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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 79001. |
(a) 172 . 17-3-17-117 |
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Answer» 17².17^(-3) =17^(2-3) =17^(-1) =1/17 |
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| 79002. |
3 1/12 + 1 1/12 + 1 1/12 |
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Answer» 37/12+13/12+13/12=63/12=5 3/12 |
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| 79003. |
Lutlesponding chordA chord of a circle of radius 15 cm subtends an angle of 60° at theof the corresponding minor and major segments of the circle.6.(Use T-3.14 and 3 1.73) |
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Answer» 1 2 |
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| 79004. |
\sqrt{12} + \sqrt { 12 + \sqrt { 12 + \dots \dots \dots } } |
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Answer» we can take the above expression as x.since it's an infinite expression √(12+X)=X therefore x^2=12+X therefore X=-3/+4but since radical is used for positive value , the answer is 4. |
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| 79005. |
If the perimeter of a sector of a circle is fourtimes the radius of the circle, find the centralangle of corresponding sector in radians.(3 |
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| 79006. |
21. A chord of a circle is equal to the radius of the circle. Find the angle subtended by the chord at apoint on the minor arc and also at a point on the major arc. |
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| 79007. |
the free ze is -10°C for defort thefreeze js-loc forallowed to rise 14° What will be thewasThe temperature inside theallowed to risetemperature wastemperature atten nie?e what will be5 negative andthe sign of integer ife we multiplypositive integen? |
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Answer» sign will be negative the temperature after rise =-10°c+14°c=4°c the sign of integer if we multiply 5 negative integers and 2 positive integers will be negative |
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| 79008. |
A chord of a circle is equal to the radius of thecircle. Find the angle subtended by the chord ata point on the minor arc and also at a point on themajor arc2. |
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| 79009. |
7. Find the 31st term of an AP whose lIth anu un8. An AP consists of 50 terms of which 3rd term is 12 and the last term is 106. Find the 29thterm1538Tterm. |
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Answer» a+2d=12a+49d=106a+49d-a-2d=106-12=94so d=2so a=12-4=8so 29th term=a+28d=8+56=64 |
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| 79010. |
0)6. Check whether-150 is a term of the AP : 1 1 , s, s,t. Find the 31st term of an AP whose 1 Ith term is 38 and the 16th term is 73,i inAP sosists of S0 terns of which 3rd term is 12 and the last term is 106. F |
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| 79011. |
John's income is 20% more than that of Mr Thomas. How much per cent is the income ofMr Thomas less than that of John? |
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| 79012. |
Long Answer Type Questions (4 Marks)Solve the following and check your solution:\frac{9 x+\frac{4}{7}}{2 x-\frac{3}{4}}=\frac{268}{35} |
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Answer» (63x+4/7)*35=268*(8x-3/4)5(63x+4)=67(8x-3)315x+20=536x-201221x=221X=1 |
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| 79013. |
עושוExampSana deposited * 4000 in a bank for 15 years. Thebank gives a half-yearly compound interest at 10%per annum. Find the compound interest.15 |
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| 79014. |
9. In a test, (+4) marks are given for every correctanswer and (-2) marks for every wrong answer.Rohit answered all the questions and scored68 marks. 25 of Rohit's answers were correct.How many of the questions he attempted wereincorrect?(a) 22 (b) 5 (c) 16 (d) 8 |
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Answer» Corect answer=25Marks for corect answer=25*4=100Marks scored=68So negative marks=100-68=32So, negative questions=32/2=16 |
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| 79015. |
38e Two men on either side of the cliff 80 m high observes the angles of elevation of thetop of the cliff to be 30° and 60° respectively. Find the distance between the two menCBSE 2016]53 |
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| 79016. |
10. Two men are on either side of a cliff which is 80 m high. They observe the angles ofelevation of the top of the cliff to be 30° and 60° respectively. Find the distance betweenthe two men. |
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Answer» thns |
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| 79017. |
Add and write the answer in the blanks.15 + 1 =11 + 0 =19 + 0 =10 + 1 =19 + 1 =14 + 0 =16+0 =14 + 1 =12 + 0 =12 + 1 =IDOL17 + 0 =34 |
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Answer» 161920161218111114151317 16 11 111920161218 |
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| 79018. |
A(ABCE(3) PXR is a minor arc of a circle with centre O. ZPOR 54°. What is the measure of themajor arc corresponding to the arc PXR? |
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| 79019. |
10/0+12/0= |
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Answer» 10/0+ 12/0 10+ 12 =22 infinite + infinite =infinite 10/0+12/0 10+12=22 10\0+12\0=22 so, 22 is the right answer of the following infinite is the right answer. infinite is the correct answer of the question |
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| 79020. |
