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13^-2/3÷(1/13)^1/213^-2/3*13^1/213^-2/3+1/213^-4+3/613^-1/6=(1/13)^1/6

this is not answer to your questions but this is similar to your question i think this might help to solve q by your own .

Q.A cannon ball (mass = 2 kg) is fired at a target of 500 meters away. The 400 kg cannon recoils by 50 cm. Assuming cannon ball moves with constant velocity, when will it hit the target? [Resistance offered by ground to cannon is 100 N]

A.

Force by ground on the cannon = 100N.

Work done by ground on the cannon = 100 x(0.5) = 50J.

Applying conservation of energy

work done by ground on canon = Kinetic energy of canon immediately after firing = (1/2) mv2= 50J.

Velocity of cannon (v) = 0.5m/sec.

By applying law of conservation of momentum

400(0.5) = 2 (velocity of cannon ball)

Velocity of canon ball = 100m/sec.

Time taken by the canon ball to hit = 500/100 = 5 seconds.

thanks

As it is parallelogram the opposite sides are equal.

hence the distance PQ = distance SR root (1-1)^2 + (-3-4)^2 = root (a-7)^2 + (4-11)^20 + (-7)^2 = a^2 - 14 a + 49 + (-7)^20 = a^2 - 7a - 7a +490= ( a-7) (a- 7)a= 7

Herea= 7d= 619 the term = a+18d= 7+18*6= 108+7= 115

a = 7 and d = 6a(n) = a + (n-1) da(18) = 7 + (18-1)×6a(18) = 7 + 17×6a(18) = 109

tq so much your answer is correct

12x^2-15x+3x=3 -> 12(3)^2-15(3)+3=108-45+3=66x=1/2-> 12(1/4)-15(1/2)+3=3-15/2+3=-3/2

when two angles and the side between them are equal to the corresponding angles and the side between them of the second triangle, the triangles are said to be congruent. this is known as ASA congruency.the minimum number of equal elements required to prove congruency is three.No there is no such congruency rule for triangle.

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A(2,3) ------------------P(4,m)--------------B(6,-3)

Applying section formula , Let λ is the ratio by which P divides the line joining A and B.x = (λx₂ + x₁)/(λ + 1) here , x = 4 , x₁ = 2 , x₂ = 6 Now, 4 = (6λ + 2)/(λ + 1)4(λ + 1) = 6λ + 2 4λ + 4 = 6λ + 2 2 = 2λ ⇒ λ = 1 Hence, p divides the line AB into 1 : 1 ratio.

Now, for y - co - ordinate y = (λy₂ + y₁)/(λ + 1) m = (1 × -3 + 3)/(1 + 1) = 0Hence , m = 0

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Tnx

ans. 4812+6=1818+8=2626+10=3636+12=48also 12÷2=618÷2=9(+3)26÷2=13(+4)36÷2=18(+5).....48÷2=24(+6)

I will do it tomorrow

good

volume = 4πr³

= 4*22*4*4*4/7

= 804.57142857 m³

Applying section formula , Let λ is the ratio by which P divides the line joining A and B.x = (λx₂ + x₁)/(λ + 1) here , x = 4 , x₁ = 2 , x₂ = 6 Now, 4 = (6λ + 2)/(λ + 1)4(λ + 1) = 6λ + 2 4λ + 4 = 6λ + 2 2 = 2λ ⇒ λ = 1 Hence, p divides the line AB into 1 : 1 ratio.

Now, for y - co - ordinate y = (λy₂ + y₁)/(λ + 1) m = (1 × -3 + 3)/(1 + 1) = 0Hence , m = 0

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First five odd Numbers are 1,3,5,7,9

Mean=1+3+5+7+9/5=25/5=5

total 36 possibilities i) doublet (1,1),(2,2),(3,3),(4,4),(5,5),(6,6) so probability = 6/36 = 1/6 ii) sum of 10 so possibilities (4,6),(5,5),(6,4) so probability = 3/36 = 1/12

There are a total of 36 possibilities :

{ (1,1), (1,2), (1,3), (1,4), (1,5),(1,6) (2,1)(2,2)… …..(6,5) (6,6)}

The doublets among these are (1,1), (2,2),(3,3)(4,4),(5,5),(6,6)

So the probability of getting a doublet is :

No. Of doublets / total no. of outcomes =6/36=1/6

2)Let B be the event of getting a sum of 10 of the numbers of two dice.

n(B) = {6,4},{4,6},{5,5}

= 3.

Required probability P(B) = n(B)/n(S)

= 3/36

= 1/12

1/6 is the correct answer of the given question

1----6. is. the. answer. 👆👆👆👆👆

1/6 is the correct answer of the given question

probability of getting an even number= probability of not getting an odd number. probability of getting odd number. = 1(2/5) = 3/5

probability= no. favourable outcomes/ total no. of outcomes

3/5= no. of times odd number obtained/ 100.

no.of times odd number obtained= 60

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Given that, mth term=1/n and nth term=1/m.

then ,let a and d be the first term and the common difference of the A.P.so a+(m-1)d=1/n...........(1) and a+(n-1)d=1/m...........(2).subtracting equation (1) by (2) we get,md-d-nd+d=1/n-1/m=>d(m-n)=m-n/mn=>d=1/mn. again if we put this value in equation (1) or (2) we get, a=1/mn.

then, let A be the mnth term of the APa+(mn-1)d=1/mn+1+(-1/mn)=1

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1 m = 100 cm required bricks = (900×150×32.5)/(22.5×10×7.5) = 2600

Given area of path = L×B = 6500 m²Height = 14 cm = 0.14 mTotal volume = L×B×HTotal volume = 6500 m² × 0.14 mTotal volume = 910 m³

Cost of gravel of 1 m³ is Rs 5.6

So, for 910 m³ cost is Rs 910 × 5.6 = Rs 5096

Please check this solution

Given, Area of path = 6500 m^2Deepness of gravel = 14 cm or .13 m

Then,Volume of gravel used to cover path = 6500 *.14= 65*14= 910 cubic metre

Cost of covering with gravel= 910*5.60= Rs 5096