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51.

PLD contains a large number of _________(a) Flip-flops(b) Gates(c) Registers(d) All of the MentionedThe question was posed to me in an interview for internship.The above asked question is from Programmable Logic Array in chapter Memory Devices of Digital Circuits

Answer»

Right OPTION is (d) All of the Mentioned

Easiest EXPLANATION: Programmable Logic DEVICES is a collection of a large number of gates, flip-flops, registers that are INTERCONNECTED on the chip. Thus, it is used for designing logic circuits.

52.

The full form of PLD is _________(a) Programmable Load Devices(b) Programmable Logic Data(c) Programmable Logic Devices(d) Programmable Loaded DevicesThis question was addressed to me by my school teacher while I was bunking the class.Query is from Programmable Logic Array in section Memory Devices of Digital Circuits

Answer» CORRECT choice is (c) Programmable Logic Devices

Easiest EXPLANATION: The full form of PLD is Programmable Logic Devices. It is a collection of GATES, flip-flops and registers on a SINGLE chip.
53.

How many 16K * 4 RAMs are required to achieve a memory with a capacity of 64K and a word length of 8 bits?(a) 2(b) 4(c) 6(d) 8This question was addressed to me in my homework.This question is from Programmable Logic Array in chapter Memory Devices of Digital Circuits

Answer»

The correct answer is (d) 8

To explain I WOULD say: 16K * 4 = 64K RAM is of 64K. THEREFORE, for a word of length 8-bits,

 64 * 8 = 512K RAM required. Thus, number of 16K * 4 RAMS = 512/64 = 8.

54.

How many 1024 * 1 RAM chips are required to construct a 1024 * 8 memory system?(a) 4(b) 6(c) 8(d) 12I have been asked this question in a job interview.Enquiry is from Programmable Logic Array in division Memory Devices of Digital Circuits

Answer»

The correct OPTION is (c) 8

For explanation: ONE 1024 * 1 RAM chips is of 1-bit. SO, for construction of 1024 * 8 RAM CHIP of 8-bits, it will require 8 chips.

55.

To construct 16K * 4-bit memory, how many 4116 ICs are required?(a) 1(b) 2(c) 3(d) 4I got this question in my homework.I would like to ask this question from Programmable Logic Array in chapter Memory Devices of Digital Circuits

Answer»

Right option is (d) 4

The BEST explanation: SINCE, IC 4116 is organised as 16K * 1, which can store about 16KB data. So, four ICS are required for 16K * 4 memory implementation.

56.

How memory expansion is done?(a) By increasing the supply voltage of the Memory ICs(b) By decreasing the supply voltage of the Memory ICs(c) By connecting Memory ICs together(d) By separating Memory ICsThe question was asked in class test.The query is from Programmable Logic Array topic in portion Memory Devices of Digital Circuits

Answer» RIGHT choice is (C) By connecting Memory ICS TOGETHER

Easiest explanation: Memory ICs can be connected together to expand the number of memory words or the number of bits PER word.
57.

IC 4116 is organised as _________(a) 512 * 4(b) 16 * 1(c) 32 * 4(d) 64 * 2I had been asked this question in examination.My question is from Programmable Logic Array topic in division Memory Devices of Digital Circuits

Answer»

The correct answer is (C) 32 * 4

The best EXPLANATION: IC 4116 is organised as 16 * 1 K which has capability to STORE 16 KB.

58.

How many address bits are required to select memory location in the Memory decoder?(a) 4 KB(b) 8 KB(c) 12 KB(d) 16 KBThis question was posed to me during an online interview.My question is taken from Programmable Logic Array in division Memory Devices of Digital Circuits

Answer»

Correct OPTION is (c) 12 KB

To elaborate: Memory decoder decodes the memory to be SELECTED for a specific address. Since the given EPROM and RAM are of 4 KB (4 * 1024 = 4096) CAPACITY, it requires 12 address bit to select one of the 4096 memory locations.

59.

The first step in the design of memory decoder is __________(a) Selection of a EPROM(b) Selection of a RAM(c) Address assignment(d) Data insertionI have been asked this question in exam.My doubt is from Programmable Logic Array in division Memory Devices of Digital Circuits

Answer»

The CORRECT choice is (c) Address assignment

To explain I WOULD say: Memory DECODER decodes the memory to be selected for a SPECIFIC address. The first step in the design of memory decoder is address assignment in non-overlapped MANNER.

