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2+2+5-4+7+7+6-46+7-5%7+8+8-8+6+8+76+8+86-+

7+7+7+7+7+7+777+64+4+9+4+8+5+

Find the average of six numbers, if the sum of the first four is 40 and the sum of the other two number is 26

S7= 49S17= 289S7

=7/2[2a+ (n- 1)d]S7= 7/2[2a+ (7 - 1)d]49 = 7/2[2a+16d]7 = (a+ 3d)a+ 3d= 7 ...(i)Similarly,S17= 17/2[2a+ (17 - 1)d]289 = 17/2 (2a+ 16d)17 = (a+ 8d)a+ 8d= 17 ...(ii)Subtracting equation(i)from equation(ii),5d= 10d= 2From equation(i),a+ 3(2) = 7a +6 = 7a =1Sn=n/2[2a+ (n- 1)d]=n/2[2(1)+ (n- 1)× 2]=n/2 (2+ 2n- 2)=n/2 (2n)=n²

The term October heat refers to the post-monsoon, pre-winter rise in temperatures across the nation. During the southwest monsoon, most parts of India cool down due to precipitation (rainfall), increased moisture, cloud cover, and sea winds in coastal areas.

The Krebs cycle occurs in the mitochondrial matrix of all eukaryotic cells that have mitochondria

(i) Shri Shantilal’s investment = No. of shares × MV

= 150 × 120 = ₹18000

(ii) Dividend per share = FV × Rate of dividend

= 100 × 7%=7/100x 100= ₹7

(iii) Total dividend received : = No. of share × dividend per share

= 150 × 7

= ₹1050

(iv) Rate of return (ROR)=Dividend−received/Sum−investedx100=1050/18000x100= 5.83∴ The rate of return on investment = 5.83%

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Given: □ABCD is a trapezium where, AB ll CDDiagonals AC and BD intersect at point O.

Construction: Draw a line EF passing through O and also parallel to AB.

Now, AB ll CD, since by construction, EF ll AB ⇒ EF ll CDConsider the ΔADC,EO ll DCThus, by Basic proportionality theorem, (AE / ED) = (AO / OC) .... (i)Now, consider Δ ABD, EO ll AB,Thus, by Basic proportionality theorem, (AE / ED) = (BO / OD) .... (ii)From (i) and (ii), we have, (AO / OC) = (BO / OD) (since L.H.S of i and ii are equal)Hence we proved that, (AO / OC) = (BO / OD)

GivenFV of share = Rs 10Amount invested = Rs 12000MV of share = 10 + 2= 12

Number of shares bought = 12000/12= 1000

FV=100 MV=120Dividend 7% therefore dividend 7% on investment of 120

Rate of return=Dividend income/ sum invested × 100=7/120 ×100=5.83

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calculator te krla brother

5 months 14 days

Thank u. Hi My name is Aashish

5 months and 14 days

Time span = 31+30+31+31+30+15

= 168 days

as this is in AP 2q=p+r----eq(1)

as in GP q=p.c & r=p*c2where c=common difference,

putting in eq(1) 2*p.c=p+p*c2hence c^2+1-2c=0 or ( c-1)2=0 so c=1

frm(1) p-q=q-r or

(p-q)/(q-r)=1=c or

(q-r)/(p-q)=1=c

y = a(x-g)² + hLet x = 0 and y = 0 at the vertex of the parabola, the highest point of the arch at the midpoint of the bridge. Further, let y be positive in the downward direction so that y = 0 at the midpoint and 10 at the ends of the span where x = ±50.Then g = h = 0 and:y = ax²

We know that y = 10 at x = ±5010 = a(±50)² = 2500aa = 10/2500 = 1/250

At x =±10, the height of the bridge will be h = 10-y(±10)h = 10 - 100/250 = 10 - 2/5 = 10-.4 = 9.6 ft

Given that the man gets 4% profit on his investment.Hence income on 1 share of market value Rs 80 = 4% of Rs 80= (4/100) × 80 = Rs 3.20Therefore on Rs 50 the company pays Rs 3.20Thus for Rs 100 the company has to pay, The rate percent paid by the company is 6.4%We got Income on1 share = Rs 3.20Therefore, income on 200 shares = Rs 3.20 × 200 = Rs 640

from where digit 18 comes

a+b /2 is the answer of ur question prasana

IN ΔABD and ΔCBD ,

AD = CD [ given ]BD = BD [ Common ]AB = BC [ given ]

ΔABD ≅ ΔCBD [ SSS ]∠ABD = ∠1 ∠CBD = ∠2∠1 =∠2 [ CPCT ]

Also ,∠3 = ∠4 [ CPCT ]

Hence ,

BD bisects both the angles ABC and ADE

Given:diagonal AC of parallelogram ABCD bisects ∠A.

