InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 79251. |
-(-sqrt(5) %2B 7)/(sqrt(5) %2B 7) %2B (sqrt(5) %2B 7)/(-sqrt(5) %2B 7)=a %2B b*((7*sqrt(5))/11) |
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Answer» The given equation is :(7 + sqrt(5))/(7 - sqrt(5)) - (7 - sqrt(5))/(7 + sqrt(5))= a + 7sqrt(5)b/11 Solving the LHS of the above equation, we get (7+sqrt(5))(7+sqrt(5)) - (7- sqrt(5))(7-sqrt(5))/49-5 = 7 + 5 + 14sqrt(5) - 7 - 5 + 14sqrt(5)/44 = 28 sqrt (5)/44 = 7 sqrt(5)/11 Now, comparing with the RHS of the equation, we get a=0 and b=1 |
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| 79252. |
17. 2316710010013. 25.0614. 7.004convert each of the following into a decimal:158919.1021415251000175037000107250de Using decimals, express |
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Answer» 2.31.6715.895.41321.415 2.31.6715.895.413 2.31.6715.895.41321.415 1)2.32)1.673)15.894) 5.4135) 21.4156) 6.25 is the correct answer 2.316715.895.41321.415 1) 2.32) 1.673) 15.894) 5.4135) 21.4156) 6.25 |
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| 79253. |
11. Find the missing frequencies in the following frequency distributionwhose mean is 34.102030405060 Total4 |
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| 79254. |
Find the mean of the following data, using step-deviation method:Class 5-15 15-25 25-35 35-45 45-55 55-65 65-75Frequency | 6 10 16 15 24 8 |
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| 79255. |
Subtract the following.(a) 3 h 34 min from 5 h 55 min |
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Answer» 5 h 55 min - 3h 34 min= (5h - 3h) ( 55 min - 34 min)= 2h 21 min |
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| 79256. |
Ex. 8A person covers a certain distance with a speed of 18 km/h in 8wants to cover the same distance in 6 min, what should be his spesd |
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Answer» Case 1:-Speed=18 km/hrTime=8 mins=8/60 hr∴Distance=speed×time=18×8/60=2.4 km Case 2:-Distance=2.4 kmTime=6 min=1/10 hr∴Speed=Distance/time=24 km/hr |
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| 79257. |
If a cart is moving at a speed of 2.5 km/h and coversdistance in 8 hours 15 min. Then find the distance covered by thecart. |
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| 79258. |
10. An A.C cools the room at the rate of 5 C per hour What would be the final temperatureof the room after 6 hours, if the initial temperature of the room is 40C? |
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| 79259. |
9+5+2+0+5+5+3+4+8+8 |
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Answer» 49 is the answer 49 is the answer....... 49 is the correct answer 49 is the right answer.................. |
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| 79260. |
Fun with Addition5+2=7&&&&&&&5 and 2 make 7together and so do 2and 5 together. Whata fun! That's nice!It means thatchanging theorder does notchange the sumThat's right! Now, to check thisout, do the following additions5 + 93+78 + 3 =8+4 -5+6=0+3 - 01000DD1 + 4 =9+5=7+33 + 8 =4+8=6 + 5 =3 +00PHUKH. |
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Answer» 4+1=55+9=143+7=108+3=118+4=125+9=140+3=3 4+1=55+9=143+7=108+3=11 |
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| 79261. |
Solve completely (1 +i)^1/3 using De Moivre's theorenmusingDeMoivre'stheorem |
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Answer» 1 |
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| 79262. |
MATHEMATICSSAVNEETOR. Find the median of the following frequency distribution10-20 20-30 30-40 40-50 50-60 60-70 70-8ě´80-90Class2419985Frequency915if it ic nondefertive, Shopkeeper takes out one toy |
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| 79263. |
\left. \begin{array} { l } { 45 ^ { 2 } - 43 ^ { 2 } + 44 ^ { 2 } - 42 ^ { 2 } + 43 ^ { 2 } - 41 ^ { 2 } + 42 ^ { 2 } - 40 ^ { 2 } + \ldots \text { till } 1 } \\ { \text { (a) } 1982 } \\ { \text { (b) } 2592 } \\ { \text { (c) } 2756 } \\ { \text { (d) } 2832 } \end{array} \right. |
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| 79264. |
If the median of the distribution given below is 28.5, find the values of x and yClass intervalo- 1010- 2020- 3030-4040-5050-60TotalFrequency |
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| 79265. |
