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3101.

Find the value of both x and y in the parallelogram.2x + 1y+34X-5-3, y = 1x= 30, y = 3x= 1, y = 3x = 30.7. y = 35.4

Answer»

2x + 1 = 4x-5; 4x - 2x = 1 + 5; 2x=6; x=6/2=3; 4y=y+3, 4y-y=3; 3y=3; y=3/3=1

x=3y=1Is correct answer

3102.

(a/b)^(-16)=ldots*ldots

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3103.

2 + 4 + 6 + \ldots \ldots + 200

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3104.

(138) Find the discriminant of the following quadratic equation and discuss the nature of the rootsx2-3 3x-30-0

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3105.

hy is Axiom 5, in the list of Euclid'saxioms,considered a 'universal truth"? (Notehe question is not about the fith postulate.)

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3106.

5.cos 60° + 4 sec 30 - tan2 4sin 30° + cos 30°

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thanks

3107.

R.H.S.=(9)4+4-30×4×2+25×4Solve :

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3108.

Why Axiom 5, in the list of Euclid's axioms, is considered a 'Universal Truth' ?Note that the question is not about the fifth postulate]

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Euclid's Axiom 5 states that "The whole is greater than the part."

Since this is true for anything in any part of the world.So, this is a universal truth.

3109.

Section-INote: (1) Answer all the questions.(2)Each question carries 1 mark.Find q and r satisfying a - bq+ , where a 13 and b 3

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Given,a = 13, b = 3

Then,a = bq + r13 = 3q + r13 = 3*4 + 1

Therefore value of q = 4, r = 1

3110.

PracticalRelatedQuestionsNote: Below given are few sample questons for reference. Tes so as to ensure the achievement of identifieGive the significance of internal resistance of a EMF sourcesuch question1.

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EmfandInternal Resistance.

Incidentally, a pure voltagesourceis usually referred to as anemf(which stands forelectromotive force). Of course,emfis measured in units of volts. A battery can be modeled as anemfconnected in series with aresistor, which represents itsinternal resistance.

3111.

1हल करें : +41-H-7-30-4,+7

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1/ x + 4 - 1/ x-7=11/30; x-7- x+4/( x-7)( x+4)= 11/30; 3/x^2 +4x-7x-7(4) = 11/ 30; 3/x^2 -3x -28 = 11/30; 3(30)=11( x^2-3x-28); 90 = 11x^2-33x-308;; 11x^2 -33x -308-90; 11x^2 -33x -398=0;

1/x+4 -1/x-7=11/30x-7-x-4/(x+4)(x-7)=11/30-11/x^2-3x-28=11/30x^2-3x-28=-30x^2-3x+2=0x^2-2x-x+2=0x(x-2)-(x-2)=0(x-2)(x-1)=0either x-2=0, x=2or x-1=0, x=1

3112.

20.In the given figure, O is the centre and AocA.is a diameter of the circleFindi) The sum of the areas of the two shadedsegments made by the chords AB and BCii) The area of the shaded segment made by Bthe chord PQ (useTr224 cm4 cm

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3113.

DRAx+4x-7-30 ,4,

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x-7-(x+4)/(x-7)(x+4)=11/3030(-11)=11(x²-3x-28)x²-3x-28+30=0x²-3x+2=0x²-x-2x+2=0x(x-1)-2(x-1)=0(x-1)(x-2)=0x=1,2

3114.

c0s (30°-A)-cos (30° + 4) =sinA

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sahih

3115.

4. List the solution set of 30 - 4 (2x1)<30,giventhat x is a positive integerICSE)

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Given :

30 - 4 ( 2x - 1) < 30

-4 (2x - 1) < 0

2x - 1 < 0

2x < 1

x < 1/2

So, only satisfying element is 0

3116.

L.C.M of 455 , 117, 138

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3117.

138 \div 3 =

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138/3=46 basic addition

138÷3=46..don't u know even this simple division....shame on your part

very easy Q not difficult easy divide

i was only testing scholar this was not my own question.

don't be shameless taha

138 me 3 ka bhag dene par 34.5

3118.

138 =5 =3/

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13a - 5 = 3/2 13a = 5 + 3/2 13a = 13/2 a = 13/(2*13) a = 1/2

If you find this answer helpful then like it.

3119.

11311x-101383x+6

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sum of angles for a Pentagon is 540° so on addition of all the angles => 11x-10+3x+6+138°+85-x+113 = 540° => 14x -x + 332 = 540° => 13x = 540-332= 208 => x = 16°

so , the other angles are 3x+6 = 54°11x-10 = 166° 85-16 = 69°

3120.