60.

What is memory decoding?(a) The process of Memory IC used in a digital system is overloaded with data(b) The process of Memory IC used in a digital system is selected for the range of address assigned(c) The process of Memory IC used in a digital system is selected for the range of data assigned(d) The process of Memory IC used in a digital system is overloaded with data allocated in memory cellI had been asked this question in class test.I'm obligated to ask this question of Programmable Logic Array in division Memory Devices of Digital Circuits

Answer»

Right option is (b) The process of Memory IC used in a digital system is SELECTED for the RANGE of address assigned

The EXPLANATION: The Memory IC used in a digital system is selected or enabled only for the range of ADDRESSES assigned to it and this process is CALLED memory decoding. It decodes the memory to be selected for a specific address.

61.

Which of the following is not a primary storage device?(a) Optical disk(b) Magnetic tape(c) Magnetic disk(d) RAMI have been asked this question during an online interview.The question is from Random Access Memory topic in division Memory Devices of Digital Circuits

Answer» RIGHT CHOICE is (d) RAM

Explanation: RAM (i.e. Random Access Memory) is not a PRIMARY STORAGE device.
62.

A place which is used as storage location in a computer __________(a) A bit(b) A record(c) An address(d) A byteThe question was posed to me during an interview.I'd like to ask this question from Random Access Memory in chapter Memory Devices of Digital Circuits

Answer»

The correct choice is (C) An address

Easiest explanation: A storage LOCATION of a COMPUTER is an address/memory location, USED to store INSTRUCTIONS and data.

63.

CD-ROM is a __________(a) Memory register(b) Magnetic memory(c) Semiconductor memory(d) Non-volatile memoryThe question was posed to me during an interview.Query is from Random Access Memory in chapter Memory Devices of Digital Circuits

Answer»

Right answer is (d) Non-volatile MEMORY

Easiest explanation: CD-ROM is a non-volatile memory. Once a program is UPLOADED in it then it can’t be ERASABLE. Thus, it stores the data permanently.

64.

The memory which is used for storing programs and data currently being processed by the CPU is called __________(a) PROM(b) Main Memory(c) Non-volatile memory(d) Mass memoryI have been asked this question in quiz.My doubt is from Random Access Memory in chapter Memory Devices of Digital Circuits

Answer» RIGHT choice is (a) PROM

Explanation: PROM has the capability to store the data DUE to the presence of MOSFET which is processed by the CPU. It is one-time programmable by the user.
65.

Which one is self-compatible?(a) ROM(b) RAM(c) EROM(d) PROMI have been asked this question in an online interview.This intriguing question comes from Random Access Memory topic in portion Memory Devices of Digital Circuits

Answer»

The correct choice is (b) RAM

Easy explanation: As semiconductor memories ENJOY common interface and technology between SENSING and decoding circuitry and the storage ELEMENT itself, so RAMs are self-compatible. Also, they provide high SPEED and fast operation.

66.

Which one is more economical?(a) ROM(b) RAM(c) EROM(d) PROMI have been asked this question during a job interview.I want to ask this question from Random Access Memory topic in section Memory Devices of Digital Circuits

Answer»

The correct ANSWER is (B) RAM

To explain: RAM is more economical than ROM because MOS MEMORIES are more economical than the magnetic core for small and medium sized systems.

67.

RAMs are utilized in the computer as __________(a) Scratch-pad(b) Buffer(c) Main memory(d) All of the MentionedThe question was posed to me in an interview for internship.Query is from Random Access Memory topic in chapter Memory Devices of Digital Circuits

Answer» CORRECT answer is (d) All of the Mentioned

For explanation: RAMs are UTILIZED in the computer as a scratch-pad, buffer and main memories. These are the APPLICATIONS of RAMs. Mostly, these RAMs are DRAMs as they provide HIGH speed.
68.

