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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 451. |
Which one of the following orders is not in according with the property stated against it ?A. `F_(2) gt Cl_(2) gt Br_(2) gt I_(2)` Oxidising powerB. `Hl gt HBr gt HCl gt HF` acidic property in waterC. `F_(2) gt Cl_(2) gt Br_(2) gt I_(2)` ElectronegativityD. `F_(2) gt Cl_(2) gt Br_(2) gt I_(2)` Bond dissociation energy |
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Answer» Correct Answer - D Incorrect order of bond dissociation energy `F_(2) gt Cl_(2) gt Br_(2) gt I_(2)` due to following order of size `I gt Br gt Cl gt F` |
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| 452. |
Co gas is absorbed by aqueous suspension of cuprous chloride forming the complex like `[CuCl(CO)(H_(2)O)_(2)]` Choose the correct statement regarding the above molecule:A. Cl-atom is seperated by equal angle from both of the water molecule.B. Magnetic moment of the above complex is 1.73 B.MC. There are two stereoisomers for the above complex.D. Both (a) and ( c) |
| Answer» Correct Answer - A | |
| 453. |
Co gas is absorbed by aqueous suspension of cuprous chloride forming the complex like `[CuCl(CO)(H_(2)O)_(2)]` Comment on the shape of the above complex:A. tetrahedralB. TBPC. square planarD. can not be predicted |
| Answer» Correct Answer - A | |
| 454. |
B can be absorbed by :A. `Ca(OCl)Cl`B. `H_(2)S`C. Both (a) and (b)D. none of these |
| Answer» Correct Answer - A | |
| 455. |
When D reacts with `C_(2)H_(5)OH` then product will be :A. `C_(2)H_(5)Cl,H_(3)PO_(4)`B. `C_(2)H_(5)Cl,H_(3)Cl,H_(3)PO_(3)`C. `CH_(3)COCl,H_(3)PO_(3)`D. only `H_(3)PO_(3)` |
| Answer» Correct Answer - B | |
| 456. |
Silicon forms a very large number of compounds containing `SiO_(4)^(4-)` anion as the basic unit. The structure of this basic unit is a tetrahedron in which oxygen atoms are arranged tetrahedral around a silicon atom. The total number of oxygen shared per tetrahedron in Beryl `[Be_(3)Al_(2)Si_(6)O_(18)]`A. 4B. 3C. 2D. 1 |
| Answer» Correct Answer - C | |
| 457. |
Write chemical equations for the following processes : (i)Chlorine reacts with a hot concentrated solution of sodium hydroxide (ii)Orthophosphorous acid is heated (iii)`PtF_(6)` and xenon are mixed together |
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Answer» Correct Answer - (i)`3CI_(2)+6NaOHto5NaCl+NaCIO_(3)+3H_(2)O` (ii)`4H_(3)PO_(3)overset("heat")to3H_(3)PO_(4)+PH_(3)` (iii)`PtF_(6)+XetoXe^(+)[PtF_(6)^(-)]` |
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| 458. |
Choose the correct statements (s) for group-18 elements:A. Ionisation enthalpy decrease down the groupB. Density increases down the groupC. M.P (except He) increases down the groupD. B.P increase down the group |
| Answer» Correct Answer - A::B::C::D | |
| 459. |
Identify the reaction(s) in which the stereochemistry of underlined species has changed.A. `XeFD_(2)+underline(P)F_(5) rarr[XeF]^(+)[PF_(6)]^(-)`B. `underline(X)eF_(4)+SbF_(5) rarr[XeF_(3)]^(+)[SbF_(6)]^(-)`C. `XeF_(4)+underline(S)bF_(5) rarr[XeF_(3)]^(+)[SbF_(6)]^(-)`D. `underline(X)eF_(6)+2CsF rarr(Cs^(+))_(2)[XeF_(8)]^(2-)` |
| Answer» Correct Answer - A::B::C::D | |
| 460. |
An inorganic compound (A) made of two most occuring elements into the earth crust, having a polymeric tera-hederal network structure. With carbon, compound (A) produces a poisonous gas (B) which is the most stable diatomic molecule. Compounds (A) and (B) will beA. `SiO_(2).CO_(2)`B. `SiO_(2).CO`C. `SiC. CO`D. `SiO_(2).N_(2)` |
| Answer» Correct Answer - B | |
| 461. |
At room temperature, `CO_(2)` is a gas while `SiO_(2)` is a solid because |
| Answer» (a) For inert pair effect | |
| 462. |
