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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 71001. |
1. Given âłABC ~ âłJKL, find JK.6.1 ft17 ft30.5 ft |
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Answer» JK = 17 ft as both are congruent triangle |
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| 71002. |
Prove that diagonal AC of a rhombus ABCD bisects ZA as well as ZC. |
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| 71003. |
Theorem 8.7 :If the diagonals of a quadrilateralbisect each other then it is a parallelogram. |
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| 71004. |
9 ft39 ft27 ftArea: |
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Answer» please like my answer if you find it useful thankyou so much for your answer I appreciate it even though I didn't get line number 2 but I still liked your answer😊 |
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| 71005. |
A carpenter can frame 8 windows with 20.4 ft of lumber. How many windows can be framed with 816ft lumber?7. |
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Answer» 8 windows can be framed with 20.4 ft of lumber.=> 1 window can be framed with (20.4/8) = 2.55 ft of lumber.=> 2.55 ft of lumber is used to frame one window=> (816) ft of lumber would be used to frame (1/2.55)*816= 320 windows. PLEASE HIT THE LIKE BUTTON |
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| 71006. |
The diameter of a circle is 7.5 cm. From one end point of the diameter a chordof length 6 cm is drawn. What is the distance between the second end points ofthe diameter and the chord?65. |
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| 71007. |
If the face value of both the shares is same, then which investment ouf of thefollowing is more profitable ?Company A : Dividend 16%. MV= ₹ 80.Company B : Dividend 20%. MV=₹ 120 |
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| 71008. |
717. Find the roots of the equation x + V-218. Sh4. |
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Answer» x + √(x - 2) = 4 √(x - 2) = (4 -x) x - 2 = (4 - x)² x - 2 = 16 + x² - 8x x² - 9x + 18 = 0 x² - 6x - 3x + 18 = 0 x ( x - 6) - 3 ( x - 6) = 0 (x - 3)(x - 6) = 0 So, x = 3 and x = 6 |
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| 71009. |
2. Find the squares of numbers given below :(1) 18(ii) 11(iv) 15(v) 200 |
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Answer» i)18=18_2 = 18×18 = 324ii)11=11_2 = 11×11 = 121iv)15=15_2 = 15×15 =225v)200= 200_2 = 200×200 =40000 |
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| 71010. |
15. If each side of a cube is doubled, then its volume is(a) is doubled(b) be comes 3 times(c) be comes 8 times(d) none of t16. The height of a cone is 24 cm and the d: |
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Answer» b is the answer i.e becomes 3 times |
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| 71011. |
(a) none of these36. The length, breadth and height of a cuboid are 10 cm, 8 cm, and 9 cm respetively then its volune is(a) 720 cm 337, The each adn nf(b) 725 cm3(c) 720 cm(d) none of these. |
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| 71012. |
Prove that the area of any quadrilateral withperpendicular diagonals =-× Product ofdiagonals.10. |
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Answer» Proof :Since the diagonals AC and BD of quadrilateral ABCD bisect each other at right angles.Therefore, AC is the perpendicular bisector of the segment BD.A and C both are equidistant from B and D.AB = AD and CB = CD ... (1)Also , BD is the perpendicular bisector of line segment AC.B and D both are equidistant from A and C.AB = BC and AD = DC ... (2)From (1) and (2), we getAB = BC = CD = ADThus , ABCD is a quadrilateral whose diagonals bisect each other at right angles and all four sides are equal.Hence , ABCD is a rhombus. now it is proved tha ABCD is a rombus and area of Rombus =1/2 product of diagonals.Hence, proved |
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| 71013. |
1. Write the next terms of the following sequences(ii) 1,5, 13, 29,1 3 7152'4'8'16'(iii) 3, 6, 11, 18, 27,(iv) 2, 5, 11, 23, ..02' 6' 24 |
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Answer» Please help me with this question.. Like this only cn i do in exm... By writing it in a proper way? since they asked u only to write the next term u can do the steps in rough work column and fill the answer |
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| 71014. |
. You are painting a wall that has a circularwindow as shown in the figure. You have enoughpaint to cover 70 sq ft of the wall. Do you need tobuy more paint? Explain how you got your answer4 ft8 ft12 ft |
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| 71015. |