The advantages of RAMs are __________(a) Non destructive read out(b) Fast operating speed(c) Low power dissipation(d) All of the MentionedI have been asked this question during an internship interview.My question is based upon Random Access Memory topic in section Memory Devices of Digital Circuits

Answer»

Correct OPTION is (d) All of the Mentioned

The explanation is: The ADVANTAGES of RAM are Non-destructive READ out, Fast operating SPEED and LOW power dissipation.

69.

When PSRAM is performing internal refresh __________(a) The read operation is performed(b) The write operation is performed(c) It can not be accessed for read or write(d) The voltage goes HIGHThis question was addressed to me in an international level competition.This intriguing question comes from Random Access Memory in division Memory Devices of Digital Circuits

Answer»

The correct option is (C) It can not be accessed for read or write

Best explanation: The FULL form of PSRAM is Pseudo Static RAM. It is a dynamic RAM having built-in fresh logic, which is IMPLEMENTED as a SRAM. So, it can not be accessed for read or write during the refresh operation.

70.

Pseudo static RAM is a __________(a) Static RAM(b) Dynamic RAM(c) Cache(d) ROMThe question was asked by my college professor while I was bunking the class.Question is taken from Random Access Memory in chapter Memory Devices of Digital Circuits

Answer»

The correct choice is (b) DYNAMIC RAM

The best I can explain: The full FORM of PSRAM is Pseudo STATIC RAM. It is a dynamic RAM having built-in FRESH logic, which is implemented as an SRAM.

71.

How many supply voltage IC 4116 requires to operate the IC unit?(a) 3(b) 2(c) 1(d) 4This question was addressed to me during an online interview.The above asked question is from Random Access Memory in portion Memory Devices of Digital Circuits

Answer»

The correct choice is (a) 3

The best I can EXPLAIN: IC 4116 is a DRAM of 16 KB storage memory. It requires three supply voltages (+5V, -5V, and +12V) to operate the IC unit.

72.

The full form of PSRAM is __________(a) Plugged Static RAM(b) Plugged Stored RAM(c) Pseudo Stored RAM(d) Pseudo Static RAMI got this question in exam.Question is from Random Access Memory topic in portion Memory Devices of Digital Circuits

Answer»

The correct choice is (d) PSEUDO STATIC RAM

For explanation I would SAY: The full FORM of PSRAM is Pseudo Static RAM. It is a dynamic RAM which is implemented as a SRAM.

73.

DRAM is fabricated by using IC __________(a) 2114(b) 7489(c) 4116(d) 2776The question was posed to me in an international level competition.This interesting question is from Random Access Memory in division Memory Devices of Digital Circuits

Answer» RIGHT option is (c) 4116

The explanation: DRAM is Dynamic RAM which TAKES more access time COMPARED to SRAM and is thus, slower in operation comparatively. ALTHOUGH, in general it offers high speed and is used in most computers nowadays. DRAM is fabricated by using IC 4116.
74.

IC 4116 is of ______ storage memory.(a) 16 KB(b) 32 KB(c) 64 MB(d) 2 KBI had been asked this question in examination.The doubt is from Random Access Memory topic in section Memory Devices of Digital Circuits

Answer»

The CORRECT answer is (a) 16 KB

The explanation is: IC 4116 is a DRAM of 16 KB storage memory. It requires three SUPPLY voltages (+5V, -5V, and +12V) to operate the IC unit.

75.

What is a sense amplifier?(a) It is an amplifier which converts ac current into dc current(b) It is an amplifier which lowers the input voltage(c) It is an amplifier which increases the input voltage(d) It is an amplifier which converts the low voltage to a sufficient voltageThe question was posed to me in an interview for job.I need to ask this question from Random Access Memory in division Memory Devices of Digital Circuits

Answer»

Right CHOICE is (d) It is an amplifier which converts the LOW voltage to a sufficient voltage

Explanation: A sense amplifier for each COLUMN is necessary to convert from the low voltage and low ENERGY to a sufficient LEVEL on the I/O data line.

76.

An address multiplexing in DRAM is of _____ bits.(a) 10240(b) 15289(c) 16384(d) 17654This question was posed to me in an online interview.This interesting question is from Random Access Memory topic in portion Memory Devices of Digital Circuits

Answer»

Right option is (C) 16384

The BEST explanation: A Dynamic RAM USUALLY EMPLOYS a technique called address multiplexing to reduce the number of address LINES and thus the number of input/output pins on the IC package. Address multiplexing has 2^14 = 16384 bits.

