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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 73301. |
3. .. ina ABC, m/ B = 90, BM is an altitude on AC . If BM-2130 , MC = 6 then find ACA-ind thg porimoter of A ARG |
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| 73302. |
Lied the values of |
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Answer» value of x is= 2π/3. |
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| 73303. |
EXAMP 11 In the given figure, D and E arethe points on the base BC ofAABC such that BD CEAD - AE and LADE- LAEDProve that AABE AACDSOLI Ä°TION |
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Answer» Given :BD = CE and AD = AE and ADE = AED, InABE and ACD AE = AD ( Given ) ADE = AED ( Given )AndBD = CE ( Given )We add both side DE and get BD + DE = CE + DEBE = DC Hence ABE ACD ( By SAS rule ) ( Hence proved ) |
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| 73304. |
How5. Using a measuring tape, measure the length and fill in the blanks(a) Your bed is 180 cm.(b) Your notebook is 26.5 cm.(C) Your pencil box is 18(d) Your study table is 30cm.(e) -is the longest of all four.is the shortest of all four.cm.(0) - |
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Answer» e.)bedf.) pencil box is best answer🏆🏆🏆 a. 200 cmb. 30 cmc. 15 cmd. 60 cme. bedf. pencil box e).Bed is the longest of all four.f). Pencil box is the shortest of all four. |
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| 73305. |
सब us — | ()V पथ + ¥ 098 = e |
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Answer» By doing rationalization √ (1+sin)(1+sin)/(1-sin^2 theta√(1+sin)^2 theta/ cos^2 theta1+sintheta/cos theta sec theta+ tan thetaplease like the solution 👍 ✔️👍 |
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| 73306. |
are root of the following trinomi32. 144+ 24x +x |
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| 73307. |
(-9)/5 %2B (-3)/7 %2B 4/5 %2B 5/3 |
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Answer» LCM WILL BE 105 now175+84-45-189/10525/105 |
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| 73308. |
Find the product of (5-9)5. (x +5) (x + 4) |
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| 73309. |
5. If the temperature ofa liquid can be measured in Kelvinunits as x"Korin Fahrenheitunits as y F the relation between the two systems of measurement of temperatureis given by the linear equation(r-273) +32Find the temperature of the liquid in Fahrenheit if the temperature of theliquid is 313°K.If the temperature is 158"E then find the temperature in Kelvin.(0)(ii) |
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| 73310. |
02.ne na bicycleuntut-T were 21, find the unl o ple who beoloed their ticketsIn particular bag ofr ando r ities. Find the amount ofpote Sugar Mr. Mohan can ver, if he lours of swart that hasA new crida aluse01. |
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| 73311. |
12. Find the length of the height of an equilateral triangle of side 24 cm. ITake 3 -1.73]Hint··) x 24 x h-va-24 x 24 . Find h. |
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| 73312. |
Write the unit that is used to measure the following.(a) A shoe(b) A train(c) Teacher's height(d) A book(e) A building(f) Length of a car(g) A pencil box(h) Length of a bridge |
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Answer» 1. Foot2. Km, m3. mm, cm, m, km.4. Cm, mm, km5. Foot, m6.m7. m8. m footkm,mmm,cm,m,kmcm,mm,kmfoot,mmmm foot km,mmm,cm,m,kmcm,mm,kmfoot,mmmm |
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| 73313. |
While dividlymainder is zero or the degree of the Tomdivisior polynomial.Note that, in the above example (3), thethe degree of the divisior 3p. Similarly in the(2r - 6) is less than the degree of the divisicPractice Set1. Divide. Write the quotient and the remain(1) 21m + 7m(2(3) (-48p) + (-9p?)(5) (5r- 3x?) + x(7) (2y + 4y + 3) = 27² (8.(9) (6x - 4x + 8x' + 2x) + 2x? (1 |
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Answer» 1 3m.m3. -8p. p5. 5 x- 37. y+ 2y.y /3 remainder 9. 3x.x.x-2x.x +4x +1is the correct answer of all |
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| 73314. |
the triangle.12. Find the length of the height of an equilateral triange of side 24 cm. ITake 3 -1.73)vs3-x 24x h =2x 24x 24 . Find h.4Hint. |
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Answer» thank you |
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| 73315. |
-28/45 - 4/15 %2B (4/9)/5 %2B (3/10)*(4/9) |
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Answer» 4/45-12/45+12/90-28/458-24+12-56/90-60/90-2/3 -2/3 is the correct answer of the given question -2/3 is the correct answer |
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| 73316. |
