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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Read the following extract and answer the question given below With the onset of winter the picturesque nalaban bird sancturary inside the chilika lake is agog with the presence of thousands of migratroy birds from faraway siberia itraq and central europe The birds arrice at their iwngter abode inside the bord sancturary which is spreasd over 15.5 sq km to stay fr five months till monosoon sets in this year the migration of winter bords has begun tow weeks ahead due to disturbances nad sacricty of food in their navtive places The bords have taken sheltr in artifical mounds inside the sancturary lake the second largest in the workd has increased over the year due to the conductive atomospher prevaling there A survey conducted by the chilika wildlife division has revealed that the number of migratory birds arriving at the lake has increased to over two million Many rare birds like the smew duck mallard nakta marbled tela and goliath heron have also been spotted last year application of pesticides and chemical in the fields and loss of natural habitat affect bird mirgration birds and animals have a relation ship and their harmonius presence is benefical for the continuity of a santuary Rewrite the following sentences in the ways instructed The birds have taken shelter in artifical mounds |
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Answer» (i) where the birds have taken shelter (ii) The bird sancturary provides winter abode to the birds when they arrive (iii) They have spotted the rare birds like smew duck mallard nakta etc |
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| 2. |
Reading skill, Grammar , Vocabulary , Note making and summary Read the following extract and answer the question given below Like any other migrant in serach of new apportunites I came to meet you alone the fearsome monsoon had just broken grey clouds were hanging low over the arabian sea buffeted by sheets of rain unnerved by the aggressive winds i stood treambling outside the imposing RBI building today as I bid adieu I explore again the internalites and externalites of memorey the gothic the fort area the impossible sophistication of NCPA where i enjoyed so many theater permormances the nehru center with its classical music concerts the old lady of boribunder the sweep of tall skyscrapers and wide roads fringed by plam trees which bend with the wind teaching the narrow fourth seat on the local valiantly fought for triumphantly acquired the jahangir alrt gallery the stae bank of india building and the canteen close by which offered affordable are the amazing street fare bheluri and vadapav the joy of reading bombay times with its and just when a book was longingly but firmly put down from nowhere mr shanbagh would materilaize magically at one elbow with a special price not to forget the joys of traveling the book lined pavements at foutains where one could watch the word go by How is the witer interest in art and culture revelated in the extract ? |
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Answer» (i) why did you chose this nobel field (ii) how long have you been in this field (iii) what hardships did you face during pursuit of your novel work ? (iv) tell us something about your good and bad experience (v) how do your balance your personal life along with your work life (vi) which is the most meoable incident a social acitivist ? (vii) What kind of supports you gets from the government (viii) what drives your inspiration towards uyour work (ix) if your wourld want to name a few people who supported you throught thick and thin who would they be k(x) what is your message for the students of this college |
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| 3. |
