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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 3301. |
\left. \begin{array} { l l } { \sqrt { 50 } = 5 \times \sqrt { 2 } } & { \text { (B) } \sqrt { 60 } = 4 \times \sqrt { 15 } } \\ { \sqrt { 243 } = 9 \times \sqrt { 3 } } & { \text { (D) } \sqrt { ( 75 - 10 ^ { 2 } ) } = 5 } \end{array} \right. |
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Answer» The answer is option B √60 = √(15*4) = 2√15 |
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| 3302. |
हि : sin B-cosB +1 1 . : mi' |15 : Prove that —————— = ———— . ygsing the iअमर o sin B+cosB-1 secB-tanB £ ]sec?®=1 + an? 6. |
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Answer» thank you |
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| 3303. |
2 mi Pare ngents to the circle with centre O such that LAPB S0P ind theB. |
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Answer» Since OA is perpendicular to PA and also, OB is perpendicular to PB ∠APB + ∠AOB = 180° 50°+ ∠AOB = 180° ∠AOB = 180° – 50° = 130° In △AOB, OA = OB = radii of same circle ∠OAB = ∠OBA = x ( say ) Again, ∠OAB + ∠OBA + ∠AOB = 180° x +x + 130° = 180° 2x = 180° – 130° = 50° X = 25° Hence, ∠OAB =25° |
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| 3304. |
na survey orandom, find the probability that she is not |
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| 3305. |
!ââ Aoy 00 WKMWM/L Mi/ P tgasure 0 tha \aerB oy o Sepplemeny S8 L st i e22 2 2 ..mead vrt? |
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| 3306. |
. 12> =x 4 mi=l) 2XF S 3 |
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Answer» hit like if you find it useful |
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| 3307. |
सानित 50 3 +ठि+र्द्रि २३ |
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Answer» લેટ 3 - √2 = (એ / બી) એક પરિમાણીય સંખ્યા છે. બંને બાજુથી બેઠા પર મળીને મળે છે 2 + 3 - 2 +6 = (એ 2 / બી 2) તેથી, 5 - 2, 6 = (એ 2 / બી 2) એક રજિસ્ટિક સં. તો, 226 = 5- (એ 2 / બી 2) કારણ કે, 2 થી 6 એક અપ્રમાણિક સં. અને 5 - (એ 2 / બી 2) એક પરિમાણીય સંખ્યા છે. તેથી, મારો વિરોધાભાસ ખોટો છે. તેથી, (, 3 - √2) એક અદ્રશ્ય સંખ્યા છે. |
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| 3308. |
59-50+3 |
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Answer» 12..... ho ga.........................?........ = 59-50+3= 9+3= 12 |
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| 3309. |
180 - \{ 50 + ( 3 \times 60 - 2 \times 25 ) \} |
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Answer» By BODMAS rule180-{50+(180-50)}180-{50+130}=180-180=0 |
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| 3310. |
^ { 20 } C _ { r } = ^ { 20 } C _ { r + 6 } \text { find } r |
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Answer» hencer+r+6=202r=14r=7 |
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| 3311. |
9 In as sngle throw of a pair of dice, the probability of getting a doublet is |
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Answer» Total no of sample points when 2 dice are thrown =36Let E =6P(getting a doublet) =1/6 |
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| 3312. |
a+b+c=20,c=? |
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| 3313. |
Ex 32.3oh a simultaneous +hrou of a pair of diceind the probabiuty or getting a doublet s |
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Answer» When a pair of dice is thrown, the total possibleoutcome is 6^2 that is 36doublets are (1,1)....(6,6)even doublets are (2,2) (4,4) and (6,6)there fore probability is 3÷36 i.e 1/12 |
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| 3314. |
2+2×32×4÷5 |
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Answer» 2+2×32×0.82+51.253.2 2+2×32×4÷5 4×128÷5 102.4. answer what should be added to 6. 125 to get 10? |
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| 3315. |
\left. \begin{array} { | c | c | c | c | c | c | } \hline \text { Class } & { 0 - 10 } & { 10 - 20 } & { 20 - 30 } & { 30 - 40 } & { 40 - 50 } \\ \hline \text { Frequency } & { 5 } & { 18 } & { 15 } & { p } & { 6 } \\ \hline \end{array} \right. |
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Answer» mid points of all classes=5,15,25,35,45arithmetic mean=25so (5×5+15×18+25×15+35p+45×6)/(44+p)=25940+35p=1100+25pso 10p=160so p=16 |