(iii) 1 dm3iv) IO00 unl7. If the dimensions of a room are I, b and h, (I length, I - breadth and h > height)4then which of the following is the area of its four walls?(iii) 2 1(h + h)(iv) 2 h + 1+ bt ic the area of the four walls of |
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Answer» area of four wall= 2h(l+b) |
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| 73317. |
\sqrt { 7 } y ^ { 2 } - 6 y - 13 \sqrt { 7 } = 0 \quad [ J h ] |
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| 73318. |
3y xtan y then finddydxn x, then find |
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| 73319. |
for âm: 4(3m + i)-2(2m+ 3)-3(m + 4) + 2m + 7 |
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Answer» 4(3m +1) - 2(2m +3) = 3(m+4) + 2m + 712m + 4 - 4m - 6 = 3m + 12+2m + 7(12-4-3-2)m = 19 +23m = 21m = 21/3 = 7 Value of m = 7 |
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| 73320. |
3x + y = 1, (2m-1)x + (rn-by-2m+1.CBSE] |
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Answer» 3x + y =1 (2k-1)x+(k-1)y=2k+1 => 3x+y-1=0 (2k-1)x+(k-1)y-2k-1 =0 We know, a1/a2 = b1/b2 not equal to c1/c2 has no solution Now,we have, a1=3 , b1=1 a2=2k-1 , b2 = k-1 3/2k-1 = 1/k-1 3(k-1) = 2k -1 3k-3 = 2k -1 3k -2k = -1 +3 k = 2 |
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| 73321. |
jt tonsiuer an exampDivide 2r+3x+1 by r +2. |
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| 73322. |
wbeJtiusn16 In 4 years time, a baby7 Banu is 20 years older than Binu. In 5 years, Banu will be twice as old as Binu. Find their present ages |
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| 73323. |
-1/5 %2B (-2 %2B 4)/10 %2B 2 %2B 9 |
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| 73324. |
sphere is(a) 2/3(b) 3/452. [(tan(a) (tanx) ((c) 2 tan 1x+ c(b) (tan )(d) 2 (tan-1 x2 +c4253.5log x -1)dx is equal to |
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Answer» thanks |
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| 73325. |
T/2Evaluate :sin xsin x + cos xusing properties. |
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Answer» 1 |
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| 73326. |
l-find using properties:-a)-2 450H4 H 72.3 73 77 |
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Answer» -4/21 is the answer of this question |
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| 73327. |
xtan xProve that:sec x + tan x0 |
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Answer» let I = integration of (xTanx / Secx+Tanx) from o to pie -----(1) So using prop of defnite integration (i.e. by putting x = pi -x) we get I = in integration of (pi-x)Tan(pi-x) / Sec(pi-x)+Tan(pi-x) from o to pie which gives,integration of (pi-x)(-Tan(x) / (-Secx -Tanx) from o to pie , OR I = integration of (pi-x)(Tan(x) / (Secx + Tanx) --------(2) Adding (1) &(2) we get 2I = integration ofpi.Tanx / (Secx+Tanx)from o to pie, now convertingtrig termsintosinx &cosx, we get 2I =piX integration of Sinx/(1+ Sinx) from 0 to pi, which gives 2I = pi X integraiton of Secx tanx - tan^2x from 0 to pi, So 2I = piX (Secx -tanx +x) from 0 to pi, OR 2I = pi.((Secpi -tanpi +pi) - (Sec 0 -tan 0 +0)) = pi . ((-1-0+pi) - (1) ) = pi( pi-2), So I = pi .(pi -2) /2 |
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| 73328. |
sin 3x cos 4x |
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| 73329. |
Reena was standing facing North-West direction. She turns by 90° in anti-clockwise direction. Again she turns by 180° in anti-clockwise direction. Nowshe turns 45 in clockwise direction. Which direction is Reena facing now? |
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| 73330. |
A cone of height 6 cm is mounted on a cylinder of d = 16 cm and h= 8 cm. Find the total surface area of the object formed. |
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Answer» thnx Diksha |
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| 73331. |
(w)(4-k) x2 + (2k + 4) x + (8k +1)=0 |
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Answer» The given quadratic will be a perfect square if it has two real and equal roots. To have two real and equal roots the discriminant must be zero.i.e., b²-4ac=0or, (2k+4)²-4(4-k)(8k+1)=0or, 4k²+16k+16-4(32k-8k²+4-k)=0o², 4k²+16k+16-128k+32k²-16+4k=0or, 36k²-108k=0or, 36k(k-3)=0either 36k=0or, k=0or, k-3=0or, k=3∴, k=0,3 Ans. answer is ❌ wrong |
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| 73332. |
The curved surface of a cylindrical pillar is264 m2 and its volume is 924 m3. The diameterof the pillar is(a) 5 m(c) 10 m(b) 9 m(d) 14 mChapter |
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| 73333. |
Calculate the area of the shaded region gvenhe shaded region given in the2m2m2m2m2m2m2m 2mSm |
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Answer» Area = 1.5x10 + 2x8 + 2x6 + 2x4 + 2x2 = 55m2 |