A balck powder when heated with Conc. HCI gives a greenish yellow. Gas. The gas as an oxidising and bleaching agent. When it is passed over slake lime, a white poweder is formed which is a ready source of gas. The back powder and white powder respectively areA. `KClO_3` and `NaClO_3`B. `MnO_2` and `Ca(O Cl)_2`C. `MnO_2` and KClOD. `MnCl_4` and `COCl_2` |
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Answer» Correct Answer - B `underset"Black powder"(MnO_2) + underset"conc."(4HCl) to MnCl_2 + 2H_2O + underset"Greenish yellow gas "(Cl_2)` `Cl_2 + H_2O to 2HCl + [O]` Coloured matter + [O] `to` colourless matter `underset"Slaked lime"(2Ca(OH)_2) + 2Cl_2 to underset"Bleaching powder (white)"(Ca(OCl)_2) + CaCl_2 + 2H_2O` |
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| 463. |
In aqueous solution , chlorine is a stronger oxidising agent than fluorine. |
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Answer» Correct Answer - Four |
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| 464. |
Statement-1 : Fluorine is a stronger oxidising agent than chlorine because Statement-2 : It has (i) low enthalpy of dissociation of F-F bond and (ii) high hydration energy.A. Statement-1 is True, Statement-2 is True,Statement-2 is a correct explanation for Statement-1.B. Statement-1 is True, Statement-2 is True,Statement-2 is NOT a correct explalanation for Statement-2C. Statement-1 is True, Statement-2 is FalseD. Statement-1 is False, Statement-2 is True |
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Answer» Correct Answer - A |
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| 465. |
The bond energies of `F_2, Cl_2, Br_2 and I_2` are 155, 244, 193 and 151 kJ mol respectively. The weakest bond will be inA. `Br_2`B. `Cl_2`C. `F_2`D. `I_2` |
| Answer» Correct Answer - D | |
| 466. |
Which of the following statement are true regareding interhalogens:A. (A) Thermal stability order IF gt BrF gt CIFB. (B) Hydrolysis of `IF_7` produces `H_5IO_6` and HF as products.C. (C) Interhalogen compounds are diamagnetic in nature.D. `IF_7` have pentagonal bipyramidal structure |
| Answer» Correct Answer - A::B::C::D | |
| 467. |
Statement-1 : Most of the reactions of fluorine are exothermic. Statement-2: Fluorine atom is smaller in size and forms strong bonds with other elements and has low dissociation energy of the F-F bond.A. Statement-1 is True, Statement-2 is True,Statement-2 is a correct explanation for Statement-1.B. Statement-1 is True, Statement-2 is True,Statement-2 is NOT a correct explalanation for Statement-3C. Statement-1 is True, Statement-2 is FalseD. Statement-1 is False, Statement-2 is True |
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Answer» Correct Answer - A |
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| 468. |
Statement-1 :Chlorine bleaches vegetable or organic substances in the presence of moisture. Statement-2 : `Cl_(2)+H_(2)O to 2HCl + [O]`A. Statement-1 is True, Statement-2 is True,Statement-2 is a correct explanation for Statement-1.B. Statement-1 is True, Statement-2 is True,Statement-2 is NOT a correct explalanation for Statement-5C. Statement-1 is True, Statement-2 is FalseD. Statement-1 is False, Statement-2 is True |
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Answer» Correct Answer - A |
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| 469. |
Statement-1 : Halogens are more reactive than interhalogens. Statement-2 :Bond in the interhalognes (X-Y) is weaker than X-X bond in the halogens.A. Statement-1 is True, Statement-2 is True,Statement-2 is a correct explanation for Statement-1.B. Statement-1 is True, Statement-2 is True,Statement-2 is NOT a correct explalanation for Statement-4C. Statement-1 is True, Statement-2 is FalseD. Statement-1 is False, Statement-2 is True |
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Answer» Correct Answer - D |
