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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 501. |
The reactions of `CI_(2)` gas with cold-dilute and hot-concentrated NaOH in water give sodium salts of two different oxioacids of chlorine, P and Q, respectively. The `CI_(2)` gas reacts with `SO_(2)` gas, in presence of charocal, to give a product R reacts with white phosphorus to give a compound S. On hydrolysis, S gives an oxoacid of phosphorus. P and Q, respectively, are the sodium salts ofA. hypochlorus and chloric acidsB. hypochlorus and chlorus acidsC. chloric and perchloric acidsD. chloric and hypochlorus acids |
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Answer» Correct Answer - A |
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| 502. |
The noble gases have closed-shell electronic configuration and are monoatomic gases under normal conditions. The low boiling points of the lighter noble gases are due to weak dispersion forces between the atoms and the absence of other Interatomic Interactions. The direct reaction of xenon with fluorine leads to a series of compounds with oxidation numbers +2,+4 and +6. `XeF_4` reacts violently with water to give `XeO_3` The compound of xenon exhibit rich stereochemistry and their geometries can be deduced considering the total number of electron pairs in the valence shell. Argon is used In arc welding because of its:A. linearB. planarC. pyramidalD. T-shaped |
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Answer» Correct Answer - C |
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| 503. |
The noble gases have closed-shell electronic configuration and are monoatomic gases under normal conditions. The low boiling points of the lighter noble gases are due to weak dispersion forces between the atoms and the absence of other Interatomic Interactions. The direct reaction of xenon with fluorine leads to a series of compounds with oxidation numbers +2,+4 and +6. `XeF_4` reacts violently with water to give `XeO_3` The compound of xenon exhibit rich stereochemistry and their geometries can be deduced considering the total number of electron pairs in the valence shell. Argon is used In arc welding because of its:A. low reactivity with metalB. ability to lower the melting point of metalC. flammabilityD. high calorific value |
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Answer» Correct Answer - A |
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| 504. |
The noble gases have closed-shell electronic configuration and are monoatomic gases under normal conditions. The low boiling points of the lighter noble gases are due to weak dispersion forces between the atoms and the absence of other Interatomic Interactions. The direct reaction of xenon with fluorine leads to a series of compounds with oxidation numbers +2,+4 and +6. `XeF_4` reacts violently with water to give `XeO_3` The compound of xenon exhibit rich stereochemistry and their geometries can be deduced considering the total number of electron pairs in the valence shell. `XeF_4` and `XeF_6` are expected to be:A. oxidizingB. reducingC. unreactiveD. strongly basic |
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Answer» Correct Answer - A |
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| 505. |
The noble gases have closed-shell electronic configuration and are monoatomic gases under normal conditions. The low boiling points of the lighter noble gases are due to weak dispersion forces between the atoms and the absence of other Interatomic Interactions. The direct reaction of xenon with fluorine leads to a series of compounds with oxidation numbers +2,+4 and +6. `XeF_4` reacts violently with water to give `XeO_3` The compound of xenon exhibit rich stereochemistry and their geometries can be deduced considering the total number of electron pairs in the valence shell. Argon is used In arc welding because of its:A. (A) low reactivity with metalB. (B) ability to lower the melting point of metalC. (C) flammablityD. (D) high calorific value |
