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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 551. |
How does boric acid polymerise? |
| Answer» Through hydrogen bonding | |
| 552. |
A tetravalent element forms monoxide and disoxide wit oxygen. When air is passed over heated element `(1273 K)`. Producer gas is obtained. Monoxide of the lement is a powerful reducing agent and reduces ferric oxide to iron. The element and write formulas of its monoxide and dioxide. Write chemical equations for the formation of producer a gas and reduction if ferric oxide with the monoxide. |
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Answer» Since producer gas is a mixture of CO and `N_(2)`, therefore , the tetravalent element is carbon and its monoxide and dioxide are CO and `CO_(2)` respectively. `2C(s) + ubrace(O_(2)(g)+4N_(2)(g))_("Air") overset(1273K)rarrubrace(2CO(g)+4N_(2)(g))_("Producer gas")` The monoxide of carbon , is a strong reducing agent and reduces ferric oxide to iron. `Fe_(2)O_(3)(s) + 3CO(g) overset(Delta)rarr 2 Fe(s) + 3O_(2)(g)`. |
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| 553. |
Fluorine does not show positive oxidation states due to the absence ofA. d-orbitalsB. s-orbitalC. p-orbitalsD. none |
| Answer» Correct Answer - A | |
| 554. |
An inert gas atomsA. has one electron in the outermost shellB. has three electrons in the outermost shellC. has half-filled outermost shellD. has a saturated outermost shell |
| Answer» Correct Answer - D | |
| 555. |
The hybridisation of xenon in `XeF_2` isA. `sp^3`B. `sp^2`C. `sp^3d`D. `sp^2 d` |
| Answer» Correct Answer - A | |
| 556. |
Why does `O_(3)` act as a powerful oxidizing agent? |
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Answer» `O_(3)` is an endothermic compound. On heating, it readily decomposes to give dioygen and nascent oxygen. `O_(3) overset("Heat") to O_(2) + O` (nascent oxygen) Since nascent oxygen is very reactive, therefore, `O_(3)` acts as a powerful oxidizing agent. |
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| 557. |
The number of `P-O-P` bonds in cyclic metaphosphoric acid is.A. zeroB. twoC. threeD. four |
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Answer» Correct Answer - C |
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| 558. |
Nitrogen is relatively inactive element becauseA. Its atom has a stable elctronic configurationB. It has low atomic radiusC. Its elctronegative is fairly highD. Dissociation energy of its molecule is fairly high |
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Answer» Correct Answer - D `N=N` bond energy is very high `945 kJ mol^(-1)` |
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| 559. |
`CO_(2)` is iso-structural with :A. `HgCl_(2)`B. `SnCl_(2)`C. `C_(2)H_(2)`D. `NO_(2)`. |
| Answer» Both `HgCl_(2)` and `Cr_(2)H_(2)` are isostructural with carbon dioxide (linear). | |
| 560. |
Out of the following how many oxides are basic: `TiO,Sc_2O_3,Ti_2O_3,VO,V_2O_5,CrO_3,Cr_2O_3,CuO,TiO_2`A. `B_(2)O_(3)`B. `Tl_(2)O`C. `In_(2)O_(3)`D. `Al_(2)O_(3)`. |
| Answer» `Tl_(2)O` and `In_(2)O_(3)` are basic oxides. | |
| 561. |
Asseration: Mineral acids on dissolving in liquid `HF` acts like a base. Reason: Liquid `HF` acts as an acid and posses strong tendency to donate proton.A. If both assertion and reason are true and the reason is the correct explanation of the assertion.B. If both assertion and reason are true and the reason is not correct explanation of the assertion.C. If assertion is true but reason is false.D. If assertion is false but reason is true. |
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Answer» Correct Answer - A `HF+HClrarrH_(2)Cl^(+)+F^(-)` |
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| 562. |
