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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 3051. |
( - 18 ) \div \square %2B 3 = - 6 |
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Answer» (-18)÷2+3-9+3-6therefore (-18)÷2+3=-6 |
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| 3052. |
18. The wavelength of a sound wave is 66 mt. Calculate the frequency of the wave if thevelocity of sound is 330 ms1. Would this sound be audible to the human ear. [5 Hz, No] |
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Answer» frequency is velocity/wavelength=330/66=5Hz |
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| 3053. |
06238, In Fig 138, ABCD is a square of side 2n Find the ratio betweers) theiciumderecesthe areas of the incircle and the circum-circle of the squareFin 13 98 |
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Answer» We have a square ABCD havingAb = 2a From the given diagram we can observe that, Radius of incircle r1 = a Radius of circumcircle r2 = √2a (i) We have to find the ratio of the circumferences of the two circles. So the required ratio is, = perimeter of inner circle/perimeter of circumcircle = 2π(a)/2π(√2a) = 1/√2 (ii) We have to find the ratio of the areas of the two circles. So the required ratio is, = area of inner circle/area of circumcircle = π(a)²/π(√2a)² = 1/2 Like my answer if you find it useful! |
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| 3054. |
\frac{(931+138)^{2}+(931-138)^{2}}{(931 \times 931+138 \times 138)}=? |
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Answer» ((931×931+2×931×138+138×138)+(931×931--2×931×138+138×138))/(931×931+138×138)=2(931×931+138×138)/(931×931+138×138)=2 |
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| 3055. |
Convert into litres.a)93/15 dl 3 cl 7 ml |
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Answer» 93+1.5+0.03+0.007=94.537litres |
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| 3056. |
Self Practice 11EExpress the following as directed.1-(b)UNm in cm(d)L in cL.un(a) g in mg.(0) 5 kg in g.(e) kl in dal.g) kl in hl.-2o g in cg- Glaskm ini)dL in ml.-hm in40 |
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Answer» 15÷100= 1.5 mgwe can convert it by division method also 15÷100= 1.5 mgwe can convert it by division method also |
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| 3057. |
Convert the following metric measures.(a) 4 dam to cm(d) 22 hg to g1(b) 13 km to dm(e) 36 L to cL(c) 7 g to mg(f) 9 dal to dL |
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Answer» 4 decametre = 4000 cm |
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| 3058. |
: हुलेव्व्न्य & Dl कलह (डे (शा 1 1% .09 bik % bk= & L= B2 Shjie ©0 3h See Lo TWE 26 23| bB B3 =B ok i & .0tk 5 ध्यॉ भू [2 |
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| 3059. |
(2)93939384. A bucket can be filled by either of 3 mcasuring eylinders exactly as shown. Hlow much water can(3) 152753(4) 9119142the bucket hold?Bucket IL 3L 5L(1) 15 L(2) 9 L(3) 14 L(4) 20 L |
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Answer» Amount of water the bucket hold = LCM(1,3,5) = 15 L Hence, (1) is correct. |
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| 3060. |
825. In the figure, L and M are the midpoints of the sides AB andDC respectively of the parallelogram ABCD; AM and DLintersect at P, and CL cuts BM at Q. Prove that PMQL isaparallelogram. |
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Answer» hence parallelogram |
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| 3061. |
4*(-4) %2B (-10)*(-6)=square |
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Answer» according to BODMAS rule in this question first multiply then add so-60+(-16)=-76 ATP to BODMAS -6 ×-10 -4 ×4-60-16-76 answer |
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| 3062. |
-6/7 %2B 10 %2B 12 |
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Answer» 10+12-18÷2122-6/7154-6/7148/7 10+12_18÷1222_6/7148/7=21.14 According to DMASanswer is 148÷7 |