Read the following extract and answeer the question given below Once upon a time the animals decide they must do something heroic to meet the probledms of a new world so they organized a school they adopted an activity curriculum consisting of running climbing swimming and flying to make it easier to adminsiter the curriculum all the animalas took all the subject The duck was excellent in swimming in fact better than his instructor but he made only passing grades in flying and was very poor in running since he was slow in running he had to stay after schoold and slso drop swiimming in order to proctice running this was kept up unitil his webbesd feet were badly worn and he ewas only average in swimming but average was acceptabe in school sonobody worried about that except the duck The rabbit started at hte top of the class in running but had a nervous breakdwon because of so much make up work in swimming The squirrel was excellent in climbig until he developed frustrartion in the flying class where his techer made him start from the ground up instead of the treetop dwon he also developed a chalie horse from overxertion and then got a c in clombing and D in running The eagle was a problem child and was disciplined severely in the climbing class he beat all the other s to the top of the tree but insisted on suing his own ways to get there Why was the squirrel frustrated ? |
| Answer» The squirrel was frustreate in the flying class as his teacher made him start from the ground up instead of the freelop down | |
| 4. |
Read the following extract and answeer the question given below Once upon a time the animals decide they must do something heroic to meet the probledms of a new world so they organized a school they adopted an activity curriculum consisting of running climbing swimming and flying to make it easier to adminsiter the curriculum all the animalas took all the subject The duck was excellent in swimming in fact better than his instructor but he made only passing grades in flying and was very poor in running since he was slow in running he had to stay after schoold and slso drop swiimming in order to proctice running this was kept up unitil his webbesd feet were badly worn and he ewas only average in swimming but average was acceptabe in school sonobody worried about that except the duck The rabbit started at hte top of the class in running but had a nervous breakdwon because of so much make up work in swimming The squirrel was excellent in climbig until he developed frustrartion in the flying class where his techer made him start from the ground up instead of the treetop dwon he also developed a chalie horse from overxertion and then got a c in clombing and D in running The eagle was a problem child and was disciplined severely in the climbing class he beat all the other s to the top of the tree but insisted on suing his own ways to get there Name four student of the animals school and their specilaties in one word each |
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Answer» Duck - swimming Rabbit - Running Squirrel - climbing Eagle - flying |
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| 5. |
Read the following extract and answeer the question given below Once upon a time the animals decide they must do something heroic to meet the probledms of a new world so they organized a school they adopted an activity curriculum consisting of running climbing swimming and flying to make it easier to adminsiter the curriculum all the animalas took all the subject The duck was excellent in swimming in fact better than his instructor but he made only passing grades in flying and was very poor in running since he was slow in running he had to stay after schoold and slso drop swiimming in order to proctice running this was kept up unitil his webbesd feet were badly worn and he ewas only average in swimming but average was acceptabe in school sonobody worried about that except the duck The rabbit started at hte top of the class in running but had a nervous breakdwon because of so much make up work in swimming The squirrel was excellent in climbig until he developed frustrartion in the flying class where his techer made him start from the ground up instead of the treetop dwon he also developed a chalie horse from overxertion and then got a c in clombing and D in running The eagle was a problem child and was disciplined severely in the climbing class he beat all the other s to the top of the tree but insisted on suing his own ways to get there For what purpose did the animals start a schoold |
