Explore topic-wise InterviewSolutions in .

(y+z)(z^2-xy)-x(z^2+xz-x^2-xy)+y(yz+xz-x^2xy)=x^3-2x^2z+z^2x+x^2y-2xyz+yz^2+x^2z- 2xz^2+z^3=(x+y+z)(x-z)^2

Thanks for the answer provided.

To convert km/h to m/ sec multiply the following by we 18/5

(a) 72 * (5/18) = 4*5 = 20m/sec

(b) 12.6 * (5/18) = 3.5m/sec

(e) 38(5/18) =10.5m/sec

f) 54(5/18) = 15m/sec

less than 2003 in two years.

A(2003)= P(2001)(1+R/100)^n

54000 = P (2001)(1+5/100)²

54000 = P(2001)(1+1/20)²

54000= P(2001)(21/20)²

54000 = P(2001)((21×21)/(20×20))

P(2001)=( 54000×20×20)/21×21

Population in 2001 = 48979.59= 48980(approx)

ER. RAVI KUMAR ROY

(ii)ATQ, population is increasing. Therefore population in 2005,

A(2005)= P(1+R/100)^n

= 54000(1+5/100)²

= 54000(1+1/20)²

= 54000( 21/20)²

= 54000(21/20)× (21/20)

=( 54000× 441)/ 400

=( 540×441)/4

= 238140/4

= 59535

Population in 2005=59535

Total population of Mumbai in 2003 = 3,42,69,123+6,298,313-19,42,639=3,86,24,797

total calorie=1200calorie comes from fat=144% of fat calorie=144*100/1200=144/12=12%Answer

12 % is the right answer

12% is the right answer

12% is the correct answer

1 b 1 hour=60 mini10 hour=600then 600×15=3600

d=st1)960*110/60=176km2)15×36000=540000m3)250×15.5=3875cmt=d/s1)7150/780=9.17h2)800/42 *5=95.238s3)27/45=0.6h

Let ( 2x + 1 ) , ( 2x + 3 ) are two

consecutive odd terms ,

Sum of two odd numbers

= 2x + 1 + 2x + 3

= 4x + 4

= 4 ( x + 1 )

= 4k ( let k = x + 1 )

4k is divisible by 4.

Therefore ,

Sum of any two consecutive odd

numbers divisible by 4 .

Proof

An even number is divisible by 2, so it can be represented by 2n, where n is an integer. If we add 1 to an even number, then it will be odd. Therefore, an odd number can be represented as 2n + 1.

If 2n + 1 is an odd number, then the next odd number is 2n + 3 (Why?). Therefore, the sum of two consecutive odd numbers can be represented by

(2n + 1) + (2n + 3) = 4n + 4.

Factoring, we have 4(n + 1). This means that 4 is a factor of 4n + 4. This means that 4n + 4 is divisible by 4. This implies that the sum of two consecutive odd numbers is divisible by 4.

Thx

3/7 + 2/7Take LCMWe get,= (3 + 2)/7= 5/7

Like if you find it useful

2*2*2+44*2+48+4=12

2×2×2+4=4×2+4=8+4=12

Please hit the like button

😭😭😭😭😭😭

Like if you find it useful

Like if you find it useful

Let one of the smallest odd no be x therefore another consecutive odd no would be x+2 .given sum of no is 68 iex+(x+2)=682x+2=682x=66x=33therefore two no are 33 and 35

QUADRATIC RESOLUTION ★

GIVEN EQUATION : 9x² - 9( a+b)x + (2a² + 5ab + 2b² ) = 0

BY QUADRATIC FORMULA -

9 ( a + b ) ± √ 81(a+b)² - 4 (9)( 2a² + 5ab + 2b² ) / 2( 9 )

RESOLVING " D " SEPARATELY :

81 ( a + b ) ² - 4 ( 9 )( 2a²+5ab+2b² )

81( a² + b² + 2ab ) - 36( 2a²+5ab+2b² )

81a²+81b²+ 162ab - 72a²- 180ab - 72b²

9a² + 9b² -18ab = [3(a+b)]²

D = [3(a+b)]² ; √D = 3( a+b )

9( a+b ) ± 3 ( a + b ) / 18

yields two values or roots respectively ,

2/3 ( a + b ) ; a+b /3

Train leaves station A at 5:15 pmTrain reached station B next morning at 10:40 am