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| 3063. |
& L L L% ( - o : ( = )¢2 Ik ki) 20 2 1Bl [2 s_L i) B ‘2 LolBUs T व. हक Dl | 2 15k ¢ 12 1nfe 2214 ९] एफ | |
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| 3064. |
-n^2 %2B n^2=4*sqrt(m*n) |
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Answer» tanx+ secx=m; tanx-sinx=n; m^2-n^2=(tanx+ sinx)^2=tanx^2+sinx^2+2 tanxsinx____(1), (tanx-sinx)^2=tanx^2+sinx^3-2tanxsinx; m^2-n^2=tanx^2+sinx^2+2tanxsinx-tanx^2-sin^2+2:tanxsinx; 4tanxsinx=4Vmn |
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| 3065. |
hollow cylinder of length 16 cm, external dlailleA cylindrical vessel having diameter equal to its height is full of water whichpoured into two identical cylindrical vessels with diameter 42 cm and height 21which are filled completely. Find the diameter of the cylindrical vessel.6.isnd thickness 0.5 cm are placed one above |
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| 3066. |
reen, six identical blue and six identical redIn how many ways it is possible to divide six identical gamong two persons such that each gets equal number of item? |
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Answer» THERE ARE TOTAL 18 BALLS(6 GREEN+6 BLUE+6 RED) THESE BALLS SHOULD BE DISTRIBUTED EQUALLY AMONG TWO PERSONS SO THERE ARE AS MANY NUMBER OF WAYS AS IN WHICH WE CAN DIVIDE THESE BALLS IN TWO EQUAL GROUPS OF 9-9 BALLS. SO THE REQUIRED ANSWER IS 18!/(9!*9!*2!). HERE 2! IS BECAUSE TWO GROUPS HAVE SAME SIZE THAT IS 9. |
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| 3067. |
20/((2*(2 %2B 3))) %2B 10 |
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Answer» 3 is the correct answer in this question 3+2=10and 10+20=30 and 30÷10=3 eska answer 3 hai10+20÷2(3+2)30÷10=3 according to BODMAS rule12 will be right answer. first divide and then u plus the answer answer is 25 12 is the correct answer. 10+20=30,6+4=10, 30÷10=03. 10+20/2(3+2)10+20/2 x 510+10x510+50= 60(ANS) 10+20÷2(3+2)=10+20÷2×5=10+10×5=10+50=60 3 in correct answer 2(3+2)=10 10+20=3030÷10=3 according to bodmas your question is answer 12 10+20÷2(3+2)10+10(5)10+50=60 the correct answer is 3 of this question 10+20÷2(3+2) =30÷2(5) =30÷10=3 ans According to BODMAS 2+3 =5 and 5 • 2=10 and 20÷10 =2 and 10 + 2 = 12So 12 is the right answer the correct answer is 60 20/2=1010+10=2020*5=100 10+20=3030÷2=1515×3+15×245+3075 is the answer 60 is right answer use bodmos rule 3 is correct answer of this question 10+20/2*5=10+10*5=10+50=60 is correct answer. according to BODMAS rule 12 will be correct answer 3+2=10,10+20=30 and 30÷10=3.So, answer is 3 100 is the right answer 60 is the correct answer 60 is a correct answer iska uttar 75 hai jfncjccngnck 10+20÷2(5) 10+20÷2×510+10×510+5060 the answer is 20.add 20 in 10, the answer will be 30. divide 2 by 30, the answer will be 20. 3 is the right answer 12 is correct by BODMAS10+20÷1010+212 answer 12 this question 10+20 ÷2(3+2)=30÷10=3 by applying BODMAS we will get the result equal to 12 10+20÷2×(3+2) =30÷6+4=30÷10=3 60 is right answer of this question 10+10(3+2)10+30+2060 answer 60 correct answer by Harsh Sharma iska answer 10+20/1010+2=12 according to BODMAS right ans is 10 answer of question is 60 10+20/2(3+2)10+10by 510+50=60 10+20÷10=30÷10= 3 answer 3 is the correct answer correct answer is10+20÷ 2×3+230÷10then,answer is 3 3is the answer of this question answer for this question is 12 10+20÷2(3+2)30÷10=3 60 is the correct answer 10 + 20 ÷ 10 = 10+ 2= 12 3 hai iska answer bilkul sahi ha 60 answer iska answer 60 hoga 12 is correct answer 10+20/2(5) 10+20/1010+2hoga sir 10+20÷2(3+2)10+20÷2×510+10×510+5060 answer aapka question ka answer hoga 1 as per rules OF BODMAS 12 would be the correct answer ans. to this question is 12 10+20/2(3+2)=10+10×5=10+50=60 ans According to BODMAS rule . I think 12 is the right answer for this question!🙂 according to me the answer is 3 10+20÷2(3+2)=3 solve this som According to BODMAS rule use इसमे सबसे पहले छोटा कोस्टक फ़िर, भाग, गुणा, जोड, घटाया 10 +20➗2(3+2)10+20➗2x510+10x510+50=60 Ans 10+20÷2(3+2)=60 answer correct answer is 60 10+20/2(3+2) =10+20/2(5)=10+20/10=10+20×1/2=10+10=20answer bordmass ke anushar answer-12 |