In a familiar classroom demonstration, concentrated `H_(2)SO_(4)` is added to a beaker containing sucrose `(C_(12)H_(22)O_(11))`,to produce a column of carbon. In this reaction, the `H_(2)SO_(4)` is acting primarily as a :A. complexing agentB. dehydration agentC. oxidising agentD. precipating agent |
| Answer» Correct Answer - B | |
| 563. |
When two .........A...... halogen react with each other , interhalogen compounds are formed . Here , A refers toA. sameB. differentC. Either (a) and (b)D. None of these |
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Answer» Correct Answer - B When two different halogens react with each other , interhalogen compounds are formed . |
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| 564. |
An inorganic compound (A) is a Lewis acid an d light yellow in colour. It fumes in moist air. The intensity of fumes further increase when a rod dipped in `NH_(4)OH` is brough near it. The aciedic solution of the compound does not give andy precipitate on passing `H_(2)S` gas. However, it gives a white precipitate on adding `NH_(4)OH` solution in the presence of `NH_(4)Cl` and the white precipitate dissovles on adding `NaOH` in excess. The intensity of fumes increases due to the formation ofA. ammonium hydroxideB. ammonum chlorideC. ammonium sulphateD. excess of HCl vapours |
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Answer» Intensity of fumes increases when `NH_(4)OH` reacts with `AlCl_(3)` due to formation of `NH_(4)Cl` . `AlCl_(3)+3NH_($)OHrarrAl(OH)_(3)+3NH_(4)Cl`. |
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| 565. |
An inorganic compound (A) is a Lewis acid an d light yellow in colour. It fumes in moist air. The intensity of fumes further increase when a rod dipped in `NH_(4)OH` is brough near it. The aciedic solution of the compound does not give andy precipitate on passing `H_(2)S` gas. However, it gives a white precipitate on adding `NH_(4)OH` solution in the presence of `NH_(4)Cl` and the white precipitate dissovles on adding `NaOH` in excess. The solutin formed when white precipitate is dissolved in NaOH is ofA. sodium sulphateB. sodium phosphateC. sodium chlorideD. sodium meta-aluminate. |
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Answer» The white precipitate of `Al(OH)_(3)` dissolves in excess of NaOH due to the formation of sodium metaaluminate. `Al(OH)_(3)+NaOHrarrNaAlO_(2)+2H_(2)O` |
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| 566. |
`AlCl_(3)` on hydrolysis givesA. `Al_(2)O_(3). H_(2)O`B. `Al_(2)O_(3)`C. `Al(OH)_(3)`D. `AlCl_(3).6H_(2)O` |
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Answer» Correct Answer - C `AlCl_(3)+3H_(2)OtoAl(OH)_(3)+3HCl` |
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| 567. |
`AlCl_(3)` on hydrolysis givesA. `Al_(2)O_(3).H_(2)O`B. `Al(OH)_(3)`C. `Al_(2)O_(3)`D. `AlCl_(3).6H_(2)O` |
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Answer» Correct Answer - B `AlCl_(3)+3H_(2)toAl(OH)_(3)+3HCl` |
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| 568. |
The dissolution of `Al(OH)_(3)` by a solution of `NaOH` results in the formation ofA. `[Al(H_(2)O)_(2)(OH)_(4)]^(-)`B. `[Al(H_(2)O)_(4)(OH)]^(2+)`C. `[Al(H_(2)O)_(3)(OH)_(3)]`D. `[Al(H_(2)O)_(6)(OH)_(3)]` |
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Answer» Correct Answer - A `Al(OH)_(3)+OH^(-)to[Al(OH)_(4)^(-)]`. Coordinate number is `6`, thus, it exist as `[Al(H_(2)O)_(2)(OH)_(4)]^(-)` |
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| 569. |
Identify the correct order of acidic strength of `CO_(2),CuO, CaO` and `H_(2)O`.A. `CaO lt CuO lt H_(2)O lt CO_(2)`B. `H_(2)O lt CuO lt CaO lt CO_(2)`C. `CaO lt H_(2)O lt CuO lt CO_(2)`D. `H_(2)O lt CO_(2) lt CaO lt CuO` |
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Answer» Correct Answer - A |
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| 570. |