Time taken by train From 5:15 pm to 5:15 am next morning = 12 hoursFrom 5:15 am to 10:40 am= 5 hours 25 minutes

Therefore,Total time taken by train from station A to station B= 17 hours 25 minutes

x+x+1+x+2+x+3=464x+6=464x=46-64x=40x=40/4x=10

X= 10 is the correct answer of the given question

let four consecutive odd number be2x +1 , 2x+3, 2x+5, 2x+7According to question,2x +1 + 2x+3 + 2x+5 + 2x+7 = 808x + 16 = 808x = 64x = 64/8 = 8So , numbers are,17, 19, 21, 23

1/5 is the correct answer of the given question

1/p+q+z -1/x=1/a+1/b; ; x-(a+b+x)/x(a+b+x)=a+b/ab; -( a+b)/x(a+b+x)=a+b/ab; -ab(a+b)=a+b(×(a+b+x); (a+b){x(a+n+x)+ab}=0; x(a+b+x)+ab=0;; x^2+xa+xb+ab=0; x( x+a)+b(x+a)=(x+a)(x+b)=0; x= A, b

Answer: c) 12hoursExplanation:

Time taken by one tap to fillhalf of the tank= 3 hrs.

Part filled by the four taps in 1 hour =4 x1/6=2/3

Remaining part =1 -1/2=1/2

2/3:1::1 :x

So, total time taken = 3 hrs. 45 mins.

5a^2-b^2-4ab+7a-7b=5a^2-5ab+ab-b^2+7(a-b)5a(a-b)+b(a-b)+7(a--b)=(a-b)(5a+b+7)

0.04 = 4/100 = 1/25 2.34 = 234/100 = 117/50

a is the right answer

Divide different levels of the same language

The time taken by Rohan to cover 355 m = 1 min15 sec

But 1065 = 3 × 355

Therefore

The time taken by Rohan to cover

1065 kms

= 3 × ( The time taken to cover 355kms )

= 3 × 1 min 15 sec

= 3 min 45 seconds.

1 min 15 sec = 75 minSpeed = distance/time = 355/75 = 71/15Time = distance/speed = 1065/(71/15) = (1065 × 15)/71 = 15 × 15 = 225 sec = 3 min 45 sec

Distance of 355 m can be covered in 1 minute 15 seconds or 75 seconds

Then,Distance of 1 m can be covered in 75/355 seconds

Therefore,Distance of 1065 m can be covered in1065*75/355 = 3*75 = 225 secods= 3 min 45 seconds

(a) is correct option

3 min 45 sec will be the ans

3min 45 sec need to cover 1065m

(sinA + secA)^ + (cosA + cosecA)^

(1/cosecA + secA)^ + ( 1/ secA. + cosecA)^

[( 1 + secA× cosecA)/cosecA]^ + [ (1 +cosecA×secA)/secA]^

(1 + secA×cosecA)^/cosecA^ + ( 1 + cosecA×secA)^/ secA^

taking common ,

(1 + secA× cosecA)^ (1/cosec^A + 1/ sec^A)

(1 + secA× cosecA)^ (sin^A +cos^A)

(1 + secA×cosecA)^ 2

( 1 + secAcosecA)^ 2

(sinA + secA)^ + (cosA + cosecA)^

(1/cosecA + secA)^ + ( 1/ secA. + cosecA)^

[( 1 + secA× cosecA)/cosecA]^ + [ (1 +cosecA×secA)/secA]^

(1 + secA×cosecA)^/cosecA^ + ( 1 + cosecA×secA)^/ secA^

taking common ,

(1 + secA× cosecA)^ (1/cosec^A + 1/ sec^A)

(1 + secA× cosecA)^ (sin^A +cos^A)

(1 + secA×cosecA)^ 2

( 1 + secAcosecA)^ 2

3x/4 + x/6 = 22 9x+2x = 22(12) 11x = 22×12 x = 24 (2x-3)/(4x+9) = (2×24-3)/(4×24+9) = 45/105 = 9/21 = 3/7

-5+8

-5+8

-5+8 = +3-5-2 = -76-10 = -49+5 = 14-9+6 = -38-4 = 4-6+3 = -3-6-3 = -9

a..3

b..7c..-4d..14e..-3f..4g..-3h..-9

-5+8= 3-5-2 = -76-10 = -49+5 =14-9+6 = -38-4 = 4-6+3 = -3-6-2 = -8

+3