77.

Why do a DRAM employ the address multiplexing technique?(a) To reduce the number of memory locations(b) To increase the number of memory locations(c) To reduce the number of address lines(d) To increase the number of address linesThe question was asked during an online interview.The doubt is from Random Access Memory in section Memory Devices of Digital Circuits

Answer»

Correct answer is (C) To REDUCE the number of address LINES

To EXPLAIN I would SAY: A Dynamic RAM usually employs a technique called address multiplexing to reduce the number of address lines and thus the number of input/output pins on the IC package.

78.

Which characteristic of RAM memory makes it not suitable for permanent storage?(a) Unreliable(b) Too slow(c) Too bulky(d) It is volatileThe question was asked in homework.My doubt stems from Random Access Memory in portion Memory Devices of Digital Circuits

Answer»

The correct ANSWER is (d) It is volatile

Best EXPLANATION: RAM is volatile. Therefore, it stores data only as long as the d.c POWER is on.

79.

Cache memory acts between __________(a) RAM and ROM(b) CPU and RAM(c) CPU and Hard Disk(d) CPU and ROMI had been asked this question in an online interview.Query is from Random Access Memory topic in section Memory Devices of Digital Circuits

Answer»

Correct choice is (B) CPU and RAM

The explanation is: In a COMPUTER, cache MEMORY acts between CPU and RAM.

80.

Dynamic RAM is used as main memory in a computer system as __________(a) It has a lower cell density(b) It needs refreshing circuitry(c) Consumes less power(d) Has higher speedI got this question at a job interview.I need to ask this question from Random Access Memory topic in division Memory Devices of Digital Circuits

Answer»

The correct option is (d) Has higher speed

To explain: Dynamic RAM is used as main memory in a computer system as it has a higher speed DUE to the presence of MOSFET TECHNOLOGY. HOWEVER, it’s access time is more compared to SRAM and OPERATION is slow.

81.

Virtual memory consists of __________(a) SRAM(b) DRAM(c) Magnetic memory(d) Main MemoryThis question was posed to me during a job interview.My question is based upon Random Access Memory topic in division Memory Devices of Digital Circuits

Answer»

Right OPTION is (a) SRAM

The EXPLANATION is: Most modern operating systems employ a method of EXTENDING RAM capacity, known as virtual memory which consists of SRAM.

82.

The main memory of a PC is made of __________(a) Cache(b) Dynamic RAM(c) Static RAM(d) Both cache and dynamic RAMThis question was posed to me during a job interview.This intriguing question originated from Random Access Memory topic in portion Memory Devices of Digital Circuits

Answer»

The correct OPTION is (d) Both cache and dynamic RAM

For explanation I would SAY: The main memory of a PC is made of cache and DRAM. DRAM offers reduced power consumption and large STORAGE CAPACITY in a single memory CHIP.

83.

The DRAM stores its binary information on __________(a) MOSFET(b) Transistor(c) Capacitor(d) BJTThe question was posed to me in an interview.The question is from Random Access Memory in chapter Memory Devices of Digital Circuits

Answer»

Correct answer is (c) CAPACITOR

To explain: Capacitor has high storing capability only, so DRAM STORES its binary information in the form of electric charges on CAPACITORS. However, DRAM takes more time time to ACCESS data.

84.

The dynamic RAM offers __________(a) High power consumption, large storage capacity(b) Reduced power consumption, large storage capacity(c) Reduced power consumption, short storage capacity(d) High power consumption, short storage capacityThis question was posed to me by my school principal while I was bunking the class.My question is based upon Random Access Memory in chapter Memory Devices of Digital Circuits

Answer» CORRECT answer is (b) Reduced power consumption, large storage capacity

For EXPLANATION I would say: The dynamic RAM offers reduced power consumption and large storage capacity in a SINGLE memory chip. With the AVAILABILITY of such high packing density memory ICs, the capacity of memory will CONTINUE to grow. However, it’s access time is more and thus operation is slow.
85.