The mode of the following distribution is 55. Find k.CI0 15 15 30 30 45 45 60 60 75 75 90 TotalFrequency 66151051 |
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| 79266. |
6x5JUEXERCISE 3.1thatere aremberledtoere2.1. Write all the factors of the following numbers:(b) 15 (c) 21(a) 24(1) 20(d) 27 (e) 12(h) 23 (1) 36(g) 18Write first five multiples of:(b) 8 (c) 9.(a) 53. Match the items in column l with the items in column 2.Column 2Column 1(a) Multiple of 8(b) Multiple of 7.(c) Multiple of 70(d) Factor of 30( 35.(ii) 15(i) 16(iv) 20. |
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Answer» 1a)2*2*2*3B)5*3C)7*3D) 3*3*3E)2*2*3F)5*2*2G)3*3*2H)1*23I)3*3*2*2 2a)5,10,15,20,25B)8,16,24,32,40C)9,18,27,36,45 3)1)35.....b 2)15.....d 3)16....a 4)20.....c 1. (a). 2 × 2 × 2 × 3(b). 3 × 5(c). 3 × 7(d). 3 × 3 × 3 (e). 2 × 2 × 3(f). 2 × 2 × 5(g). 2 × 3 × 3(h). 1 × 23(i). 3 × 3 × 2 × 22. (a). 5, 10, 15, 20, 25.(b). 8, 16, 24, 32, 40.(c). 9, 18, 27, 36, 45.3. (i). 35 →(b)(ii). 15 → (d)(iii). 16 → (a) |
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| 79267. |
(v) 385(11) -99.9A. 1. What are integers W2. lu cach of the pairs given below, find the larger(01) 4.-61) 0. 33. Write the following integers in increasing order:-18. 16. 0. -5, 8. -36.-1.14. Find the value of:() 8-1-3110.9 -|-6 2-6 40 6 +1-41 6+43. Write four intégers less than -6 and four integers greater than -6.(11) (-361(viil) (-30) -6, Evaluate:(1) 8 H -16) ((111) (-6) (-8)(-5) + (-6)(vii) 8(H) (-40) + (-10)(-5)(v) 30 - (-50)7/The sum of two integers is -12. If one of them is 34. find the other.8. Simplify:(1) F-24) (68) + (-24) 32( 9) Ⓡ18 - (-9) * 8 9 x(iii) (-147) + (-21)(iv) 16+ (-1) 92-9Mark (1) against the correct answer in each of the following:9. The successor of -89 is1-9)(a) -90(b) -88(c) 90The predecessor of -99 is(a) -98(b) -100(c) 98(d) 100Additive inurgon(d) 880 |
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Answer» 3) -36, -18, -5, -1, 0, 1, 8, 16,. (4) (4)9-(-6)=15, (ii)6+(-4)=2, (iii)-8-(-3)=-8+3=-5; (6)i)8+(-16)=-8, (ii)-5+(-6)=-10, (v)30-(- 8i)(-24)×(68)+(-24)×32=-1632- (-24)×(68)=-1632; (-24)×32=-7 3) -36,-18,-5,-1,0,1,8,16 |
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| 79268. |
2. Subtract:a) 40 min 50 s from 45 min 20 s(c) 25 min 10 s from 5 h 16 min 8 s(e) 8 h 26 min 29 s-3 h 35 min 30 s |
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Answer» hit like if you find it useful |
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| 79269. |
2. If the coefficient of rth term and (r+ 1)h term in theexpansion of (1 + x)20 are in the ratio 1:2, thenr is equal to(2) 7(4) 9(3) 8 |
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| 79270. |
$\left.\begin{array}{ll}{a^{2}+b^{2}} & {b^{2}+c^{2}} \\ {a^{2}+c^{2}} & {a^{2}+b^{2}}\end{array}\right]+\left[ \begin{array}{cc}{2 a b} & {2 b c} \\ {-2 a c} & {-2 a b}\end{array}\right]$ |
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| 79271. |
ves - Kharna's car holds 43 l 530m/ of Petroler hus husband's car held 63 1 4some of pelostral How much petrol must they buy to fillth the car if both are empty ? |
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Answer» both car needed 106 litre 980 ml petrol They have to bought 106.98 litres of petrol. they have to bought 106.98 leter of petrol both car need 106 litre 980 petrol both car needed 106 liter 980ml petrol both car needed 106 liter 980ml petrol. |
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| 79272. |
sel is half-filled with water. The dimensions of its base are 50 cm x 30 cm.A tall rectangular vesA heavy metal cube of edge 10 cm is dropped into the vessel. Find the rise in the water level in thevessel |
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Answer» Let the rise in water level in the rectangular vessel behcm.Given, edge of the cube = 9 cm Dimension of the base of the rectangular vessel = 15 cm × 12 cm Since, the cube is completely immersed in the rectangular vessel, Volume of water displaced in the rectangular vessel = Volume of the cube 15 cm × 12 cm ×h= (9 cm)3 15 cm × 12 cm ×h= 729 cm3 h = (729/180) cm ⇒ h =4.05 cm Thus, the rise in water level in the rectangular vessel is 4.05 cm approximately. Like if you find it useful |
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| 79273. |
30.if the median of the following frequency distribution is 28.5, find the valueof x and y.Measurements 0-10 10-20 20-30 30-4040-50 50-60 TotalFrequency20 15 y 5 60 |
