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We know that the corresponding sides of similar triangles are in proportion.∴ AB/PQ = AC/PR = BC/QR ...(i)Also, ∠A = ∠P, ∠B = ∠Q, ∠C = ∠R …(ii)Since AD and PM are medians, they will divide their opposite sides.∴ BD = BC/2 and QM = QR/2 ...(iii)From equations(i)and(iii), we getAB/PQ = BD/QM ...(iv)In ΔABD and ΔPQM,∠B = ∠Q [Using equation(ii)]AB/PQ = BD/QM [Using equation(iv)]∴ ΔABD ~ ΔPQM (By SAS similarity criterion)⇒ AB/PQ = BD/QM = AD/PM

No correct answer

1) 4 is in unit place -> place value =4*1 =4

2)9 is in hundreds place -> place value of 9 =9*100 =900

3) 6 is in tens place-> place value of 6 =6*10=60

*) tens*)tens*)tensin two digit no. place value of last digit is ones and first digit is tens

Place value of 5 in 501is hundredth

1.1) 7,14,21,28,35,42,492) 2,4,6,8,10,12,14,163)3,6,9,12,15,18,21,244) 4,8,12,16,20,24,285)11,22,33,44,55,66,77,88

2.multiple of 4- 4,8,12,16,20,24,28multiple of 6- 6,12,18,24,30,36,42common - 12, 24

the length of AD is 2.4 cm it came by applying BPT

Applying BPTso hereAD/ DB= AE/ECx/7.2= 1.8/5.4x/7.2= 1/3x= 7.2/3= 2.4 cm

given when x = 1 p(x) = x/15 so herep(1) = 1/15 option (a) is correct answer

please give us the shaded region

Let side of first square be x and the side of another square be y.difference in perimeter of twosquares:-4x-4y=164(x-y)=16x-y=16/4therefore, x-y=4and x=4+y---take this(1)sum ofareas of two squares:-x²+y²=400Put (1) here(4+y)²+y²=400(4)²+(y)²+2×4×y+y²=40016+y²+8y+y²=4002y²+8y+16-400=02y²+8y-384=02(y²+4y-192)=0 (y²+4y-192=0we have done with factorisation method:-y²-12y+16y-192=0y(y-12)+16(y-12)=0(y+16) (y-12)=0either:- | or:-y+16=0 | y-12=0y=-16 | y=12

we will take y=12 because y being side cannot be negative.So, y=12put y=12 in (1)x=4+yx=4+12therefore,x=16and hence, Side of first square=x=16cmand Side of another square= y =12cm

In number 6000Face value of 6 = 6Place value of 6 = 6*1000 = 6000

Difference of place value and face value= 6000-6 = 5994

(c) is correct option

thanks

In Right Δ P SQ

P Q²= PS² + SQ²→→[By Pythagoras theorem]

a²= PS² + c²

→PS² = a² - c²-------(1)

In Right Δ P SR

PR²= PS² + SR²→→[By Pythagoras theorem]

b²= PS² + d²

PS²= b² - d² ------(2)

From (1) and (2)

b²- d²= a² - c²

a² - b²= c² - d²

(a -b)(a+b)= (c-d)(c+d)→→Using the identity, A²-B²= (A-B)(A+B)

Hence proved.

thanks

AC=26cmthereforeradius AO=1/2AC=1/2x26=13cmNow AB=10 cmsince distance from centre of circle to a chord bisect the chord therefore AM=1/2AB=1/2x10=5cmIn right ΔAMO using pythagoras theorem we getAO²=AM²+OM²13²=5²+OM²OM²=169-25OM²=144OM²=12²OM=12cmtherfore correct option is (c) 12cm

OA^2= OM^2+AM^2(13)^2= OM^2+(5)^2169-25=OM^2√144= OM12 CM= OMdist from center is 12cm

option c is the right answer

option c is the right answer

option c is the correct answer

A + B = 180 [sum of supplementary angles]

3x-3+2x+3 = 180

5x = 180

x = 36°

angle A = 3*36 - 3

= 105°

angle B = 2*36 + 3

= 75°

A rectangular courtyard is 3.78 m long broad it is desired pave it with square tiles of the same size . what is the largest size of the tile that can be used? also , find the number of such tiles

ans. and method is wrong ☹️☹️

Length (l) of cardboard = 8 cmBreadth (b) of cardboard = 5 cmArea of cardboard including margin = l × b = 8 × 5 = 40 cm2From the figure, it can be observed that the new length and breadth of the cardboard, when margin is not included, are 5 cm and 2 cm respectively.Area of the cardboard not including the margin = 5 × 2 = 10 cm^2Area of the margin = Area of cardboard including the margin − Area of cardboard notincluding the margin= 40 − 10 = 30 cm^2

8000, 890, 9 70000, 7 is the correct answer of the given question

a. place value =1000face value =8b.place value =10face value =9c.place value =10000face value = 7

a. place value is 8000 face value is 8

b. place value is 90 face value is 9

c.place value is 70000 face value is 7

thanks a lot

360° = 2πr1° = 2πr/360°120° = 2πr/360° *120°2πr/3(2*(22/7)*3.5)/37.32 cm

As she scored 75% so she must have done 75% of questions correct.75% of 20 = 15.

(1) (-13/5 + 12/7) ÷ (-13/7 * - 1/2)= (-13*7 + 12*5)/35 ÷ 13/14= (-91 + 60)/35 * 14/13= - 31/35 * 14/13= - 31*2/5*13= - 62/65

(2) x^2 + 5x + 6= x^2 + 3x + 2x + 6= x(x + 3) + 2(x + 3)= (x + 2)(x + 3)

On division by (x + 2), we get(x + 3)

x²+5x+6=x²+2x+3x+6=x(x+2)+3(x+2)=(x+3)(x+2)(x+3)(x+2)/(x+2)=(x+3)

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2nd one is the correct answer

if the symbol between numbers is + then 2nd one is correct

if the symbol between the numbers is ÷ both values is same

questions is find the the length of longest pole

1st jump=65cm2nd jump=1st jump+14cm=65+14=79cm

1st jumy by Sonu=65cm2nd higher jump by Sonu=14cmtherefore, he jumps second time==(65+14)cm=79cm

put X=24(-2)^3-3(-2)^2+2(-2)-4=4*-8-3*4-4-4=-32-12-8=-32-20=-52

all details

0.006+ 9.8+26.04=35.846