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2151.

Find the equation of the circle with centre C and radius r where C = (a,-b) , r= a+b

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ANSWER :`X ^(2) + y^(2) -2ax +2by-2ab =0 `
2152.

Definite integration as the limit of a sum : lim_(ntooo)(1)/(n)sum_(r=n+1)^(2n)log(1+(r)/(n))=.............

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`log((27)/(4E))`
`log((27)/(e^(2)))`
`log((4)/(e))`
NONE of these

Answer :A
2153.

If f and g are not derivable at x_0then f+g is not derivable at x_0.

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ANSWER :F
2154.

The radius of the circle which has the lines x+y-1=0, x+y-9=0 as tangents is

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`SQRT(2)`
`2sqrt(2)`
`3sqrt(2)`
`4sqrt(2)`

ANSWER :B
2155.

Let I_(n)=int_(0)^(pi//4) tan^(n)x dx. Statement-1: (1)/(n+1)lt 2I_(n) lt (1)/(n-1) for all n=2,3,4,….. Statement-2: I_(n)+I_(n-2)=(1)/(n-1),n=3,4,5,…...

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Statement-1 is true, Statement-2 is True,Statement-2 is a correct explanation for Statement-1.
Statement-1 is True, Statement-2 is not a correct explanation for Statement-1.
Statement-1 is True, Statement-2 is FALSE.
Statement-1 is False, Statement-2 is True.

Solution :We have,
`I_(n)+I_(n-2)=UNDERSET(0)overset(PI//4)int tan^(n)x dx+underset(0)overset(pi//4)int tan^(n-2)x dx`
`rArr I_(n)-I_(n-2)=underset(0)overset(pi//4)int tan^(n-2)x sec^(2)x dx=[(tan^(n-1)x)/(n-1)]_(0)^(pi//4)=(1)/(n-1)`
So, statement-2 is true.
We know that
`0 lt tan xlt1` for ll `x in (0,(pi)/(4))`
`rArr tan^(n+2)xlt tan^(n-2)x` for all `x in (0,(pi)/(4))`
`rArr underset(0)overset(pi//4)int tan^(n+2)x dx lt underset(0)overset(pi//4)int tan^(n-2)x dx`
`rArr I_(n+2)lt I_(n)lt I_(n-2)`
`rArr I_(n)+I_(n+2)lt 2I_(n)+I_(n-2)`
`rArr (1)/(n+1)ltI_(n)lt(1)/(n-1)""`[Using statement-2]
So, statement-1 is true and statement-2 is a correct explanation for statement-1.
2156.

For a normal distribution if the mean is M, mode is M_(0) and median is M_(d), then

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`M GT M_(d) gt M_(0)`
`M LT M_(d) lt M_(0)`
`M=M_(d)M_(0)`
`M=M_(d)=M_(0)`

SOLUTION :It is OBVIOUS.
2157.

Show that the relation R in the set {1,2,3} given by R = {(1,2),(2,1)} is symmetric but neither reflexive nor transitive.

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SOLUTION :N/A
2158.

(cos 13^(@) - sin 13^(@))/(cos 13^(@) + sin 13^(@)) + (1)/(cot 148^(@)) is equal to

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A.1
B.`-1`
C.0
D.`(1)/(2)`

ANSWER :c
2159.

If the equation (x + m)^(2) - (x + n)^(2) = ( m - n)^(2) where m , n are non- zero constants and m^(2) ne n^(2) , satisfied by x = pm + pn , then the ordered pair (p , q) is equal to

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(0 , -1)
(-1 , 0)
(1 , 0)
(0, 1)

ANSWER :A
2160.

The sum of two numbers is 13, and their product is 30. What is the sum of the squares of the two numbers?

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`-229`
`-109`
`139`
`109`

ANSWER :D
2161.

State with reason,"Collection of all residents of Odisha who will live for more than 100 years " is set or not ?

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Solution :It is not t set, as we do not KNOW, that who will LIVE for more than 100 YEARS.
2162.