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| 79274. |
19. An incomplete distribution is given as follows:1 Variable: 0-10 10-20 20-30 30-40 40-50 50-60 60-70204015Frequency: 10You are given that the median value is 35 and the sum of all the frequencies is 170. Usingthe median formula, fill up the missing frequencies.25 |
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| 79275. |
32. खरा थरथरता ५५ ५ ५। । । । ।ब नारस 100 120 12() ।।।।) 100|1) 1() । () 2000बारबार । । ।।। । । । ।। । ।Find the mean of the following frequencydistributionClass Internal 100 120|120 1100 100|100 180|18(020)Frequency 12 1 4| 108 |
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| 79276. |
( For2x 3x 3x5 4 52b 7b 13b10. 32 75- 34For rem51512 314. と+y-19yЗа 4ax + 216. x+18.20. m-26(x-4)(p)(2p +5)(2p-2322,7)1026. Y.2ySo9a-3b+8(9a-3b+8)+5 from 3a -8+4b) (2b-7a+ 5)x-8y |
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Answer» 6.2p/3-3p/5(2px5 - 3px3)/(3x5)(10p-9p)/15p/15 |
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| 79277. |
-3×-2=3-(-3)=3+3 |
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Answer» The answer will be 6 in all the cases. 6,for only this expression |
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| 79278. |
3+3+3=3*3 |
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Answer» 9=9 please accept best 3+3+3=3×39=9=00 is correct answer according to your question. 1 is correct answer. 9=9 is correct answer yes 0 is the best answer 9=9 is correct answer 9=9 is the correct and best answer 0 is correct answer of the question L.H.S =3+3+3 =9R.H.S =3*3 =9L.H.S = R.H.STherefore , this equation is verified 3+3+3=93×3=99=9=00 is correct answer 0 is your correct answer 0 is the right answer |
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| 79279. |
Complete thelete the entries in the third column of the table.S.No.EquationValue of variableEquation satisfiedYes/NoSSSSSSSS10y = 8010y = 8010y 80412041 204/ 20b159b59b5 9h 8 5h 851-8-5p+3-1p+3=1p+31p+3=1P3-y 10y 8y-51 =201-801-5b=5b-9b-4h - 13h=8h-0p=3p=1p=0LI(p)(9)p=-23. Pick out the solution from the values given in the bracket next to cach equatShow that the other values do not satisfy the equation.(a) 5m= 60(10, 5, 12, 15)(b) n+12-20 (12, 8, 20,0)(c) p-55(0, 10,5-5)(d) -7(7,2, 10, 14)(c) r-40(4,- 4, 8, 0)(1) x+42(-2,0, 2, 4) |
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Answer» Yes are B, F,I,J,Q else are no |
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| 79280. |
28. Find the distance of the point (-1,-5,-10)from the point of intersection of the liner 2i-j + 2k + (3i + 41 + 2k) and theplane r (i -j+ k) 5. |
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| 79281. |
5. (a) Add: p(p-9), 9 ( -) and r( -p)(b) Add 2r(-x - y) and 2y (z-y - x)7) Subtract: 31(1 - 4 m + 5 n) from 41( 10 n-3 m +21).d) Subtract: 3a (a + b + c)-2 b (a - b + c) from 4c (-a+b. |
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| 79282. |
Show that the volume of the largest right circular cone that can be inscribed in a sphere of radius a is 8/27 (volume of the sphere). |
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| 79283. |
Find the radius of sphere.0) Find the volume of the largest right circular cone that can be cut out from a cube of edge 4.2 crm |
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| 79284. |
24. The following data gives the information on the observed life times (in hours) of 2clectrical components. Find the modal life time of the components. (Find the Mode)Life time0-20(in hours)Frequency 102040 40608o060-80 80-100 100-12035613829 |
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Answer» mode is the maximum frequency of an work so answer is 61 |
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| 79285. |
3, Fabina borrows? 12,500 at 12% per annum for 3 years at simple interest andRadha borrows the same amount for the same time period at 10% per annum,compounded annually. Who pays more interest and by how much? |
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| 79286. |
0. If the mean of the following frequency distribution is 54, find the valueof p.Class0-2020-40 40-6060-80 80-10010913Frequency[CBSE 20060 |
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Answer» step devision method by step division method |