| Answer» Animals had organized a school to meet the problems of a new world | |
| 6. |
Draw ________map of ________world |
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Answer» (i) Draw a map of the world (ii) In a meeting the physical teacher decided to spend two hours in the play ground for warm up activites (iii) The boys were asked by the tutor to sit on the benches as he had something interesting to tell them |
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| 7. |
What is the position of iron (Z=26) in periodic table? |
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Answer» Iron `(Z = 26)` Electronic configuration : `1s^(2), 2s^(2), 2p^(6), 3s^(2), 3p^(6), 4s^(2), 3d^(6)`. It is a d-block element lies in the fourth period and eighth group in periodic table. |
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| 8. |
Define the following: (a) Cationic detergents ltBrgt (b) Broad spectrum antibiotics (c) Tranquilizers |
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Answer» (a) Cationic detergents are quaternary ammonium salts of amines with acetates, chlorides or bromide as anions. Examples : Cetyl trimethyl ammonium chloride `[(" "CH_(3)),(" |"),(CH_(3)-(CH_(2))_(15)-N-CH_(3)),(" |"),(" "CH_(3))]^(+) Br^(-)` (b) Tranquillizers : The chemical substance used for the treatment of stress, fatigue, mild and severe mental disease are called tranquillizers. Examples : Iproniazid and phenelzine. |
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| 9. |
Select and write the most appropriate answer from the given alternatives for each sub-question : What is natural rubber?A. Cis-1, 4-polyisopreneB. NeopreneC. Trans-1, 4-polyisopreneD. Butyl rubber |
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Answer» Correct Answer - A cis-1, 4-Polyisoprene |
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| 10. |
The resistance of a conductivity cell filled with `0.1 M KCl` solution is `100 Omega`. If `R` of the same cell when filled with `0.02 M KCl` solution is `520 Omega`, calculate the conductivity and molar conductivity of `0.02 M KCl` solution. The conductivity of `0.1 M KCl `solution is `1.29 S m^(-1)`. |
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Answer» Step I : Let us first calculate the cell constant, Cell constant, `(G^(**))=` Conductivity `(K) xx` Resistance (R) Resistance of 0.1 M KCl solution `=100 Omega` Conductivity of 0.1 M KCl solution `=1.29 Sm^(-1)` Cell constant `=1.29 (Sm^(-1))xx100 Omega` `=129 m^(-1)` `=1.29 cm^(-1)` Step II : Calculation of conductivity of 0.02 M KCl solution Resistance of solution `=520 Omega` Cell constant `(G^(**))=1.29 cm^(-1)` Conductivity, `kappa=("Cell constant")/("Resistance")` `=(1.29 cm^(-1))/(520 Omega)` `=0.248xx10^(-2) S cm^(-1)` Step III : Calculation of molar conductivity `lambda_(m)=(1000xx kappa)/C` `C=0.02 M, kappa =0.248xx10^(-2) S cm^(-1)` `lambda_(m)=(1000xx0.248xx10^(-2))/(0.02)` `=124 S cm^(2) mol^(-1)` |
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| 11. |
Ammonia and oxygen react at high temperature as: `4NH_(3) (g) + 5O_(2)(g) rarr 4NO(g) + 6H_(2)O (g)` In an experiment, the rate of formation of `NO` is `3.6 xx 10^(-3) Ms^(-1)`. Calculate (a) the rate of disappearance of ammonia and (b) the rate of formation of water. |
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Answer» For the reaction `4NH_(3)(g)+5O_(2) (g) rarr 4NO(g)+6H_(2)O(g)` Rate `=-1/4 (d[NH_(3)])/(dt)` `=1/5 (d[O_(2)])/(dt)=1/4 (d[NO])/(dt)` `=1/6 (d[H_(2)O])/(dt)` (i) Rate of disappearance of ammonia Rate of disappearance of `NH_(3)` = Rate of formation of NO `=3.6xx10^(-3)` mol `L^(-1) S^(-1)` (ii) Rate of formation of water Rate of formation of `H_(2)O=(d[H_(2)O])/(dt)` From rate, equation, `1/6 (d[H_(2)O)])/(dt)=1/4 (d[NO])/(dt)` `:. (d[H_(2)O])/(dt)=6/4 xx3.6 xx10^(-3)` `=5.4xx10^(-3)` mol `L^(-1) S^(-1)` |
