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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 79151. |
5*x^2 %2B 13*x %2B 8=0 |
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Answer» x=-8/5 or x=-1 answer for this question is this x= -8/5 and x= -1, is right answer 5x²+8x+5x+8=05x²+5x+8x+8=05x(x+1)+8(x+1)(5x+8)(x+1)=0x=-8/5x=-1 -8/5 and -1 the correct answer of the given question x=-8/5,-1 is the correct values of x x=-1 , -8/5 is the right answer. |
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| 79152. |
-3*x/2 - 11/2 %2B (2*x %2B 7)/5=(2*x %2B 8)/3 - 5 |
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Answer» Is a right answers 5.22 The right answer is 5.22 |
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| 79153. |
\left. \begin array c z ^ q - z ^ v = h q - x v \\ q %2B v = h %2B x \end array \right. |
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| 79154. |
Fold stanдо площ Монмалоor's Signature015) mayo |
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Answer» 10 coin of 10p make 1 rupee 10 coins of 10p make 1 rupee 10 coin of 10 p make 1 rupees 1$\100p so 100p divided by 10p and the answer is 10 coins 10 coins of 10 paisa can make Rupees 1 10 coins of 10 paise can make 1 rupee 10 coins of 10p make 1 Rupee |
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| 79155. |
(d) a+b+cWhich one of the following matrices is an elemen-tary matrix?[10 0751 50710 0 010 10(b)10 0 1T1007ToolsTo 2 0710 10(c) 100(d)© loot10 52 |
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Answer» what is your question what is your question a is the right answer. B is the right answer the correct answer could be option c B is right here........ B is the correct answer to that question |
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| 79156. |
14. A river 2 m deep and 45 m wide is flowing at the rate of 3 km/h. Find the quantity of waterееthat runs into the sea per minute. |
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Answer» thanks for your answer. |
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| 79157. |
takes 40 seconds to complete 200 oscillations. What is the timeA simple pendulumperiod of the pendulum? |
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Answer» Time taken = 40 secsNo. of oscillations = 200Time Period = Time Taken/ No. of oscillations =40/200 = 0.2 secs |
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| 79158. |
Sixth part of a number exceeds its eighth part by 20. What is the number? |
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Answer» the equation becomes x/6 - x/8 = 20 => 2x/48 = 20 => x = 20*48/2 => x = 480 |
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| 79159. |
NG ANSWER THEOne fourth of a number exceeds one fifth ofnumber exceeds one fifth of its succeeding number by JThe numerator of a rational number is less than its dertal number is less than its denominator by 3. If the numeratorbecomes three times and the denominator is increased by 20. heheand the denominator is increased by 20, the new number becomesFind the original numberto 12 % more than the chair |
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Answer» let the numerator of the rational number = XThen denominator = X+3 ER. RAVI KUMAR ROY A/Q3X/((X+3)+20) = 1/824X = X + 2324X - X = 23X = 23/23X = 1original number = 1/(1+3) = 1/4 let numerator be Xdenonumeter= x+3fraction = x/x+33x/x+3+20=1/83x/x+23=1/824x= x+2323x=23x=1so fraction= x/x+3= 1/1+3= 1/4 |
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| 79160. |
19. If-of a number exceeds its by 44, find the number.35720. At a cricket test match of the spectators were in a covered place while 127Find the total number of spectators. |
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| 79161. |
A bookseller sells a book at a gain of 10%. If he had bought it at 4% less andsold it for Rs 6 more, he would have gained 18 3/4 %. The cost price of thebook is: |
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Answer» Let the C.P of the book= ₹ x gain = 10% S.P =110x/ 100 If he had bought it at 4% less and sold it for Rs 6 more, C.P=96x/ 100 S.P =(110x/100)+6 Gain=((110x/100)+6)− 96x/100 = (14x/100)+6 Now, the gain=18 3/4%=75/ 4% Therefore, (14x/100)+6=(96x/100)×75/400 (14x/100)+6=(96x/4)×3/ 400 14x+600=(96x/ 4)×3/ 4 14x+600=6 x(×3) 14x+600=18x 18x-14x=600 4x=600 x=150 The C.P of the book is ₹ 150 tnx |
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| 79162. |
A bookseller sells a book at a gain of 10%. Ifhe had bought it at 4% less andsold it for Rs 6 more, he would have gained 18-.%. The cost price of thebook is:s(S.S.C. 2007) |
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Answer» 1 |
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| 79163. |
Which of the following rational numbers have the terminating decimalrepresentation?63/5 ()7/20(ii)2/13(iv) 27/49 () 135/1.5 (V) 23/7The best at intervals of 12 min.c. 15 minutos and 10 mtogether, after what time will they next toll together?esit spectively if they start*************** ********** |
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Answer» 1,2,4,5 as denominator is powers of 2 and 5 |
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| 79164. |