∠CAB =∠CAD

To show:

(i) It bisects ∠C also,

(ii) ABCD is a rhombus.

Proof:

i)

In ΔADC and ΔCBA,

AD = CB

(Oppositesides of a ||gm)

DC = BA

(Oppositesides of a ||gm)

AC = CA (Common)

Therefore,

ΔADC ≅ ΔCBA

( by SSS congruence rule.)

∠ACD = ∠CAB ……(i)

(by CPCT)

∠BCA= ∠CAD…..(ii)

(By CPCT)

& ∠CAB = ∠CAD…..(iii)

(Given)

From eq i,ii,iii,

All 4 above angles are equal to each other..

Hence, ∠ACD = ∠BCA

Thus, AC bisects ∠C also.

(ii) ∠ACD = ∠CAD (Proved)

AD = CD (Opposite sides of equal anglesof a triangle are equal)

But, AB= CD & AD= BC

[Opposite sides of a parallelogram]

AB = BC = CD = DA

Hence, ABCD is a rhombus.

=========================================================

Hope this will help you...

Total surface area of cubiod = 2(lb+bh+lh);so 2(8*7.6 +7.6*3.5+8*3.5);2(60.8 + 26.6 + 28);2(115.4);230.8 m square;so door is 25 m square;so total = 230.8-25;205.8 m square

no it is of Perimeter and area.and answer is 84.2m2 how

1) FOOT : A foot is a unit for measuring length, height, or depth, and is equal to 12 inches or 30.48 centimetres. When you are giving measurements, the form 'foot' is often used as the plural instead of the plural form 'feet'.HANDSPAN : The maximum distance between the tips of the thumb and little finger, taken as the basis of a measurement equal to 9 inches. 'Use your hand span to measure the distance around a tree trunk.'

2) METRE :The metre or meter is the base unit of length in some metric systems, including the International System of Units. The SI unit symbol is m.KILOMETERS: A kilometer is a metric unit of distance or length. One kilometre is a thousand metres and is equal to 0.62 miles. About twenty kilometres from the border.

F(x) = sin^2(x) + cos^2(x)

f '(x) = 2 sin(x) cos(x) + 2 cos(x) (-sin(x))

= 2 sin(x) cos(x) - 2 cos(x) sin(x)

= 0

Since the derivative is zero everywhere the function must be a constant.

Take f(0) = sin^2(0) + cos^2(0) = 0 + 1 = 1

So

sin^2(x) + cos^2(x) = 1

FV=₹50 and Premium=₹100MV=FV+premium=50 + 100=₹150No. of shares=200Purchase price of 200 shares=No. of shares×MV=150×200=₹30,000Brokerage=₹20Total investment=₹30000+₹20=₹30020Dividend=50%Dividend=Rate of dividend×FV=50% × 50₹25.*.Dividend on 200 shares=200×25=₹5000He sold 100 shares at a discount of ₹10.MV=FV- Discount =50-10₹40Selling price of 100 shares=No. of shares×MV=100×40₹4000Brokerage=₹20Amount received after selling 100 shares=selling price - brokerage=4000-20=₹3980Remaining 100 shares were sold at a premium of ₹75MV=FV +Premium₹50 + 75=₹125Selling price of 100 shares=No. of shares×MV₹|00×125=₹12500Brokerage=₹20Amount received after selling remaining 100 shares=selling price- brokerage=12500-20=₹12480.*.Total amount received=5000+3980+12480=₹21460Total investment=₹30020Loss=Total investment-total amount received=₹30020-₹21460=₹8560.*. Mr D'souza incurred a loss of ₹8560.

In case of a rectangle the length of the two diagonals are always equal, and they both meet at their midpoint.

Thus, AC = BD

or, (1/2) AC = (1/2) BD

or, OA = OD

or, 2x + 4 = 3x + 1

or, -x = -3

or, x = 3

Therefore, value of x is 3.

(100/720)100

13.88 %

-7 because it has numerator-7 so -7is the write answers

1/√2 is right answer

by contradiction methodroot 2 is irrationalthe reciprocal of irrational is irrational

2. root 5 is irrational product of rational and irrational is irrational

Initial number = 650

Increased number = 715

Increase in number = 715 - 650 = 65

Percentage of increase = 65/650 × 100

Percentage of increase = 10 %

27 - composite number35 - composite number41 - prime number

thanks

Angle CDB = 52°

Please refer the above photograph for the used process.

KEY POINTS TO REMEMBER :-

In a Rhombus :-1)All sides are equal to each other.

2)Opposite angles are equal to each other.

3)Diagonals will bisect each other at 90 degrees.

4)All the properties of a Parallelogram is followed by a Rhombus.