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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 74551. |
rishna bought mangoes at? 30 per dozen. He had to sell them at a loss of 6%. Findthe selling price of 1 orange. |
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Answer» now C.P.=30 per dozen6% is lossso S.P.=30-(30*6)/100=30-1.8=28.2 per dozen1 dozen=12 piecesso S.P. of 1 orange=28.2/12=2.35 |
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| 74552. |
/4 marks/4. Attempt the following:In the figure, BCBD and ray DE I| ray CB and rayBE bisects ZABD. Prove:(i) < EBD= <BDC(ii) BCDE is a parallelogram.Proof: |
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| 74553. |
9. In figure ray OS stands on a line POQ ray OR and ray OT are angle bisector of 13]LPOS and LS00 respectively If 4POS -. Find ZROT0 |
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| 74554. |
The cost of 3 kg of apples and 2 kg of. grapes on a day was found to be 160. After amonth the cost of 4 kg of apples and 2 kg of grapes is 300. Represent the situationas a pair of linear equations in two variables |
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Answer» I have another question |
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| 74555. |
Construct a line I, make a point A outside it and construct a line parallel to linewhich passes through A. Can there be any other line parallel to line I which asopasses through point A? |
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Answer» No not possible as it will contradict playfair axiom. |
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| 74556. |
1. Draw a line I. Take a point A outside the line. Through point A draw a lineparallel to line 1 |
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| 74557. |
Draw line AB. Take point M anywhere outside the line. Using a compass and ruledraw a line MN perpendicular to line AB. |
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| 74558. |
In a class, one-third of students had gone to watch drima Twice the squane routofthestudentshadgonetowatchnagic show and nemaining 12 students had gone to watch Soothall masch. Find the total number of stadests in the |
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Answer» Let the total number of students in Class be XThus according to questionStudent went to drama = A = X/3Student went to magic show =B =2 root XStudent went to football = C = 12Thus X= X/3 + 2 root X + 122X/3 = 2 root X + 122 root X= 2X/3 - 12Squaring both sides4X = 4X^2/9 + 144 - 48X/34X^2/9 - 60X/3 + 144 = 04X^2/9 - 20X + 144 = 04X^2 - 180X + 1296 = 0X^2 - 45X + 324 = 0X^2 - 36X - 9X + 324 = 0X(X - 36) - 9 (X-36) = 0X = 36thus total Students = 36 |
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| 74559. |
A vendor is selling apples at 84 a dozen and pears at96 a dozen. If the apples had been bought at 12 apair and the pears at 14 a pair, in selling which fruidoes the vendor earn a higher profit margin? |
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Answer» apples are 84 a dozen => each one sells at 84/12 =7pears are 96 a dozen => each sells at 8 rupees. apples are brought 12 a pair i.e., cost price of each is 6 rupees.for pears it is 14 a pair i.e., cost price od each is 7 rupees. |
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| 74560. |
Toffees are bought at 15 a dozen andsold at 2.50 per toffee what is the sellingprice per dozen? What is the loss or gain? |
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| 74561. |
21A man invests 10400 in 6% shares at 104 and 11440 in 10.4% shares at 143. Hoymuch income would he get in all? |
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Answer» =Rs 14.32 is the correct answer |
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| 74562. |
2. The cooking club is making fruitsalad for the class. They use 2 kgapples, 2 kg grapes, I kg orangesand 500 g bananas. What is theweight of the fruit salad? |
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Answer» total weight=2 kg+0.5kg+1 kg+0.5kg=4 kg |