19. In a circle of radius 10.5 cm, the minor arc is one-fifth of the major34.Find the area of the sector corresponding to the major arc. |
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Answer» how bro |
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| 79021. |
8.)A chord of a circle is equal to the radius of the circle. Find the angle subchord at a point on the minor arc and also at a point on the major arc. |
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| 79022. |
uestions x 2 Mark 12 Marks)Ih the given figure, ABCD is aet19 9 to 14 carry 2 marks each.elogram. E, F. G and H are mid-points of sides AB, BC, CD and DA sare EFGH-ar ABCD.-F |
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Answer» If you find this solution helpful, Please like it. |
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| 79023. |
l. A chord of a circle is equal to the radius of the circle. Find the angle subtendedchord at a point on the minor arc and also at a point on the major arc. |
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Answer» Thank you sir In ΔOAB,AB = OA = OB (radii)Hence ΔOAB is an equilateral triangleThat is each angle of ΔOAB is 60°∴ ∠AOB = 60°∠AOB = 2∠ACB [Angle subtended by an arc of a circle at the centre is double the angle subtended by it on any part of the circle]Hence∠ACB = 30°In cyclic quadrilateral ADBC∠ADB +∠ACB = 180° (Sum of opposite angles in cyclic quadrilateral is 180°)⇒ ∠ADB = 180° − 30° = 150°Therefore, angle subtended by the chord at a point on the major arc and the minor arc are 30° and 150° respectively |
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| 79024. |
Find the AP whose 3rd term is 5 and 7th term is 9. |
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| 79025. |
: Determine the AP whose 3rd term is 5 and the 7th term is 9. |
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| 79026. |
Ajit secures 1 2.5% more marks than Baiju. Then how much less per cent marksdid Baiju secure than Ajit?(1)10 (2) 11 (3) 12.5 (4) 3393 |
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Answer» thanx dear |
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| 79027. |
PracticePapere Allowed : 3 hours]IMax. Marks:80eralInstructions- Questions 1-6 (1 Mark), 7-12 (2 Marks), 13-22 (3 Marks).23-30 (4 Marks)SECTION A. The graph of a polynomialy p) is given below. By looking at the graph, find the number of zeros of px)ya p(x) |
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Answer» The number of times curve intersects x axis is the number of zeroes. Here it is four times therefore there are four zeroes |
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| 79028. |
5. In a class test, the sum of Shefali's marks in Mathematics and English is s0marks less in English, the product of their marks2 marks mowould have been 210. Find her marks in the two subjects.re in Mathematics and 3de Ifthe longer |
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| 79029. |
x18 cm = 9 cm.2Two Marks Questions4. AABC is an equilateraltriangle. D and E are mid-points of sides BC and ABrespectively. If BC = 4 cm,find ariABED). |
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Answer» Here D and E are mid points of BC and AB , We join DE and from " converse of mid-point theorem " we get AC | | ED And BC = 4 cm , SO AB = BC = CA = 4 cm ( As given ABC is a equilateral triangle )AndD and E are mid points of BC and AB , So BE = EA = BD = DC = 2 cm Now In ∆ BAC and ∆ BED ∠ ABC = ∠ EBD ( Same angles ) ∠ BAC = ∠ BED ( As we know AC | | ED and take AB as transversal line , So these angles are Corresponding angles ) And ∠ BCA = ∠ BDE ( As we know AC | | ED and take CB as transversal line , So these angles are Corresponding angles ) Hence ∆ BAC ~ ∆ BED ( By AAA rule ) So we know BA÷BE = AC÷ED⇒4÷2 = 4÷ED⇒ED = 2 And Area of BAC÷Area of BED = AC²÷ED²⇒Area of BAC÷Area of BED = 4²÷2²⇒Area of BAC÷Area of BED = 16÷4So,Area of ∆ BED = 4 cm2 ( Ans ) |
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| 79030. |
Find the amount and the compound interest ont 10,000for 15 years at l0% perannum, compounded half yearly. Would this interest be more than the interest hewould get if it was compounded annually? |
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| 79031. |
Find the amount and compound interest on 10000 for 12 years at 10% perannum, compounded half yearly. Would this interest be more than the interest hewould get if it was compounded annually? |
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Answer» thank you so much |
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| 79032. |
87. Age of two men among 8 is 21 years diluyears. In their place two new men are broughtsuch that the average age increases by 2 years.So what is the average age of two new men.(b) 24 years(a) 22 years(d) 30 years(c) 28 yearsin the value of |
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Answer» 30 Is the correct answer for this question 30 is the correct answer 3rd question 30 d is the correct answer for this question |
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| 79033. |
5. Anil deposited20000 in a bank at 10% per annum. Find the differenceyears if the interest is compoundedin the compound interest after 1ii. half yearly.i. yearly |
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Answer» Compound interest after 1 and a half years is interest is compounded yearly = P[(1 + r/n)^nt] - P = 20000[(1 + 0.1/1)^1.5] - 20000 = Rs 12210.2Compound interest after 1 and a half years is interest is compounded half yearly= P[(1 + r/n)^nt] - P = 20000[(1 + 0.1/2)^(1.5X2)] - 20000 = Rs 3152.5Difference = Rs (12210.2 - 3152.5) = Rs 9057.7 |
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| 79034. |
