InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 11251. |
A dice is thrown twice and the sum of the numbers appearing is observed to be 6. What is the conditional probability that the number 4 has appeared at least once ? |
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| 11252. |
Solve e^((dy)/(dx))=x+1, given that when x=0, y=3. |
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| 11253. |
Integrate the function (x+2)/(sqrt(x^(2)-1)) |
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| 11254. |
The normal at a point theta to the curve x=a(1+cos theta),y=a sin theta always passes through the fixed point |
| Answer» ANSWER :C | |
| 11255. |
Which of thefollowingfunctionis notdifferentiableat x=1? |
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Answer» `F(x) =(x^(2)-1)|(x-1)(x-2)|` |
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| 11256. |
int_(0)^(2) x sqrt(x+2) dx " (put x+2 " =t^(2)")" |
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Answer» Solution :`"LET B " x+2 =t^(2) rArr dx=2t dt` `x=0 rArr t= sqrt(0+2)=sqrt(2)` `x=2 rArr t=sqrt(2+2)=2` `=int_(sqrt(2))^(2)(t^(2)-2)sqrt(t^(2)).2t dt= 2 int_(sqrt(2))^(2)(t^(4)-2t^(2))dt` `=2[(t^(5))/(5)-(2t^(3))/(3)]_(sqrt(2))^(2)=(2)/(15)[3T^(5)-10t^(3)]_(sqrt(2))^(2)` `=(2)/(15)[(96-80)-(12sqrt(2)-20sqrt(2))]` `=(2)/(15)(16+8sqrt(2))=(16)/(15)(2+sqrt(2))` |
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| 11257. |
Coloured balls are distributed in four boxes as shown in the following table: A box is selected at random and then a ball is randomly drawn from the selected box. The colour of the ball is black, what is the probability that ball drawn is from the box III? |
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| 11258. |
Find the equation of the circle passing through the point (– 6, 0) if the power of the point (1, 1) w.r.t. the circle is 5 and it cuts the circle x^(2) + y^(2) – 4x – 6y – 3 = 0 orthogonally. |
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| 11259. |
Three urns A, Band C contain 6 red and 4 white, 2 red and 6 white, and 1 red and 5 white balls respectively. An um is chosen at random and a ball is drawn. If the ball drawn is found to be red, find the. probability that the ball was drawn from the urn A. |
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Answer» <P> `P(E_1)=P(E_2)=P(E_3)=1/3` `P(E/E_1)=6/10,P(E/E_2)=2/8,and P(E/E_3)=1/6`. Required probability `=P(E_1/E)` `=(P(E_1)XXP(E/E_1))/(P(E_1)xxP(E/E_1)+P(E_2)xxP(E/E_2)+P(E_3)xxP(E/E_3))` `=((1/3xx6/10))/((1/3xx6/10)+(1/3xx2/8)+(1/3xx1/6))=36/61`. |
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| 11260. |
When positive integer A is divided by positive integer B, the result is 4.35. Which of the following could be the remainder when A is divided by B? |
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Answer» 13 |
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| 11261. |
Find the angle between the line oversettor=(overset^i+2overset^j-overset^k)+lambda(overset^i-overset^j+overset^k) and the plane oversettor(2overset^i-overset^j+overset^k)=4 |
| Answer» Solution :For the line `oversettob=i-j+k` and NORMAL to the PLANE `=oversettoN=2i-j+k.` Let `THETA` is the ANGLE between the line and the plane. `thereforesintheta=(oversettob.oversettoN)/(|b||N|)=(2+1+1)/(sqrt3sqrt6)=(2SQRT2)/3ifftheta=sin^(_1)((2sqrt2)/3)` | |
| 11262. |
Let f(x)=e^(x)cos x + 1. Which of the following statements is always true? |
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Answer» Between any two consecutive roots of `F (X)=0` |
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| 11263. |
Find (dy)/(dx) ify+siny=cosx |
| Answer» Solution :`y+siny=cosx` DIFFERENTIATING THROUGHOUT w.r.y.x we GET `(dy)/(DX)+cosy(dy)/(dx)=-sinx(dy)/(dx)(1+cosy)=-sinx(dy)/(dx)=(-sinx)/(1+cosy)` where `cosyne-1` | |
| 11264. |
A set A contains m elements another set B contains n elements. A relation is formed from A to B. Then the probability that the relation is a function is |
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Answer» <P>`(.^(n)P_(m))/(2^(MN))` |
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| 11265. |
If a matrix has 18 elements, what are the possible orders it can have? What if it has 5 elements? |
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| 11266. |
Assertion (A): If the roots of (a^(2)+b^(2))x^(2)-2b(a+c)x+ (b^(2)+c^(2))=0are real and equal then a, b, c are in G.P. Reason (R): If the sum of two non-negative reals is zero then each of them is zero. |
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Answer» Both A, R are TRUE and R EXPLAIN Assertion |