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| 3316. |
\left. \begin{array} { | c | c | c | c | c | c | } \hline \text { Classes } & { 0 - 20 } & { 20 - 40 } & { 40 - 60 } & { 60 - 80 } & { 80 - 100 } \\ \hline \text { Frequency } & { 17 } & { 28 } & { 32 } & { P } & { 19 } \\ \hline \end{array} \right. |
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Answer» 17+28+32+p+19/5 = 50 p+96 = 250 p = 154 Please show by using class 10 stats formula |
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| 3317. |
simplify: 5√2 +2√8-3√32 ++4√128 |
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| 3318. |
के. ०८: जाया : 5 /2 +2/8 -3/32 +4/128 |
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Answer» √8=2√2√32=4√2√128=8√2hence5√2+4√2-12√2+32√29√2+20√2=29√2 |
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| 3319. |
if the die is thrown at random find the probability of getting 3 |
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Answer» 1/6 is the correct answer i don't know 😃😃😃😃😃 the probability will be 1/6 1/6 is the probability of getting a 3 when the die is thrown random once is the best answer. 1/6 is a right answer 1/6 is the correct answer |
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| 3320. |
r+1/43.37(2) 32(4) rk(3) 3 |
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| 3321. |
9. Find the mean proportional between 2 and 32e) 15(1) 32(2) 4 |
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Answer» the answer is option 3 that is 16 and like my answer |
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| 3322. |
of:Find the value o8+216+32(1) 1010.4(2) 11(3) 12(4) 32 |
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| 3323. |
486 आदमी 10 दिन में 150 रुपये कमाते है, तो 8 आदमी 7 दिन में कितने रुपये कमायेंगे?(a) 120 रुपये (b) 140 रुपये (0) 160 रुपये (d) 180 रुपये। |
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Answer» In 10.days 6men.earn =150in 1day 1 man earn =150/10/6in 7 days 8men earn =150/10/6×7/8 160 is the correct answer 140 is the correct answer of the following question option b is the right answer option b is the right answer option b is the right answer option c is the right answer b is the correct answer........... option c is the right answer |
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| 3324. |
2/sqrt(50)+3/sqrt(32)+4/sqrt(18) |
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Answer» 2/sqrt(50)+3/sqrt(32)+4/sqrt(18)= 2/5root2 + 3/4root2 + 4/3root2= 2root2/10 + 3root2/8 + 4root2/6 [Multiplying and dividing each by root2]= root2/5 + 3root2/8 + 2root2/3= (24root2 + 45root2 + 80root2) / 120= 149root2 / 120 |
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| 3325. |
3.Two dice are rolled. What is the probability of getting(i) the sum of numbers on two dice is 11.(ii) odd numbers on both diceCind the |
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Answer» Total outcomes = 36Favourable outcome = 2Probability of getting sum 11 = 2/36 = 1/18Probability of getting odd no. on both dice = 7/36 |
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| 3326. |
Two different dice are rolled together. Find the probability of getting(i)(ii)(iii).the sum of numbers on two dice to be 5,even number on both dicea doublet. |
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Answer» (i) (1, 4) ; (2, 3) ; (3, 2) and (4, 1) = 4 outcomes Probablity = Number of favorable outcomes/Total number of possible outcome=4/36 = 1/9 (ii) (2, 2) ; (2, 4) ; (2,6) (4, 2) ; (4, 4) ; (4,6) (6, 2) ; (6, 4) and (6, 6) = 9 outcomes Probablity = Number of favorable outcomes/Total number of possible outcome=9/36 = 1/4 iii) (2,2) ; (4,4) ; (3,3) ; (1,1) ; (5,5) ; (6,6) = 6 outcomes Probablity = Number of favorable outcomes/Total number of possible outcome=6/36 = 1/6 Like my answer if you find it useful! |
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| 3327. |
sun5)Two dice are thrown simultaneously. What is the probability that thedice is (a) 7(b) not a prime number (c) 1Two dice are th6 (b) 12(c) 7rown together. Find the probability that the product of numbers on the top of the dice is (a)nottine fal doublet of prime numbers (b) a doublet of |