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| 3068. |
2324 (1-2) .. apton terms =2 |
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Answer» Like my answer if you find it useful! |
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| 3069. |
-2*sqrt(3) %2B 20*sqrt(2) %2B 10*(6*sqrt(2)) |
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Answer» simplify => 72^1/2 + 800^1/2 - 18^1/2 take common = 3×8^1/2 + 10×8^1/2 -3×2^1/2 = Answer √72 + √800 - √186√2 + 20√2 - 3√226√2 - 3√223√2 is correct answer please like and accept as best answer |
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| 3070. |
-45*(m %2B n)^2 %2B 20 |
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| 3071. |
283 11831□ (b)-183148(a) -6(c) 1d) 3112. For which valu10. Which of the following is not equivalent torational numbe(a) 1(c) 0151535351421II. Fill in the blanks:1. The sum of two rational numbers is always a |
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Answer» -15/-45=3/715/35=3/70=06/14=3/7-9/21=-3/7 thanks |
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| 3072. |
1. Find the product:a (4)×2=(1) 15 x(-3)(-) =(ii) (-12) (-4) * (-5) =(iv) (-21) * (- 6) =(W) (-18) 15 -(vi) 25 * (-4)*(-61) -Der (-8) 0 x 96 =un (-2)*(-36) (4) -(1x) 50 (-8) * (-4) -00 (-1)×2x3x (-4) = |
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Answer» a= -8 8= 0 is correct answer (i) -8,(vii) -8,(x)24 |
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| 3073. |
4. Solve the foilowing equationsWritOn(iv)o=39-52(i)(o)(ir)(ii) x+36 =-40(vi) 2 (7 + x) = 9xx+x=15(iii)(vii) 3x + 8 =-1(xi)x+8=9(viii)-5x + 2-9= 2143-2 = 01-7"=-8(x) |
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Answer» (i) x+8=9=>x=9-8=1(ii)x+36=-40=>x=-40-36=-(40+36)=-76(iii)x-9=5=>x=5+9=14(iv)x/2=3=>x=3*2=6(v)-9x=21=>x=-21/9=-7/3(vi)2(7+x)=9x=>14+2x=9x=>14=9x-2x=7x=>x=14/7=2(vii)3x+8=-1=>3x=-1-8=-9=>x=-3(viii) question not clear.(ix) (x/3)-2=0=>x/3=2=>x=6(x)(4/5)x+x=18/5=>9x/5=18/5=>x=(18/5)*(5/9)= 2(xi)1-1x/7=-8=>1+8=x/7=>9*7=x=>x=63 |
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| 3074. |
5 %2B 20 %2B 500 %2B 30000 |
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Answer» 30000+500=30500 and then 30500+20+5=30525 answer is 30,525 of the que given aboove 30000 +500 =30500 and then30500+20+5=30525 30000+500+20+5=30525 is the correct answer. The correct answer is 30,525 30525is correct answer 30525 is correct answer The answer is 30,525 question is 30,000+500+20+5 and the solutuon is 30,525 30000+500=30500 +20+5=30525 solution is :- 30,000+500+20+5=30,525 |
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| 3075. |
) M-24 12 -50 -3(ii) 5M +31-43 21+ 2M 303, find the[2008]matrix M. |
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| 3076. |
-8 %2B (-21)/4 %2B (-3)/4 %2B 5/20 %2B 9/20 %2B 15/10 |
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| 3077. |
16 %2B 8 %2B 20 |
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Answer» iska answer 64 hoga pakka 44 64 hoga iska answer ........... 64is the correct answer |
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| 3078. |
brave that: los 30Lot dire+ Dip 30 - (1t sin Ocare)rino-eart |
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| 3079. |
10 %2B 20 %2B 30 |
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| 3080. |
-24 %2B 20 %2B 16 |
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Answer» 152is the correct answer of your question. 20 - (3 × 8 ) + 16 (By using BODMAS rule)20 - 24 + 1620 - 40 = (-20) 20 - (3 × 8) + 1620 - 24 + 16(-4) + 1612 12 is the answer of your question |
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| 3081. |
sqrt(x %2B 4) %2B sqrt(x %2B 20)=2*sqrt(x %2B 11) |
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| 3082. |
