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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 3551. |
the probability of getting:(i)(ii)A red ballNon-white ball. |
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| 3552. |
(B)30 () -சுருக்குக : V360" (டு - c)" = 2a (6 - c),(A) 18a" (6 - c)*(C) 3a (6 - c)(D)30 (b - |
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Answer» A) is the correct answer a) is the right answer of the following A) is the correct answer |
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| 3553. |
termProve that in a right angled triangle square of the hypotenuse is equal to sum of the squaresof other two sides.425.ilar to AABC |
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Answer» Given:A ∆ XYZ in which ∠XYZ = 90°. To prove:XZ2= XY2+ YZ2Construction:Draw YO ⊥ XZProof:In ∆XOY and ∆XYZ, we have,∠X = ∠X → common∠XOY = ∠XYZ → each equal to 90°Therefore, ∆ XOY ~ ∆ XYZ → by AA-similarity⇒XO/XY = XY/XZ⇒ XO × XZ = XY2----------------- (i)In ∆YOZ and ∆XYZ, we have,∠Z = ∠Z → common∠YOZ = ∠XYZ → each equal to 90°Therefore, ∆ YOZ ~ ∆ XYZ → by AA-similarity⇒ OZ/YZ = YZ/XZ⇒ OZ × XZ = YZ2----------------- (ii) From (i) and (ii) we get, XO × XZ + OZ × XZ = (XY2+ YZ2) ⇒ (XO + OZ) × XZ = (XY2+ YZ2) ⇒ XZ × XZ = (XY2+ YZ2) ⇒ XZ2= (XY2+ YZ2) |
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| 3554. |
In the right angled triangle, the square of the hypotenuse is equal to the sum of thesquare of the other two sides. PROVE7. |
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Answer» Like if you find it useful |
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| 3555. |
11. A fire at the building B is reported by a telephone to two fire-stations, F, and Fa 10 km apartfrom each other on a straight road. Fi and F2 observe that the fire is at an angle of 60 and 45°respectively to the road, which station should send its team and how much will it have to travel? 4 |
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| 3556. |
A fire in a building 'B' is reported on telephone in two fire stationsPapart from each other on a straight road. P observes that the fire is atato the road, and Q observes, that it is at an angle of 45o to the road. Wshould send its team to start the work at the earliest and how much distateam has to travel?34. |
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| 3557. |
1) 7The sum to infinity of1) 1/5+2) 7/243) 5/484) 3/16 |
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Answer» Note that we can split this into two different sums [1/7 + 1/7^3 + 1/7^5+......] + [ 2/7^2 + 2/7^4 + 2/7^6+....] The sum of the first series = [1/7] / [1 -1/7^2 ] = 7/48 And the sum of the second series = [ 2/7^2] / [ 1 - 1/7^2] = 1/24 So.....the sum of the whole series = 7/48 + 1/24 = 7/48 + 2/48 = 9/48 = 3/16 hence, the correct option is (d) |
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| 3558. |
1(i)(a)Find: (16)^{\frac{1}{4}} \text { (b) }(7)^{\frac{1}{2}} \cdot(8)^{\frac{1}{2}} |
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Answer» Thanks for answer |
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| 3559. |
In a bag there are 6 white balls, 11 red ballsand 7 yellow balls. What is the probability ofgetting white ball ? |
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Answer» Total balls = 6 + 11 + 7 = 24 E = Getting a white ball P(E) = 6/24 = 1/4 |
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| 3560. |
distributionanddrawilsogveChange the distribution to a 'more than typerandom from the numbers 1, 4, 9 and 16. Find the probability that product of x and y is less than 16.430. A nuer x is selected at random from the numbers 1, 2, 3 and 4. Another number y is selected atOR |
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| 3561. |
( x - 1 ) ^ { 2 } + ( y - 3 ) ^ { 2 } + ( z - 5 ) ^ { 2 } + ( t - 7 ) ^ { 2 } = 0 \text { then } x y z t + 16 |
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Answer» 1 2 |
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| 3562. |
4Howmany pieces of tape 37 cm long can be cut from a long tape, which is 1 metre 75 cm ?tional umbere betweenand1 |
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Answer» Length of long tape = 1 m 75 cm = 175 cmLength of piece = 3 4 / 7 cm = 25 / 7 cmNumber of pieces = (175 / 1) / (25 / 7)= ( 175 x 7) / 25= 7 x 7= 49Therefore, number of pieces are 49 hit like if you find it useful |
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| 3563. |
A carpet is 30 m 75 cm long and 80 cm wide. Find its cost at 150 per square |
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| 3564. |
Question 4(a)IfA-2x2 _ 5 + 3x,B-4f-3r + 8 and Cx2 + 6x + 7, find A + 2B+3C.[ |
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Answer» A + 2B + 3C= (2x^2 - 5 + 3x) + 2(4x^2 - 3x + 8) + 3(x^2 + 6x + 7)= (2 + 8 + 3)x^2 + (3 - 6 + 18)x+ (-5 + 16 + 21)= 13x^2 + 15x + 32 |
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| 3565. |
A carpet is 30 m 75 cm long and 80 cm wide. Find its cost at20 per square metre |
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Answer» Wrong answer |