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| 12. |
Select and write the most appropriate answer from the given alternatives for each sub-question: The hybridisation of phosphorus in phosphorus pentachloride is :A. `dsp^(3)`B. `sp^(3) d`C. `d^(2)sp^(3)`D. `sp^(3)d^(2)` |
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Answer» Correct Answer - B In `PCl_(5)`, phosphorus undergoes `sp^(3)d` hybridization and has trigonal bipyramidal geometry. |
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| 13. |
Select and write the most appropriate answer from the given alternatives for each sub-question: The rate constant for a first order reaction is `100 S^(-1)`. The time required for completion of 50% of reaction is :A. 0.0693 millisecondB. 0.693 millisecondC. 6.93 millisecondD. 69.3 millisecond |
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Answer» Correct Answer - C 6.93 milliseconds We known `t_(1//2)=0.693/k` Here `k=100 s^(-1)` `t_(1//2)=0.693/100=0.00693 s` or `6.93` millisecond. |
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| 14. |
Read the following headlines of the news items and write the dateline itro and a short continuing paragraph Honest auto driver felicitated |
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Answer» Honest auto driver Felicitated Pune august 28 20xx honest auto drivers were elecitated by the local police officals at a small function at the local police headquarter the mayor of the city was also present at the function The S.P of cirime branch told the press reporter that lady visitor had hired and auto rickshaw from mumbai central railway station to the taj hotel and while leaving the richkshaw she forgot her phone and a baog of valuable in the auto a little later the lady lso came to the same station to register a compliant agianst the lost items the driver upon reconginzing the lady immediately handed over the things tho her the lady thanked the aurto driver for his honesty and sincerity |
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| 15. |
Select and write the most appropriate answer from the given alternatives in each of the following : If `A^(-1) = 1/3 {:((1,4,-2),(-2,-5,4),(1,-2,1)):} and |A| = 3`, then (adj A) = …A. `(1)/(9)[{:(1,4,-2),(-2,-5,4),(1,-2,1):}]`B. `[{:(1,2,1),(4,-5,-2),(-2,4,4):}]`C. `[{:(1,4,-2),(-2,-5,4),(1,-2,1):}]`D. `[{:(-1,-4,2),(2,5,-4),(1,-2,1):}]` |
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Answer» Correct Answer - C Given, `A^(-1)=(1)/(3)[{:(1,4,-2),(-2,-5,4),(1,-2,1):}]and|A|=3` We know that , `A^(-1)=(1)/(|A|)(adj.A)` `therefore.A=|A|*A^(-1)` `=(3)/(3)[{:(1,4,-2),(-2,-5,4),(1,-2,1):}]` `=[{:(1,4,-2),(-2,-5,4),(1,-2,1):}]` Hence ,the correct answer from the given alternative is |
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| 16. |
What is criss-cross inheritance ? |
| Answer» X-linked recessive disorders like color blindness diseases is inherited from father to grandson through his daughter. This inheritance is called crisscross inheritance. | |
| 17. |
Trichoderma konigi is a source of …………… enzyme.A. invertaseB. lipaseC. pectinaseD. cellulase |
| Answer» Correct Answer - A::C::D | |
| 18. |
Find the inverse of the matrix `A=[{:(1,3,3),(1,4,3),(1,3,4):}]` by using column transformations. |
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Answer» The given matrix is `A=[{:(1,3,3),(1,4,3),(1,3,4):}]` We know that, A = AI `[{:(1,3,3),(1,4,3),(1,3,4):}]=A[{:(1,0,0),(0,1,0),(0,0,1):}]` Applying `C_(2)toC_(2)-3C_(1),C_(3)toC_(3)-3C_(1),` we ,get `[{:(1,0,0),(1,1,0),(1,0,1):}]=A[{:(1,-3,-3),(0,1,0),(0,0,1):}]` Applying `C_(1)toC_(1)-C_(2)`, we get `[{:(1,0,0),(0,1,0),(1,0,1):}]=A[{:(4,-3,-3),(-1,1,0),(0,0,1):}]` Applying `C_(1)toC_(1)-C_(3)`, we get `[{:(1,0,0),(0,1,0),(0,0,1):}]=A[{:(7,-3,-3),(-1,1,0),(-1,0,1):}]` `A^(-1)=[{:(7,-3,-3),(-1,1,0),(-1,0,1):}]` |
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| 19. |
In any `triangle ABC`, prove that than `((A-B)/(2))=((a-b)/(a+b))cot .(C)/(2)`. |