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| 74563. |
\begin{array} { l } { \text { Write the ratio of the second quantity with the first. } } \\ { 10 \text { dozen pencils, } 90 \text { pencials } } \end{array} |
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Answer» second quantity is 90 pencilsFirst quantity 10 dozen of pencilsWe know 1 dozen = 12 unitsSo, 10 dozen = 120 unitsSo, ratio is 90: 120 = 3 : 4 |
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| 74564. |
If $u=\tan ^{-1}\left(\frac{x^{3}+y^{3}}{x-y}\right),$ prove that $x \frac{\partial u}{\partial x}+\frac{\partial u}{\partial y}=\sin 2 u$ |
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| 74565. |
selling 8 dozen pencils, a shopkeeper gains the selling price of one dozen pencils. Findhis gain per cent. |
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Answer» 8 dozen - 96let 1 pencil be for re. 1so 96 pencil is for9612 pencil is for 12.gain-12CP : SP- gain96- 1284gain percentage : gain/cp * 10012/84*100 |
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| 74566. |
Baseu IBy selling 8 dozen of pencilsshopkeeper gains the sellinof one dozen pencils. Find hisper cent.i dgain |
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| 74567. |
2. By selling 8 dozen ofpenciishopkeeper gains the sellinof one dozen pencils. Find higeper cent.prnis gain |
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Answer» thanks |
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| 74568. |
Write the ratio of the second quantity with the first.10 dozen pencils, 90 pencials6) |
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Answer» Explanation : 1 dozen = 12 items 10 dozen = 120 items ratio = 90 pencils : 120 pencils = 9 : 12 = 3 : 4 Solution : 3 : 4 If you find this answer helpful then like it |
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| 74569. |
Write the ratio of the second quantity with the first.10 dozen pencils, 90 pencials(6) |
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Answer» thanks |
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| 74570. |
. Find the length of the diameter 8. The circumference of a circle is 31.4 cm. Find the radius and the area of the circllCTE U(Take Ď = 3.14)whose area is 144 cm2 |
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Answer» Given circumference = 31.4 2* pie* r =31.4 r = 31.4/2*3.14 = 5area = pie*r*r =3.14 *5*5 =78.5 sq cm |
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| 74571. |
l. A lair die is 1nta U2. Find the length of lhe side of a square who!ơ area is44) ma. |
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| 74572. |
tIND K So THAT THE AREA OFAe is 2 u OVITS WITH VERTICES |
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Answer» A (1,-1), B(-4,2k) and C(-k,-5) ArΔABC = 1/2 [x1 (y2-y3) + x2(y3-y1) + x3 (y1-y2) ] 24 = 1/2 [1(2k+5) + -4(-5+1) + -k(-1-2k) 24 = 1/2 [2k+5 + 16 +(k+2k²)] 24 = 1/2 (2k+5+16+k+2k²) 24 = 1/2 (2k² +3k+21) 48 = 2k² +3k + 21 2k²+3k-27 = 0 2k² + 9k - 6k - 27 = 0 or 2k² -6k + 9k - 27 =0 2k(k-3) + 9(k-3) = 0 (2k+9) (k-3) = 0 ∴ k = -9/2 or 3 |
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| 74573. |
1. Two stones, having masses in the ratio of 3 2, aredropped from the heights in the ratio of 4 : 9. Theratio of magnitudes of their linear momenta justbefore reaching the ground is (neglect air resistance)(2) 2:3(4) 1 1(3) 3 2 |
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Answer» v²=u²+2as here in both case u will be zero momentum(p)=velocity × mass here we need v v=√2as (a=g=10m/s²) in first case v = √2×10×4 =4√5 p = 4√5 × 3 = 12√5in case 2 v=√2×10×9 = 6√5 p= 6√5 × 2 =12√5HENCE RATIO IS 1:1 |
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| 74574. |
1. Two stones, having masses in the ratio of 3:2, aredropped from the heights in the ratio of 4 9. Theratio of magnitudes of their linear momenta justbefore reaching the ground is (neglect air resistance)(2) 2: 3(4) 1 1(3) 3 2 |
