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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 79101. |
val ues aquarShow that the coefficient of (r+1)th term in the expansion of (1+x)" +1iequal to the sum of the coefficients of the rth and (r1)th term in thexpansion of (1 +x)" |
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Answer» page 1 |
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| 79102. |
y ues will be planted by the students?ral is made up of successive semicircles, with centres alternately at Awith centre at A, of radii 0.5 cm, 1.0 cm, 1.5 cm, 2.0 cm,.. . as slFig, 5.4. What is the total length of such a spiral made up of thirteen consemicircles? (Take π =-) |
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| 79103. |
Do them fast!ttoWhat is the cost of I kg of each of the following vegetables i-(a) 2 kg onions cost Rs 18(b) 500 g potatoes cost Rss(c) 100 g peas cost Rs 22The cost of I kg apples is Rs 40. |
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| 79104. |
The mean of 35 observations is 20, out of which mean of first 18 observations is 15and mean of last 18 observation is 25. Find the 1 8th observation.) |
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Answer» Mean=Sum/n Mean of 35 observation=Sum/3520=Sum/35sum=35*20=700 Mean of first 18 observation=S1/15=S1/18S1=15*18=270 Mean of last 18 observation=S2+18th term/1825=S2/18S2=25*18=450 Sum-270=450-18th term700-270-450=-18th term18th term=720-700=20 |
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| 79105. |
L iswer the tonoWings. (2 marks each)(20]Mean of 11 observations is 60. If mean of first six observations is 58and that of last six numbers is 61 then find 6th observation. |
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| 79106. |
) Find three rational numbers betwee |
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Answer» answer the question 3*3/5*3=9/152*5/3*5=10/159.1/15,9.2/15,9.3/15 |
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| 79107. |
3 a - 2 b - a b - ( a - b + a b ) + 3 a b + b - a |
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Answer» 3a-2b-ab-(a-b+ab)+3ab+b-a =3a-2b-ab-a+b-ab+3ab+b-a =3a-a-a-2b+b+b-ab-ab+3ab =3a-2a-2b+2b-2ab+3ab =a+ab=a(1+b) |
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| 79108. |
-100 - 30 %2B 40 %2B 284 |
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Answer» 194 is the right answer please mark me the best answer 😊😊😊😊😊 284-(6×65÷13+20×5-40)=284-(6×5+20×5-40)=284-(30+100-40)=284-(130-40)=284-90=194.your answer is 194 The right answer is 194. 194 is the right answer 194 is the correct answer of the following 284-(6*65/13+20*5-40) 284-(6*5+20*5-40) 284-(30+100-40) 284-(130-40) 284-90194 The answer is 194 |
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| 79109. |
Acuboidalfishtank with the internal lengthand width of its base being 50 cm and 40 cmrespectively, contains 60 dm^3 of waterWhat is the height of the water in the fish tank |
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Answer» The volume of water we can keep in tank is cube volume that equals to cuboid volumelet height of cuboid is h50*40*h=6*6*6*1000216*10/20=hh=108cm wrong anyone help meeeee......... |
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| 79110. |
3. Solve.(1) Suyash bought 2 kg of sugar and Ashish bought 3 kg Howthey buy altogether? If sugar costs 32 rupees per kg, how much to theasendon the sugar they bought? |
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Answer» check it from book answer sheet ucfufugucigocufuicvifufcchfucsrrxxx they bought together 6 kg sugar and they spent on the sugar =192Rs they bought together 6 kg sugar and they spent on the sugar =192Rs they bought together 6 kg sugar and they spent on the sugar =192Rs they bought together 6 kg sugar and they spent on the sugar =192Rs they bought together 6 kg sugar and they spent on the sugar =192Rs they spent 192 rs on sugar they bought together 6 kg sugar and they spent on the sugar =192Rs they bought together 6 kg sugar and they spent on the sugar =192Rs they bought together 6 kg sugar and they spent on the sugar =192Rs given quantities of sugar =2+1/2,3+1/2total sugar=(2+1/2)+(3+1/2) = 5/2+7/2 =5+7/2 =12/2=6kgeach kg cost =32cost of 6kg=32×6= 192 rs |
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| 79111. |
LET'S DRAVwDraw a circle, triangle, rectangle and square. Using these shapes, draw anobject and colour it. One example has been given belowTHE PRECISION OF MATHEMATICSGRADE ONE |
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Answer» circle : fan regulatortriangle : traingular measurerectangle : compass boxsquare : square shaped small note books |