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| 470. |
By which of the following reactions is borazine prepared?A. `B_(2)H_(6)+NH_(3)(excess) overset("Low temperature")rarr`B. `B_(2)H_(6)+NH_(3)(excess) overset("High temperature")rarr`C. `B_(2)H_(6)+NH_(3)(excess)underset("High temperature") overset("Ratio 2 "NH_(3):1B(2)H_(6))rarr`D. None of the above |
| Answer» Correct Answer - C | |
| 471. |
Explain why is `NH_(3)` basic while `"BiH"_(3)` is only feebly basic. |
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Answer» `NH_(3)` is basic while `"BiH"_(3)` is only feebly basic. Explanation : `to` Due to small atomic size of nitrogen, the electron density on nitrogen atom is greater than that on Bi atom. So electron releasing tendency is greater in `NH_(3)`. Hence `NH_(3)` is basic and `"BiH"_(3)` is feebly basic. |
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| 472. |
Arrange the hydrides of group - 15 elements in the increasing order of basic strength and decreasing order of basic strength and decreasing order of reducing character. |
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Answer» i. Increasing order of basic strength of Group - 15 elements hydrides is `"BiH"_(3) lt"SbH"_(3)lt"AsH"_(3)lt"PH"_(3)lt"NH"_(3)`. ii. Decreasing order of reducing character of Group - 15 elements hydrides is `"BiH"_(3)gt"SbH"_(3)gt"AsH"_(3)gt"PH"_(3)gt"NH"_(3)`. |
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| 473. |
The acidic strength for the hydrides of group 15 follows the orderA. `NH_(3)gtPH_(3)gtAsH_(3)gtSbH_(3)`B. `NH_(3)ltPH_(3)ltAsH_(3)ltSbH_(3)`C. `NH_(3)gtPH_(3)gtSbH_(3)gtAsH_(3)`D. `NH_(3)ltPH_(3)ltSbH_(3)ltAsH_(3)` |
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Answer» Correct Answer - B `" " NH_(3) lt PH_(3) lt AsH_(3) lt SbH_(3)` |
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| 474. |
Consider the following statements, I. S-S bond is present in `H_(2)S_(2)O_(6).` II. In peroxodisulphuric acid `(H_(2)S_(2)O_(8))`, sulphur is in `+6` oxidation state. The correct set of statement isA. Only IB. Only IIC. Both I and IID. Neither I nor II |
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Answer» Correct Answer - A In `H_(2)S_(2)O_(6), S-S` bond is present . |
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| 475. |
Which one of the following molecules hydrides acts as a Lewis acid ?A. `NH_(3)`B. `H_(2)O`C. `B_(2)H_(6)`D. `CH_(4)` |
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Answer» Correct Answer - C Key Idea Electron dificient molecules behave as Lewis acid. Among the given molecules, only dibrorane is electron deficient, i.e, does not have complete octet. Thus, it acts as a Lewis acid. `NH_(3)` and `H_(2)O` begin electrons rich molecules behave as Lewis base. |
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| 476. |
Which of the following molecular hydrises acts as a Lewis acid?A. `NH_(3)`B. `H_(2)O`C. `B_(2)H_(6)`D. `CH_(4)` |
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Answer» Correct Answer - C `B_(2)H_(6)` acts as Lewis acid since it is electron deficient in nature. |
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| 477. |
The stability of `+1` oxidation state increases in the sequence :A. `TiltInltGaltAl`B. `In ltTiltGaltAl`C. `GaltInltAlltTi`D. `AlltGaltInltTi `. |
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Answer» Correct Answer - D Group-13 elements exhibit +3 and +1 oxidation states. Stability of the lower oxidation state increaes on moving down the grou. Thus the order is `Al^(+)ltGa^(+)ltIn^(+)ltTI^(+)` |
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| 478. |
Write one chemical reaction to show that conc. `H_(2)SO_(4)` can act as an oxidising agent. |
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Answer» Hot concentrated sulphuric acid oxidises carbon to `CO_(2)` `C + 2 H_(2)SO_(4)(conc.) to CO_(2)+2 SO_(2)+ 2 H_(2)O` |