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| 3328. |
Two dice are rolled once. Find the probability of getting such numbers on two dice, whoseproduct is a perfect square |
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| 3329. |
Divide 8m3-730-108m2 +486 m by 2m-9.Write down the quotient andremainder .Also check your answer |
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| 3330. |
. Twe diferent dice are rolled together. Find the probability of getting() the sum of numbers on two dice to be 5,i even number on both dice) a doublet. |
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Answer» (i) (1, 4) ; (2, 3) ; (3, 2) and (4, 1) = 4 outcomes Probablity = Number of favorable outcomes/Total number of possible outcome=4/36 = 1/9 (ii) (2, 2) ; (2, 4) ; (2,6) (4, 2) ; (4, 4) ; (4,6) (6, 2) ; (6, 4) and (6, 6) = 9 outcomes Probablity = Number of favorable outcomes/Total number of possible outcome=9/36 = 1/4 iii) (2,2) ; (4,4) ; (3,3) ; (1,1) ; (5,5) ; (6,6) = 6 outcomes Probablity = Number of favorable outcomes/Total number of possible outcome=6/36 = 1/6 Like my answer if you find it useful! |
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| 3331. |
45. The hypotenuse of a right angled triangle is 17 cm and the difference of the other two sides is!7 cm, find the measure of the unknown sides of the triangle. |
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Answer» Let other two sides of a triangle are a and b Then,a - b = 7a = 7 + b....... (1) Given,Hypotenuse h = 17 cm Using pythagoras theoramh^2 = a^2 + b^2Put value of a from eq(1)(17)^2 = (7 + b)^2 + b^2289 = 49 + b^2 + 14b + b^22b^2 + 14b - 240 = 0b^2 + 7b - 120 = 0b^2 + 15b - 8b - 120 = 0b(b + 15) - 8(b + 15) = 0b = - 15, 8 Negative value not possible So,Other two sides are a = 7 + 8= 15, b = 8 |
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| 3332. |
Two numbers are in the ratio of 7:9. If their sum is 320, find the numbers. |
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| 3333. |
Two dice are thrown random. Find probabiilty ofgetting same face number on both dice. |
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Answer» No of observation {(1,1),(1,2),(1,3).......(5,6),(6,6)=361)your required event ,{(1,1),(2,2),(3,3).......}No of event =6since probability =no. of events / no. of sample spaceso = 6/36=1/6 |
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| 3334. |
Fit the probability of occurrence uleauThr ee coins are tossed simultaneously 200 times with the following frequencies of diferent outcomes:Outomes: 3heads 2heads 1head No headFrequency: 23 72 77328Find the probability of getting: (i) three heads (ii) two heads and one tail(i) at least two heads.d rnndomh and the following data were recorded |
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| 3335. |
Prove that the line drawn through the telQ14 Explain the example of probability in daily life? Any two.Orwo coin are tossed simultaneously 500times and we getTwo heads: 105timesOne heads: 275timesNo heads: 120timesFind the probability of occurrence of each of these eventses on the same base and between the |
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Answer» Probability = possible outcomes/ total outcomes Probability that two head occurs=105/500=21/100 Probability that exactly one head appears=275/500. Probability that no head appears=120/500=6/25 |
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| 3336. |
F60 cm of a metal weighs 1kg, find the weight of a block of the same metal of the size 20 cm by 12cm by 5 cm. |
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Answer» 60 cm=1kg =1200cm=1200/60 |
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| 3337. |
20. A cylinder is open at both ends and is made of 1.5-cm-thick metal. Its external diameter is12 cm and height is 84 cm. What is the volume of metal used in making the cylinder? Alsofind the weight of the cylinder if 1 cm3 of the metal weighs 7.5 g |
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| 3338. |
X. Find the LCM of the following.(a) 72 and 96(c) 180 and 210(e) 192 and 320 |
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| 3339. |