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| 79287. |
9 Explain why 5 x 11 x 17+17 is not a composite number while 7 x 6 x 3x 5+5 is a compositenumber |
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Answer» is product of prime number a composite number |
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| 79288. |
2*x - 3=(3/10)*(5*x - 12) |
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Answer» (2x-3)=(3/10)(5x-12)10(2x-3)=3(5x-12)20x-30=15x-3620x-15x=-36+305x=-6x=-6/5 10(2x-3)=3(5x-12) 20x-30 = 15x-36 20x-15x= -36+30 5x = -6 X = -6/5 |
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| 79289. |
1. Solve the following equationsXin 3-4=1435 3ivy-2-p=112(v) 94 y 13(vii) 5-1 412 5 5 10 5(vii) 2-3 -23x +2 37p+1 4x+5 x+1 x+31+1 2t-3 t+3 3t-18 144(xii)167 |
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Answer» please mention which question to be solved?1] n/5 = 2/3 + 5/7 = 14+15 /21 = 29/21 , n/5 =29/21 , n=29 *5/21=145/21 |
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| 79290. |
। 5. नीचे दिए जाल की मदद से 15 का गुणा 13 से कीजिए -15 x 13= ( 10+5 ) x (10+3 )= (। ।+ _) x _ + ( _+_)x।।।।X+५॥।+।_X_ ++++||।॥।।। |
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Answer» = 15 x 13 = 10 + 5 x 10+3 = 1+2 × 5 ×10 ×1+3×1 = 10 x 5 x 10+3 24+33÷(34-23 |
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| 79291. |
Evaluate : (TTT3-8 x 10-5 Ă 1255-4 x (18)-5) |
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Answer» Please hit the like button if this helped you. |
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| 79292. |
3 x - 10 = 5 ( x - 10 ) |
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Answer» 3x-10=5×-50;5x-3x=-10+50;2x=40;x=20 |
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| 79293. |
4.140, x, y E N, how many ordered pairsIf 7x +4y(x, y) satisfy the given equation?9. |
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| 79294. |
the mean age of a family of 6 members is 25 years.find the mean age of members after 45 years old leaves a family |
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Answer» Mean of 6 members is 25 so sum is 6×25 = 150 now 45 years old member leaves a family so sum of remaining = 150 - 45 = 105 so mean = 105/5 = 21 years If you find this answer helpful then like it. |
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| 79295. |
\begin{array} { l } { \text { Q12. Find the radius of of the largest right circular cone that can be cut out } } \\ { \text { from a cube of edge } 4.2 \mathrm { cm } \text { . } } \end{array} |
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Answer» Diameter of cone= edge of cube Radius= edge of cube/2 =4.2/2 =2.1 cm |
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| 79296. |
Q2.The value of 'k' for which the followingequation has equal roots.(k-12)x2 + 2 (k-12)x + 2 = 0.ICQ12.3 |
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| 79297. |
1. What sum will amount to 6,593.40 in2 years at C., if the rates are 10 percent and11 percent for the two successive years?(2.The value of a machine depreciated by10% per year during the first two years and15% per year during the third year. Expresthe total depreciation of the machine, aspercent, during the three years3. Rathnx borrows 12.000 at 10 |
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Answer» total depreciation of the machine as percent , during the three years is= 7 |
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| 79298. |
sabayon deposited 18000 in a bank for 3 years which pays 6% interest per year find simple interest she will get at the end of 3 years |
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Answer» Principal=Rs. 18000Time=3 yrs.Rate of interest=6% p.a.∴SI=PRT/100=(18000×3×6)/100=Rs.3240 please answer to my English question anna |
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| 79299. |
Find the mean of the following frequency distribution.Class40-50 50-60 60-70 70-80 80-90 90-100Frequency10 202 |
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| 79300. |
68Express the following as mixed fractions:20 (b) 51775 (c)196285 (e)359Express the following as improper fractions |
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Answer» a)20/3 =20÷3=3)20(6 -18_ 02 = 6 thanks |
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