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Cost of fencing a square field per metre = Rs.125total cost of fencing = Rs.8000

the perimeter of square field =8000/125= 64 m

Suppose length of each side of square field bea.So perimeter of square field = 4a= 64 m⇒a=644= 16 mlength of each side of square field = 16 m

Given:

A right angled ∆ABC, right angled at B

To Prove- AC²=AB²+BC²

Construction: draw perpendicular BD onto the side AC .

Proof:

We know that if a perpendicular is drawn from the vertex of a right angle of a right angled triangle to the hypotenuse, than triangles on both sides of the perpendicular are similar to the whole triangle and to each other.

We have

△ADB∼△ABC. (by AA similarity)

Therefore, AD/ AB=AB/AC

(In similar Triangles corresponding sides are proportional)

AB²=AD×AC……..(1)

Also, △BDC∼△ABC

Therefore, CD/BC=BC/AC

(in similar Triangles corresponding sides are proportional)

Or, BC²=CD×AC……..(2)

Adding the equations (1) and (2) we get,

AB²+BC²=AD×AC+CD×AC

AB²+BC²=AC(AD+CD)

( From the figure AD + CD = AC)

AB²+BC²=AC . AC

Therefore, AC²=AB²+BC²

This theroem is known as Pythagoras theroem..

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this is rong answer

Height (h) of the cylindrical part = 2.1 m

Diameter of the cylindrical part = 3 m

Radius of the cylindrical part = 3/2 m

Slant height (l) of conical part = 2.8 m

Total canvas used = CSA of conical part + CSA of cylindrical part

= πrl + 2πrh

= πr(2h+l)

= (22/7)×3/2(2×2.1+2.8)

= (22/7)×3/2(4.2+2.8)

= (22/7)×3/2(7)

= 11×3

= 33 m²

Cost of 1 m² canvas = ₹ 500

Cost of 44 m² canvas = 33 × 500 = 16500

The cost of Canvas needed to make the tent= ₹ 16500

Hence, it will cost ₹ 16500 for making such a tent.

right thanks

LHS = ( 1 + secA )/secA

= ( 1 + 1/cosA ) / ( 1/cosA )

= [ ( CosA + 1 ) / cosA ] / ( 1/ cosA )

= Cos A + 1

= ( 1 + cosA ) ( 1 - cosA ) / ( 1 - cosA )

= ( 1 - cos² A ) / ( 1 - cosA )

= Sin² A / ( 1 - cosA )

= RHS

Radius of the bigger circle = R = 14 cm

Radius of the smaller circle = r = 6 cm

Height of the frustum = h = 6 cm

Slant height of frustum = l =10cmLateral surface area of frustum = π (R + r) l

= 628.57 cm2

Total surface area = Lateral surface area + π R² + π r²

=1357.71cm cube.

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Fundamental theorem of arithmetic implies that we write a number in form of the products of its prime factors.

We use this to get the LCM of two numbers by getting the prime numbers with the largest powers between the two numbers and getting their product.

We get the HCF/GCD by getting only the prime factors that are present in both with taking the one with the least power between the two.

144=2^4 × 3^2

840=2^3 × 3^1 × 5^1 ×7^1

LCM=2^4 ×3^2 × 5 × 7=5040

HCF=2^3 × 3^1=24

short nnahi hai kya

ha ilma answer kitna badha deadiya

Let us consider √5 is rational.

So,

√5 = p/q.

(where p and q are co-prime number and q ≠ 0)

Squaring on both sides give,

5 = p²/q²

5q² = p²

From this we can say that 5 divides p² so 5 will also divide p.So, 5 is one of the factor of p.

So we can write,p = 5a

Therefore,

5q² = (5a)²

5q² = 25a²

q² = 5a²

From this we can say that 5 divides q² so 5 will also divide q.So, 5 is one of the factor of q.

As, we know p and q are co-prime so it cannot have common factor. But here a contradiction arise that 5 is factor of both p and q.

So, by this we can say that √5 is not rational which means √5 is irrational.

Let us assume that√5 is a rational number.

We know that the rational numbers are in the form of p/q form where p,q are intezers.

so,√5 = p/q

p =√5q

we know that 'p' is a rational number. so√5 q must be rational since it equals to pbut it doesnt occurs with√5 since its not an intezer

Therefore, p =/=√5q

This contradicts the fact that√5 is an irrational number .

Hence our assumption is wrong and√5 is an irrational number.

asume √5 as rational first then solve

√5 is an irrational number we have to prove it so let us assume for a while that it is a rational number

then we look at the question once again and we found that it is written that we should prove it as irrational so or is actually an irrational number so no need to prove it as we now know that it is an irrational number

where is the answer

FactoringPrime Factors of712

Positive Integer factors of712= 2, 4, 8, 89,712divided by 2, 2, 2, 89, gives no remainder

712=2×356=2×2×178=2×2×2×89therefore prime factorisation of 712 is 2×2×2×89.

Total area of sheet =πr² =22/7*14*14 =616 cm²area of 2 circles = 2*πr² =2*22/7*3.5*3.5 =77 cm²area of rectangle = 3*1 =3 cm²area of remaining sheet = area of total sheet - [area of 2 circles+area of rect.] =616-77+3 =536cm²

find the circumference and area of a circle of radius 20 CM (use pi is equal to 3.14)

Area of the circle with radius 4 cm = πr² = π(4)² = 16 π cm²

Area of the circle with radius 3 cm which is removed = π(3)² = 9π cm²

Remaining area = 16π - 9π = 7π = 7 x 3.14 = 21.98 cm²

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(i) 5(ii) 10(iii) 17

(i)pythagorus theorum(hypotenus)sq.=( base)sq.+(pependicular)sq.(x*x)=(3*3)+(4*4)(x)sq.=9+16(x)sq.=25x=25\2x=12.5

(1) =5

(2)=10

(3)=17

1)1*3*5 is the right answer

a) 15=3×590 = 2×45 =2×3×15 =2×3×3×5LCM of 15 and 90 = 3×5×3×2=90

A)3*5=153*3*2*5=90L.c.m of 15 and 90=90

1. 3×52. 2×3×3×53.90

1) 3*5 = 152) 2*3*3*5 =903) 90 is the best answer of this que

(2^8)*(5)

Which is the same as = 2 8 x 5

Prime Factors Tree of 1280

1280

/ \2 640

/ \2 320

/ \2 160

/ \2 80

/ \2 40

/ \2 20

/ \2 10

/ \2 5

/ \5 1

The Factor Tree of 1280 above shows the level of divisions carried out to get the factor numbers.

we know that tan theta= P/Bin this P= 30mbase= 10√3tan(theta)= 30/10√3=√3theta= 60°

The number15470is a composite number so, it is possible to factorize it.

The prime factorization of15470= 2•5•7•13•17.

The prime factors of15470are 2, 5, 7, 13 and 17.

The prime factors are: 2 x 2 x 5 x 7 x 7

or also written as { 2, 2, 5, 7, 7 }

Written in exponential form: 22x 51x 72

√980=√2×2×2×2×5×5×7×7×7×7√980=2×2×5×7×7