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1)Given, volume of each cube is 64 cm³⇒s³=64⇒s=∛64⇒s=4 cm.When two cubes are joined ,the length of the resulting cuboid(l) = side + side = 4+4 = 8 cmits breadth(b) = side = 4cmAnd its height(h) = side = 4cmTotal surface area of a cuboid = 2(lb+bh+hl)⇒TSA=2[(8)(4)+(4)(4)+(4)(8)]⇒TSA=2(32+16+32)⇒TSA = 2(80)⇒TSA = 160 cm²∴ The surface area of the resulting cuboid is 160 cm².

Let the distance traveled by the car in 6seconds=AB=X metresHeight of the tower CD=h metresThe remaining distance to be traveled by the car BC =d metresAC =AB+BC=x+d metresANGLE PDA=ANGLE DAC=30ANGLE PDB=ANGLE DB*C=60

TRIANGLE BCD TAN60=CD/BC=root3=h/dh=root3dTRIANGLE ACD TAN30=CD/AC1/root3=h/(x+d)h=(x+d)/root3(x+d)/root3=root3dx+d=3dx=2dd=x/2Time taken to travel x metres =6secondsTime taken to travel the distance of D metres i. e., x/2=6/2=3seconds

first integer 156 &second integer122

let the integer is xthen,-156 + x = -278x = -278 + 156x = 122 correct answer

the answer will be -122

first integer 156 and second integer 122

let integers be x. =-156+x=-286. x=-286+156=-130

first integer 156 and second integr 122 hi hoga this is aright answer hai

x + y = - 278- 156 + y = - 278y = 122

-122 is correct answer

-156+x =-278 x= -278+156x=-122

first integer 156 second integer 278-156=122

let us consider the integer as xthen,-156+x=-278x=-278+156therefore,x=-122 correct answer

The answer of this question is -122

let the integer is X, then --156+X=-278x=-278+156X=-122 ans

iska answer mujhe nahi pata hai bhai log sorry

First integer is 156 and second integer is 122

let the no. is x then sum of two no. is = x + (-156) = -278 x - 156 = -278 × = -278 + 156x = -122

first is 156 and second is 122

-122 is correct answer

the sum of two integer is= -278 one of the integer is =-156the other is = -278 - (-156) = -122

The another integer is -122Therefore, -156+(-122)=-278

122 is the correct answer

x should be 122 and integer

x+(- 156)=- 278 x=- 278+156x=-122 (-++=- चिन्ह बड़ी संख्या का लगता है)

the answer is 122 finally

first integer 156 and second integer 122

let the integer is xthen,-156+x=-278x=-278+156x=-122first integer is -122 and second is -156

the sum of two I integers are=_278one of then is=_156let the integers be=× so,one is _156 and another is=×so,×_156=_278×=_278+156×=_122

let,the second integer be xa/q -150+x=-278or, x=-278+150or,. x=128

(-122) is the required answer.

the answer will be -122 right answer

f falan hai kyonki har ek x ke lie unique ( alag) value prapat karta hai, example ke lie f ko x = 3 ke lie check kare to

f (3) = 9

Par, g x = 2 par do value de sakta hai g ( 2) = 2² = 4

g(2) = 6

Jo ek falan ke definition ke virudh hai

388499+66935647390286

Original price = Rs.1New Price = Rs.65

Increase in price = 65-1 = Rs 64

Therefore, increase percentage =(Increase in price÷ Original price)×100=64÷1 × 100=6400%

Original price = Rs.1New Price = Rs.65

Increase in price = 65-1 = Rs 64

Therefore, increase percentage =(Increase in price÷ Original price)×100=64÷1 × 100=6400%

i) No. Value of sin(x) always lies between -1 and 1.

ii) tan A means tangent of angle A.

iii)4x=28 x=28/4 x=7is the best answer

vii)2x-3=9 2x=9+3 x=12/2 x=6is the best answer

iii) x=7is the best answer. vii)x=6is the best answer.

x=7&x=6is the answer to the question.

The PF of 10 is 2*5. 10 is not a perfect square, because 2 and 5 only appear once, and one is odd.

The PF of 16 is 2*2*2*2. 16 is a perfect square, because 2 appears four times, and four is even.

The PF of 24 is 2*2*2*3. 24 is not a perfect square, because 2 appears three times, and 3 appears once. Three and one are both odd numbers.

Any multiple of 10, 16, and 24mustcontain each of their prime factorsat leastas many times as they appear in the numbers being multiplied. So for example, the LCM (least common multiple) of 10, 16, and 25 must contain four factors of 2 (since 2 appears four times in the PF of 16), one factor of 3 (since 3 appears once in the PF of 24, and nowhere else), and one factor of 5 (since 5 appears once in the PF of 10, and nowhere else. Here is the PF for the LCM of 10, 16, and 24:

2*2*2*2*3*5 = 240

But 240 isn’t a perfect square, since the factors 3 and 5 appear only once.

If we multiply 240 by any other number, the result willstillbe divisible by 10, 16, and 24. And since the number we’re seeking has even numbers of prime factors, we can simply multiply 240 by 3*5 (or 15) to get the smallest perfect square that is divisible by 10, 16, and 24:

2*2*2*2*3*3*5*5 =3600.

To find the least length of rope which is sufficient to encircle the region, we have to find out the circumference of the circular region.Given : radius = 63 cmCircumference of circle = 2πr= 2*22/7*63Circumference = 396 cmLength of rope to encircle the region is 396 cm

lets put m=4 so 6*4-4=24-4=20m=6 so 6*6-4=36-4=33 so m=6

lets put x=5 so 7*5+2=35+2=37m=-5 so 7*-5+2=-36+2=-33 so m=-5

thanks very much

144 is correct answer

the correct answer is 85

the cost of 12 pencil is 12/4×483×48=144

Cost of 4 pen = Rs. 48cost of 12 pen = 48 × 3 = Rs. 144Hence, the cost of 12 pens is Rs. 144

cost of 12 pens is rupees 144

144 is the correct answer

If u draw the height which the line perpendicular from the vertex to base it divides the 120 degree angle into 2 equal angles.

And Also this perpendicular bisector bisect the base into equal parts.

So u get two 30 -60 -90 triangleswhere side opp the 60 degree angle = 9also by the formula for this special trianglelength of side opp 60degree angle= x√3

9 = x*√39/√3 = x3√3 = xalso side opp the 30 degree angle = altitude= x = 3√3

thanks but can u do it

thanks

Hypotneuse = 5 mBase = ?altitude = 4 mBase² = hyp² - alt²b² = 5² - 4²b² = 25 - 16b =√9b = 3 m

When base is reduced by 1.6 mBase = 3 - 1.6 = 1.4 mhypotneuse = height of ladder = 5 maltitude = ?

alt² = hyp²- base²alt² = 5² - 1.4²alt² = 25 - 1.96alt =√23.04alt = 4.8 m

a

Flatworm, also called platyhelminth, any of the phylum Platyhelminthes, a group of soft-bodied, usually much flattened invertebrates. A number of flatworm species are free-living, but about 80 percent of all flatworms are parasitic—i.e.,livingon or in another organism and securing nourishment from it.

Total possiblites in tossing is 2

Favourable possiblites in tossing of getting heads is 1so probability is 1/2 = 1/2so Harish statement is false

For this find 7/10 of 30hence7/10*30=7*3=21 pieces.

21 pieces

thanks

As jug have 275 ml of water

If Sophia poured 1/5 of water out of jug

Then,Amount of water left in jug= 275(1 - 1/5)= 275(4/5)= 55*4 = 220 ml