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| 3566. |
4. A carpet is 30 m 75 cm long and 80 cm wide. Find its cost at 150 per square metre |
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| 3567. |
saar e netres. A carpet is 30 m 75 cm long and 80 cm wide. Find its cost at 150 per square metre. |
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| 3568. |
4many pieces of tape 3cm long can be cut from a long tape, which is 1 metre 75 cm |
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Answer» Length of long tape = 1 m 75 cm = 175 cmLength of piece = 3 4 / 7 cm = 25 / 7 cmNumber of pieces = (175 / 1) / (25 / 7)= ( 175 x 7) / 25= 7 x 7= 49Therefore, number of pieces are 49 hit like if you find it useful |
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| 3569. |
How many pieces of tape 3cm long can be cut from a long tape, which is 1 metre 75 cm |
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Answer» As each piece is of (25/7)cm=>The no of pieces=175/(25/7)=7×175/25=49 pieces. |
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| 3570. |
Question 4. Find the value ofr +when x = 4 + 15 |
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| 3571. |
EXERCISE 4.4. Give the geometric representations of y 3 as an equationin one variable(i)(ii)in two variables |
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| 3572. |
Question 4(a)Without using a trigonometric table calculate:4 \frac{\sin 32^{\circ}}{\cos 58^{\circ}}+5 \frac{\tan 48^{\circ}}{\cot 42^{\circ}}-8 \frac{\sec 72^{\circ}}{\csc 18^{\circ}} |
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| 3573. |
DQuestion 442. Find m2 KIM. The diagram is noIn the parallelogram.to scale.12060 |
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Answer» hi first take a clear picture The answer is 78 because of the property of a parallelogram that opposite angles are equal |
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| 3574. |
Question 4(a) A box consists of 4 red, 5 black and 6 white balls. One ball is drawn out atrandom. Find the probability that the ball drawn is:(i) black(ii) red or white |
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Answer» Total balls=15Black balls=5Probability of getting a black ball= 5/15 =1/3Probability of getting a red or white ball =4/15 +6/15 =10/15 =2/3 |
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| 3575. |
4 x 416er every question. Each question carries 4 marks.A) The sum of the three terms which are in A.p. is 33. If the product of thefirst and the third terms exceeds the second term by 29. Find the A.p. |
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Answer» First term = aCommon difference = d Given,Sum of the first three terms = 33 Second term = a + dthird term = a + 2d 33 = a + a + d + a + 2d33 = 3a + 3d33 = 3 ( a + d ) 11 = a + d d = 11 - a Given, Product of first and third term exceeds second term by 29 a1 × a3 = a2 + 29 a × a + 2d = a + d + 29 a² + 2 ad = a + d + 29 a² + 2ad - a - d = 29 a² + 2a ( 11 - a) - a - (11 - a) = 29 a² + 22a - 2a² - a - 11 + a = 29 - a² + 22a - 11 = 29 - a² + 22a - 11 - 29 = 0 - a² + 22a - 40 = 0 a² - 22a + 40 = 0 Splitting the middle term a² - 20 a - 2a + 40 = 0 (a² - 20a) - (2a - 40) = 0 a ( a - 20) - 2 (a - 20) = 0 ( a - 2) ( a -20) = 0 a - 2 = 0a = 2 a - 20 = 0a = 20 Case - 1 a = 2 d = 11 - a = 11 - 2 = 9 A.P = 2 , 11 , 20 ... Case - 2 a = 20d = 11 - a = 11-20 = -9 A.P = 20 , 11 , 2 ... |
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| 3576. |
Question 4 (4 points)Kendra used synthetic division to determine points of the graph of fxi, as showrt 4 3 -21 -2 7 161 12 A2 11 620Which ordered pair is not on the graph of fx)?112-O1-1.-8)(2, -20) |
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Answer» (-2,-2)(-1,-8) (1,-4)(2,-20)= (1,-4) |
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| 3577. |
4. Find the product:(i) 5.4 x16(iv) 36.73 X 48(vii) 6.032 x 124(ii) 3.65 x19(v) 4.125 x 86(viii) 0.0146 x 69(ii) 0.854x12(vi) 104.06x75(ix) 0.00125 x 327 |
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| 3578. |
24.8 m of a uniform iron rod weighs 82.15 kg, what will be the length of 26.5 kg of the same rod? |
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| 3579. |
Solve the following linear equations2(x +1)3(x -2) |
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Answer» 2(x + 1) 3(x - 2)------------ = ------------- 3 5 10 ( x + 1) = 9 ( x - 2) 10x + 10 = 9x - 18 10x - 9x = - 18 - 10 x = -28 |
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| 3580. |
Given the family of lines, a (3x + 4y + 6)b(x+y+2)0. The line of the family situatedat the greatest distance from the point P(2, 3)has equation:(2) 5x + 3y 10 0(3) 15x + 8y + 30 0(4) 4x- 3y +8 0 |
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Answer» Find the common point of intersection of this family of lines. Here it is (-2,0). Now, given point is (2,3). Equation of line passing through both the points is : 3x + 6 =4y. You actually only need the slope of this line which is : 3/4 Line perpendicular to this line passing through the common point will be at the greatest distance. Slope of the required line: -4/3 Equation of the line :-4/3{x-(-2)} = y-0 After solving, equation is : 4x + 3y + 8 =0. The answer is Option 1. |