Integrate the following functions : int(2x+5)/(x^(2)+5x+9)dx

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ANSWER :`log|x^(2)+5x+9|+c`
2163.

Let A=[(0,2),(0,3)] and B=[(2,3),(0,0)], then AB equals :

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`[(0,6),(0,0)]`
`[(0,4),(0,0)]`
`[(0,6),(0,4)]`
`[(0,0),(0,0)]`

ANSWER :D
2164.

If the coefficient of x^(3) is 1140 in the expansion of (1+2x+kx^(2)), then the value of k is______.

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ANSWER :A
2165.

Find the order and degree (if defined) of the following differential equations. y' + 5y = 0

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Solution :The HIGHEST ORDER DERIVATIVE in the differential equation is y. . Order of the differential equation = !, The degree of y. is 1. `therefore` The degree of the differential equation = 1.
2166.

Find the angles between the pair of lines whose slopes are , sqrt3,-1 .

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SOLUTION :LET `m_1=sqrt3,m_2=-1`
`THEREFORE` `TANTHETA=(m_2-m_1)/(1+m_1m_2)=(-1-sqrt3)/(1-sqrt3)`
=`((sqrt3+1)/(1+sqrt3))=(sqrt3+1)/(sqrt3-1)=tan75^@ `
`therefore` `theta=75^@`.
2167.

int(3x)/(1+2x^(4)) dx

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ANSWER :`3/(2sqrt2)tan^(-1)sqrt2x^(2)+C`
2168.

If sum_(i=1)^(4)a_(i)^(2)x^(2)-2sum_(i=1)^(4)a_(i)a_(i+1)x+sum_(i=1)^(4)a_(i)^(2)+1) le 0, " where " a_(i) gt 0 and all are distinct. Then,

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`a_(1)+a_(5) GT 2a_(3)`
`SQRT(a_(1)a_(5))=a_(3)`
`2/sqrt(a_(1)a_(4)) gt 1/a_(1)+1/a_(4)`
`prod_(i=1)^(5)a_(i)=a_(3)^(5)`

Answer :A::B::C
2169.

The point P(alpha,alpha +1) will lie inside the triangle whose vertices are A(0,3), B(-2,0) and C(6,1) if

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`alpha =- 1`
`alpha =- (1)/(2)`
`alpha = (1)/(2)`
`-(6)/(7) lt alpha lt (3)/(2)`

Solution :We have `A(0,3), B(-2,0)` and `C(6,1)`
Equation of AC is `X +3y - 9 =0`
Equation of BC is `x - 8y +2 = 0`

`P (alpha, alpha +1)` lies on the line `y = x +1`
whichcuts BC at `D(-(6)/(7),(1)/(7))` and AC at `E ((3)/(2),(5)/(2))`
`:. alpha` must lie between `-(6)/(7)`and `(3)/(2)`.
2170.

Find the vector equation of the line passing through (1, 2, 3) and parallel to the planes vecr.(hati-hatj+2hatk)=5 and vecr.(3hati+hatj+hatk)=6

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ANSWER :`THEREFORE VECR=(hati+2hatj-4hatk)+LAMBDA(-3hati+5hatj+4hatk)`
2171.

Find the unit vector in the direction of the vector 2hati-2hatj+hatk.

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Answer :`(2)/(3)hati-(2)/(3)hatj+(1)/(3)HATK`
2172.

If sum_(i=1)^(15)x_(i)=45,A=sum_(i=1)^(15)(x_(i)-2)^(2) B=sum_(i=1)^(15)(x_(i)-3)^(2) and C=sum_(i=1)^(15)(x_(i)-5)^(2) then Statement 1: min(A,B,C)=A Statement 2: The sum of squares of deviations is least when taken from man.