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Answer» We know that, `(a)/(sinA)=(b)/(sinB)=K` `a=KsinA,b=KsinB` `(a-b)/(a+b)=(KsinA-Ksinb)/(KsinA+KsinB)` `=(sinA-sinB)/(sinA+sinB)` `=(2"cos"(A+B)/(2)"sin"(A-B)/(2))/(2"sin"(A+B)/(2)"cos"(A-B)/(2))` `(a-b)/(a+b)=("tan"(A-B)/(2))/("tan"(A+B)/(2))` `="cot"(A+B)/(2)"tan"(A-B)/(2)` We know that, `(A+B+C)/(2)=90^(@),(A+B)/(2)=90^(@)-(C)/(2)` `cot((A+B)/(2))=cot(90^(@)-(C)/(2))` `="tan"(C)/(2)` `(a-b)/(a+b)="tan"(C)/(2)"tan"(A-B)/(2)` `"tan"(A-B)/(2)=((a-b)/(a+b))"cot"(C)/(2)` |
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| 20. |
Discuss the continuity of the following functions at the points shown against them : `{:(f(x)=(1-sinx)/(((pi)/(2)-x)^(2))",", "for"x ne(pi)/(2)),(=3",","for"x=(pi)/(2)):}}at x=(pi)/(2)*` |
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Answer» R.H.L. `=lim_(hto0)f((pi)/(2)+h)=lim_(hto0)(1-sin((pi)/(2)+h))/(((pi)/(2)-(pi)/(2)-h)^(2))` `=lim_(hto0)(1-cosh)/((-h)^(2))` `=lim_(hto0)(1-1+2sin^(2)((h)/(2)))/((-h)^(2))` `=lim_(hto0)(2sin^(2)((h)/(2)))/(h^(2))` `=lim_(hto0)(2sin^(2)((h)/(2)))/(4((h)/(2))^(2))` `=(1)/(2)lim_(hto0)(("sin"(h)/(2))/((h)/(2)))^(2)` `=(1)/(2)xx1=(1)/(2)` L.H.L. `=lim_(hto0)f((pi)/(2)-h)` `lim_(hto0)(1-sin((pi)/(2)-h))/(((pi)/(2)-(pi)/(2)+h)^(2))` `=lim_(hto0)(1-cosh)/(h^(2))` `=(1)/(2)` `=(1)/(2)ne3` R.H.L=L.H.L `ne((pi)/(2))` So,function is discontinuous at `x=(pi)/(2)`. |
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| 21. |
Find k ,such that the function `P(x)={{:(k({:(4),(x):}),,x=0","1","2","3","4,kgt0),(0,"otherwise."):}` is a probability mass function (p.m.f.) |
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Answer» Given , `P(x){{:(K((4)/(x))","x=0","1","2","3","4,kgt0,),(0" "", " "otherwise",):}` `thereforeP[X=0]=K({:(4),(0):})=Kxx.^(4)C_(0)=K(1)=K` `P[X=1]=K({:(4),(1):})=Kxx.^(4)C_(1)=K(4)=4K` `P[X=2]=K({:(4),(2):})=Kxx.^(4)C_(2)` `=K((4xx3)/(1xx2))=6K` `P[X=3]=K({:(4),(3):})=Kxx.^(4)C_(3)=K(4)=4K` `P[X=4]=K({:(4),(4):})=Kxx.^(4)C_(4)=K(1)=K` Since `P[X=x]` is p . m .f., `sum_(x=0)^(4)P[X=x]=1` `thereforeP[X=0]+P[X=1]+P[X=2]+P[X=3]+P[X=4]=1` `thereforeK+4K+6K+4K+K=1` `therefore16K=1` `thereforeK=(1)/(16)` |
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| 22. |
If `I=int_(-pi//2)^(pi//2)(sin^(4)x)/(sin^(4)x+cos^(4)x)dx,` then the value of I is |
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Answer» Correct Answer - C Let `f(x)=(sin^(4)x)/(sin^(4)x+cos^(4)x)` `f(-x)=(sin^(4)(-x))/(sin^(4)(-x)+cos^(4)(-x))` `=(sin^(4)(x))/(sin^(4)(x)+cos^(4)(x))=f(x)` `therefore` f is an even function. `thereforeint_(-pi//2)^(pi//2)(sin^(4)x)/(sin^(4)x+cos^(4)x)dx` `=2int_(0)^(pi//2)(sin^(4)x)/(sin^(4)x+cos^(4)x).dx` `thereforeI=2int_(0)^(pi//2)(sin^(4)x)/(sin^(4)x+cos^(4)x)dx` ... (i) By using the property, `int_(0)^(a)f(x)*dx=int_(0)^(a)f(a-x)*dx`, we get `I=2int_(0)^(pi//2)(sin^(4)(pi//2-x))/(sin^(4)(pi//2-x)+cos^(4)(pi//2)-x)dx` `=2int_(0)^(pi//2)(cos^(4)x)/(cos^(4)x+sin^(4)x)dx` . . . (ii) Adding equation (i) and(ii) ,we get `=2int_(0)^(pi//2)(sin^(4)x+cos^(4)x)/(sin^(4)x+cos^(4)x)dx` `I=int_(0)^(pi//2)dx` `I=[x]_(0)^(pi//2)=[(pi)/(2)-0]=(pi)/(2)` Hence ,the correct answer from the given alternative is |
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| 23. |
If `tan^(-1)((x-1)/(x-2))+cot^(-1)((x+2)/(x+1))=(pi)/(4)` , find x. |
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Answer» Given , `"tan"^(-1)(x-1)/(x-2)+"cot"^(-1)(x+2)/(x+1)=(pi)/(4)` `"tan"^(-1)(x-1)/(x-2)+"tan"^(-1)(x+1)/(x+2)=(pi)/(4)` `"tan"^(-1)((x-1)/(x-2)+(x+1)/(x+2))/(1(x-1)/(x-2)xx(x+1)/(x+2))=(pi)/(4)` `((x-1)(x+2)+(x+1)(x-2))/(((x-2)(x+2))/(((x^(2)-4)-(x^(2)-1))/((x-2)(x+2))))="tan"(pi)/(4)` `(x^(2)+2x-x-2+x^(2)-2x+x-2)/(x^(2)-4-x^(2)+1)=1` `(2x^(2)-4)/(-3)=1` `2x^(2)-4=-3` `2x^(2)=1` `x^(2)=(1)/(2)` `x=+-(1)/(sqrt(2))` |
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| 24. |
If `y=sec^(-1)((sqrt(x-1))/(x+sqrt(x)))+sin^(-1)((x+sqrt(x))/(sqrt(x-1)))`, then `(dy)/(dx)=` ……………A. xB. `(1)/(x)`C. 1D. 0 |
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Answer» Correct Answer - C Given , `y=sec^(-1)((sqrt(x)-1)/(x+sqrt(x)))+sin^(-1)((x+sqrt(x))/(sqrt(x)-1))` `y=cos^(-1)((x+sqrt(x))/(sqrt(x-1)))+sin^(-1)((x+sqrt(x))/(sqrt(x-1)))` `y=(pi)/(2)[becausesin^(-1)x+cos^(-1)x=(pi)/(2)]` `therefore(dy)/(dx)=0` Hence the correct answer from the given alternative is . |