| Answer» Correct Answer - A | |
| 506. |
The correct statement(s) regarding, (i) `HCIO`, (ii) `HCIO_(2)`, (iii) `HCIO_(3)` and (iv) `HCIO_(4)` is (are)A. the number of `Cl=O` bonds in (ii) and (iii) together is twoB. the number of lone pair of electrons on `Cl` in (ii) and (iii) together is threeC. the hybridisation of `Cl` (in (iv) is `sp^(3)`D. amongst (i) to (iv), the strongest acid is (i) |
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Answer» Correct Answer - B::C |
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| 507. |
The correct statement(s) about the oxoacids, `HCIO_(4)` and `HCIO`, is (are)A. The central atom in both `HCIO_(4)` and `HCIO` is `sp^(3)`-hybridisedB. `HCIO_(4)` is formed in the reaction between `CI_(2)` and `H_(2)O`C. The conjugate base of `HCIO_(4)` is weaker base than `H_(2)O`D. `HCIO_(4)` is more acidic than `HCIO` because of the resonance stabilisation of its anion |
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Answer» Correct Answer - A::C::D |
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| 508. |
An inorganic compound `(X)` gives a brick red flame on performing flame test. This compound gives the following tests also. (a) Smells of chlorine when placed in moist air. (b) If `KI` and `CH_(3)CooH` are added to the suspension in water, a brown colour is obtained. Identify `(X)` and down equations for reactions at steps (a) and (b) . |
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Answer» Correct Answer - `(X)=CaOCl_(2)` |
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| 509. |
Excess of `PCl_(5)` reacts with concentrated `H_(2)SO_(4)` giving :A. chlorosulphonic acidB. thionyl chlorideC. sulphuryl chlorideD. sulphurous acid |
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Answer» Correct Answer - C `PCl_(5)` reacts with conc. `H_2SO_4` to give sulphuryl chloride by replacing its hydroxyl groups with chlorine atoms. `underset(or H_(2)SO_(4)" Sulphuric acid ")(SO_(2)(OH)_(2))+2PCl_(5) to underset("Sulphuryl chloride ")(SO_(2)Cl_(2))+2POCl_(3)+2HCl ` |
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| 510. |
Statement-1 :Noble gases have very low boiling points. Statement-2 : Noble gases being monoatomic have weak dispersion interatomic forces.A. Statement-1 is True, Statement-2 is True,Statement-2 is a correct explanation for Statement-1.B. Statement-1 is True, Statement-2 is True,Statement-2 is NOT a correct explalanation for Statement-10C. Statement-1 is True, Statement-2 is FalseD. Statement-1 is False, Statement-2 is True |
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Answer» Correct Answer - A |
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| 511. |
Iodine reacts with hot concentrated NaOH solution. The products are NaI and _____ |
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Answer» Correct Answer - `NaIO_(3)` |
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| 512. |
Arrange the following : (i)Increasing order of thermal stability `HOCl, HClO_(2), HCIO_(3), HCIO_(4)`. (ii)Increasing acid strength `HCIO, HCIO_(2), HCIO_(3), HCIO_(4)` (iii)Increasing reducing nautre `F^(-),Cl^(-),Br^(-),I^(-)` (iv)Increasing oxidation number of iodine `I_(2),HI,HIO_(4).ICI`. (v)Increasing acid strength `HOF, HOCl, HOBr, HOI`. (vi) Increasing oxidising power `F_(2),Cl_(2),Br_(2),I_(2)` (vii)Increasing acid strength `HF, HCl, HBr, HI`. (viii)Increasing electronegativity `F,Cl, Br,I`. |