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Answer» v²=u²+2as here in both case u will be zero momentum(p)=velocity × mass here we need v v=√2as (a=g=10m/s²) in first case v = √2×10×4 =4√5 p = 4√5 × 3 = 12√5in case 2 v=√2×10×9 = 6√5 p= 6√5 × 2 =12√5HENCE RATIO IS 1:1 answer is d 1:1hope it helps |
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| 74575. |
जात काये ।cobs. Since 1casua since |
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Answer» ( cosx - sinx/ cosx+ sinx)= ( cosx-sinx/ cosx+ sinx x cosx + sinx/ cosx+ sinx)= ( cosx^2- sinx^2/ ( cosx × sinx)^2= . ( cosx^2- sinx^2- cos2x; ( cosx+ sinx)^2- cosx^2-2sinxcosx+ sinx^2-1+ sin2x, cosx - sinx/cos+ sinx= cos2x/1+sin2x please like my answer |
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| 74576. |
792Find the cost of one pencil if a dozen pencils costs 18. |
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Answer» Given cost of dozen pencils = 18 Cost of one pencil = 18/12= 3/2= Rs 1.5 |
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| 74577. |
A shopkeeper bought some pencilsaRs. 18 a dozen and sold them atprofit of 20%. Find the selling price ppencil: |
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Answer» CP = 18 ruppesgain percentage= 20selling price = sp-cp/CP*100 = 20(sp-18/18)*100= 20sp-18= 20*18/100sp= 18+3.621.6rupee |
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| 74578. |
20. The excise duty on a certain item has beenreduced from 1275 to 969. Find thepercentage reduction in the excise duty forthat item. |
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| 74579. |
The cost price of an item is two-third of itsselling price. What is gain or loss percent onthat item ?(a) 45(c) 35(b) 50(d) of these |
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Answer» Let selling price of item SP = xThen cost price of item CP = 2x/3 Gain% = [(SP - CP)/CP]×100 = [(x - 2x/3)/(2x/3) ]×100 = [(x/3)*(3/2x)]×100 = (1/2)*100 = 50 (b) is correct option |
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| 74580. |
3. Theuced to R760 from 950. Find the reductionexcise duty on a certain item has been redper cent in the excise duty on that Item. |
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Answer» Thanks;) |
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| 74581. |
Hence, required ratio -(69+ 8):(161 +15)-7:16.EXAMPLE31 If there are (2n +1) terms in A.P., then prove that the ratio of the ssan gfeven terms is in +1):n.um of odá terms ani[ N CERT EXEMPLAm and ommon difference respectively of the given |
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| 74582. |
u cieetive area of the screen.4. A bicycle wheel has a diameter of 7 m 70 cm. How many times would the wheel rotatto cover a distance of 4.4 km?A o |
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Answer» Circumference of wheel = 2*pi*r = 2*22/7*7.7/2= 2.2 m In one rotatipn of wheel distance covered = 2.2 m To cover distance of 4.4 km number of wheel rotations= 4400/2.2= 2000 |
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| 74583. |
1. The diamener of a bicycle wheel is 28 m hat distance will it cover in 100 revolutions ? |
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Answer» Radius = diameter/2= 28/2 = 14cm Circumference = 2πr = 2π (14)= 28πDistance travelled in 100 revolutions = 28π*100= 2800π= 8796.46 cm Please hit the like button |
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| 74584. |
Two similar cones have volumes 12π cu, units and96π cυ.units,the curved surface area of the smaller cone is 15t sq units, what isthe curved surface area of the larger one?s |
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Answer» Let R = radius of base and L = lateral height, H = height of cone. curved surface or lateral surface = A = π R L , and volume = V = π/3* R² H, Similar cones have the same (cone) angle at the apex. Hence the same ratios among R, H and L. Let Cone 1 be the larger cone. Let R₂ = x R₁, H₂ = x H₁ and L₁ = x L₂ V₁ / V₂ = π R₁² H₁ / π R₂² H₂ = x³ = 96 π / 12 π = 8 Hence x = 2 Lateral Surface areas A₁ / A₂ = π R₁ L₁ / π R₂ L₂ = x² = 4 , as x = 2 A₁ = 4 A₂ = 4 * 15 π = 60 π square units. |