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| 79112. |
\frac{2^{n}+2^{n-1}}{2^{n+1}-2^{n}}=\frac{3}{2} |
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| 79113. |
10. Rohit takes 4 minutes to make a complete round of a circular park. How much time willhe take to make 15 rounds? |
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| 79114. |
.Answer the following questions:15.16X2-32âłABC maDEF and their areas are 64 cm2 and 121 cm2 respectively. If EF = 15.4 cm, find BC.mbers |
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Answer» ar(ABC)/ar(DEF) = (BC/EF)^264 cm^2 / 121 cm^2 = (BC/15.4 cm)^28/11 = BC/15.4 cmBC=11.2 cm hit like if you find it useful |
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| 79115. |
3. Find the mean of x + 1, x + 3, X + 4, x + 8.mean of x + 3 x + 5+ 10 is 9. what is the mean onwhat is the mean of last three observations?monlaced by 15 |
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| 79116. |
42 Find the number of natural numbers betweeand 543. If the seventh term of an A.P. is 1/9 and its ninth term is 1/7, find its (63)d term.CBSE 20[CBSE 2014]nfnn i 30 If its 25th term is three times its 8h term, find |
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| 79117. |
a(x+y)+b(x - y)=a square - ab+b square;a(x+y)- b (x - y)=a square + ab+b square. |
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Answer» Solution: _____________________________________________________________ Given: a(x+y) + b(x-y) = a² - ab + b² ..(i)., a(x+y) - b(x-y) = a² + ab - b² ...(ii) _____________________________________________________________ To find, The values of x and y. _____________________________________________________________ Adding both the equations, We get, => a(x + y) + b(x - y) + a(x + y) - b(x - y) = a² - ab + b² + a² +ab - b² => 2a(x + y) = 2a² => x + y = a ...(iii),____________________ Subtracting (ii) from (i), => a(x + y) + b(x - y) -(a(x + y) - b(x - y)) = a² - ab + b² - (a² + ab -b²) => a(x + y) + b(x - y) - a(x - y) + b(x - y) = a² - ab + b² - a² - ab + b² => 2b(x - y) = -2ab + 2b² => 2b(x - y) = 2b² - 2ab => 2b(x - y) = 2b(b - a) => x - y = b - a ..(iv) _______________________ Adding (iii) & (iv), We get, => (x + y) + (x - y) a + b- a => 2x = b => ∴ x= b/2 __________________________ Substituting value of x in (iv), We get, => x - y = b - a => b/2 - y = b - a => y = a + b/2 - b => y = a - b/2 Chirantan the right answer is x=b square/5a,y=-a- 4b/5b..Your answer is wrong |
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| 79118. |
ä¸, 160č1401) 363) 48(4) 5480 70 |
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| 79119. |
687=square %2B 10*square %2B 100*square |
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Answer» 6x100+8x10+7 is a right answer 687=6 x 100+ 8 x 10+ 7 x 1 6×100+8×10+7 is the right answering 6×100+8×10+7×1 is the right answer 6×100+8×10+7 is the correct answer 6×100+8×10+7×1 is the right amswer 687=5×100+10×10+87×1 |
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| 79120. |
44. A hemispherical bowl of internal diamet36 cm contains liquid. This liquid is filleinto 72 cylindrical bottles of diamete6 cm. Find the height of each bottie, if IOliquid is wasted in this transfer |
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Answer» Given : Diameter of hemispherical bowl = 36 cm , So radius of hemispherical bowl, r = diameter/2 = 18 cm And we know Volume of hemisphere =2πr^3/3, So Volume of hemispherical bowl =23πr^3=23π(18)^3cm^3 And ,now, the liquid is transferred into 72 bottles and 10% liquid is wasted in this transfer.So,volumeofliquidthatistransferred=23π(18)^3−10/100×23π(18)^3=910×23π(18)^3cm^3 Given diameter of each cylindrical bottle = 6 cm , So radius , R = 3 cmAnd let the height of each bottle = h cmWe know volume of cylinder =πR^2h, So we get72(πR^2h)=910×23π(18)^3⇒72×π×(3)^2×h=910×23π(18)^3⇒h=5.40cmSo,Height of each cylindrical bottle =5.40 cm |
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| 79121. |
How many packets of 1o kg sugarcan be made from 3- kg of sugar?4(1) 64(2) 52(3) 48(4) 12 |
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| 79122. |
The minute hand of a wall clock is 7 cm longthe area covered by it in 30 minute. |
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Answer» Area = πr^2/2 = 22/7×7×7×1/2 = 11×7 =77 sq cm 60minute = 360°1 minute = 360/6030 minute= 360×30/60=180°area of sector= πr2× 180/360 = 22×7×7/7×1/2 = 77 sq cm |
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| 79123. |
( 1 + \frac { 3 } { 1 } ) ( 1 + \frac { 5 } { 4 } ) ( 1 + \frac { 7 } { 9 } ) \dots ( 1 + \frac { 2 n + 1 } { n ^ { 2 } } ) = ( n + 1 ) ^ { 2 } |