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| 73334. |
Evaluate:integral dx/ (1- sin x) |
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| 73335. |
prove that tan4x=4tanx(1-tan^2x)÷1-6tan^2x+tan^4x |
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Answer» LHS = tan4x = tan(2x + 2x) use, the formula, tan(A + B) = (tanA+tanB)/(1-tanA.tanB) = (tan2x + tan2x)/(1-tan2x.tan2x) =2tan2x/(1-tan²2x) again, use the formula, tan2A = 2tanA/(1-tan²A) = 2{2tanx/(1-tan²x)}/[1-{2tanx/(1-tan²x)}²]=4tanx.(1-tan²x)²/(1-tan²x)(1+tan⁴x-2tan²x-4tan²x)=4tanx.(1-tan²x)/(1-6tan²x+tan⁴x) = RHS |
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| 73336. |
I=Integral(log((-sin(x) %2B 2)/(sin(x) %2B 2), 10), (x, (-pi)/2, 2)) |
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| 73337. |
Using properties of integral, evaluate 1+ sinOR |
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Answer» so putting limits we get[ tan pi - sec pi ] - [ tan0 - sec0]0 -(-1) -1 = 0so Integral will be zero |
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| 73338. |
Express tan4x in terms of tanx 5:44 pm |
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Answer» tan(-4x) = tan(4x)=-2 tan(2x)/(1-2tan(2x)^2, we substitute tan(2x)=2 tanx_/(1-tanx^2) |
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| 73339. |
4tanx (1 - tan?x)tan4x = 1-6tan2x + tan"XProve that |
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Answer» hit like if you find it useful |
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| 73340. |
Find p and q so that y p sin 3xcos 3x satisfy the equationdr4dx |
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Answer» dy/dx=3Acos3x-3bsin3xd2y/dx2= -9Asin3x-9bcos3x-9Asin3x-9bcos3x+4(3Acos3x-3bsin3x)+3(Asin3x+bcos3x)=10cos3x-9A-12b+3A=0=>-6A-12b=0=>A=-2b-9b+12A+3b=10=> -6b+12A=10=>-6b-24b=10=>-30b=10=>b=-10/30=-1/2so a= 2/3Ans a=2/3, b=-1/3 |
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| 73341. |
Harpreet's motorbike is facing towards West. He turns left anddrives 10 km and turns left again and drives 10 km. Then he turns rightand drives 40 km. He turns right again and drives 30 km. lastly; he turnsright and drives 50 km. How far is Harpreet from the starting point?(A) 10 km(C) 40 km(B) 20 km(D) 60 km |
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Answer» Ending and starting point are on the same line and they are 20kms away from each other. |
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| 73342. |
G=i-7j+7k X b=31-2j+ त༠|
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Answer» mod of this = √(19^2+(19^2)= 19√2 |
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| 73343. |
+4k. Find a vector d12. Let di+4)+2k, 2)+ 7k and +4k. Find a vd 15which is perpendicular to both a and b, and |
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| 73344. |
Miscellaneous Exercise on Chapter 10Find the values of k for which the line (k-3) x (4-)y -7k+6isa) Parallel to the x-axis,Parallel to the y-axis,Passing through the origin. |
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Answer» Equation of line is (k -3)x -(4 - k²)y+ (k²-7k+6) = 0 (a) we know, when any line parallel to x-axis then slope of line is equal to zero. slope of given line = (k-3)/(4-k²) 0 = (k-3)/(4 - k²)(k -3) = 0k = 3 (b) when line parallel to y - axis then, slope of line = ∞ = 1/0 here, Slope of line = (k-3)/(4-k²)1/0 = (k-3)/(4-k²)(4-k²) = 0k = ±2 (c) when line passing through origin Then, x = 0, and y = 0 So, (k-3)0 -(4-k²)0 + k²-7k+6 = 0k²-7k+6 = 0k²-6k-k+6 = 0k(k-6)-(k-6)=0(k-1)(k-6)=0k=1,6 |
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| 73345. |
TO TRIGONOMETRYplEXEREvaluate the following:sin 60° cos 30 + sin 30 cos 60°cos 45ll) sec 30° + cosec 30° |
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| 73346. |
Find the product of the following pa(i) 6, 7k (ii) -31,-2m |
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Answer» i) 6 × 7k = 42k ii) (-3l) × (-2m) = 6 lm |
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| 73347. |
sin 3x = 3 sinx -4 sinâx |
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Answer» Sin 3x = sin (2x+x)= sin 2x cos x + cos 2x sin x = 2sin x cos x cosx + (1–2sin^2x) sin x = 2 sin x (1–sin^2 x) + (1- 2 sin^2 x) sin x = 2 sin x - 2 sin ^3 x + sin x - 2 sin^3 x = 3 sin x - 4 sin^3 x Hence sin 3x = 3sin x - 4 sin^3 x |
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| 73348. |
1=Integral((sin(x)*cos(x))/(cos(x)^2 %2B 3*cos(x) %2B 2), (x, 0, pi/2)) |
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| 73349. |
17. sín 3x = 3 sin x = 4 síar财? |
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| 73350. |
'3 | (sinx/sin 3x) dx =कं. आर... अं T |
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