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| 74585. |
The cost of 12 dozen pencil is Rs 450.Then how many pencil will be sold in Rs 325 |
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Answer» 1 dozen=12pencils12 dozen=12*12=144 pencilscost of 1 pencil= 450/144=3.125then in Rs 325 ,104 will be sold 1dozen=12pencil12dozen=12*12=144pencilscost of1pencil=450/144=3.125then in Rs325,104 will be sold answers is = 12×12/450×325 = correct answer is =12×12/450×325= |
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| 74586. |
In fig, seg DH i seg EF andseg GK J seg ER If DH 12 em.GK 20 em and A (ADEF 300 cm2then find (i) EF (ii) A (ΔGEF) Eii) A (O DFGE).6. |
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| 74587. |
3.A bicycle wheel whose radius is 30 cm covered a distance in 70 revolutions.How many kilometres was this distance? (Take Ď =). |
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Answer» Like if you find it useful |
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| 74588. |
532ve that no matter what the real numbers a and bare, the sequence with nth terma+noisalways an A.P. What is the commons. Prove, Write the sequence with nth term |
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| 74589. |
The diameter of a bicycle wheel is 28 cm. What distance will it cover in 140 revolutions? |
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Answer» D = 28 cm ,r = 14c = 2πr = 2 x 22/ 7 x 14 =88 cm distance covered in 140 revolution = 88 x 140 = 12320m |
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| 74590. |
UPaw a histograrn tor the following data.Wt. (in Kg)No. of students 230. E, F, G, H are midpoints of sides AB, BC, CD, DA40-44 45-49 50-34 55-59 160-64 65-69812 1084respectively of a parallelgram ABCDProve that ar (EFGH)ar (11gm ABCDy |
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Answer» Like if you find it useful |
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| 74591. |
show that the diagonals of a 11gm divides it is four triangle of equal area |
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| 74592. |
00 ml of Dettol. How much Dettol is contained in 12 dozen sel OOll(1) 70 litres(3) 72 litres(2) 60 litres(4) 84 litres |
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Answer» 1 dozen has 12 bottles. 12 dozen = 12*12= 144 bottlesDettol contained in 12 dozen bottles= 500 *12*12= 72000 ml= 72 litres option 3 is correct. |
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| 74593. |
5. If the volumes of two cones are in the ratio of 1:4 and their diametersare in the ratio of 4:5, find the ratio of their heights. |
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| 74594. |
Find out the value of mode for the following data. If the frequency of item 15 changes from 3 to 9, find out the new mode. x = 6,9,12,15,18 f= 4,5,6,3,2? |
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| 74595. |
Find out the value of mode for the following data. If the frequency of item 15 changes from 3 to 9, find out the new mode. x = 6,9,12,15,18 f =4,5,6,3,2 |
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| 74596. |
OPORS is a rhombus. O is any point on theOPQRS is arhombus. Ois anydiagonal QS. Prove that seg OPseg OR.3 marks |
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| 74597. |
9. ABCD is a trapezium in which AB | DC and itsdiagonals intersect each other at the point O. ShowAO COBO DOthat |
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| 74598. |
9. ABCD is a trapezium in which AB 11 DC and itsdiagonals intersect each other at the point O. ShowAO COBO DOthat |
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| 74599. |
s. Ravi has a bicycle whose wheel makes 5000 revolutions in moving 11 km. Find the diameterof the wheel. |
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| 74600. |
12. In the adjoining figure, O is any point inside aparallelogram ABCD. Prove that(i) ar(AOAB) + ar(AOCD)--ar(11gm ABCD),(ii) ar(AOAD) + ar(AOBC) =-ar(11gm ABCD), A |
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