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Statement 1: is TRUE, Statement 2 is True , Statement 2 ISA correct explanation for statement 1
Statement 1 is True, Statement 2 is True Statement 2 is NOT a correct explanation for Statement 1
Statement 1 is True, Statement 2 is False
Statement 1 is False, Statement 2 is True

Solution :`sum_(i=1)^(n)(x_(i)-barx)^(2)`
`implies "min" (A,B,C)=B`
2173.

Express in polar form (mod-Amplitude form) -2 + 2isqrt3

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ANSWER :B::C::D
2174.

A slip of paper is given to a person A who marks it either with a plus sign or a minus sign. The probability of his writing a plus sign is 1//3. A passes the slip to B, who may either leave it alone or change the sign before passing it to C. Next C passes the slip to D after perhaps changing the sign. Finally D passes it to a refere after perhaps changing the sign. B,C,D each change the sign with probability 2//3. The probability that the referee observes a plus sign on the slip if it is known that A wrote a plus sign is

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`14//27`
`16//27`
`13//27`
`17//27`

SOLUTION :`(c )` Let `E_(1)=` Event that `A` WROTE a plus SIGN
`E_(1)=` Event that `B` wrote a plus sign
`E=` Event that the REFEREE observes a plus sign.
Given `P(E_(1))=(1)/(3)impliesP(E_(2))=(2)/(3)`
`P(E//E_(1))=` PROBABILITY that none of `B`, `C`, `D` change sign `+` Probability that exactly two of `B,C,D` change sign
`=(1)/(27)+3((1)/(3)xx(2)/(3)xx(2)/(3))=(13)/(27)`
`P(E//E_(2))=` Probability that all of `B,c,d` change sign `+` Probability that exactly one of `B,C,D` changes sign ,brgt `=(8)/(27)+3((2)/(3)xx(1)/(3)xx(1)/(3))=(14)/(27)`
`:.P(E_(1)//E)=(13)/(41)` (Using Bayes' Theorem)
2175.

A slip of paper is given to a person A who marks it either with a plus sign or a minus sign. The probability of his writing a plus sign is 1//3. A passes the slip to B, who may either leave it alone or change the sign before passing it to C. Next C passes the slip to D after perhaps changing the sign. Finally D passes it to a refere after perhaps changing the sign. B,C,D each change the sign with probability 2//3. If the refree observes a plus sign on the slip then the probability that A originally wrote a plus sign is

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`13//41`
`19//27`
`17//25`
`21//37`

Solution :`(a)` Let `E_(1)=` Event that `A` wrote a plus sign
`E_(1)=` Event that `B` wrote a plus sign
`E=` Event that the referee observes a plus sign.
Given `P(E_(1))=(1)/(3)impliesP(E_(2))=(2)/(3)`
`P(E//E_(1))=` Probability that none of `B`, `C`, `D` change sign `+` Probability that exactly two of `B,C,D` change sign
`=(1)/(27)+3((1)/(3)XX(2)/(3)xx(2)/(3))=(13)/(27)`
`P(E//E_(2))=` Probability that all of `B,c,d` change sign `+` Probability that exactly one of `B,C,D` changes sign ,brgt `=(8)/(27)+3((2)/(3)xx(1)/(3)xx(1)/(3))=(14)/(27)`
`:.P(E_(1)//E)=(13)/(41)` (USING BAYES' Theorem)
2176.

Match the following. {:( "I." C_0 + 3.C_1 + 5. C_2 + …...(2n + 1). C_n=,"a)" (n+1)2^(n)),( "II." 3. C_0+7. C_1 + 11. C_2 + ….+ (4n+3). C_n=,"b)" (2n+3)2^(n)),( "III." C_0 + 4. C_1 + 7. C_2 + …. (n+1) "terms" =, "c)" (2n+3) 2^(n-1)),( "IV." (3n+2)^(n) C_0 + (3n - 1) ^n C_1+ (3n-4)^n C_2 + .......+ (""^n C_n)=,"d)" (3n+4) 2^(n-1)):}

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a, b, C, d
d, c, b, a
a, c, d, b
d, a, b, c

Answer :A
2177.

