Explore topic-wise InterviewSolutions in .

The domain is x belongs to R

and range is y belongs to R

C = D ( C+1 )

O= 4 ( 4th Vowel )

D = E ( D+1 )

E = 2 ( 2nd Vowel )

So Each Consonant is to be replaced with next Alphabet .

And Each Vowel is to be replaced with its place value ( A =1 E =2 I =3 O = 4 U =5).

LATE = M1U2

the right answer is option d

Sport psychologyis aninterdisciplinaryscience that draws on knowledge from many related fields includingbiomechanics,physiology,kinesiologyandpsychology. It involves the study of how psychological factors affect performance and how participation in sport and exercise affect psychological and physical factors. In addition to instruction and training of psychological skills forperformance improvement, applied sport psychology may include work with athletes, coaches, and parents regardinginjury,rehabilitation, communication,team building, and career transitions.

Tan^-1 ( sin x / 1 + cos x)

= Tan^-1 ( 2 sin x/2 cos x/2 / 2 cos^2 x/2 )

= Tan^-1 ( sin x/2 / cos x/2 )

= Tan^-1 ( tan x/2 )

= X/2. hence now d/dx(X/2)=1/2

your answer would be 39

let numbers at one place =2x; ten's place be = x; 10(x) + 1(2x)=10x+2x; 10x + 2x = 3x + 18; 12x-3x=18; 9x=18; x=18/9=2; the digit at one's place = 2x X = 2x2=4; digit in ten's place = x =2; the numbers is 10( x)+12(×) = 10(2)+1(2x)=20+(4)=24

let tenth place digit = xunit digit = x^2no = 10x+x^254 added digit reversenew no 10x^2+x10x^2+x= 10x+x^2+549x^2-9x=549(x^2-x)= 54x^2-x-6=0.x^2-3x+2x-6=0x(x-3)+2(x-3)=0(x-3)(x+2)=0x= -2(impossible)x= 3so nos= 10x+x^2 = 10×3+9 = 39

Unit Digit of Perfect Square. Squares: There is a definite relationship between the unit digits when square of a number is considered, E.g. 81, 121, 441, 961 all are Perfect Square having unit digit 1 and tens digit is even. – If unit digit of a number is 2 then it can't be a perfect square .

tan(A+B)=1/2+1/3/1-1/2*1/3=5/6/5/6=1henceA+B=tan^-1(1)=π/4hencesin^2(π/4)+cos^2(π/4)=1/2+1/2=1

V6=V2x3; V9=V3x3; V12= V4x3= V6×2;

tell me

given:two sides =18cm and 10 cmlet 3rd side be xcmperimeter=42 cm perimeter=18+10+x42=28+xx=42-28x=14cm

s=perimeter/2s=42/2s=21

using herons formulaarea of triangle=√s(s-a)(s-b)(s-c)=21(21-18)(21-10)(21-14)=21*3*11*7=4851cm^2

Area is triangle is 4851cm^2

1/1² + 1/3² + 1/5² + ...= (1/1² + 1/2² + 1/3² + 1/4² + 1/5² + 1/6² + ...) - (1/2² + 1/4² + 1/6² + ...)= (1/1² + 1/2² + 1/3² + ...) - (1/2²)(1 + 1/2² + 1/3² + ...)= (1 - 1/2²)(1 + 1/2² + 1/3² + ...)= (3/4)(π²/6)= π²/8.

first question first answer

14/9 is the right answer

Please give the fresh photo then I will give you the right answer

please select in one question

first question first answer.second question second answer third question second answer

first question first answer.second questions second answer.third questions second answer 😊

Let n a.m, between a,b are a1,a2,a3,............ana,a1,a2,a3,.............an,bsum of n a.m.Sn = n[2a1 + (n-1)d]/2 ----------(1)a.m. of a,b is (a+b)/2b = a+(n+1)da.m. = [2a+(n+1)d]/2 -------------(2)a1 = a+d put in (1)Sn = n[2a + 2d + (n-1)d]/2 = n[2a+(n+1)d]/2 ------------(3)from equation (2) & (3)Sn = n*a.m.where d = common difference of a.p.

thanks

Let two parts of 28 are x and (28 - x)

Then,As per given condition6x/5 = 2(28-x)/318x = 280 - 10x28x = 280x = 280/28 = 10

Therefore,Two parts of 28 are 10 and 18

Let edge length is 'a', so as per given data6 a^{2}=1536cm ^{2}=> a= 16cm

volume = a^{3}=4096 cm^{3}

convert mm to cm i.e 5mm = 0.5cmvolume of the material used= 6x 1536x0.5cm=4608 cm^{3}

in eq. 1st cube both side

x³-1/x³-3x*1/x(x-1/x)= (3+2√2)³. (x cut by x)(x³-1/x³)=9+16√2+3*3*2√2(3+2√2)+3(3+2√2) =81+70√2+9+6√2 =90+76√2 ans.

90 +76√2 the correct answer of the given question

90+76√2 is the right answer of the following

-5 the correct answer of the given question

-5 is right answer of this question. .please like my answer

-5 the correct answer

Your correct answer is -5

awesome

Answer:c)small and negativeExplanation:Since it is the ratio of two magnetic fields, susceptibility is a dimensionless number. Diamagnetic substances have negative susceptibilities (x < 0)

If you find this solution helpful, Please like it.

wonderful excellent

Given:AB is a line segment and C and D are two points lying on the same side of AB such that ∠ACB = ∠ADB.

To prove:A, B, C and D are concyclic.

Proof:

If possible, suppose D does not lie on this circle. Let D´ be the point which lies on the circle.

Since, C and D´ are two point on the circle lying on the same side of AB.

∴ ∠ACB = ∠AD´B (Angles in the same segment are equal)

⇒ ∠ADB = ∠AD´B (∠ACB = ∠ADB)

∴ An exterior of ΔDBD´ is equal to the interior opposite angle. But, an exterior angle of a triangle canneverbe equal to its interior opposite angle.

∴ ∠ADB = ∠AD´B

⇒ D coincides with D´.

⇒ D lies on the circle passing through the points A, B and C.

Hence, the points A, B, C and D are concyclic.

Bricks Wall

l=25 cm l=6 m =600 cm

b=12.5 cm b=50 cm

h=7.5 cm h=5 m =500 cm

volume of wall=l x b x h

=600 x 50 x 500

=15000000 cubic cm

volume of mixture =1/20 x 15000000

=750000 cubic cm

volume left =15000000 - 750000

=14250000 cubic cm

required brick =14250000/25 x 12.5 x 7.5

=6080 bricks

Radius of cylinder R =3.5cmheight H =14cmradius of the ball r=7/12cmlet n be the number of balls that can be form from the cylinder. Since the cylinder is recast into the small spherical balls, so n x volume of sphere = volume of cylinder n4/3 πr^3= πR^2H [ pi get cancelled ]nx4/3r^3=R^2H nx4x7x7x7/3x12x12x12= 3.5x 3.5x141372n/5184=171.5n =171.5x5184/1372n=889056/1372n=648 hence 648 small balls can be formed by the cylinder.

this not 7:6 this is 7:5

n’th term of an AP is a + (n-1)d and is given to be 6n+2

So,

a + (n-1)d = 6n+ 2

ie (a-d) + nd = 6n+2

In the above equation, compare the coefficient of n on both sides, ie , dn = 6n, so d= 6.

With d known, compare the constant terms on both sides, ie, a-d = 2, but d being 6, a-6 = 2 . Hence a = 6+2 = 8