g = \frac z %2B x ( z - x ) z %2B \frac 1 - x z %2B x g |
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| 79165. |
-z/7 %2B z/2 %2B 31=7*z |
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| 79166. |
-3*x*y^2*z/4 %2B b*y %2B ((-8)/5)*(x^2*(y*z^3)) |
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| 79167. |
(v*(v %2B z))*(v %2B z) |
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Answer» (a+2)²a²+2ab+b² is the answer |
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| 79168. |
(-z %2B x %2B y)^2 %2B (z %2B x - y)^2 |
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Answer» yes this is right ................ |
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| 79169. |
-16*x*z - 24*y*z %2B 12*(x*y) %2B 16*z^2 %2B 4*x^2 %2B 9*y^2 |
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| 79170. |
A river 2 metres deep and 45 metres wide is flowing at the rate of 3 km per hour. Find the amount ofwater that runs into the sea per minute. |
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| 79171. |
. A river 2 m deep and 45 m wide is flowing at the rate of 3 km per hour.Find the volume of water that runs into the sea per minute. |
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| 79172. |
10.)or a number exceeds its by 44. And the number, |
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| 79173. |
A number exceeds 20% of itself by 40. The number is |
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| 79174. |
A number exceeds 20% of itself by 40. Find the number. |
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Answer» Let the number be x. So, 20% of x = (20/100) *x =x/5Given,x - x/5 = 40 4x/5 = 40 x = 40*5/4 = 50 |
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| 79175. |
\begin{array}{l}{\text { Answer any five questions: }} \\ {\text { (a) Find } \int\left(2 \sqrt{x}+\frac{3}{\sqrt{x}}\right) d x}\end{array} |
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| 79176. |
IO. A and B begin to play with equal sums, and when B has lostfive-clevenths of what he had to begin with, A has gained Rs 6 morethan haif of what B has left: what had they at first? |
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Answer» Let the sum be x Then,B lost = 5x/11A gained = (x - 5x/11)/2 + 6= 6x/22 + 6 As per given condition(x - 5x/11) + (x + 6x/22 + 6) = 2x5x/11 - 6x/22 = 610x - 6x = 6*224x = 132x = 132/4 = 33 Therefore, sum is 33 |
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| 79177. |
Questions himer t 103toll at intervals of 9, 12, 15 minutes respectively. If they start tolling togetherafter what time will they next toll together? |
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| 79178. |
(-4*x %2B 6*z)^3 %2B (4*x - 5*y)^3 %2B (5*y - 6*z)^3 |
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| 79179. |
(z - 5)*(z %2B 3)=(z %2B 2)*(z %2B 7) |
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| 79180. |
z/2 - 2*z/3 %2B z=5 |
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| 79181. |
Find the Value of-2 x(3 x-4 y)+2 y(6 y-9 z)+2 z(4 z-x) |
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| 79182. |
"A rectangular field is 72 m by 58 m. Amar walksround it at the rate of 3 km per hour. What timewill he take in taking 2 rounds.100 m How |
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Answer» aDimensions of a rectangular field= 72cm y 58cmperimeter of the rectangular field= 2( l+b ) =2×( 72+58) = 2×130 = 260cm∴ Distance taken by Amar in taking two rounds= 2×260m = 520mSpeed of Amar= 3km/hr =3×1000/3000 m/sec = 5/6 m/secTotal time taken by Amar to cover the distance= Distance/speed = 520/5/6 = 520×5/6 = 104×6 = 104×6/60 min. = 10.4 min. Hope this helps you!! |
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| 79183. |
In1,34,400.E 15 (A)A rectangular field is 72 m by 58 m. Amar walksround it at the rate of 3 km per hour. What twill he take in taking 2 rounds.6.ime. A rectangular |
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Answer» The perimeter is 2(72+58) = 260m 260(3) = 780 m total distance = 0.78 km km/(km/hr) = hours 0.78/3 = 0.26 hours (0.26 hours)(60 min/hr) = 15.6 minutes (0.6 min)(60 sec/min) = 36 seconds 15 minutes 36 seconds 10 minutes 24 seconds |
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| 79184. |
6. in a particular year a company produced 8765435 bicycles. Next year, the number obicycles produced was 1378689 more than those produced in the preceding yearHow many bicycles were produced during the second year?How many bicycles were produced during these two years? |
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Answer» Bicycles produced by the company in the first year = 8765435Bicycles produced by the company in the second year = 8765435 + 1378689 = 10144124 ∴ Total number of bicycles produced during these two years = 8765435 + 10144124 = 18909559 therfore toTotal number of bicycles produced during these two years = 10144124 |
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| 79185. |
vote, find how many votes were registered.5. A survey conducted on an Indian state shows that 1623546 people have only primaryeducation; 9768678 people have secondary education; 6837954 people have highereducation and 2684536 people are illiterate. If the number of children below the age ofschool admission is 698781, find the total population of the state.- a company produced 8765435 bicycles. Next year, the number of |