Let abs(a)=sqrt(3), abs(b)=5, b*c=10, angle between b and c is equal to pi//3. If a is perpendicular to b times c, " then "abs(a times (b times c))=_________

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ANSWER :30
2178.

Let A, B, C be three events and barA, barB, barC be their corresponding complementary event. If the probabilities of events B, AnnBnnbarC and barA nnB nnbarC are (5)/(6),(1)/(2) and (1)/(4) respectively, then the probability of the event BnnC is

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`(1)/(12)`
`(1)/(4)`
`(1)/(6)`
`(1)/(3)`

ANSWER :A
2179.

What is the correct order of nitration of the following compounds? {:(C_(6)H_(5)CH_(3),C_(6)H_(6),C_(6)D_(6),C_(6)T_(6),C_(6)H_(5)Br,C_(6)H_(5)overset(+)NR_(3),C_(6)H_(5)NMe_(2)),("a","b"," c"," d","e","f","g"):}

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`G GT a gt b gt c gt d gt e gt F`
`g gt b gt c gt d gt e gt a gt f`
`g gt a gt b = c = d gt e gt f`
`g gt a gt b gt c = d gt e gt f`

Solution :r.d.s of NITRATION does not involve (C-H) bond cleavage
`:. C_(6)H_(6)=C_(6)D_(6)=C_(6)T_(6)`
2180.

lim_(xto0) {(1)/(x3sqrt(8+x)-(1)/(2x))} is equal to

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`(1)/(12)`
`(-4)/(3)`
`(-16)/(3)`
`(-1)/(48)`

ANSWER :D
2181.

Amar and Bimal are two contestants for an election, probability that Amar will win is 1/4 and that Bimal will win the election is 1/5, then what is probability that either Amar or Bimal will win the election.

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`13//20`
`9//20`
`11//20`
NONE of these

Answer :B
2182.

Find the number of ways of forming a committee of 5 members out of 6 Indians and 5 Americans so that always the Indians will be in majority in the committee.

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ANSWER :281
2183.

The volume of the parallelepiped whose coterminous edges are represented by the vectors 8vec(b)xxvec(c),3vec(c)xxvec(a)and4vec(a)xxvec(b), where vec(a)=(1+sintheta)hat(i)+costhetahat(j)+sin2thetahat(k), vec(b)=sin(theta+(2pi)/(3))hat(i)+cos(theta+(2pi)/(3))hat(j)+sin(2theta+(4pi)/(3))hat(k), vec(c)=sin(theta-(2pi)/(3))hat(i)+cos(theta-(2pi)/(3))hat(j)+sin(2theta-(4pi)/(3))hat(k) is 18 cubic units, then the values of theta, in the interval (0,(pi)/(2))," is/are"

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`(pi)/(9)`
`(2PI)/(9)`
`(pi)/(3)`
`(4PI)/(9)`

ANSWER :A::B::D
2184.

If A+B+C+D= 2pi , " then " -4 cos""((A+B)/(2)) sin""((A+C)/(2)) cos""((A-D)/(2))=

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`SIN A + sin B+ sin C-sin D `
`sin A - sin B + sin C - sin D `
`sin A + sin B + sin C + sin D `
`sin A - sin B +sin C + sin D `

ANSWER :B
2185.

int(Inx)/x^5dx

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Solution :`int(INX)/x^5dx=int1nx.x^-5dx`
[TAKE 1n x as FIRST and `x^-5` as second function]
=`1nx.x^-4/-4-int1/x.x^-4/-4dx`
=`-(1n x)/(4x^4) +1/4intx^-5dx`
=`-(1nx)/(4x^4)+1/4 x^-4/-4+C`
=`-(1nx)/(4x^4)-1/(16x^4)+C`
2186.