What is the disadvantage of MOS capacitor in DRAM?(a) It can’t hold the data till a long period(b) It doesn’t holds the charge till a long period(c) It is highly densed(d) It is not flexibleThe question was posed to me by my school teacher while I was bunking the class.My doubt is from Random Access Memory topic in portion Memory Devices of Digital Circuits

Answer»

The correct answer is (b) It doesn’t holds the charge till a long PERIOD

For explanation: The disadvantage of MOS capacitor in DRAM is that it can’t hold the stored charge over a long period of time and it has to be refreshed EVERY few millisecond. THUS, DRAM is slow in OPERATION.

86.

DRAM uses of integrated MOS capacitors as _______ instead of a flip-flop.(a) Storage cell(b) Memory cell(c) Dynamic cell(d) Static cellThe question was asked during an internship interview.My question is from Random Access Memory in section Memory Devices of Digital Circuits

Answer»

Right answer is (b) Memory cell

For explanation I would say: DRAM uses of integrated MOS capacitors as memory cell INSTEAD of a flip-flop. The advantage of this cell is that it allows very large memory arrays to be constructed on a CHIP at a lower COST per bit than in STATIC MEMORIES.

87.

Most modern operating systems employ a method of extending RAM capacity, known as __________(a) Magnetic memory(b) Virtual memory(c) Storage memory(d) Static memoryThe question was posed to me in unit test.My question comes from Random Access Memory topic in chapter Memory Devices of Digital Circuits

Answer»

The correct choice is (b) VIRTUAL memory

The explanation: Most modern OPERATING systems EMPLOY a METHOD of extending RAM capacity, known as virtual memory. Virtual memory is SEEN as part of main memory but is actually a secondary memory.

88.

The memory size of DRAM is ____________(a) 1 to 100 MB(b) 512 to 1024 MB(c) 64 to 512 MB(d) 16 to 256 MBThe question was posed to me during an internship interview.Origin of the question is Random Access Memory in chapter Memory Devices of Digital Circuits

Answer»

Right answer is (d) 16 to 256 MB

The best I can explain: The DYNAMIC Random Access Memory is the LOWEST cost, highest density random access memory available. Nowadays, computers use DRAM for MAIN memory. However, it’s access TIME is more compared to SRAM. The memory size of DRAM lies between 16 to 256 MB.

89.

Dynamic RAM is more preferable than static RAM, why?(a) DRAM is of the lowest cost, lowest density(b) DRAM is of the highest cost, reduced size(c) DRAM is of the lowest cost, highest density(d) DRAM is more flexible and lowest storage capacityI got this question during an interview.I need to ask this question from Random Access Memory topic in section Memory Devices of Digital Circuits

Answer»

Correct answer is (c) DRAM is of the lowest cost, highest density

For EXPLANATION: The Dynamic Random ACCESS Memory is the lowest cost, highest density random access memory available. Nowadays, computers use DRAM for main memory. However, it’s access TIME is more compared to SRAM.

90.

In TMS 4016, the data in/data out are ______________(a) Unidirectional(b) Parallel(c) Serial(d) BidirectionalThis question was addressed to me in class test.This interesting question is from Random Access Memory in portion Memory Devices of Digital Circuits

Answer» CORRECT CHOICE is (d) Bidirectional

The EXPLANATION is: In TMS 4016, the data in/data out are bidirectional TERMINAL. It means that the input/output can be transmitted or received through the same terminal.
91.

What types of arrangements a TMS 4016 has?(a) 1024 * 4(b) 1024 * 8(c) 2048 * 4(d) 2048 * 8This question was addressed to me during an online exam.The query is from Random Access Memory topic in section Memory Devices of Digital Circuits

Answer»

Correct ANSWER is (d) 2048 * 8

Explanation: The IC TMS 4016 is a 2KB static MOS RAM. There are ELEVEN address inputs available to select the 2014 locations.

Therefore, ARRANGEMENTS in TMS 4016 = 2048 * 8 = 2KB.

92.

How many address inputs are available in TMS 4016?(a) 10(b) 9(c) 12(d) 11This question was posed to me during an online exam.This question is from Random Access Memory in chapter Memory Devices of Digital Circuits

Answer»

Right choice is (d) 11

The best I can explain: The IC TMS 4016 is a 2KB static MOS RAM. There are ELEVEN address inputs available to SELECT the 2014 locations.