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| 479. |
Hot conc. `H_(2)SO_(4)` acts as molderately strong oxidising agent It oxidises both metals and non - metals. Which of the following element is oxidised by conc. `H_(2)SO_(4)` into two gaseous products. ?A. CuB. SC. CD. Zn |
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Answer» Correct Answer - C `H_(2)SO_(4)` is a moderately strong oxidising agent which oxidises both metals and non - metals as shown below `Cu+2H_(2)SO_(4)(conc)to CuSO_(4)+SO_(2)+2H_(2)O` `S+2H_(2)SO_(4)(conc)to3SO_(2)+2H_(2)O` While carbon on oxidation with `H_(2)SO_(4)` produces two types of oxides `CO_(2)` and `SO_(2)`. `C+2H_(2)SO_(4)(conc)toCO_(2)+2SO_(2)+2H_(2)O` |
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| 480. |
`I.underset((cold and dlll))(2NaOH)+Cl_(2)rarr...A...+...B...+H_(2)O` `II.underset((hot and conc.))(6NaOH)+3Cl_(2)rarr...C...+...D...+3H_(2)O` Here, A, B, C and D refer to |
| Answer» Correct Answer - C | |
| 481. |
The reactions in which conc. `H_(2)SO_(4)` is used as an oxidising agent are I. `2HI+H_(2)SO_(4)rarrI_(2)+SO_(2)+2H_(2)O` II. `NaCl+2H_(2)SO_(4)rarrNaHSO_(4)+HCl` III. `CaF_(2) | H_(2)SO_(4)rarrCaSO_(4)+2HF` IV. `Cu+2H_(2)SO_(4)rarrCuSO_(4)+SO_(2)+2H_(2)O` Choose the correct option.A. I and IIB. II and IIIC. I and IIID. I and IV |
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Answer» Correct Answer - D In the following reactions , conc. `H_(2)SO_(4)` is used as an oxidising agent . `2Hl + H_(2)SO_(4) rarr l_(2) + SO_(2) + 2H_(2)O` `Cu + 2H_(2)SO_(4) rarr CuSO_(4) + SO_(2) + 2H_(2)O` |
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| 482. |
In the prepartion of `HBr` or `HI, NaX (X=Br,I)` is treated with `H_(3)PO_(4)` and not by concentrated `H_(2)SO_(4)` since,A. `H_(2)SO_(4)` makes the reaction reversibleB. `H_(2)SO_(4)` oxidises `HX` to `X_(2)(Br_(2),I_(2))`C. `Na_(2)SO_(4)` is water soluble and `Na_(3)PO_(4)` is water insolubleD. `Na_(3)PO_(4)` is water insoluble and `Na_(2)SO_(4)` is water soluble |
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Answer» Correct Answer - B |
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| 483. |
`H_(3)PO_(2) overset(140^(@)) rarrA overset(220^(@)C) toB overset(320^(@)C)rarrC.` Compound ( C) is :A. `H_(2)PO_(3)`B. `H_(3)PO_(3)`C. `(HPO_(3))_(n)`D. `H_(4)P_(2)O_(7)` |
| Answer» Correct Answer - C | |
| 484. |
Dissociatuion of `H_(3)PO_(4)` occurs in following stagesA. 1B. 2C. 3D. 4 |
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Answer» Correct Answer - C `H_(3)PO_(4) hArr H^(+) +H_(2)PO_(4)^(-)` `H_(2)PO_(4)^(-) hArr H^(+) +HPO_(4)^(2-)` `HPO_(4)^(2-) hArr H^(+) +PO_(4)^(3-)` |
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| 485. |
Phosphorus is manufactred by heating in an electric furnace a mixture ofA. Bone ash and cokeB. Bone ash and silicaC. Bone ash, silica and cokeD. None of these. |
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Answer» Correct Answer - C `2Ca_(3)(PO_(4))_(2)+6SiO_(2)overset(1770K)rarr6CaSiO_(3)+P_(4)O_(10)` `P_(4)O_(10)+10Coverset(1770K)rarrunderset(White)P_(4)+10CO` |
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| 486. |
The hydribes of group 15 elements act as :A. lewis acidsB. lewis basesC. bothD. none |
| Answer» Correct Answer - B | |
| 487. |
Asseration: On dissolution of xenates, `[HXeO_(4)]^(-)` in alkaline solution perxenate and `Xe` are obtained. Reason: Xenates, `[HXeO_(4)]^(-)` shows disproportionation in alkaline solution.A. If both asseration and reson are true and the reason is the correct explanation of the asseration.B. If both asseration and reason are true ans the reason is the correct explanation of the asseration.C. If asseration is true but reason is false.D. If asseration is false but reason is true. |
