We can do this using the characteristic equation and using Euler method. y' + 2 y = 0 r + 2 = 0 => r = -2. Generic solution: c * e^{r x} = c e^{-2x}

2) To solve particular solution: y' + 2 y = Sin x Let y = a Sin x + b Cos x So y' = a Cos x - b Sin x

So a Cos x - b Sin x + 2 (a sin x + b cos x) = Sin xCompare the coefficients: 2a - b = 1 a + 2 b = 0Solving these equations we get: a = 2/5 and b = -1/5Particular solution: (2 Sinx - Cos x) / 5

Complete solution: y = A e⁻²ˣ + 2/5 Sin x - 1/5 * Cos x

4)i) Given one is a first order linear differential equation in the form of (dy/dx) + f(x)*y = g(x)Applying with a special method of using integrating factor this can be solved in a simple form.

ii) Here f(x) = sec(x); so ∫f(x) dx = ln|sec(x) + tan(x)|So the integrating factor is: [e^{∫f(x) dx}] = e^{ln|sec(x) + tan(x)|} = sec(x) + tan(x)

iii) Multiplying the given equation through out by the integrating factor,{sec(x) + tan(x)}*(dy/dx) + [sec(x){sec(x) + tan(x)}]*y = tan(x)*{sec(x) + tan(x)}

Integrating both sides, y*{sec(x) + tan(x)} = ∫{sec(x)*tan(x) + tan²x} -------- (1)

[Note: Derivative of y*{sec(x) + tan(x)} = (dy/dx)*{sec(x) + tan(x)} + {sec(x)*tan(x) + sec²x}*y]

iv) ∫{sec(x)*tan(x) + tan²x} dx = ∫{sec(x)*tan(x) + sec²x - 1} dx = sec(x) + tan(x) - x + C ----- (2)

Thus from (1) & (2):y*{sec(x) + tan(x)} = sec(x) + tan(x) - x + C

From which book have you taken this question? Please tell us so that we can provide you faster answer.

can you please explain me in easy way

This is easiest

Please hit the like button if this helped you

9x+6y=154x-6y=14

Adding both equations,13x=29x=29/13Put this value of x in any equation and get the value of y

x=ay/bax+by=a^2+b^2a*ay/b+by=a^2+b^2a^2y+b^2y=b(a^2+b^2)so y=b(a^2+b^2)/(a^2+b^2)=bso y=bso x=a*b/b=a

121 ÷ [17- {15 - 3 (7-4)}]= 121 ÷ [17 - (15 - 9)]= 121 ÷ [17 - 6]= 121 ÷ 11= 11

y = -xy = x + 5

solving we get

y = -y + 5

2y = 5

y = 5/2

y = 2.5

x = - 2.5

no

cosθ+ secθ = 2cosθ+ 1/cosθ = 2 cos²θ + 1 = 2cosθcos²θ + 1 - 2cosθ = 0(cosθ - 1)² = 0cosθ = 1

So,cos²θ+ sec²θ cos²θ+ 1/cos²θ (cos⁴θ + 1)/cos²θ2/1 = 2

Θ and (3θ-30°) are acute angles such thatsinθ=cos(3θ-30°)or, sinθ=sin[90°-(3θ-30°)] [∵, cosθ=sin(90°-θ)]or,θ=90°-3θ+30°or,θ+3θ=120°or, 4θ=120°or,θ=30°∴, tanθ=tan30°=1/√3

(1+sin theta)/ sin theeta1/sin theta+1cosec theta+1please like the solution 👍 ✔️👍

Thanks menon

7th term=a+6d=4a+6(-4)=4a=4+24=28

3y² - 20 = 160 - 2y²

5y² = 180

y² = 180/5 = 36

y = √(36)

So, y = 6 or -6

(x - 2y - 5z)²

Use (a+b+c)² = a²+b²+c² + 2(ab+bc+ac)

x² + (-2y)² + (-5z)² + 2 ( -2xy - 5xz + 10yz)

x² + (-2y)² + (-5z)² - 4xy - 10xz + 20yz

Hit like and BeScholr

Like if you find it useful

Et the sum be 100.100. Then double the sum means, 200.200.

From the above we can say that for 2020 years the amount is 200200 and the interest is 100100 for 2020 years. for one year the interest is 5.5.

We can easily say that, 55 is 5%5% of 100.100. Therefore rate of interest is 5%5%

or

let sum=100,100

then using given data, for 2020 years,amount = sum + interest =22(sum)=200200

therefore interest is 100100 for 2020 years. For one year it is 55Then interest =5100×100=5%5/100×100=5%

It will be5/100×100=5%

l=1mb=70cm70cm =0.7 m

area =lb=1(0.7)=0.7sqmcost =₹80(0.7)=₹56

Area = Length * Breadth

=(80*35)m

=2800m²

The cost of levelling = 4.50*2800

= Rs 12600

a+b=a^3+b^312+8=12^3+8^3 =1728+512 =2240Therefore, the answer is 2240

tq

ok

2/5 is the answer for thos

sorry the answer isa^-6/7

area of rectangle = l×b1250=50×bb=25cm

perimeter of rectangle=2×(l+b) =2×(50+25) =150cm

10000 - 8000 = 2000

: 18 percent of 2000

is your answer

that is 360 rupees GST

THEREFORE , CGST and SGST are 180 rupees.

Like my answer if you find it useful!

Area = 1540/10 = 154 m²

Area of Circle = πr² => πr² = 154=> r² = (154 * 7)/(22)=> = 49=> r = 7m

Cost is 30000 which is 10 per m*m so area = 30000/10 = 3000 m*m Breadth = 50m Length = Area / Breadth = 3000/50 = 60m

If you find this answer helpful then like it.