Correct order of indicated bond length is/are:

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`CH_(2)OVERSET(a)=CH-O"Me" lt O_(2)N-CH_(2)overset(b)=CH-O"Me"`

`CH_(3)CH_(2)ul(a)Cl lt CH_(2) =CH-CH_(2)ul(b)Cl`
`CH_(3)-UNDERSET(O)underset(||)CUL(a)OH lt CH_(3)-underset(O)underset(||)Cul(b) O^(Ѳ)`

Answer :A::B::C
2187.

If a^(2)-3(b-|d|) lt 0 prove that f(x) = x^(3) + ax^(2) + bx +dsinx is an increasing function in the set of real number R.

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2188.

If A, B and C are three sets such that A nn B=A nn C and AuuB=AuuC, then

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A = C
B = C
`AnnB=Phi`
0

Answer :B
2189.

If int(2x^(2)+5)/(x^(2)+a)dx=f(x), where f(x) is a polynomial or ratio of polynomials, then the number of possible value(s) of a isequal to

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0
1
2
3

Answer :C
2190.

Find the value of k if the following equations have equal roots i) x^(2)–2(1+3k)x+7(3+2k)= 0 ii) x^(2) -15 - k(2x – 8) = 0 iii) (3k+1)x^(2)+2(k+1)x+k=0 iv) x^(2)+2(k+2)x+9k=0

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Answer :i) `(-10)/(9)`, 2 ii) 3, 5 iii) `(-1)/(2)`, 1 IV) 1, 4
2191.

Let P(n) be a statement such that truth of P(n)impliesthe truth of P(n + 1)[ n inN, then P(n) is true

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`AA N GT 1`
`AA n`
Nothingcan besaid
`AAn gt k`( k issomefixedpositiveinteger )

ANSWER :C
2192.

Computethe shortestdistancebetweenthe lines vec(r )=(hat(i) -hat(j)) + lambda (2hat(i) -hat(k))" and" vec(r ) =(2hat(i) -hat(j))+ mu (hat(i) - hat(j) -hat(k)) Determinewhether theselinesintersect of not.

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ANSWER :`SD =(SQRT(14))/(14) NE 0`the givenlinesdo notintersect
2193.

Assertion (A) : The remainder of x^(3)+2x^(2)-5x-3 which is divided by x-2 is 3. Reason (R) : The remainder of the polynomial f(x) when divided by x-a is f(a)

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Both A & R are TRUE and R is CORRECT EXPLANATION of A
Both A & R are true and R is not correct explanation of A
A is true but R is false
A is false but R is true

Answer :A
2194.

Fundamental theorem of definite integral : int_(a)^(b)(logx)/(x)dx=...... (where a binR^(+) )

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`(1)/(2)LOGAB`
`LOG((b)/(a))`
`2log((b)/(a))`
`(1)/(2)log(AB)log((b)/(a))`

Answer :D
2195.

Determine the truth of falsity of the{1,2} in {1,2,3} propositions with reasons.

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SOLUTION :`{1,2} in {1,2,3}` is FALSE, as {1,2} is not an ELEMENT of {1,2,3} but it is a SUBSET.
2196.

In a bivariate distribution the regression equation of y on x is 8x – 10y + 66 = 0. If barx= 13, find bary

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ANSWER :`bary=17`
2197.

Show that a function p is a polynomial function is continuous.

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<P>

ANSWER :HENCE, p is a CONTINUOUS FUNCTION.
2198.

Line L has intercepts a and b on the axes of co ordinates. When the axes are rotatedthrough a givenn angle, keeping the origin fixed, the straight line L has intercpets p and q on the transformed axes. Prove that1/(a^(2))+1/(b^(2))=1/(p^(2))+1/(q^(2)).

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SOLUTION :NA
2199.

Contraction of muscles results from :-

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A contraction of MYOSIN filaments.
The SLIDING of the ACTIN over myosin.
The formation of PEPTIDE bonds that link actin and myosin.
Contraction of actin.

Answer :A
2200.

If three dice are thrown, the probability that they show the numbers in A.P.is

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`(1)/(36)`
`(1)/(12)`
`(2)/(9)`
`(5)/(18)`

Answer :B