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Answer» (1+3/1)(1+5/4)(1+7/9).... (1+2n+1/n²)= 4/1*(9/4)*(16/9)*(25/16).....((n²+2n+1)/n²).. here all the denominator will cancel its earlier numerator terms like 4 and 4, 9 and 9 , leaving behind the numerator of last term so, at last it will become (n²+2n+1)/1 = (n+1)² |
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| 79124. |
( 1 + \frac { 3 } { 1 } ) ( 1 + \frac { 5 } { 4 } ) ( 1 + \frac { 7 } { 9 } ) \dots ( 1 + \frac { ( 2 n + 1 ) } { n ^ { 2 } } ) = ( n + 1 ) ^ { 2 } |
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Answer» The terms written are (1+3/1)(1+5/4)(1+7/9) = (4/1)(9/4)(16/9)....and so on here the denominator will cancelled , its precedding numerator, like 4 will be cancelled by !(9/4 ) similarly 9 will be cancelled by 16/9 ...and so on And the final term left will be (n²+2n+1)/1 =(n+1)² |
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| 79125. |
\frac { 4 + 3 \sqrt { 5 } } { 4 - 3 \sqrt { 5 } } 4 -3.5 |
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| 79126. |
(3/10)*(4/5) %2B (4*(4/5))/(((3/5)*(text*(5*(f*o))))) - 1/5 |
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Answer» 4 4/5 ÷ 3/5 * 5 + 4/5 * 3/10 - 1/5) = (24/5 * 5/3 * 5 + 6/25 - 1/5 = 8 * 5 + (6 - 5)/25 = 40 + 1/25 = 1001/25 |
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| 79127. |
i)63 x 5 3Whthreefind threeis rationaldipperentno betweenRational and1813Express0.63onthe form of 2 |
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| 79128. |
13. Find three consecutive numbers if three timesmiddle number is greater than the sum of the firstthe last number by 176. |
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Answer» Let the first no. be x-1second no. be xThird no. be x+1Given that, 3(second no.)=(first+third+176)3x=x-1+x+1+1763x=2x+1763x-2x=176x=176So three consecutive numbers are 175,176,177 |
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| 79129. |
Show that if the diagonals of a quadrilateral are equal and bisect each other at righangles, then it is a squarenals of a quadrilateral are equal and bisect each other at nigt |
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| 79130. |
conical heap is 24 cm, find the radius and slant height of the m8. Water in a canal, 6 m wide and 1.5 m deep, is flowing with a speed of 10 km h.Howmucconearea will it irrigate in 30 minutes, if 8 cm of standing water is needed?iointernal diameter 20 cm from a canal into a cylindrical tanlurouah the pipeat tiee a |
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Answer» Width of canal = 6 mDepth of canal = 1.5 mFlow rate of water = 10 km/hDistance= speed × timeDistance travelled by the water in 30 minutes = 1000×1/2 = 500mAmount of water irrigated in 20 minutes= 6 x 1.5 x 500 m^3= 4500 m^3Area irrigated by this water if 8 cm standing water is desired i.e 8cm = 0.08 m= 4500 / 0. 08 m2= 56250 m^2= 0.05625 km^2 |
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| 79131. |
Question 5:Three coins are tossed simultaneotislyFind the probability of getting(a) Three heads(b) Three heads(c) Exactly 2 heads(d) At least 2 'heads. |
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| 79132. |
The sum to infinity of $ \frac{1}{7}+\frac{1}{7^{3}}+\frac{2}{7}+\ldots= $1) 162) 7/243) 5/484) 3/16 |
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Answer» 1/7 +2/7^2 +1/7^3 +2/7^4+.........=(1/7 +1/7^3+......)+2(1/7^2 +1/7^4+.....)2 GPs are formedfor both common ratio r=1/7^2since it is infinite series for thissum=a/(1-r)for 1stsum1=(1/7)/(1-1/7^2)=7/48for 2ndsum2=2×(1/7^2)/(1-7^2)=2/48total sum = sum1 + sum2sum=7/48 + 2/48=9/48=0.1875 |
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| 79133. |
tan^-1(1/7)+tan^-1(4/7)+tan^-1(9/7)= |
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Answer» π/2 is the correct answer of this question |
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| 79134. |
26. if f is a real valued function given by f(x)2and o, B are rools3x12. Then,(a) f(α) f(B) (b) f(α)-10(c)/(B)--10(d) none of these |
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| 79135. |
\frac{\frac{9}{4}+\frac{7}{8}}{\frac{9}{4}-\frac{7}{8}}+\frac{8}{9}\left(2 \frac{3}{11}+\frac{13}{22}\right) |
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| 79136. |
Q.5: The nth term of an A.P. is 1(-2)/n 1, Find the fifth and sixthtermofA.P |
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| 79137. |