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| 79186. |
19.of a number exceeds its by 44. find the number |
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Answer» thankyou |
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| 79187. |
6. The following data show the expenditure of an individual over various itemsitems Education food Rent Clothing OthersExpenditure 1600 3200 4000 2400 3200Draw a pie chart |
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| 79188. |
Example 5: Five bells begin to toll together and toll respectively at intervals of 6, 7, 8 and 12seconds. After how much time will they toll together again? |
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Answer» what is your question |
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| 79189. |
Five bells commence tolling together and toll at intervals of 2,4 6, 8 & 10 seconds respectively. In 30 minutes how mantimes do they will toll together?noo ind210000 |
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| 79190. |
x ^ { 3 } + y ^ { 3 } + z ^ { 3 } - 3 x y z = \frac { 1 } { 2 } ( x + y + z ) [ ( x - y ) ^ { 2 } + ( y - z ) ^ { 2 } + ( z - x ) ^ { 2 } ] |
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Answer» R.H.S.=1/2(x+y+z)((x-y)^2+(y-z)^2+(z-x)^2) =1/2(x+y+z)(x^2-2xy+y^2+y^2-2yz+z^2+z^2-2zx+x^2) =1/2(x+y+z)(2x^2+2y^2+2z^2-2xy-2yz-2zx) =(x+y+z)(x^2+y^2+z^2-xy-yz-zx) =x^3+xy^2+xz^×-x^2y-xyz-x^2z+x^2y+y^3+yz^×-xy^2-y^2z-xyz+zx^2+y^2z+z^3-xyz-yz^2-z^2x =x^3+y^3+z^3-3xyz =L.H.S.Hence Proved |
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| 79191. |
x ^ { 3 } + y ^ { 3 } + z ^ { 3 } - 3 x y z = \frac { 1 } { 2 } ( x + y + z ) [ ( x - y ) ^ { 2 } + ( y - z ) ^ { 2 } + ( z - x ) ^ { 2 } |
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Answer» R.H.S. = 1/2(x+y+z)[(x-y)^2+(y-z)^2+(z-x)^2] = 1/2(x+y+z)(x^2-2xy+y^2+y^2-2yz+z^2+z^2-2zx+x^2) =1/2(x+y+z)(2x^2+2y^2+2z^2-2xy-2yz-2zx) =(x+y+z)(x^2+y^2+z^2-xy-yz-zx) =x^3+xy^2+xz^2-x^2y-xyz-x^2z+x^2y+y^3+yz^2-xy^2-y^2z-xyz+zx^2+y^2z+z^3-xyz--yz^2-xz^2 =x^3+y^3+z^3-3xyz =L.H.S. |
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| 79192. |
x(y - z)^3 %2B y(-x %2B z)^3 %2B z(x - y)^3 |
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| 79193. |
2 x - [ 3 y - \{ x - ( 2 z - 3 y ) + 4 z - 3 ( x - y - 2 z ) \} ] |
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| 79194. |
T9lfp : q1,1 : 19.ABJÄ° CE what are the values of p.q&r.82 |
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| 79195. |
The distance between Delhiand Howrah is 1980 Km. TrainA which runs at a speed of80 km per hour takes 18 2 houto me ach Howrah from DelhiIf it runs at a speed of lookm per hour, how muchtime will it take |
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Answer» where is solution wrong answer. correct answer is 14 4/5 |
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| 79196. |
Ayush runs 15.6 km per hour. How many metres does he run in 2 minutes? |
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Answer» He runs 15.6 km in 60 minutesIn 1 minute he will run = 15.6/60In 2 minutes = 0.52kmThanksPlease like the solution 👍 ✔️ |
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| 79197. |
4. A and B walk around a circular track. They start at 9a.m.from the same point in the opposite directions. A and Ewalk at a speed of 2 rounds per hour and 3 rounds perhour respectively. How many times shall they cross eachother before 9.30 a.m.?A, 810B. 7D. 5 |
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Answer» Let us find their respective speed. - Respective speed = Total speed of A + Total speed of B = 2 + 3 = 5 So respective speed or relative speed is equal to 5 rounds \ hr. ⇒ So by this statement we derive that A and B cross 5 times. ⇒Hence we can say that A And B cross 5 times in only 1 hr. A and B cross 2 times in 1 \ 2 hrs Time lapse between 8 a.m and 9.30 a.m is 1.5 hrs. No. of times did A and B cross in 1 hr +No. of times did A and B cross in 1 \2 hrs = ⇒ 5 + 2 = 7 hrs |
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| 79198. |
6. In a particular year a company produced 8765435 bicycles. Next year, the number ofbicycles produced was 1378689 more than those produced in the preceding year.How many bicycles were produced during the second year?How many bicycles were produced during these two years? |
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Answer» Bicycles produced by the company in the first year = 8765435Bicycles produced by the company in the second year = 8765435 + 1378689 = 10144124 ∴ Total number of bicycles produced during these two years = 8765435 + 10144124 = 18909559 |
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| 79199. |
Draw a pie chart for the following data.Item ofexpenditureAmount spent in rupees 3750 1875Food Health Clothing Education Sa187512007500 |
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| 79200. |
( 3 x + y ) ^ { 2 } + 2 ( 3 x + y ) ( 3 x - y ) + ( 3 x - y ) ^ { 2 } |
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