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Answer» Correct Answer - A Explanation is correct reason for statement. `2[HXeO_(4)]^(-)overset(20H^(-))(rarr)[XeO_(6)]^(4-)+underset(Zero)(Xe)+O_(2)+2H_(2)O` |
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| 488. |
`[HXeO_(4)]^(-)+OH^(-)rarr[X]+[Y]+O_(2)+H_(2)O` The products `[X]` and `[Y]` in unbalanced reaction are:A. `[XeO_(6)]^(4-)` and `Xe`B. `[XeO_(6)]^(4-)` and `XeO_(3)`C. `XeO_(3)` and `Xe`D. `H_(2)XeO_(4)` and `Xe` |
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Answer» Correct Answer - A Hydrogen xenate ion `[HXeO_(4)]^(-)(OS` of `Xe=+ 6)` disproportionates slowly in solution to give perxenates, `[XeO_(6)]^(4-)(OS"of"Xe=+8)` and xenon. |
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| 489. |
The unbalanced chemical reactions given In list I show missing reagent or condition (?) Which are provided in List II. Match List I with List II and select the correct answer using the code given below the list: A. `{:(P,Q,R,S),(4,2,3,1):}`B. `{:(P,Q,R,S),(3,2,1,4):}`C. `{:(P,Q,R,S),(1,4,2,3):}`D. `{:(P,Q,R,S),(3,4,2,1):}` |
| Answer» Correct Answer - D | |
| 490. |
`[HXeO_(4)]^(-)+Ohrarr[X]+[Y]+O_(2)+H_(2)O` The products `[X]` and `[Y]` in unbalanced reaction are:A. `[XeO_(6)]^(4-)` & `Xe`B. `[XeO_(6)]^(4-)` & `XeO_(3)`C. `XeO_(3)` & `Xe`D. `H_(2)XeO_(4)` & `Xe` |
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Answer» Correct Answer - A |
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| 491. |
`[HXeO_(4)]^(-)+Ohrarr[X]+[Y]+O_(2)+H_(2)O` The products `[X]` and `[Y]` in unbalanced reaction are:A. `[XeO_6]^(4-) & Xe`B. `[XeO_6]^(4-) & XeO_3`C. `XeO_3 & Xe`D. `H_2XeO_4 & Xe` |
| Answer» Correct Answer - A | |
| 492. |
Upon heating`KCIO_(3)` in presence of catalytic amount of `MnO_(2)`, a gas `W` is formed. Excess amount of `W` reacts with white phosphours to given `X`. The reaction of `X` with pure `HNO_(3)` gives `Y` and `Z`. Y and Z are, respectivelyA. `N_(2)O_(4)` and `HPO_(3)`B. `N_(2)O_(4)` and `H_(3)PO_(3)`C. `N_(2)O_(3)` and `H_(3)PO_(4)`D. `N_(2)O_(5)` and `HPO_(3)` |
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Answer» Correct Answer - A |
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| 493. |
The unbalanced chemical reactions given in Column I show missing reagent or condition (?) which are provided in Column II. Match Column I with Column II and select the correct answer using the codes gives below the Columns. `{:(Column I,Column II),(P.PbO_(2)+H_(2)SO_(4) overset(?)rarrPbSO_(4)+O_(2)+"other product",1.NO),(Q.Na_(2)S_(2)O_(3)+H_(2)O overset(?)rarrNaHSO_(4)+ "other product",2.I_(2)),(R.N_(2)H_(4)overset(?)rarrN_(2)+ "other product",3."Warm"),(S.XeF_(2)overset(?)rarrXe+ "other product",4.CI_(2)):}`A. `{:(P,Q,R,S),(4,2,3,1):}`B. `{:(P,Q,R,S),(3,2,1,4):}`C. `{:(P,Q,R,S),(1,4,2,3):}`D. `{:(P,Q,R,S),(3,4,2,1):}` |
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Answer» Correct Answer - D |
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| 494. |
Which of the following are correct statements ?A. Oxides of phosphorus, `P_(2)O_(3)andP_(2)O_(5)` exist as monomersB. Solid `PCI_(5)` exists as tetrahedral `[PCl_(4)]^(+)` and octahedral `[PCl_(6)]^(-)` ionsC. Solid `PBr_(5)` exists as `[PBr_(4)]^(+)Br^(-)`D. Solid `N_(2)O_(5)` exists as `NO_(2)^(+)NO_(3)^(-)` |
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Answer» Correct Answer - B::C::D Option (a) is wrong because `P_(2)O_(3)andP_(2)O_(5)` exist as dimers. All other options are correct. |
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| 495. |
Upon heating`KCIO_(3)` in presence of catalytic amount of `MnO_(2)`, a gas `W` is formed. Excess amount of `W` reacts with white phosphours to given `X`. The reaction of `X` with pure `HNO_(3)` gives `Y` and `Z`. W and X are, respectivelyA. `O_(2)` and `P_(4)O_(10)`B. `O_(2)` and `P_(4)O_(6)`C. `O_(3)` and `P_(4)O_(6)`D. `O_(3)` and `P_(4)O_(10)` |