8/(-2 %2B 4) %2B 20 |
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Answer» 20 + 8 ÷ (4 - 2) = 20 + 8 ÷ 2 = 20 + 4 = 24 20 + 8 ÷ (4-2) =20+8÷220+4=24 |
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| 3083. |
3 I oÂĽ | 88. "es |
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Answer» 1/30+1/2 = 1/30+15/30 = 16/30 =8/15 75×8/15 =8×5 =40 |
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| 3084. |
32*x %2B x^3 %2B 13*x^2 %2B 20 |
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Answer» 5 is the correct answer what 5? pls look wisely |
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| 3085. |
Find (-19)ex b6 using the appropriate law of exponents. |
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Answer» (-19)^6 x b^6(-19*b)^6 = (19b)^6 |
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| 3086. |
. P3. Perform the calculation using distributive law 25x 96. Simplify:() (355. Multiply:4x(s-3x) |
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Answer» 4th question was not clear......if this is not the solution for it then please given clear question ,👍 |
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| 3087. |
Perform the calculation using distributive law 25 x 96Simplify: (3Multiply : 4x (x-x)74(395 |
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| 3088. |
(2 leb डा) ० है % Uik b ३४९५६Uk 58 150 % वि). %81 ५६ ४७ %५1से ।है &४ 000६ 2७% ४ 0०० % 1t &b "101. | (3 उ |
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| 3089. |
n) lim |
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| 3090. |
A water tank is 3 m long, 2 m broad and 1 m deep. What is the capacity of thetank (in litre) if 1 cubic m2.1000 1t. |
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Answer» Volume=length*breadth*height=3*2*1=6m^3=6000litres |
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| 3091. |
AN P 3 S9, x&m[x [कि बीच आठं परिमेय न. =A e - कीजिए, जबकि » -1t |
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| 3092. |
1T 8,000 का 3. वर्ष के लिए 5% वार्षिक ब्याज की दर से चक्रवृद्धि ब्याज ज्ञात कीजिये।... |
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| 3093. |
5 + 15 + 45 + \ldots \ldots \ldots + 5 ( 3 ) ^ { n - 1 } = \frac { 3 } { 2 } \left( 3 ^ { n } - 1 \right) |
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Answer» thnku |
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| 3094. |
54,51,48,45 , \ldots \ldots \ldots |
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| 3095. |
\frac{x}{7}=\frac{y}{3}=\frac{3 x+5 y}{\ldots \ldots}=\frac{7 x-9 y}{\ldots \ldots} |
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Answer» suppose x/3=y/7=kso x=3k and y=7kso 3x+5y=3(3k)+5(7k)=44kso 44now 7x-9y=21k-63k=-42kso -42 |
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| 3096. |
\begin{array}{l}{\sum_{n=1}^{\infty} \frac{x^{n}}{\sqrt{n}}} \\ {x+2 x^{2}+3 x^{3}+4 x^{4}+\ldots \ldots} \\ {1-2 x+3 x^{2}-4 x^{3}+\ldots \ldots} \\ {2-\frac{4}{5} x+\frac{6}{5^{2}} x^{2}-\frac{8}{5^{3}} x^{3}+\ldots \ldots} \\ {\sum_{n=0}^{\infty} \frac{(-1)^{n}}{n+1} x^{2 n}}\end{array} |
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| 3097. |
5. In a right angled triangle with sides a and band hypotenuse c, the altitude drahypotenuse is x. Prove that ab = cx.6. In Fig. 4.13 |
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| 3098. |
1. IfAB || CD in each of the following, find x.3x -5°3x + 155x +1°2x+30° |
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| 3099. |
\begin{aligned} \text { The value of } \lim _{n \rightarrow \infty} \frac{1+2^{4}+3^{4}+\ldots \ldots+n^{4}}{n^{5}} \\-\lim _{n \rightarrow \infty} \frac{1+2^{3}+3^{3}+\ldots \ldots+n^{3}}{n^{5}} & \text { is } \end{aligned} |
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| 3100. |
\sin 70^{\circ}=\cos (\ldots \ldots) |
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Answer» Sin A =Cos(90-A)Sin 70=Cos 20 |
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