&. Which of the following statements are true and which are false?(al The diagonals of a parallelogram are equal.(b) The diagonals of a rectangle are perpendicular to each other(c) The diagonals of a rhombus are equal. |
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| 71016. |
. a) In a rhombus ABCD, the diagonals intersect at (3, 4) If the point A is (1, 2 find the equationsof the diagonals. |
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| 71017. |
ez 2 oh WihBle biDilelei) & [l © Blk © SF M6 .0 i o5L S0+,= |
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Answer» sin 67 + cos 75 sin (90 - 23) + cos ( 90 - 15) cos (23) + sin ( 15) |
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| 71018. |
If diagonals of a parallelogram bisect its angles, then prove that the diagonals will beperpendicular to each other. |
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| 71019. |
You are painting a wall that has a circularwindow as shown in the figure. You have enoughpaint to cover 70 sq ft of the wall. Do you need tobuy more paint? Explain how you got your answer.4 ft8 ft12 ft |
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| 71020. |
Find the cost of a plot which is 70 m long and 60 m wide if the cost of 1 sq. m is rupees sixthousand |
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Answer» area of plot is 70×60 = 420m²total cost is 420× 6000 =2,520,000 rupee thanku yrr |
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| 71021. |
3. An aquarium is in the form of a cuboid whose external measures are 70 cm x 28 cm x35 cm. The base, side faces and back face are to be covered with coloured paper. Findf rest a n gular hall are 15 m Ă 12 m Ă 4 m. There are 4the area of the paper needed |
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Answer» Given length = 70cm breadth = 28 cm height = 35 cm. Area of base = l * b = 70 * 28 = 1960 Area of side base = b * h = 28 * 35 = 980 Area of back face = l * h = 70 * 35 = 2450. Area of the paper needed = 1960 + 2450 + 2(980) = 1960 + 2450 + 1960 = 6370 cm^2. |
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| 71022. |
1. Nazma's sister also has a trapezium shaped plot. Divide it into three parts as shown(a + b)2(Fig 1 1.4). Show that the area of trapezium WXYZ = hă 2. lf h = 10cm, c = 6 cm, b = 12cm,d 4 cm, find the values of each oflo its parts separetely and add to findthe area WXYZ. Verify it by puttingthe values of h, a and b in thebth(a + b)expression-taFig 11.4 |
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| 71023. |
If the perimeter of a rectangle is 100 cm and its length (l) is 20 cm more thanIts breadth (b), find its length and breadtha)l=30 cm, b = 10b)l=40cm, b = 60 cmc)l=35 cm, b = 15 cmd) of these |
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Answer» 2x+2(x+20) = 100 4x = 100-40 4x = 60 x = 15 cm = breadth length = 20+15 = 35 cm |
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| 71024. |
eyl 18 0 0= Ol ¢ हक - ‘ 1 |
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| 71025. |
EXERCISE 5.2sill in the blanks in the following table, given that a is the first term, d the cdifference and a, the nth term of the AP:(ii)18(iii)(iv)-18.9(v) 3.510018IV2.53.60105 |
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| 71026. |
12 18 32 lcm |
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Answer» 2| 12, 18, 32 2| 6, 9, 16 2| 3,9, 8 2| 3,9, 42| 3,9, 2 3| 3, 9, 1 3| 1,3, 1 | 1,1, 1 LCM = 2 x 2 x 2 x 2 x 2 x 3x 3 =288 right |
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| 71027. |
HCF of two numbers is 82 and their LCM is 244188. If one of them is 1428, findsother numberI find their HSE |
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Answer» 14022 is your answer 14,022 is the right answer |
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| 71028. |
The number of sides of a polygon with35 diagonals is ................. |
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| 71029. |
Area of a Rhombus is 70 sq.cm. whose diagonals are of length x + 2 cm, x-2 cm. Findthe lengths of diagonals. |
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| 71030. |
(c) 8244. यदि L का अर्थ X,M का अर्थ +, N का अर्थ -,P काअर्थ + हो तो 44M64N64P15L4 का मान क्याहोगा?(a) 13(b) 82(c) 72(d) 92 |
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Answer» option (c) is the correct answer the answer is opttion a l= x, m =+, n = - , p = ÷, 44m64n64p15l4; 44+ 64-64÷15×4= 44 + 64-64÷15 × 4 =44 + 64 -4.266×4 = 44 + 64-17.06=108-17.06 = 90.94 B) is correct answer |
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| 71031. |
1. Find the perimeter of each of the following figures :2cmI cm15 cm23 cm35 cm35 cm15 cm(c)40 cm |
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Answer» Exe 10.1. chapter 10 |