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| 11267. |
Show that (1 xx 2^(2) + 2 xx 3^(2) + ... +n xx (n + 1)^(2))/(1^(2) xx 2 + 2^(2) xx 3+ ... + n^(2) xx (n + 1)) = (3n + 5)/(3n + 1) |
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| 11268. |
inttan^3theta d theta |
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Answer» SOLUTION :`inttan^3theta d THETA=inttantheta.(tan^2theta) d theta` =`inttantheta.(sec^2theta-1) d theta` =`inttantheta.sec^2theta d theta- inttantheta d theta` =`inttantheta d (TANTHETA)- inttantheta d theta` =`1/2tan^2theta+In abscostheta +C` |
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| 11269. |
If alpha, beta, gammaare the roots of the equation x^3 + px^2 + qx + r = n then the value of (alpha - 1/(beta gamma)) (beta -1/(gamma alpha)) (gamma-1/(alpha beta)) is: |
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| 11270. |
In a book of 450 pages, it is found that there are 400 typing errors. Assume that poisson law holds for the number of errors per page, find the probability that a random sample of 5 pages will contain no errors. |
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| 11271. |
If |z + 2- i| = 5 then the maximum value of |3z- 9 - 7i| is |
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Answer» 18 |
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| 11272. |
Two dice are thrown simultaneously. If X denotes the number of sixes. Find the mean (expectation) of X. |
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| 11273. |
For n in N, the value of int_(0)^(pi) sin^(n) x*cos^(2n-1)x dx is |
| Answer» ANSWER :A | |
| 11274. |
Find the second order derivatives of the functions. e^(6x) cos 3x. |
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| 11275. |
If 7x+4y le 28, 2y le 7, x ge 0then the maximum value of f=4x-2y is |
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Answer» 16 |
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| 11276. |
Rain falling vertically is appeared to fall at 37^@ with vertical for a man running on horizontal ground with 8 m/s. What is the speed of rain ( in m/s) relative to ground. |
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| 11277. |
Find tha area of theregion containing the points (x, y) satisfying 4 le x^(2) + y^(2) le 2 (|x|+ |y|). |
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Answer» Solution :The points in the required region satisfy `""4le x^(2) + y^(2) le 2 (|x| + |y|)""` (i) Since curve (i) is symmetrical about both the AXES, the required area is 4 times the area of the region in the first quadrant. Therefore, it is sufficient to sketch the region and to find the area in the first quadrant. In the first quadrant, curve (i) consists of two curves : `""x^(2) + y^(2) ge 4 ""(C_(1))""and x^(2)+y^(2)-2x -2Y ge0""(C_(2))` `therfore ""` Required area = 4 area ABCDA = 4 (area of semi-circle ABCA)- (area of sector ADCA) = 4 (area of semi-circle ABCA)-(area of sector sector OADCO- area of triangle OAC) `= 4 {pi- (pi-2)}= 8` sq. units |
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| 11278. |
If A , B are event such that P(A)=0.6, P(B)=0.4 and P(A cap B)=0.2, then find P(B | A) |
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Answer» <P> SOLUTION :`P(B/A)=(P(A capB))/(P(A))=0.2/0.6=2/6=1/3` |
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| 11279. |
Let F be the set of all 4 digited numbers whose sum is 34. If a number is selected from F then find the probability that the selected number is even. |
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| 11280. |
Ifveca,vecb,veccare three vectors, prove that[veca+vecc,veca+vecb,veca+vecb+vecc]=-[veca,vecb,vecc] |
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| 11281. |
If the line 4x + 4y - 11 = 0 intersects the circle x^(2)+y^(2)-4x-6y+4=0 at A and B, then the point of intersection of the tangents drawn at A, B is |
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Answer» `(-1,2)` |
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| 11282. |
The mean deviatons about the median of the data set 4,10,6,4,13,11,19,m,8,7, where m ge 11 is an integer is 4, Then m is equal to: |
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Answer» 14 |
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| 11283. |
" If" f(x) =int_(0)^(x)" t sin t dt tehn " f(x) is |