(1) 12 yeal0. Sachin is twice Priyanka's age. After two years. Priyanka will be10 years old. What is Sachin's age today?(1) 16 years (2) 18 years (3) 14 years(4) 20 years |
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| 79035. |
16. A man deposited 8,000 5% pa. in the name of his two sons aged 15 and 12 years in such away that at their age of 18, both of them get equal amounts. What are the sums in each name ? |
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| 79036. |
. 3.2निम्नलिखित ऑफितियों में 7 की -y :Al 29"e e Tl St R L S LRSS DR S S |
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| 79037. |
\begin{array} { l } { \text { In Figure } 11 , \text { AD and CE are respectively perpendiculars } } \\ { \text { to sides } B C \text { and } A B \text { of } \Delta A B C \text { . } } \\ { \text { If } \angle E C D = 45 ^ { \circ } , \text { find } \angle B A D \text { . } } \end{array} |
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| 79038. |
in a circle with radius r a minor arc subtends an angle of measures theta at the centre. then the length of that minor arc = |
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Answer» txs |
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| 79039. |
()Prove that (2, 2), (8, -2), (-4, -3) are-3) arevertices of a right-angled triaat which it is right-angledhee pointangle. Find the po(in) Show that the points (3, 3), (9, 0) and (1are the vertices of a right-angled triangle |
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Answer» plz solve ii part also |
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| 79040. |
\begin { equation } \begin{array}{l}{\text { Determine the } 25^{\text { th }} \text { term of an AP whose } 9^{\text { th }} \text { term }} \\ {\text { is }-6 \text { and common difference is } \frac{5}{4} \text { . }}\end{array} \end { equation } |
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| 79041. |
c)A bottle contains 1.25 L of juice. Rahul drank 0.350 L of juice from it. Howmuch juice is left in the bottle? |
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Answer» right answer is900 letters left As he took 0.350 Lor 350mlso remaining= 1250 litrenow1250-350900ml total juice =1.25 L convert into ml=1250ml he drank 350ml Subtract 350 ml from 1250 ml |
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| 79042. |
in a mixed fruit drink,orange juice ,apple juice and pineapple juice are mixed in the ratio 11:10:9 . find the amount of the three juices in a carton of l 200 ml of juice. |
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Answer» 30x = 1200 ml x = 40 ml orange juice 11x = 440 ml apple juice 10x = 400 ml pineapple juice 9x = 360 ml Let the orange juice =11 x the apple juice = 10x the pineapple juice = 9x Then, According to the question, 11x + 10x + 9x = 1200 ml 30x = 1200 So, x = 1200/30 = 40 Hence, the orange juice = 11x = 11× 40 = 440ml the apple juice = 10x = 10 × 40 = 400ml the pineapple juice = 9x = 9×40 = 360 ml Hope you have got your answer properly. |
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| 79043. |
-accouses aslidesh and Ramesh together invested, inte144o do zupeer in the ratio 485 and cherbought aplots of land After some siyears they sold it at apaofitof,20% What is the profit each eof them got? |
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Answer» Which of these animals lives in the thar Desert? |
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| 79044. |
Short Answer Type (l) Questions(3 marks e9. Find the value of k for which a - 3b is a factor of a -7a b+kb. Hence, forvalue of k, factorise a -7a b2 +kb completely. |
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| 79045. |
. A dinner set is quoted for?1500. A customer pays ? 1173for it. If the customer get aseries of two discounts and therate of first discount is 15%then the rate of seconddiscount was, |
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| 79046. |
R e S P o‘piea g पॉप st B ki sem gk O d OPutamen Tt YR sy e DU FORGTE O |
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| 79047. |
12. A man borrows 10,000 at 10% cominterest compounded yearly. At the endeach year, he pays back 20% of the amoufor that year. How much money is left unpaijust after the second year ? |
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Answer» For first year: P = 10000 R = 10% T = 1yr Interest = 1000 A = P + I = 10000 + 1000 = 11000 We know that he pays 20% of amount every year 20 / 100 x 11000 = 2200 So the total amount paid = 11000 - 2200 = 8800 For second year: P = 8800 R = 10% T = 1 yr Interest = 880 A = P+ I = 8800 + 800 = 9680 He pays 20% of amount again 20/100 x 9680 = 1936 Total amount paid = 9680 - 1936 = 7744 So the loan is 7744 |
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| 79048. |
t. Ram buys a refrigerator for Rs 4000 on credit. The rate of interest for the firsyear is 5 % and the second year is 15 %. How much will it cost him if he paysthe amount after two years?rvece |
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Answer» Price of refrigerator = Rs 4000 Price of refrigerator after first year = 4000(1 + 5/100) = 4000(21/20) = 200*21 = 4200 Price of refrigerator after second year = 4200(1 + 15/100)= 4200(23/20)= 210*23 = 4830 Therefore fridge will cost him after two years = Rs 4830 |
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| 79049. |
A man deposited9000 in a bank which gave interest at 11% per annum. What amount5)will he receive after 3 years and 4 months?as |
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| 79050. |
If (r-1) is a factor of ar+brcr2+dr te,show that atcte b+ d 0 |
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