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143/3=143*2/3*2=286/6kgand 307/6kg307/6>286/6 hence Amit weighs more

Volume of wall=length×breadth×height=6×5×0.5 m³=15 m³

Volume of 1 brick= 0.25×0.125×0.075 m³= 0.000234 m³

Number of bricks required=15/0.00234=64102 bricks

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here consider theta as x

here consider theta as x

To find two rational number between -1/3 and 1/2 we have to take LCM of 2 and 3 which is 6 Now we have to multiple the both rational number to 6 at denomenater -1/3 *2/2=-2/61/2 * 3/3=3/6we get the rational numbers which are -2/6 and 3/6 so the two rational number are -1/6 , 1/6

Let us assume : x= root(6+root(6 + root(6 + ………

So,

x= root(6+x)

x^2=6+x

x^2-x-6=0

(x-3)(x+2)=0

So, x=3 or -2.

But taking -2 as the answer would mean we are taking root of (-2) . Considering the fact that x belongs to the set of real numbers , we discard the solution x=-2.

So the answer is x =3.

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GIVEN:parallelograms PSTQ and parallelogram PQRT.TO PROVE:ar(PST)=ar(QTR)=1/3*ar(PQRS)SOLUTION:ar(||gm PSTQ)=ar(||gm PQTR)•Since both the ||gms are on the same base and between the same ||'s.

Now,In ||gm PQTSar(PTS)=ar(PQT)-1•diagonal of a ||gm dived it into 2 triangles.Similarly,In ||gm PQTRar(PQT)=ar(QRT) -2=> by 1 & 2ar(PTS)=ar(PQT)=ar(QTR)=ar(PQRS)ar(PTS)=1/3ar(PQRS)SO....ar(PTS)=ar(QTR)=1/3ar(PQRS)

किलास6 पाठ विजयी विश्व तिरंगा प्यारा कवि के अनुसार हमारा ध्येय क्या है।

13x13=169 reverse 916

15 1062

the answer of the question is; (15)^2= 15*15 = 225

the answer of the question is225

import java.util.*;class print{public static void main (String args[ ]){System.out.println("B");System.out.println("LL");System.out.println("UU");System.out.println("EEEE");}}

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nooooooooooo..... what the heck is this???

LHS= -2/3 - [-4/5 - 1/2] = -2/3 - [-13/10] = -2/3 + 13/10 = 19/30RHS =[-2/3 - (-4/5)] -1/2 =[-2/3 + 4/5] - 1/2 = 2/15 - 1/2 = -11/30LHS is not equal to RHSTherefore substraction is not associative for the rational number

answer

We have to find three rational number between1515and1414.Let us considerx=1515, y=1414.Let us considern = 3.

We find the value ofd.d=y−xn+1=14−153+1=1204=180y-xn+1=14-153+1=1204=180.

Thus, the three rational numbers lying betweenxandywill be given as,

(x+d), (x+ 2d) and (x+ 3d).Substituting the values ofxandd,we get,

(15+180),(15+280)and(15+380)15+180,15+280and15+380

Thus,1780,1880, and19801780,1880, and1980Therefore, the rational numbers lying between1515and1414are1780,1880,1980

x²-5x-2 is the correct answer of the given

The correct answer =3600000

Area ABC=1/2× ABX AC=1/2×30×40=120/2=60 cm^2, Area ACB=VS(S-a)(S-b)(S-c)=:40×30=1200 cm^2

zbzhgxvz zbzbx xbz zb x

nshsvsbdbdbxc xbxbxbx

RHS= cos theta( 1+sin theta)/(1-sin ^2 theta)(1+sin theta)/cos thetasec theta+ tan theta

Length X breath X height 50 ×40× 30 = 60000 cm cube

decimals 28 .94 - 16.53/12.41/

25 +17.50+12.50=55in pieces-25 +17.50=42.5042.50+12.50=55

55 is the correct answer

the correct answer is 54

We add all and get 55$

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thanks very much

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Bhai acha aur full question puch

the answer is

We Have ,a - (-6) = 4a = 4 + (-6) = -2a = -2

Given, Exam paper contain 14 sheetsNumber of students = 1050

Then, Total number of sheets consumed = 1050*14= 14700

Xj

I pay ₹2720 for 8kg of coffee.how much do I have to pay for 40kg of coffee?

Loss = 18 - 13 = 5

Loss % = (5/18) * 100

= 27.7%.

Since the middle number of the three consecutive numbers is x, the other two numbers are x -1 and x +1.According to the given condition, we havex² = [(x +1)² -(x -1)²] +60x² = (x² +2x +1) -(x² -2x +1) +60 = 4x +60x² -4x -60 = 0 => (x -10)(x +6) = 0x = 10 or -6Since x is a natural number, we get x = 10Hence the three numbers are 9, 10, 11