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| 3581. |
5x+3y=9 |
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Answer» 5x+3y=93y=-5x+9y=-5/3x+9/3y=-5/3x+3Here m=-5/3 and c=3 |
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| 3582. |
26 + 7-33 = LHS. (as22EXERCISESolve the following linear equations.1.2.4 |
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| 3583. |
Solve the following linear equations by the Elimination method:3x + 4y10 and 2r-2y2. |
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Answer» 3x+4y=10 2x-2y=2... Multiply with 24x-4y=4 Add equations 7x=14; x=2 x-y=1y=x-1=2-1=1 |
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| 3584. |
Solve the following linear equations by the Elimination method3x + 4y 10 and 2x- 2y 2 |
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Answer» 3x+4y= 102x-2y=2multiply with 2to equation first and 3 to equation second6x+8y=206x-6y=6subtract second from first14y=14y=1after putting value of y in any equation x =2 |
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| 3585. |
Solve the following pair of linear equations: |
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Answer» 3x - 5y = 4....... (1)9x - 2y = 7........(2) Multiply eq(1) by 39x - 15y = 12......(3) Subtract eq(2) from eq(3)-13y = 5y = - 5/13 Put value of y in eq(1), we get3x - 5*(-5/13) = 43x + 25/13 = 43x = 4 - 25/133x = (52 - 25)/133x = 27/13x = 9/13 Therefore, value of x = 9/13 and y = - 5/13 |
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| 3586. |
Give the geometric representations of y 3 as an equationi) in one variableii) in two variablesGive the geometric representations of 2x+9 0 as an equationi) in one variablei) in two variables |
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Answer» write the equation X = 8 in two variable |
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| 3587. |
Give the geometric representation of 2x +9 0 as an equation(i) in one variable (the number line)(ii) in two variable (the Cartesian plane) |
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| 3588. |
EXERCISE 4.41. Give the geometric representations of y 3 as an equationin one variable(i) in two variables2,/Give the geometric representations of 2x + 9 = 0 as an equationin one variable(ii) in two variables |
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| 3589. |
QUADRATIC EQUATIONS WITH ONE VARIABLE |
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Answer» Aquadratic equationis anequationof the second degree, meaning it contains at leastoneterm that is squared. The standard form is ax² + bx + c = 0 with a, b, and c being constants, or numerical coefficients, and x is an unknownvariable.Oneabsolute rule is that the first constant “a” cannot be a zero. |
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| 3590. |
174Ă312193 |
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| 3591. |
Give any two examples for linear equation in one variable |
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Answer» 2 examples: 2x+8 = 4x - 42, z+ 8 = 34. |
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| 3592. |
\frac { 7 x - 1 } { 4 } - \frac { 1 } { 3 } \left( 2 x - \frac { 1 - x } { 2 } \right) = \frac { 19 } { 3 } |
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| 3593. |
Exercise 1.1Give any two examples for linear equations in one variable.. |
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Answer» 2y + 1 = -7=> 2y = -8=> y = -4 Other examples: y + 3 = 2y -8, x+5 = 89. |
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| 3594. |
1. Give the geometric representations of y 3 as an equation0 in one variable |
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| 3595. |
5. The volume of a circular iron rod of length 1 m is 3850 cm3. Find its diameter |
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| 3596. |
3y 5x 30. Find the measures of the angles ofthe triangle.Solution:TWO VARIABLES |
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| 3597. |
\tan 15^{\circ}+\tan 75^{\circ}=\frac{\sec ^{2} 15^{\circ}}{\sqrt{\sec ^{2} 15^{\circ}-1}} |
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| 3598. |
1. Give the geometric representations of y 3 as an equationin one variable(i)(ii)in two variables |
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Answer» In one variable because it solved above |
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| 3599. |
Find the cost of carpeting a room 13 m by 9 m with a carpet of width 75 cm at the fate105 per metre.h a carnet of width 75 cm at 80 per metre isit |
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| 3600. |
In how much time will a certain sum be 1.5 times the principal at 10% per annum? |
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Answer» P=xA=1.5xA=P+I1.5x-x=II=0.5xSI=PRT/1000.5x=x X 100 X T/1000.5x X 10/x=TT=5Years what's means SI si is simple interest |
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