14.IQ of a person is given by the formulaMA1QCAx 100,where MA is mental age and CA is chronological age. If 80 s IQ 3 140 for a group of12 years old children, find the range of their mental age.

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Thank you so much

3121.

Iqac-u2

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1/x+y = u1/x-y = v19u - 2v = 1.......(1)15u +7v = 10.......(2)(1)×7;133u - 14v = 7....(3)(2)×2;30u + 14v = 20....(4)(3)+(4);163u=27u = 27/163513/163 - 2v =1v= 175/163so, x+y = 163/27....(5)x-y = 163/175....(6)(5)+(6);x=16463/4725

3122.

e) State the full form of EQ, IQ, and SQ

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EQ is Emotional Intelligence Quotient.

IQ is Intelligence Quotient.

SQ is Social intelligence Quotient.

3123.

in the blanks to make the following statements tru(-5) + (-8) = (一8)-+ ( )+ -5317+..0[134 (-12)] + () = 134 [(-12) + (-MULTIPLICATION OF INTEGERS

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Answers are following-70-17-3

3124.

3e3(x2 + Ууі, then, where x, y, p, q E RIf (x + iy) (p + iq)(1) p x, q

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3125.

4. There are 250 and 425 litres of milk in two containers. What is the maximumcapacity of the container which can measure completely the quantity of milk in thetwo containers? What is the necessity of milk for human ?

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3126.

8. Lateral surface area of a cuboid is 486m2breadth is 12 m and length and height are inthe ratio 5: 3. Find the length and height dthe cuboid.

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3127.

A man covers equal distances at the rateof 2 kms/hr., 3 kms./hr. and 4 kms./hr. Find hisaverage speed (in kms./hr.) for the wholejourney

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Let the distance be x kms. For speed = 2 km/hr, time taken = distance/speed. => time = x/2. For speed = 3 km/hr, time taken = distance/speed. => time = x/3. For speed = 4 km/hr, time taken = distance/speed. => time = x/4. Total speed = Total distance/ Total time= (x+x+x)/(x/2 + x/3 + x/4)= 3x/(13x/12)= 36/13 kms/hr

3128.

A particle at rest starts moving with uniformacceleration covers a distances 114 meters in 8thsecond. The acceleration of the particle is

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a=d/(t×t) = 114/64 = 1.78 m/s.s

3129.

(sec²Q-1)(1-cosec²Q) =-1

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3130.

ot Ao 3 Lec ™ A -tdaun A

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To prove(CotA -1) /( 2- Sec²A )= CotA / (1+tanA)Solution:

LHS = (CotA -1) /( 2- Sec²A )

= ( CotA-1) / (1 + 1 - Sec²A)

= (1/tanA)-1 / ( 1 - tan²A) [Since tan²A +1 = sec² So, 1- Sec²A = - tan²A]

= (1-tanA) / tanA (1+tanA)(1-tanA) [ identity a² -b² = (a+b) ( a-b)]

= 1/ tanA(1+tanA)

= CotA / (1+tanA) = RHS

Hence Proved

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thanks baby

that will be 2*secA

not 2-secA

u r wrong

3131.

&amp; State ‘bau.—c हर हा ही हा ््ज gow aus'ux’t I

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False.

Reason :

We know √2 is irrational.

Let assume √2/3 be rational

So, √2/3 = r, where is some rational number

So, √2 = 3r,

Therefore this is a contradiction as LHS is irrational and RHS is rational, a contradiction to our assumption that √2/3 is rational so it is irrational.

Hit like and BeScholr

false, because root 2 is not a rational number.......

3132.

( \text { vii } ) ( 2 q ^ { - 3 } ) ^ { 2 } \div ( 4 q ) ^ { 1 / 2 } \times ( 2 q ^ { 1 / 6 } ) ^ { 3 }

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3133.

\frac{5 \sin ^{2} 30^{\circ}+\cos ^{2} 45^{\circ}+4 \tan ^{2} 60^{\circ}}{2 \sin 30^{\circ} \cos 60^{\circ}+\tan 45^{\circ}}

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3134.

2.Find the volume of a cuboid whose dimensions is :(a) 1 30 cm, b -15 cm and h12 cm(b) 1

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We knowVolume of cuboid= length*breadth*height

Given,Length l = 30 cm, Breadth b = 15 cm, Height h = 12 cm

Then,Volume of cuboid = 30*15*12= 5400 cm^3

3135.