Nitrogen forms the largest number of oxides as it is capable of forming stable multiple bonds with oxygen. They range of `N_(2)O` (O.S of nitrogen +1) through `NO, N_(2)O_(3),NO_(2),N_(2)O_(4) to N_(2)O_(5)` (O.S of nitrogen +5). Following points are improtant regarding the study of oxides of nitrogen. (a) All oxides of nitrogen expect `N_(2)O_(5)` are endothermic as a large amount of energy is required to dissociate the stable molecule of oxygen and nitrogen. (b) The small electronegativity difference between oxygen and nitrogen make N-O bond easily breakle to give oxygen and hence oxides of nitrogen are said to be better oxidising agents. (c) Expect `N_(2)O_(5)`, all are gases at ordinary temperature. `N_(2)O_(3)` is stable only at lower temperature (253K). (d) Expect `N_(2)O` and NO which are neutal oxides, all are acidic oxides which dissolve in water forming coresponding oxy acids. (e) They are also good example for illustrating the concept of resonance. Which of the following statements is corect for the oxides of nitrogen?A. Dinitrogen trioxide dissolves in potassium hydroxide forming potassium nitrate.B. Aqueuous slution of nitrogen dixide behaves both as a reducing agent and as a oxidising agent.C. Nitrogen oxide is fairly soluble in cold water and turns blue litmus red.D. Nitrogen dioxide is not acidic oxide. |
| Answer» Correct Answer - A | |
| 571. |
Why the elements of the second row (first short period) show a number of difference in properties from other members of their respective families ? |
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Answer» The differences in the properties of the first member of a group from those of the other members are due to (i) The smaller size of the atom. (ii) presence of one inner shell of only two electrons and (iii) absence of d-orbitals |
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| 572. |
When a brown compound of Mn (A) is treated with HCl, it gives a gas (B). The gas (B) taken in excess reacts with `NH_(3)` to give an explosive compound (C). The compouns A, B and areA. `A=MnO_(2),B=Cl_(2),C=NCl_(3)`B. `A=MnO,B=Cl_(2),C=NH_(4)Cl`C. `A=Mn_(3)O_(4),B=Cl_(2),C=NCl_(3)`D. `A=MnO_(3),B=Cl_(2),C=NCl_(2)` |
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Answer» Correct Answer - A `underset((A))(MnO_(2))+4HCl"toMnCl_(2)+underset((B))(Cl_2)+2H_(2)O` `NH_(3)+3underset((B))(Cl_(2))tounderset((C))NCl_(3)+3HCl` |
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| 573. |
Which of the following is a cyclic oxo acid ?A. `H_(4)P_(2)O_(7)`B. `H_(4)P_(2)O_(6)`C. `H_(3)P_(3)O_(9)`D. `H_(5)O_(5)O_(15)` |
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Answer» Correct Answer - C `(HPO_(3))_(3)=H_(3)P_(3)O_(9)` is a six-membered cyclic oxoacid. `(HPO_(3))_(5)=H_(5)P_(5)O_(15)` cannot be regarded as a cyclic oxo acid since ten-membered rings are difficult of form. Therefore, it has a chain structure. |
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| 574. |
Sulphurly chloride `(SO_(2)Cl_(2))` reacts with white phosphorus `(P_(4))` to giveA. `PCl_(5),SO_(2)`B. `PCl_(3),SOCl_(2)`C. `PCl_(5),SO_(2),S_(2)Cl_(2)`D. `OPCl_(3),SO_(2),S_(2)Cl_(2)` |
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Answer» Correct Answer - A Refer to page 11/134 `P_(4)(s)+10SO_(2)Cl_(2)(l)to4)PCl_(5)(s)+10SO_(2)(g)` |
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| 575. |
Which of the following is an interpseudohalogen (pseudohalogen analogues of interhalogen)?A. `HSCN`B. `ICN`C. `BrF_(5)`D. `C_(2)N_(2)` |
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Answer» Correct Answer - B `.F_(2),Cl_(2),Br_(2)` and `I_(2)=` Halogen `. ICl,ICl_(3)`, etc. =Interhalogen `.bar(C)N,bar(S)CN,bar(O)CN`=Pseudohalogen `.ICN`=inter pseudohalogen |
