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(5,-1)(20,-4)(-5,1)(-20,4)(-10,2)

-2 b^3 is the correct answer of your question

-2 b^3 is correct answer

-2^3 is correct answer

Area of shaded region=20*7-π(7/2)²=140-38.48=101.52m²

P (A hits) = 4/5P (A not hits) = 1 - 4/5 = 1/5

P (B hits) = 3/4P (B not hits) = 1 - 3/4 = 1/4

P (C not hits) = 1/3P (C hits) = 1 - 1/3 = 2/3

Probability target hit at least twice =P(A hits)*P(B hits)*P(C not hits) + P(A hits)*P(B not hits)*P(C hits) + P(A not hits)*P(B hits)*P(C hits) + P(A hits)*P(B hits)*P(C hits)

= 4/5*3/4*1/3 + 4/5*1/4*2/3 + 1/5*3/4*2/3 + 4/5*3/4*2/3

= 12/60 + 8/60 + 6/60 + 24/60

= (20 + 30)/60

= 50/60

= 5/6

6)You need to find the probability that at least one of them solve the problem.

This is equal to, = 1 - probability that none will solve.

Because they will only fail when none of the A B C will solve problem. In other cases problem will be solved.

Probability that no one solve := [1-(4/5)]x [1-(2/3)] x [1-(3/7)]= 4/105

So the answer is = 1-(4/105) = 101/105

8) Probability that he is getting both contracts = prob. ELE * prob. PLU = (2/7)*(3/5) = 6/35

bacchon ko darane ke liye

Letprobabiltyofsuccesbep,henceaccordingtoquestion3C2p2(1−p)=9×3C3p3⇒3p2(1−p)=9p3⇒1−p=3p⇒4p=1⇒p=14

sdtvhf431-326+46742

Letprobabiltyofsuccesbep,henceaccordingtoquestion3C2p2(1−p)=9×3C3p3⇒3p2(1−p)=9p3⇒1−p=3p⇒4p=1⇒p=14

If you toss a coin thrice then one of the following 8 outcomes is possible.

HHH

HHT

HTH

HTT

THH

THT

TTH

TTT

Favourable outcome = HHT or THH or HTH

No. Of favourable outcome (FO)= 3

Total No. Of outcome (TO) =8

Probability =FO/TO =3/8

The answer is 2464.99

2464.99 is the correct answer of this question

2464 is the correct answer.

given, area of base =2πr=176height =65we know that, lateral surface area = 2πrh = 176*65

Oceansare the lifeblood of planet Earth and humankind. They flow over nearly three-quarters of our planet, and hold 97% of the planet's water. They produce more than half of the oxygen in the atmosphere, and absorb the most carbon from it.

Like my answer if you find it useful!

r = 28.

12x^2-4x-3x+14x(3x-1)-1(3x-1)(3x-1)(4x-1)

let radius be r

circumference 176

but circumference of circle is 2pier

2pie×r =1762×22/7×r=176r=176×7/44r=28

thanks

thank you very much

it is not a answer

number of possible outcomes=(1,1),(1,2),(1,4),(1,6),(2,1),(2,3),(2,5),(3,2)(3,4)(4,1)(4,3)(5,2)(5,6)(6,1)(6,5)=15

Probability = 15/36 = 5/12

When two dice are thrown total number of outcomes = 6*6= 36

Possible outcomes for score 5 are (1,4), (2,3), (3,2), (4,1)

Therefore,Probability of getting score of 5 when two dice are thrown= 4/36 = 1/9

P (sum as 5) 4/36=1/9

bhai answer

bhai nahi aya

tan {(B+C)/2}=tan A/2=tan 90/2=tan 45=1

We know tan² + 1 = sec²

So,

given tan = 3/5

(3/5)² + 1

9/25 + 1 = 34/25

So, sec² = 34/25

sec = √34/5

Area of small circle:

=22/7×3×3=198/7 cm sq.

now,

Area of bigger circle :

198/7×49=1386cm sq.

20.933 is the correct answer

(n+2)(n+1)n(n-1)!=60(n-1)!(n+2)(n+1)n=60so n=3

The answer is to your question is 81

In the 1950's, biochemists Stanley Miller and Harold Urey, conducted an experiment which demonstrated that several organic compounds could be formed spontaneously by simulating the conditions of Earth's early atmosphere.

They designed an apparatus which held a mix of gases similar to those found in Earth's early atmosphere over a pool of water, representing Earth's early ocean. Electrodes delivered an electric current, simulating lightning, into the gas-filled chamber. After allowing the experiment to run for one week, they analyzed the contents of the liquid pool. They found that several organic amino acids had formed spontaneously from inorganic raw materials. These molecules collected together in the pool of water to form coacervates.

q=3/2 is the right answer

4*5q=2*1520q=30q=30/20q=3/2

q=3/2 is the correct answer of the given question

5 q = (15×2)/45 q =15/2q = 15/(2×5)q = 3/2us correct answer

q=3/2 is the right answer