EXERCISE 9.2I.Write the answer of each of the following questions:0What is the name of horizontal and the vertical lines drawn to determine theposition of any point in the Cartesian plane?(ii) What is the name of each part of the plane formed by these two lines?(iii) Write the name of the point where these two lines intersect. |
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| 79138. |
-3/2 %2B sqrt(5)/2 %2B (-7*sqrt(5) %2B 6 %2B 9*sqrt(5))/4 |
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Answer» Answer to this question is 3 6 - 7√5 + 9√5 - (6+7√5-9√5) /46 - 6 - 7√5 - 7√5 + 9√5 +9√5 /4- 14√5 + 18√5 /44√5/4correct answer is √5 please like my answer |
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| 79139. |
(7/8)*(quad*(text*((6/8)*(i*i)))) - 5/2 %2B 7*(3/4) - 1/6 - 1/2 %2B 3*(7/25) |
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| 79140. |
(2/7)/5 %2B (3/7)/5 %2B 4/35 |
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Answer» 3/7*1/5 - (-1/5)*4/7 + 2/7*1/5 = 3/35 + 4/35 + 2/35 = (3 + 4 + 2)/35 = 9/35 |
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| 79141. |
Find three-sixth of 60. |
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Answer» 60*3/6180/630 will be the answer thanks |
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| 79142. |
The light of three traffic signals is changed to 16 seconds, 28 seconds, 40 seconds, respectively. If you change 8 tie together then calculate it again and when will you change once? |
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Answer» something missing in question ...may be language mistake Please post the question clearly! |
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| 79143. |
Time duration of 6 minutes and 50 seconds is wrongly noted as 5 minutes and 40 seconds. What is thepercentage error? [Ans:1 7%). |
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Answer» Percentage error = 70/410 * 100 = 17% |
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| 79144. |
9-5(v) O.SE(1)e following rational numbers in ascending order:4 -5-912–18 37 -2ii) 3 -7 -11 -13-5'to' 15 20g 13 -23rrange the following(ii)345 -7-12' 16-24(iv)714 -28° 42 |
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| 79145. |
A clock takes three seconds to strike three. How longwill it take to strike nine?352 |
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Answer» Like old times, at 3:00 hours, there would be three strikes and at 9:00 hours, nine strikes. The first strike takes place at exactly 3:00. Since the first strike is over, the next 3 seconds is used to do two left over strikes. Hence for every strike, it takes 3/2 =1.5 seconds. Now at 9:00 hours:First dong takes place at 9. Subsequently, 8 strikes remain. For every dong, it takes 1.5 second. Hence the next 8 will take 1.5 seconds each.= 8*1.5=12 seconds i think it 9 ......3×3 |
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| 79146. |
7The sixth term of the expansion (2 x+(1 / \sqrt{x}))^{7} |
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| 79147. |
( 7 ) \frac { - 9 } { 20 } + ( \frac { - 14 } { 5 } ) + ( \frac { - 2 } { 10 } ) + \frac { 3 } { 7 } + \frac { 5 } { 14 } |
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Answer» Page 1 page 2 |
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| 79148. |
EXERCISE 1(e)Short Answer Type Questions (SLAB-I)1. If a/b is a rational number (b + 0) in its lowestform. What is the condition on b so that thedecimal representation of a/b is terminating. |
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Answer» b must be the factor of 2^m5^n form |
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| 79149. |
l umbers in the decimal forbers in the decimal form up to 3 decimal planeEXERCISE 15write the following b4) 5325write the following rational number in decimal form up to 3 decimal places3) 13Comert the flowing decimals into rational numbers.4) 19.093) 8.1224.479actually dividing find out whether the rational numbers are teremom-terminating decimals.w3) 154) 25find the decimal representation of the following rational numbers.v115-5VL Express the following as decimals.-133) 16VII. Convert each the following recurring decimals into fractions.1) 07 21 0133) 0.7335 0.31274) 4.196) 0.4712320 |
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Answer» u should click the picture carefully |
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| 79150. |
Let f(x-x2 and g(x)2b.2x + 1 be two real valued functions, find27. Fird tho |
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Answer» f(x) = x*x g(x) = 2x+1 (f+g)(x) = f(x)+g(x) = x*x+2x+1 = (x+1)(x+1) (f-g)(x) = f(x)-g(x) = x*x-2x-1 (fg)(x) = f(x)g(x) = x*x(2x+1) = 2x*x*x+x*x |
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