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Answer» Correct Answer - (i)`HCIOltHCIO_(2)ltHCIO_(3)ltHCIO_(4)` (ii)`HCIOltHCIO_(2)ltHCIO_(3)ltHCIO_(4)` (iii)`F^(-)ltCl^(-)ltBr^(-)ltI^(-)` (iv)`HIltI_(2)ltIclltHIO_(4)` (v)`HOIltHOBrltHOClltHOF` (vi)`I_(2)ltBr_(2)ltCl_(2)ltF_(2)` (vii)`HFltHClltHBrltHI` (On the basis of their bond dissociation energies) (viii)`IltBrltClltF` |
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| 513. |
Concentrated `HNO_(3)` reacts with iodine to give:A. HIB. HOIC. `HOIO_(2)`D. `HOIO_(3)` |
| Answer» Correct Answer - C | |
| 514. |
Explain the following with proper reason : (i)Fluorine cannot be prepared from fluorides by chemical oxidation. (ii)Anhydrous HCl is a bad conductor of electricity while aqueous HCl is a good conductor. (iii)Halogens are strong oxidising agents. (iv)Bleaching of flowers by chlorine is permanent while after bleaching with `SO_(2)`, the colour returns. (v)Iodine dissolves more in KI solution than in water. (vi)`KHF_(2)` is well known whereas `KHCI_(2)` or `KHBr_(2)` does not exist. (vii)Ferric iodide is very unstable but ferric chloride is stable. (viii)Fluorine does not form `F_(3)^(-)` (polyhalide) ion. (ix)HF is not stored in glass bottles but kept in wax lined bottles. (x)HF has a greater electronegativity difference and more ionic character than HCl, HBr and Hl but it is the weakest acid. |
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Answer» Correct Answer - (i)The standard reduction potential of fluorine is maximum. `:ddotunderset(..)F.+e^(-)to:ddotunderset(..)F.^(-)` Thus, it cannot be oxidised by any other reagent. `F^(-)` ion is very stable due to small size and high electronegativity of fluorine atom. (ii)In anhydrous state, `HCI` is a covalent molecule. In aqueous solution, `HCI` combines with water molecule to form `H_(3)O^(+)` and `CI^(-)` ions. `HCl (g)+H_(2)O(l)toH_(3)O^(+) (aq)+Cl^(-)(aq)` (iii)Halogens act as a strong oxidising agents because they have high tendency to accept electron, i.e., they have high electron affinity values.Their reduction potentials are high (positive) and decrease from `F_(2)` to `I_(2)`.Thus, oxidising nature decreases from `F_(2)` to `I_(2)`. (iv)Chlorine bleaching action is due to oxidation while that of sulphur dioxide is due to reduction.Hence, the substance bleached by `SO_(2)` is reoxidised by the oxygen of the air to its original state. `Cl_(2)` bleaches coloured material by oxidation and thus bleaching is permanent. `CI_(2) + H_(2)Oto2HCI + [O]` Coloured material +`[O] to` colourless on the other hand beaching by `SO_(2)` is by reduction and thus temporary because colourless articles are further oxidised by air. `SO_(2)+2H_(2)Oto2H_(2)SO_(4) + 2[H]` Coloured material + `[H] to` Colourless `overset([O])to` coloured (v)`I_(2)` is a covalent molecule.Thus, its solubility is less in polar solvent, i.e., water.Potassium iodide combines with iodine and forms a polyhalide with an ionic compound.Being ionic, `KI_(3)` is more soluble. `KI+I_(2)toKI_(3)(K^(+)I_(3)^(-))` (vi)Hdrofluoric acid exists as dimeric molecule `(H_(2)F_(2))` due to hydrogen bonding.It, thus, exhibits dibasic nature and forms two series of salts, `KHF_(2)` as `[K^(+)` and `F^(-)---H--F]` and `KF[K^(+)` and `F^(-)]`.`HCl` and `HBr` exists as monomeric molecules as hydrogen bonding is not present. (vii)`I^(-)` ions is a strong reducing agent.Iodide thus reduces ferric into ferrous, `Cl^(-)` ion is a weak reducing agent and does not reduce `Fe^(3+)` to `Fe^(2+)`. (viii)`F`-does not have empty `d`-orbital liked other halogen. The formation of `X_(3)^(-)` ions involves `sp^(3)d`-hydridization. (ix)`HF` attacks glass bottles. The sodium and potassium silicates are converted into flurosilicates `Na_(2)SiO_(3)+6HFtoNa_(2) SiF_(6) + 3H_(2)O` (x)The weakest acidic nature of `HF` is due to following three factors: (i)Strong `H-F` bond as the dissociation energy is high. (ii)Large heat of dehydration due to hydrogen bonding. (iii)Low value of electron affinity. |