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| 576. |
Bleaching powder is prepared by passing chlorine intoA. `CaO`B. `CaCO_(3)`C. `CaSO_(4)`D. `Ca(OH)_(2)` |
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Answer» Correct Answer - D `Ca(OH)_(2)+Cl_(2)rarrCaPCl_(2)rarrunderset("bleaching powder")(CaOCl_(2))+H_(2)O` |
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| 577. |
When a vapour, at atmosphere pressure was gradually heated from `25^(circ)C` its colour wasa found to deepen at first and then to fade as the temperature was raised above `160^(circ)C`. At `600^(circ)C`, the vapour was almost colourless, but its colour deepended when the pressure was raised at this temperature. The vapour was:A. the bromine.B. a mixture of nitrogen dioxide and dinitrogen tetraoxide.C. pure nitrogen dioxide .D. pure dinitrogen tetraoxide. |
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Answer» Correct Answer - B `underset("Colourless")(N_(2)O_(2)(g))overset(160^circC)hArrunderset(Brown)(2NO_(2))overset(600^circC)hArrunderset(("Colourless"))(2NO_(2)+O_(2))` As the conersion of NO and `O_(2)` is accomained by decrease in number of moles of agases ( from 3 to 2) it is favoured by high pressure. Thus incresing pressure at `600^(circC)` shifts the equilibrium in the backward direction and this leads to the formation of `NO_(2)`- a brown coloured gas. Thus original vapour was `N_(2)O_(2)` or dinitrogen tetraoxde. |
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| 578. |
Which of the following statements about `N_(2)O` is false ?A. A neutral oxide which does not form hyponitrous acid with waterB. An oily liquidC. Used as propellant for whipped ice-cream.D. Used as an anaesthetic. |
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Answer» Correct Answer - B Actually `N_(2)O` is a gas . |
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| 579. |
What is//are not true abut phosphine `(PH_(3))`?A. It turns red litmus blue.B. It reacts with `HCl(aq)`.to give `PH_(4)Cl`.C. Phosphonium compounds are obtained when anhydrous phosphine reacts with anhydrous halogen acids.D. It is prepared by hydrolysis of metal phosphides with acids. |
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Answer» Correct Answer - A,B (A) `PH_(3)` is a lewis base but is neutral towards red litmus. (B) It does not react with HCI(aq)or HI(aq). This is because water decomposes `PH_(4)`X formed to give back `PH_(3)`. (C ) It reacts only with anhydrous HCI or HBr. (D) `2Na_(3)P+3H_(2)SO_(4)to 3Na_(2)SO_(4)+2PH_(3)uarr, Ca_(3)P_(2)+6HCIto 3CaCI_(2)+2PH_(3)`. |
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| 580. |
The nitrogen oxide (s) that contain (s) `N-N` bonds (s) is (are).A. `N_(2)O`B. `N_(2)O_(3)`C. `N_(2)O_(4)`D. `N_(2)O_(5)` |
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Answer» Correct Answer - A::B::C |
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| 581. |
Which of the following is incorrect statement ?A. `NO` is heavier than `O_(2)`B. The formula of heavy water is `D_(2)O`C. `N_(2)` diffuses faster than oxygen through an orificeD. `NH_(3)` can be used as a refrigerant |
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Answer» Correct Answer - A |
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| 582. |
The correct statement(s) about `O_(3)` is/areA. `O-O` bond lengths are equalB. thermal decomposition of `O_(3)` is endothermicC. `O_(3)`is diamagnetic in natureD. `O_(3)` has a bent structure |
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Answer» Correct Answer - A::C::D |
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| 583. |
Which of the following is//are incorrect statement(s) for phosphine ?A. It is less basic then `NH_(3)`.B. It is less poisonous then `NH_(3)`.C. The solution of `PH_(3)` in water does not decompose.D. Phosphine on heating at `150^(circ)C` "burns forming" `H_(3)PO_(4)`. |