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| 71032. |
82 "018 . |
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| 71033. |
(-82)÷[-80+(-2)] |
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Answer» (-82)÷[-80+(-2)]=(-82)÷[-80-2]=(-82)÷(-82)=1so the answer is 1 |
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| 71034. |
LCM ..12 82 |
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Answer» lcm of 12and 82 is 2 lcm of 12and 82 wll be 492 12,82=2×6,41=6×41=246 The L.C.M. of 12 and 82 is 492 because 492 is divisible by 12 and 82..°. L.C.M. = 492 |
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| 71035. |
dyFindin the following:ах1. 2x + 3y= sin x |
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| 71036. |
2x +3y = sin x, W d‘—id का मान ज्ञात कीजिए |
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| 71037. |
15x + 3y = 9 -----(1)Place x = 3 in equation (I).5x + 3y = 92r + 3y = 12 ----- (11)Let's add equtions (1) and (IT).5x + 3y = 9+ 2x - 3y = 123y = 9-O3y = Ox=.. Solution is (x, y) = (CD). |
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| 71038. |
9, DrawABC of measure 60° such that AB-4.5 cm and BC = 5 cm. Through C draw a lineparallel to AB and through B draw a line parallel to AC, intersecting each other at D.Measure BD and CD |
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| 71039. |
=\frac{4 x y}{x+y} \times(x) \frac{p+2 x}{p-2 x}+\frac{p+2 y}{p-2 y} |
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| 71040. |
9. Find the measure of the side of a rhombus if its diagonals35 cm and 28 cm. |
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Answer» Let ABCD be a rhombus. with O as intersection of diagonals.And we know that diagonal bisect each other>OA=1/2AD=35/2=17.5>OB=1/2BC=28/2=14By Pythagoras TheoremAB^2=OA^2+OB^2AB^2=17.5^2+14^2AB^2=502.25AB=√502.25AB=22.14cm |
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| 71041. |
2.Suppose you are given a circle. Give a construction to find its centre. |
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| 71042. |
Set - 11. Find the 6th term of the sequence whose n'h term is |
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Answer» 6th term=(1/6)^6-1 =(1/6)^5 =(6)^-5 |
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| 71043. |
If the ratio between 5th and 10h terms of an A.P. is 1:2 and 12th term is 36, find that A.P. |
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Answer» n'th term in ap = a + (n-1)d Thus, here, 5th term = a+4d 10th term = a+9d 12th term = a+11d Given, (a+4d) / (a+9d) = 1/2 or, 2a + 8d = a + 9d or, a = d Also given, 12th term ⇒ a + 11d = 36 or, 12d = 36 [as a=d proved previously] or, d = 3 Thus, a = 3 Therefore, the ap: 3, 6, 9, 12, 15, 18... tq |
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| 71044. |
82-(61- 6th "S |
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| 71045. |
\frac { 3 } { 2 } \operatorname { log } 4 - \frac { 2 } { 3 } \operatorname { log } 8 + \operatorname { log } _ { 2 } = \operatorname { log } x |
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Answer» 2/3log4-2/3log8+log2=log(2^2)^2/3-(log2^3)^2/3+log2=log2^4/3-log2^2+log2=log((2^4/3×2)/2^2)=log(2^(8/3-2))=log(2^2/3)so x=2^(2/3) |
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| 71046. |
\begin { equation } \log (x+3)+\log (x-3)=3 \log 2+\log 5 \end { equation } |
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| 71047. |
Find dy / dxin the following:1, 2x+3y =sin x |
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| 71048. |
7.160Finddydxin the fol2x+3ysin x |
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| 71049. |
1.62. Add the following rational numbers:)4 and (andv)4 and (v) 36 and-and-31 and83. Simplify:7vi9 -426 - |
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Answer» i) 3/4 - 5/8 = (3×2)/(4×2) - 5/8 = 6/8 - 5/8 = 1/8 v) -31/4 - 5/8 = (-62-5)/8 = -67/8 i) 8/9 - 11/6 = (8×2-11×3)/18 = -17/18 v) 7/9 - 3/4 = (7×4-3×9)/36 = (28-27)/36 = 1/36 If you find this answer helpful then like it. |
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| 71050. |
14. Suppose ABCD is a parallelogram in which AB = 9 cm and its perimeter is 30 cm. Find the length ofeach side of the parallelogram. |
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Answer» opposite side of parallelogram is equal let breath= x9×2+2x=302x= 30-18=12x= 12/2=6 cm two opposite side length = 6cm samantar parallelogram me equal side in front of each other... (9cmx2)+(2Other)=30 = 30-18=12 =12/2=6 ans. 6 answers of this question 6cm answers of this question the opposite sides of ||gm is equalso, let breadth is= x9×2+2x= 3030-18=2x12=2x6=x the answer of the following question is 6 6cm is the correct answer |
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