section of a piece of metal 2 min length is shown inadjoining figure.glate: (G) the area of its cross-section;he16 cm-(ii) the volume of piece of metal(ii) the weight of piece of metal to the nearest kg,if 1 cm3 of the metal weighs 6.5 g.13 cm-90 cm-_ |
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| 3340. |
A cylinder is open at both ends and is made of 2-cm thick metal. Its externaldiameter is 12 cm and height is 84 cm. What is the volume of the metal used inmaking the cylinder? Also, find the weight of the cylinder if 1 cm3 of the metalweighs 6 g.1. |
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| 3341. |
16. A cylinder is open at both ends and is made of 1.5 cm thick metal. Its external diameter is 12 cmand height is 84 cm. What is the volume of metal used in making the cylinder ? Also find theweight of the cylinder if 1 cm of the metal weighs 7.5g. |
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| 3342. |
Solve these word problems.. A cylinder is open at both ends and is made of 2-cm thick metal. Its externaldiameter is 12 cm and height is 84 cm. What is the volume of the metal used inmaking the cylinder? Also, find the weight of the cylinder if 1 cm of the metalweighs 6 g. |
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| 3343. |
T ind te measure of each anglesides AB. BC and CA show that MQ17. In ÎÎ B C DF are respectively the mid points of sides AB, BC and CA. show that AABC isdivided into four congruent triangle by joining D, E and F |
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Answer» As D and E are mid-points of sides AB and BC of the triangle ABC, by Theorem 1, DE || AC Similarly, DF || BC and EF || AB Therefore ADEF, BDFE and DFCE are all parallelograms. Now DE is a diagonal of the parallelogram, therefore, ∆ BDE ≅ ∆ FED Similarly ∆ DAF ≅ ∆ FED and ∆ EFC ≅ ∆ FED So, all the four triangles are congruent. a number line is a s h o w n BEL o w a number line is s h o w n b e l o w |
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| 3344. |
the paiae, hd measure of all its sides.side from its opposite sides.ornid of a parallelogram is 12 cm. If its area is 204 cm. find the distance of the ge 675 em, find the measures of bas |
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| 3345. |
Theorem 6.8summ 6 tn a right triangle, the square of the hypotenuse is equal to theof the squares of the other two sides. |
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| 3346. |
Cnstruct a thiangle of sides 4 am, 5 em and 6 em and then a triangle similar to it[CBSE 2013, 2017]whose sides are (2/3) of the corresponding sides of it.n 0 486 such that each of its sides is (5/7)th of |
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| 3347. |
The sum of three sides of a triangle is 16 3/5 cm.If two of its sides measure 5 7/10cm and 6 3/4 cm respectively,then find the length of the third side? |
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Answer» Sum of 3 sides = 16 3/5 = 83/5 cmTwo sides measure = 5 7/10 = 57/10cm 6 3/4 = 27/4cmLet third side be xSum of 3 sides = x + 57/10 + 27/4 = 83/5(4x + 228 + 270) /40 = 83/5(4x + 228 + 270)/8 = 834x + 498 = 6644x = 166x = 166/4 = 83/2 = 41 1/2 cm |
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| 3348. |
7. The lengths of the sides of four triangles are given belotriangles are given below. Which of them is a right-angledtriangle?a. a-8 cm, b 5 cm, and c 10 cmc. a 6 cm, b -7.5 cm,b. a 7 em, b- 24 cm, and c 25 cmd. a 2.5 cm, b- 4.5 cm, and c 6.5 cmand c -11 cm |
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Answer» b) as 7² + 24² = 25² so follows pythaogras theorem |
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| 3349. |
3. A soft drink is available in two packs - (i) a tin can with a rectangular base of leng5 cm and width 4 cm, having a height of 15 cm and (i) a plastic cylinder with circulabase of diameter 7 cm and height 10 cm. Which container has greater capacity and bhow much? |
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| 3350. |
9. Simplify:IN- |
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Answer» 2/3 * 3/4 + 4/5 = 2/4 + 4/5 = 1/2 + 4/5 Take LCM = (5 + 8)/10 = 13/10 = 1.3 |
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