93.

Which of the following IC implements the static MOS RAM?(a) TMS 4015(b) TMS 4014(c) TMS 4016(d) TMS 2114I had been asked this question in my homework.I'd like to ask this question from Random Access Memory topic in section Memory Devices of Digital Circuits

Answer»

Right CHOICE is (c) TMS 4016

To explain I would say: The IC TMS 4016 is a 2KB static MOS RAM. There are eleven ADDRESS INPUTS available to select the 2014 LOCATIONS.

94.

Which one of the following IC is of 4KB?(a) IC 7488(b) IC 7489(c) IC 7487(d) IC 2114I had been asked this question in semester exam.My question comes from Random Access Memory in section Memory Devices of Digital Circuits

Answer»

Correct ANSWER is (d) IC 2114

For explanation: IC 2114 is of 4KB and it is a STATIC RAM. Both static and dynamic RAM are considered volatile, as their state is lost or reset when power is REMOVED from the SYSTEM.

95.

The first practical form of Random Access Memory (RAM) was the ____________(a) Cathode tube(b) Data tube(c) Memory tube(d) Select tubeI had been asked this question in homework.Question is from Random Access Memory in division Memory Devices of Digital Circuits

Answer»

Correct option is (c) Memory tube

For explanation: DATA can be written into the memory via the data INPUTS by supplying an address to the SELECT inputs and HOLDING both the memory enable and write enable LOW since it’s an active-low PIN.

96.

Magnetic-core memory was invented in ____________(a) 1946(b) 1948(c) 1947(d) 1945The question was posed to me in class test.My question is taken from Random Access Memory topic in chapter Memory Devices of Digital Circuits

Answer»

Correct option is (c) 1947

Explanation: Magnetic-core memory was INVENTED in 1947 and developed up until the mid-1970s. It became a WIDESPREAD form of random-access memory, relying on an array of magnetized RINGS. RAM is a volatile memory, THEREFORE it stores data as long as power is on. RAM is also known as RWM (i.e. Read Write Memory).

97.

Which of the following RAM is volatile in nature?(a) SRAM(b) DRAM(c) EEPROM(d) Both SRAM and DRAMThe question was asked during an internship interview.My question is taken from Random Access Memory topic in chapter Memory Devices of Digital Circuits

Answer»

Right option is (d) Both SRAM and DRAM

For explanation: RAM is a volatile memory, therefore it STORES data as long as power is on. RAM is also known as RWM (i.e. Read WRITE Memory). Both STATIC and dynamic RAM are considered volatile, as their state is LOST or RESET when power is removed from the system.

98.

Data is written in IC 7489 through ____________(a) Chip select(b) Enable(c) Data input(d) Memory enableThe question was asked by my school teacher while I was bunking the class.I would like to ask this question from Random Access Memory topic in chapter Memory Devices of Digital Circuits

Answer» CORRECT CHOICE is (c) Data input

Easy explanation: Data can be written into the memory via the data inputs by supplying an address to the SELECT inputs and holding both the memory ENABLE and write enable LOW.
99.

IC 7489 is of ____________(a) 32 bit(b) 64 bit(c) 512 bit(d) 1024 bitThe question was posed to me by my college director while I was bunking the class.Asked question is from Random Access Memory topic in division Memory Devices of Digital Circuits

Answer»

Correct ANSWER is (B) 64 bit

Easiest EXPLANATION: The arrangement of IC 7489 is 16 * 4 = 64 bits. Thus, it has 16 COLUMNS and 4 rows.

100.

The flip-flop in static memory cell can be constructed using ____________(a) Capacitor or MOSFET(b) FET or JFET(c) Capacitor or BJT(d) BJT or MOSFETI have been asked this question in semester exam.The origin of the question is Random Access Memory in portion Memory Devices of Digital Circuits

Answer»

Correct OPTION is (d) BJT or MOSFET

Easy explanation: The flip-flop in the static MEMORY cell can be constructed USING Bipolar Junction Transistor (BJT) and MOSFETs because of it’s storing capability. Also, it’s ACCESS TIME is less and it is faster in operation.