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Answer» Correct Answer - B,C (A) In `PH_(3)` the lone pair of electrons is present in sepherical non directional more concentrated s-orbital where as lone pair of electrons is present in dirctional `sp^(3)` hybrid orbital. As a result, the ease of donation of lone pair of electron is more in `NH_(3)` as compare to `PH_(3)`. (B) It is incorrect statement. (C ) The solution of `PH_(3)` in water decomposes in presence of light giving red phosphorus and `H_(2)`. (D) `PH_(3)+2O_(2)to H_(3)PO_(4)` is correct statement `(PH_(3) lt NH_(3)) NH_(3)` is more basic thaen `PH_(3)`. |
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| 584. |
The nitrogen containing compound produced in the reaction of `HNO_(3)` with `P_(4)O_(10)`A. can also be prepared by reaction of `P_(4)` and `HNO_(3)`B. is diamagneticC. contains one `N-N` bondD. reacts with `Na` metal producing a brown gas |
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Answer» Correct Answer - B::D |
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| 585. |
Select the incorect statement(s).A. Alkaline `H_(2)O_(2)` reduces `CIO_(2)` to `CIO_(2)^(-)`B. Ammonia reacts with excess of iodine to form an explosive, `NI_(3)`. `NH_(3)`C. The manufacture of `HNO_(3)` is based upon catalytic oxidation of `NH_(3)` by atmospheric oxygen.D. `N_(2)O_(3)` with concentrated `HCIO_(4)` forms nitrosyl salt. |
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Answer» Correct Answer - A,B,C,D (A) `H_(2)O_(2)+2CIO_(2)+2OH^(-)to 2CIO_(2)^(-)+2H_(2)O+O_(2)` (B) `2NH_(3)+3I_(2)to NI_(3).NH_(3)+3HI`,`8NI_(3)NH_(3)to 5N_(2) + 9I_(2)+6NH_(4)I` (C)`4NH_(3) (g) +5O_(2) (g) ("from air") overset("Pt//Rh gauge catalyst")underset("500K,9bar")to 4NO(g) +6H_(2)O(g)` (D) `N_(2)O_(3)+2HCIO_(4)to 2NO[CIO_(4)]+H_(2)O` |
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| 586. |
Nitrozen (i) oxide is produced byA. Thermal decomposition of ammonium nitrateB. Disproportionation of `N_(2)O_(4)`C. Thermal decomposition of ammonium nitriteD. Interaction of hydroxyl amine and nitrous acid |
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Answer» Correct Answer - D `NH_(2)OH+HNO_(2)rarrH_(2)overset(+1)(N_(2))O_(2)+H_(2)O` |
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| 587. |
Nitrozen (i) oxide is produced byA. thermal deocomposition of ammonium nitrateB. disproportionation of `N_(2)O_(4)`C. thermal decomposition of ammonium nitriateD. interaction of hydroxyl amine with nitrous acid. |
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Answer» Correct Answer - A `NH_(4)NO_(3)overset(Delta)to 2H_(2)O+N_(2)O` |
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| 588. |
Nitrozen (i) oxide is produced byA. thermal decomposition of ammonium nitrate.B. disproportionation of `N_(2)O_(4)`.C. thermal decomposition of ammonium nitrate.D. interaction of hydroxyl ammine and nitrous acid. |
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Answer» Correct Answer - A,D `NH_(4)NO_(3)overset(Delta)to N_(2)O+2H_(2)O ,NH_(2)OH+HNO_(2) to N_(2)O+2H_(2)O` |
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| 589. |
The reaction of `P_(4)` with X leads selectively to `P_(4)O_(6)` The X is :A. dry `O_2`B. a mixture of `O_2` and `N_2`C. moist `O_2`D. `O_2` in the presence of aqueous NaOH |
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Answer» Correct Answer - B `P_4+3O_2 to P_4O_6` Nitrogen prevents further oxidation of `P_4O_6` to `P_4O_10` `P_4` when treated with dry `O_2` gives `P_4O_6` and finally `P_4O_10`. With moist oxygen , `P_4` gives `H_3PO_3`. `P_4 + 3NaOH + 3H_2O to 3NaH_2PO_2 + PH_3` |
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| 590. |
Complete the following. `Pb(NO_(3))_(2)overset(673K)to` |