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| 25. |
Solve the different equation `y-x(dy)/(dx)=0`. |
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Answer» The given differential equation is , `y-x(dy)/(dx)=0` `y=x(dy)/(dx)` `ydx=xdy` `int(dx)/(x)=int(dy)/(y)` `logx+logc=logy` where c is a constant. log xc = log y y= xc |
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| 26. |
The road in front of your collenge has become accident prone write a letter to the editor of a newpaper explaining in it you problem and also suggest some soution |
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Answer» Amit kumar wagmare 12-A vinayak chowk pune The Editor The Times of India Mumbai sir , I am amit kumar waghamre student of SNDT college pune I would like to draw your attention to the road in my college that has become accident prone in the recent times manholes and broken roads make it dangeroius for all road users problem s it stheat hte raod should be reviewed by the local administrator on timely basis so as to avoid mishaps It is time to realize that the gravity of the situation is serious as it puts a lot of lives in danger hoping to see immediate relied with reagards to making the roads proper thanking you your trully amit kumar waghmore |
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| 27. |
The solution of the differential equation `(dy)/(dx)=secx-ytanx` is :A. `ysecx=tanx+c`B. `ysecx+tanx=c`C. `secx=ytanx+c`D. `secx+ytanx=c` |
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Answer» The given differential equation is , `(dy)/(dx)=secx-ytanx` `therefore(dy)/(dx)+ytanx=secx` This is the linear differential equation of the form `(dy)/(dx)+P*y=Q` where `P=tanxandQ =secx` `thereforeI.F=eintp*dx=einttanx*dxelogsec(x|)=secx` Now , `y*(I.F.)=int(I.F.)Q*dx` `y*secx=intsec^(2)x*dx` `y*secx=tanx+c` Hence ,the correct answer from the given alternative is (a). |
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| 28. |
Evaluate : `int(1)/(xlogxlog(logx))dx` |
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Answer» `I=int(1)/(xlogxlog(logx))dx` `log(logx)=t` `(1)/(xlogx)dx=dt` `I=int(dt)/(t)logt+c` `=log[log(logx)]+c` |
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| 29. |
Select and write the most appropriate answer from the given alternatives in each of the following sub-questions : If `p^^q=F,ptoq=F`, then the truth value of p and q is ………….A. T,TB. T,FC. F,TD. F,F |
| Answer» Correct Answer - B | |
| 30. |
State : (a) Second law of thermodynamics in terms of entropy. (b) Third law of the thermodynamics. |
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Answer» (a) Sencond law of thermodynamics in terms of entropy : The entropy of the universe always increases in the course of every spontaneous (natural) change. (b) Third lae of thermodynamics : The entropy of a perfectly crystalline substance is zero at zero Kelvin. |
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| 31. |
The equation of a progressive wave is `y=7sin(4t-0.02x)`, where `x` and `y` are in cm time in second. The maximum velocity of a particle is……………A. `28cm//s`B. `32cm//s`C. `49cm//s`D. `112cm//s` |
| Answer» Correct Answer - `(a)` `28cm//s` | |
| 32. |
Light of a certain wavelength has a wave number `barv` in vacum. Its wave number in a medium of refractive index n isA. `(n)/(v)`B. `(1)/(nvecn)`C. `(vecv)/(n)`D. `n vecv` |
| Answer» Correct Answer - `(d) nvecv` | |
| 33. |
An iron rod of area ofcross-section `0.1m^(2)` is subjected to a magnetising field of `1000A//m`. Calculate the magnetic permeability of the iron rod. [Magnetic susceotibility of iron `=59.9`, magneitc permeability of vaccum `=4pixx10^(-7)` S.I. unit] |
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Answer» Given: area of cross-section `(A)=0.1m^(2)` magnetising field `(H)=1000A//m` magnetic susceptibility of iron `(X_(m))` `=5.9` magnetic permeability of vacuum `(mu_(0))=4pixx10^(-7)Wb//A-m` Magnetic permeability `mu` is given by `mu=mu_(0)(1+X-(m))` `=4pixx10^(-7)(1+59.9)` `=4pixx10^(-7)xx60.9` `=765.29xx10^(-7)Wb//A-m` |