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| 515. |
Predict the products when the following reactions are carried out: (A)Red lead reacts with concentrated HCl. (B)Ammonia reacts with excess iodine. ( C)Bleaching powder reacts with lead nitrate in alkaline medium. (D)Chlorine is passed through heated freshly precipitated by HgO. (E)In acidic medium when `SO_(2)` is passed through `NaClO_(3)`. |
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Answer» Correct Answer - (A)`Pb_(3)O_(4) + 8HClto3PbCl_(2) + 4H_(2)O +Cl_(2)` (B)`2NH_(3) + 3l_(2)toNI_(3).NH_(3)+3HI` `8NI_(3).NH_(3)to5N_(2)+9l_(2)+6NH_(4)Cl` ( C)`CaOCl_(2) + Pb(NO_(3)_(2)+2NaOHtoCaCl_(2) + PbO_(2)+2NaNO_(3) + H_(2)O` (D)`2Cl_(2)+2HgO overset(Delta) HgCl_(2).HgO + Cl_(2)O`(brown) (E)`2NaClO_(3)+SO_(2)+H_(2)SO_(4)to2NaHSO_(4)+2ClO_(2)` |
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| 516. |
What happens when ? (Give balanced equations) (i)Sodium iodate is treated with sodium bisulphite solution. (ii)Chlorine is passed through hot and concentrated NaOH solution. (iii)Chlorine is passed into dilute and cold potassium hydroxide solution. (iv)Chlorine gas is bubbled through a solution of ferrous bromide. (v)Iodine reacts with concentrated `HNO_(3)`. (vi)Chlorine is passed over slaked lime. (vii)Potassium iodide is heated with `MnO_(2)` and concentrated `H_(2)SO_(4)`. (viii)Chlorine reacts with `Na_(2)SO_(3)` solution. (ix)Iodine is added to acidified stannous chloride solution. |
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Answer» Correct Answer - (i)`2NaIO_(3)+5NaHSO_(3)to3 NaHSO_(4)+2Na_(2)SO_(4)+H_(2)O+I_(2)` (ii)`3Cl_(2)+6NaOH("conc")overset("Hot")to5NaCl+NaCIO_(3)+3H_(2)O` (iii)`Cl_(2)+2KOH(aq)toKCl+KClO+H_(2)O` (iv)`2FeBr_(2)+3Cl_(2)to2FeCl_(3)+2Br_(2)` (v)`I_(2)+10HNO_(3)to2HIO_(3)+10NO_(2)+4H_(2)O` (vi)`Ca(OH)_(2)+Cl_(2)toCa(OCI)CI+H_(2)O` (vii)`2KI+MnO_(2)+3H_(2)SO_(4)to2KHSO_(4) + MnSO_(4) + 2H_(2)O + I_(2)` (viii)`SnCl_(2)+2HCl+I_(2) overset("acidified")to SnCl_(4)+2HI` |
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| 517. |
Which of the following is generally bleached by bleaching powder ?A. StrawB. IvoryC. Roll of cottonD. Silk |
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Answer» Correct Answer - C It is used as bleaching agent for cotton linen and wood pulp . However delicate article like straw, silk, ivory, etc. are not bleached by bleaching powder. |
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| 518. |
Dinitrogen pentoxide ,a colourless deliquescentsolid is ,prepared byA. heating `NH_(4)NO_(2)` with an excess of oxygenB. dehydrating `HNO_(3)` with CaOC. dehydrating `HNO_(3)` with `P_(4)O_(10)`D. heating a mixture of `HNO_(2) and Ca(NO_(3))_(2)` |
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Answer» Correct Answer - C `4NHO_3 + P_4O_(10) to 2N_2O_5+4HPO_3 ` |
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| 519. |
Dinitrogen pentoxide ,a colourless deliquescentsolid is ,prepared byA. heating `NH_(2)NO_(2)` with an excess of oxygenB. dehydrating `HNO_(2)` with CaOC. dehydrating `HNO_(3)` with `P_(4)O_(10)`D. heating a mixture of `HNO_(2)" and "Ca(NO_(3))_(2)` |
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Answer» Correct Answer - C `P_(4)O_(10) + 4HNO_(3) rarr 4HPO_(3) + 2N_(2)O_(5)` |
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| 520. |
When an article is bleached by `SO_(2)` it loses its colour. The colour can be restored by :A. exposure to airB. heatingC. dilutonD. none of these |