| Answer» `2" Pb"(NO_(3))_(2)overset(Delta)to2" PbO"+4" NO"_(2)+O_(2)` | |
| 591. |
Complete the following. `P_(4)+"conc.HNO"_(3)to` |
| Answer» `P_(4)+20" HNO"_(3)to4H_(3)PO_(4)+20" NO"_(2)+4" H"_(2)O` | |
| 592. |
Nitrozen (i) oxide is produced byA. thermal decomposition of `NH_(4)NO_(3)`B. disproportionation of `N_(2)O_(4)`C. thermal decomposition of `NH_(4)NO_(2)`D. interaction of hydroxylamine and nitrous acid |
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Answer» Correct Answer - A::D |
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| 593. |
The reaction of `P_(4)` with X leads selectively to `P_(4)O_(6)` The X is :A. Dry `O_(2)`B. A mixture of `O_(2)` and `N_(2)`C. Moist `O_(2)`D. `O_(2)` in the presence of aqueous NaOH |
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Answer» Correct Answer - B `P_(4)+3O_(2)overset`("In presence of"`N_(2))toP_(4)O_(6)`. "Here nitrogen acts as diluent". Note: "In dry" `O_(2)` "followintg reactions may take place". `P_(4)+3O_(2)to P_(4)O_(6)`. `P_(4)O_(6)to P_(4)2O_(2)to P_(4)O_(10)`. "In moist" `O_(2)` the `P_(4)O_(6)` "gets hydrolysed forming" `H_(3)PO_(3)`. `P_(4)O_(6)to 4H_(3)PO_(3)`. "In presence of NaOH". `P_(4)+3OH^(-)+3H_(2)O to PH_(3)+3H_(2)PO_(2)^(-)` |
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| 594. |
Statement I Nitrogen and oxygen are the main components in the atmosphere but these do not react to from oxides of nitrogen. Statement II the reaction between nitrogen and oxygen requires high temperature. |
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Answer» Correct Answer - A |
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| 595. |
Complete the following. `"Zn"+"dil.HNO"_(3)to` |
| Answer» `4" Zn"+10" HNO"_(3)("dil")to4" Zn"(NO_(3))_(2)+5" H"_(2)O+N_(2)O` | |
| 596. |
Extra pure `N_2` can be obtained by heatingA. `NH_(3)` with `CuO`B. `NH_(4)NO_(3)`C. `(NH_(4))_(2)Cr_(2)O_(7)`D. `Ba(N_(3))_(2)` |
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Answer» Correct Answer - D `Ba(N_(3))_(2)(s) overset(Delta) to Ba (s) +3N_(2) (g)` |
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| 597. |
Extra pure `N_2` can be obtained by heatingA. `NH_(3)" with "CuO`B. `NH_(4)NO_(3)`C. `(NH_(4))_(2)CrO_(7)`D. `Ba(N_(3))_(2)` |
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Answer» Correct Answer - D `Ba(N_(3))_(2) overset(Heat) toBas(s) + 3N_(2)(g)uarr` |
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| 598. |
In compounds of type `ECl_3` where `E= B, P, As, Bi`. The angles `Cl - E -C l` for different `E` are in the order :A. `B gt P = As = Bi`B. `B gt P gt As gt Bi`C. `B lt P = As = Bi`D. `B lt P lt As lt Bi` |
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Answer» Correct Answer - B |
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| 599. |
Among the following, the correct statement (s) is (are)A. `Al(CH_(3))_(3)` has the three-centre two-electron bonds in its dimeric structureB. The Lewis acidity of `BCl_(3)` is greater than that of `AlCl_(3)`C. `AlCl_(3)` has the three-centre two-electron bonds in its dimeric structureD. `BH_(3)` has the three-centre two-electron bonds in its dimeric structure |
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Answer» Correct Answer - A::B::C |
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| 600. |
The states of hybridisation of boron and oxygen atoms in boric acid `(H_3 BO_3)` are respecitivelty :A. `sp^2` and `sp^2`B. `sp^3` and `sp^3`C. `sp^3` and `sp^2`D. `sp^2` and `sp^3` |
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Answer» Correct Answer - D In Boric acid `(H_3BO_3)` , boron is `sp^2` hybridised (one 2s and two 2p orbital) and oxygen is `sp^3` hybridised (one 2s and three 2p orbitals) |
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