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| 34. |
The output of a two input NOR gate is in state 1 when :-A. all inputs are highB. all inputs are lowC. only one of its inputs is highD. onle one of its inputs is low |
| Answer» `(b)` all inputs are low | |
| 35. |
The angle of contact for pure water and clean glass surface isA. acuteB. obtuseC. `90^(@)`D. `0^(@)` |
| Answer» Correct Answer - `(d) 0^(@)` | |
| 36. |
A coil of `100` turns, each of area `0.02m^(2)` is kept in a uniform field of induction `3.5xx10^(-5)`T. If the coil rotates with a speed of `6000r.p.m.` about an axis in the plane of the coil and perpendicular to the magnetic induction, calculate peak value of e.m.f. indcued in the coil |
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Answer» Given: `n=100`, `A=0.02m^(2)`, `B=3.5xx10^(-5)T`, `f=6000 r.p.m=(6000)/(60)r.p.s. e_(max)=?` Induced e.m.f. in a rotating coil, `e=2pifBnAsinomegat` `e_(max)=2pifBnA` `=2pi(6000)/(60)xx3.5xx10^(-5)xx100xx0.02` `=2xx(22)/(7)xx3.5xx2xx10^(-3)` `=0.044` volt. |
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| 37. |
In biprism experiment two interfering waves are produced due to division ofA. amplitudeB. wavefrontC. amplitude and wavefrontD. neither wavefront nor amplitude |
| Answer» Correct Answer - `(b)` wavefront | |
| 38. |
A parallel beam of monochromatic light is incident on a glass slab at an angle of incidence `60^(@)`. Find the ratio of width of the beam in the glass to that in the air if refractive index of glass is `3//2`. |
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Answer» Given `i=60^(@)`, `mu_(g)=(3)/(2)` Let, `d_(g)=`Width of beam in glass slab, and `d_(a)=` Width of beam in air We know that, `._(a)mu_(g)=(sini)/(sinr)` `(3)/(2)=(sin60^(@))/(sinr)` `impliessinr=(sqrt(3)xx2)/(2xx3)` `:.sinr=(1)/(sqrt(3))` `r=sin^(-1)(0.5773)` `=35.26^(@)` `(d_(s))/(d_(a))=(cosr)/(cosi)` `=(cos35.26^(@))/(cos60^(@))` `=(0.8164)/(0.5)=1.633` `(d_(s))/(d_(a))=(16)/(10)=(8)/(5)` `:.` Ratio of the width of beam `=8 : 5`. |
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| 39. |
In a biprism experiment, when a convex lens was placed between the biprism and eyepiece at a distance of `30cm` from the slit, the virtual images of the slits are found to be separated by `7mm`. If the distance between the slit and biprism is `10cm` and between the biprism and eyepiece is `80cm`, find the linear magnification of the image. |
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Answer» From the magnification formula `(d_(1))/(d)=(v)/(u)` `(v)/(u)=(60)/(30)` `(v)/(u)=2` Linear magnification `=2` |
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| 40. |
Crippling disease is caused due to poisoning of ………………A. ArsenicB. LeadC. MercuryD. Selenium |
| Answer» Correct Answer - ( c) Mercury | |
| 41. |
Give reason: Emasculation is done in a flower which is selected as female parent. |
| Answer» Emasculation is a removal of male part of flower i.e., stamens before anthesis (formation of pollen grains). It is done in flower selected as female parent to avoid self pollination. | |
| 42. |
What is the role of microbes in sewage treatment plant? |
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Answer» (iv) Role of microbes in sewage treatment: 1) Waste water generated in large quantities is called sewage. 2) Sewage contains organic matter, human excreta, domestic waste and microbes. 3) It can not be drained directly in water bodies like rivers without prior treatment in sewage treatment plant. 4) Primary treatment is a physical process using filteration and sedimentation. 5) Secondary treatment is also known as biological treatment . Effluent and Priamry treatment is passed in aeration tanks along with air. Aerobic organisms grow in this process and decomposes organic matter. It reduces biological oxygen demand of effluent. (6) Tertiary treatment occurs after Secondary treatment. In this process anaerobic microbes grow and digest bacteria and fungi. After tertiary treatment effluent is released in water bodies. |