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Answer» x SIN x Usingpartialintegration `f(x) =[intsintdt -INT [((d)/(dt)t) int sin t dt ]dt]_(0)^(x)` `= [t( -cos t)]_(0)^(x) - int_(0)^(x) (-cos t)dt` `=[-t cos t + sin t]_(0)^(x)` `rArr f(x) =-x cos x + sin x` Nowdifferebntiate withrespect to x . f(x) = -[{x(-sin x)}+cos x] +cos x `= sin x- cos x + cos x =x sin x` |
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| 11284. |
Circles C_(1) and C_(2) are externally tangent and they are both internally tangent to the circle C_(3). The radii of C_(1) and C_(2) are 4 and 10, respectively and the centres of the three circles are collinear. A chord of C_(3) is also a common internal tangent of C_(1) and C_(2). Given that the length of the chord is (msqrt(n))/(p) where m, n and p are positive integers, m and p are relatively prime and n is not divisible by the square of any prime, find the value of (m + n + p). |
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| 11285. |
A particle of mass m is moving in a straight line is acted on by an attractive force( m k^2 a^2)/(x^2) forx ge aand( 2m K ^2 x)/( a) forx lt2.If the particle starts from rest at the point x = 2a, then it will reach the point x = 0 with a speed |
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Answer» `k sqrt(a)` |
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| 11286. |
The orbit of the Earth is an ellipse with eccentricity 1/60 with the sun at one of its foci, the major axis being approximately 186times10^6 miles in length. Find the shortest and longest distance of the Earth from the sun. |
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| 11288. |
The pole of a straight line with respect to the circle x^(2)+y^(2)=a^(2) lies on the circle x^(2)+y^(2)=9a^(2). If the straight line touches the circle x^(2)+y^(2)=r^(2), then |
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Answer» `9A^(2)=R^(2)` |
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| 11289. |
Draw aroughsketch of thecurvey= sqrt(x-1)in theintervalx in[ 1,5]. Findtheareaunder the curveand betweenthe linesx=1andx=5 . |
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| 11290. |
Let S, be a conic whose centre is M(p, q). Locus of middle points of chords of this conic, which passes through a fixed point N(alpha,beta) is: |
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Answer» ANOTHER conic which has a CENTRE |
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| 11291. |
Integration using rigonometric identities : int (sinx- cos x)/(x^(2)+x sin x)dx=....+c |
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Answer» `LOG|x+sinx|` |
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| 11292. |
A postman has to deliver five letters to five different houses. Mischievously, he posts one letter through each door without looling to see if it is the correct address. In how many different ways could he do this so that exactly two of the five houses receive the correct letters? |
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| 11293. |
If a point P is moving such that the lengths of the tangents drawn form P to the circles x^(2) + y^(2) + 8x + 12y + 15 = 0 and x^(2) + y^(2)- 4 x - 6y - 12 = 0are equal then find theequation of the locus of P |
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| 11294. |
If the third term of a G.P is P. Then the Product of the first 5 terms of the G.P is |
| Answer» Answer :D | |
| 11295. |
If(1-x+6x^(2))/(x-x^(3))=A/x +(B)/(1-x)+(C)/(1+x), then A= |
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Answer» 1 |
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| 11296. |
Let f(x) =a_0+a_1x^2+a_2x^4+…….+a_nx^(2n) be a polynomial in x in R with 0lta_0lta_1lt……lta_n then f(x) has |
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Answer» neither a maximum nor a MINIMUM |
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| 11298. |
Obtain the following integrals : int(cos(5x)+cos(4x))/(1-2cos(3x))dx |
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| 11299. |
Two particles A and B move from rest along a straight line with constant accelerationsfand h respectively.If A takes m seconds more than B and describes n units more than that of B acquiring the same speed then |
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Answer» `(f+h)m^(2)=FHN` |
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| 11300. |
Let f, g, and h be functions from R to R. Show that (f + g) o h = foh + goh |
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Answer» Solution :[ (F + g) o H ] (x) = (f + g) (h(x)) =f(h(x)) + g (h(x)) (f o h) (x) + (g o h) (x)) (FOH + GOH) (x), for all `x in R` Thus, (f + g) o h = f o h + g o h |
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