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Answer» Correct Answer - B |
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| 496. |
Upon heating `KClO_(3)` in the presence of catalytic amount of `MnO_(2)`, a gas W is formed. Excess amount of W reacts with white phosphorus to give X. The reaction of X with pure `HNO_(3)` gives Y and Z. Y and Z are, respectivelyA. `N_(2)O_(5)andHPO_(3)`B. `N_(2)O_(3)andH_(3)PO_(4)`C. `N_(2)O_(4)andH_(3)PO_(3)`D. `N_(2)O_(4)andHPO_(3)` |
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Answer» Correct Answer - A `2KClO_(3)overset(MnO_(2),Delta)to2KCl+underset((W))(3O_(3))` `P_(4)+10O_(2)overset("Oxidation")tounderset((X))(P_(4)O_(10))` `P_(4)O_(10)` acts as dehydrating agent and removes `H_(2)O` from `HNO_(3)` to give `N_(2)O_(5)` (Y) and itself gets converted into `HPO_(3)` (Z). Thus, X is `P_(4)O_(10)` Y is `N_(2)O_(5)`, and Z in `HPO_(3)` and W is `O_(2)`. `P_(4)O_(10)+4HNO_(3)tounderset((Y))(2N_(2)O_(5))+underset((Z))(4HPO_(3))` |
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| 497. |
Upon heating `KClO_(3)` in the presence of catalytic amount of `MnO_(2)`, a gas W is formed. Excess amount of W reacts with white phosphorus to give X. The reaction of X with pure `HNO_(3)` gives Y and Z. W and X are, respectivelyA. `O_(2)andP_(4)O_(6)`B. `O_(2)andP_(4)O_(10)`C. `O_(3)andP_(4)O_(6)`D. `O_(3)andP_(4)O_(10)` |
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Answer» Correct Answer - B `2KClO_(3)overset(MnO_(2),Delta)to2KCl+underset((W))(3O_(3))` `P_(4)+10O_(2)overset("Oxidation")tounderset((X))(P_(4)O_(10))` `P_(4)O_(10)` acts as dehydrating agent and removes `H_(2)O` from `HNO_(3)` to give `N_(2)O_(5)` (Y) and itself gets converted into `HPO_(3)` (Z). Thus, X is `P_(4)O_(10)` Y is `N_(2)O_(5)`, and Z in `HPO_(3)` and W is `O_(2)`. `P_(4)O_(10)+4HNO_(3)tounderset((Y))(2N_(2)O_(5))+underset((Z))(4HPO_(3))` |
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| 498. |
Which of the following pairs has almost same radii ?A. `Al, Ga`B. `Be,Mg`C. `Mg,Cl`D. `B,Be` |
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Answer» Correct Answer - A Due to inert pair effect, Al and Ga have nearly same atomic radii. |
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| 499. |
The reactions of `CI_(2)` gas with cold-dilute and hot-concentrated NaOH in water give sodium salts of two different oxioacids of chlorine, P and Q, respectively. The `CI_(2)` gas reacts with `SO_(2)` gas, in presence of charocal, to give a product R reacts with white phosphorus to give a compound S. On hydrolysis, S gives an oxoacid of phosphorus. R, S and T, respectively, areA. `SO_(2)CI_(2),PCI_(5)` and `H_(3)PO_(4)`B. `SO_(2)CI_(2), PCI_(3)` and `H_(3)PO_(3)`C. `SOCI_(2),PCI_(3)` and `H_(3)PO_(2)`D. `SOCI_(2),PCI_(5)` and `H_(3)PO_(4)` |
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Answer» Correct Answer - A |
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| 500. |
The reactions of `CI_(2)` gas with cold-dilute and hot-concentrated NaOH in water give sodium salts of two different oxioacids of chlorine, P and Q, respectively. The `CI_(2)` gas reacts with `SO_(2)` gas, in presence of charocal, to give a product R reacts with white phosphorus to give a compound S. On hydrolysis, S gives an oxoacid of phosphorus. R, S and T, respectively, areA. `SO_(2)CI_(2),PCI_(5)` and `H_(3)PO_(4)`B. `SO_(2)CI_(2),PCI_(3)` and `H_(3)PO_(3)`C. `SOCI_(2),PCI_(3)` and `H_(3)PO_(2)`D. `SOCI_(2),PCI_(5)` and `H_(3)PO_(4)` |
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Answer» Correct Answer - A |
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