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| 43. |
………………. Enzymes are used as biological scissors in r-DNA technology.A. Restriction endonucleasesB. DNA ligasesC. DNA polymerasesD. Reverse transcriptases |
| Answer» Correct Answer - A::C::D | |
| 44. |
Define parthenocarpy. |
| Answer» Parthenocarpy: When fruits are formed without fertilisation, this is called Parthenocarpy and the fruits are called Parthenocarpic fruits. These fruits are seedless. Example: banana. | |
| 45. |
Express `-hat(i)-3hat(j)+4hat(k)` as the linear combination of the vectors `2hat(i)+hat(j)-4hat(k)`, `2hat(i)-hat(j)+3hat(k)` and `3hat(i)+hat(j)-2hat(k)`. |
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Answer» Linear combination of vectors are `-hat("i")-3hat(j)+4hat(k)=x(2hat("i")+hat(j)-4hat(k))+y(2hat("i")-hat(j)+3hat(k))+z(3hat("i")+hat(j)-2hat(k))` ...(i) Here x,y,z are constant. `-hat("i")-3hat(j)+4hat(k)=2xhat("i")+xhat(j)-4xhat(k)+2yhat("i")-yhat(j)+3yhat(k)+3zhat("i")+zhat(j)-2zhat(k)` `=hat("i")(2x+2y+3z)+hat(j)(x-y+z)+hat(k)(-4x+3y-2z)` On comparing the coefficient of `hat("i"),hat(j)andhat(k)`, we get `-1=2x+2y+3z` ...(ii) `-3=x-y+z` ...(iii) `4=-4x+3y-2z` ...(iv) By equations (ii) and (iii), `(2x+2y+3z=-1)xx1` `(x-y+z=-3)xx2` Then `{:(2x+2y+3z=-1),(2x-2y+2z=-6),(ul(-" "+" " -" "+)),(" "4y+z=5):}` ...(v) By equations (ii) and (iv), `{:((2x+2y+3z=-1)xx2),((-4x+3y-2z=4)xx1),(4x+4y+6z=-2),(ul(-4x+3y-2z=4)),(" "7y+4z=2):}` ...(vi) By equations (v) and (vi), `{:((4y+z=5)xx4),((7y+4z=2)xx1),(16y+4z=20),(" "7y+4z=2),(ul(-" "-" "-)),(-9y=18),(" "y=-2):}` Put the value of y in equation (v) ,we get `8+z=5` `z=-3` Put the value of y and z in equation (iii) ,we get x-2-3=-3 x=-3+5=2 Put the value of x,y,z in equation (i) ,we get `-hat("i")-3hat(j)+4hat(k)=2(2hat("i")+hat(j)-4hat(k))-2(2hat("i")-hat(j)+3hat(k))` `-3(3hat("i")+hat(j)-2hat(k))` |
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| 46. |
If the points `(1," "1," "p)" "a n d" "(" "3," "0," "1)`be equidistant from the plane ` -> rdot(3 hat i+4 hat j-12 hat k)+13=0`, then find the value ofp. |
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Answer» Distance between the point and the plane is given by, `l_(1)=|{:(veca*vecn-d)/(|n|):}|` ...(i) `veca=hat("i")+hat(j)+hat(k)`, `vecn=3hat("i")+4hat(j)-12hat(k)` `veca*vec(n)=3+4-12=-5` `vecd=-13` From (i) , `=|(-5+13)/(sqrt(9+16+144))|=(8)/(13)` Again, `veca=-3hat("i")+0hat(j)+hat(k)` Them , `l_(2)=|((3hat("i")+0hat(j)+hat(k))*(3hat("i")+4hat(j)-12hat(k))+13)/(sqrt(9+16+144))|` `=|(-9-12+13)/(13)|` `=(8)/(13)` `thereforel_(1)=l_(2)` |
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| 47. |
Urea splitting bacteria are responsible for …………….types of stones.A. calcium oxalateB. calcium phosphateC. calcium carbonateD. struvite |
| Answer» Correct Answer - (d) struvite | |
| 48. |
Direction cosines of the line `(x+2)/(2)=(2y-5)/(3),z=-1` are |
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Answer» The given line is , `(x+2)/(2)=(2y-5)/(3)=(z+1)/(0)` `(x+2)/(2)=(2(y-(5)/(2)))/(3)=(z+1)/(0)` `(x+2)/(2)=(y-(5)/(2))/(3/(2))=(z+1)/(0)` The direction cosines are `(2,(3)/(2),0)` |
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| 49. |
If the equation given by `hxy+10x+6y+4=0` represents a pair of lines, then h is equal to |
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Answer» The given equation is , `kxy+10x+6y+4=0` On comparing the above equation with the general equation, `ax^(2)+2hxy+by^(2)+2gx+2gx+2fy+c=0,`we get, `a=0,b=0,2h=k,2g=10,2f=6,c=4h=k//2,g=5,f=3` `|{:(a,h,g),(h,b,f),(g,f,c):}|=0` `|{:(0,(k)/(2),5),((k)/(2),0,3),(5,3,4):}|=0` `0-(k)/(2)(2k-15)+5((3k)/(2)-0)=0` `-k^(2)+(15k)/(2)+(15k)/(2)=0` `-k^(2)=(-30k)/(2)` k=15 |
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| 50. |
The fundamental frequency of transverse vibration of a stretched string of radius r is proportional toA. `r^(-2)`B. `r^(-1)`C. `r-((1)/(2))`D. `r^(2)` |
| Answer» Correct Answer - `(b)r^(-1)` | |