Gind the volume of the cuboid whose dimensions are given belowLengthBreadthHeight8.2 m5.3 m2.6 m5.0 m4.0 m3.5 m4.5 m2.0 m2.5 m

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the volume of cuboid=l×b×h1. v=8.2m×5.3m×2.6 =112.996cm3

2. v=5.0m×4.0m×3.5m =70.000cm3 =70cm3

3. v=4.5m×2.0m×2.5m =22.500m3 =22.5cm3

3136.

If a parallelogram is square then is a rombus

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A square is a rhombus with all interior angle equal to 90°.

3137.

along the boundary of the plot.A wire is in the15.o lind its breadth. Which figure encloses more area and by how much?gh6. A ndown is 50 m long 40e shape of a square of side 10 cm. If the wire is rebent into a rectangle ofa squarwhitewashing its fm hroad and 10 m hirh. Find the cost of

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Perimeter of the square = 4× side=> 4×10= 40 cmAs the wire is bent into rectangle having length 12 cm Since Perimeter of square = Perimeter of rectangle40= 2(l+b)20= 12+bb= 8 cmArea of square = 10²= 100 cm²Area of rectangle= l×b= 12×8= 96cm²Lost in area = 100-96= 4cm²

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3138.

丁一11-412-13+ 43 2323-3

Answer»

a) 2/3 - 1/3 = 1/3

4/3 - 2/3 = 2/3

2/3 + 4/3 = 6/3 = 2

1/3 + 2/3 = 3/3 = 1

2-1 = 1

thanks

3139.

7 p ( 2 p ^ { 2 } - p q + q 2 ) \text { for } p = - 1 \text { and } q = 1

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7p (2q² -pq +2q)when p = -1 and q= 17× (-1) ( 2×(1)² - (-1)(1) + 1× 1)-7 (2 +2 +1)-7 (5)= -35

3140.

50+23×23÷43

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50+23×23÷4350+23×0.5350+12.1962.19

3141.

\begin{array}{l}{7+7+7+7+7=} \\ {8 \times 5=5 x} \\ {23 x-y=23} \\ {15 x-z=120} \\ {43 \times 10=}\end{array}

Answer»

Thank you

a = 35 c = 40 e = 1 g = 5 i = 430

(a) 7×7×7×7×7=35 (c) 8×5=5×8(e) 23×1=23(g) 15×8=120(i) 43×10=430g

3142.

3. Simplify and express t4. Find the value of the fo 180 + 7-23-5. Simplify.a. 63 x 43

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a

A

(8^0 + 7^-1) * 2^3

= (1 + 1/7) * 8

= (8/7)*8

= 64/7

3143.

s S11, 16, 23, 32, 43,?

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3144.

2. If the cost of 1 notebook is? 14.50, what is the cost of 9 notebooks?

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3145.

1. Find the volume, the lateral surface area and the totacuboid whose dimensions are:(0) length 12 cm, breadth 8 cm and height 4.5 cm

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3146.

SESSION 2019-20A set of school uniform is available for Rs. 250. Find the cost of 120 such school

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Answer= 120*25012*25*10030000

120*250=3000030000 is a cost of 120 school

3147.

find the value of the sin squar 30 -3cos squar 45 -4 tan squar 60

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sin²30 - 3cos²45 - 4tan²60

Substituting the values, we get

(1/2)² - 3((1/√2)² - 4((√3)²

= 1/4 - 3/2 - 12

= 1-6/4 - 12

= -5/4 - 12

= -5-48/4

= -53/4

3148.

re root of the squariv). 2645

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Simplified Square Root for √2645 is 23√5;

3149.

write any two propertis of 1 rectangle2 rombus3 squar

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1. Therectanglehas the followingproperties: All thepropertiesof a parallelogram apply (the ones that matter here are parallel sides, opposite sides are congruent, and diagonals bisect each other). All angles are right angles by definition. The diagonals are congruent.

2. All the properties of aparallelogramapply (the ones that matter here are parallel sides, oppositeanglesare congruent, and consecutiveanglesare supplementary).

All sides are congruent bydefinition.

The diagonals bisect theangles.

3. The diagonals of a square bisect each other and meet at 90°

The diagonals of a square bisect itsangles.

Opposite sides of a square are both parallel and equal in length.

All fouranglesof a square are equal. ...

All four sides of a square are equal.

The diagonals of a square are equal.

3150.

Choose the correct answers.1. Which of following numbers are perfect squar(a) 12(6) 16

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(b) 16 is a perfect square of 4

16 is the perfect square in the following numbers

16 is a perfect square because it ends with 6 . A square number never ends in 2, 3, 7 or 8

16 is a perfect square because it ends with 6 . A square number never ends in 2, 3, 7 or 8

16 is the perfect squre

16 is perfect square.

B option is true because 16 is perfect square of 4