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Answer» Correct Answer - A `SO_(2)+2H_(2)O to H_(2)SO_(4)+2H` `"coloured matter"underset("Oxidation")overset("Reduction")hArr`"colourless matter". |
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| 521. |
(a)Give reasons for the following : Nitric oxide becomes brown when released in air. (b)Ammonia acts as a ligand. Why ? ( c)Assign a reason for the following: `SCl_(6)` is not known but `SF_(6)` is known. |
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Answer» (a)Nitric oxide has one unpaired electron and hence is very reactive. As a result, it readily combines with `O_(2)` of the air to form nitrogen dioxide `(NO_(2))` which has brown colour. `underset("Colourless")(2NO)+O_(2)tounderset("Brown")(2NO_(2))` (b)Due to the presence of a lone pair of electrons on `N,NH_(3)` acts as a complexing agent (ligand).As a result, it combines with transition metal cations to form complexes.For example : `underset("Silver chloride")(AgCl)+ 2NH_(3) to underset("Diamminesilver(I)chloride")([Ag(NH_(3))_(2)]Cl)` `underset("copper sulphate")(CuSO_(4))+ 4NH_(3) to underset("Tetraamminecopper(II)suplhate")([Cu(NH_(3))_(4)]SO_(4))` `underset("Cromium chloride")(CrCl_(3))+ 6NH_(3) to underset("Hexaammine chromium(III)chloride")([Cr(NH_(3))_(6)]Cl_(3))` (c )Fluorine is a much stronger oxidizing agent than chlorine, therefore, it can easily oxidise sulphur to its maximum oxidation state of `+6` and hence forms `SF_(6)`.Chlorine, on the other hand, being a weaker oxidizing agent can oxidies sulphur at the maximum to its `+4` oxidation state and hence can form `SCl_(4)` but not `SCl_(6)`. |
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| 522. |
Which of the following properties describes the diagonal relationship between both boron and silicon ?A. `BCl_(3)` is not hydrolised while `SiCl_(4)` can be hydrolisedB. Both form oxides,`B_(2)O_(3)` is amphoteric, `SiO_(2)` is acidicC. Both metals dissolvesin cold and dilute nitric acidD. Borides and sillicides are hydrolysed by water |
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Answer» Correct Answer - D (A) `BCl_(3)` & `SiCl_(4)` can be hydrolysed (B) Both from oxides,`B_(2)O_(3)` & `SiO_(2)` are acidic in nature (C ) Both metals dissolve in hot nitric acid |
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| 523. |
Which importan t properties of aluminium are responsible for its great demand in industy? |
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Answer» (i) Aluminium is a very good conductor of electricity. (ii) Aluminium is not affected by air at room temperature. (iii) Alunimum is not attached by water. (iv) Aluminiu is a powerful reducing agent. All these prperties of the metal are responsible for tis great deman d in industyr. it is used: (i) in transmission cables for carrying electric current and also for windin g coils, motors and dynamous etc. (ii) as a reducing agent in the form of aluminium powder. this is known as thermit welding. (iii) for wrapping food preparatins, cigraettes, phthograps films etc. as it is not affected by air an d moisture. Aluminium foils are used for this purpose. |
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| 524. |
Match the columns and choose the correct options from the codes given below `{:(,,"Column I",,"Column II"),(,A.,"Orthoboric acid",1.,Na_(2)B_(4)O_(7)cdot4H_(2)O),(,B.,"Borax",2.,Na_(2)B_(4)O_(7)cdot10H_(2)O),(,C.,"Kernite",3.,H_(3)BO_(3)):}`A. `{:(,A,B,C),(,1,2,3):}`B. `{:(,A,B,C),(,3,2,1):}`C. `{:(,A,B,C),(,2,1,3):}`D. `{:(,A,B,C),(,1,3,2):}` |
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Answer» (b)Orthoboric acid is `H_(3)BO_(3)` Borax is `Na_(2)B_(4)O_(7)cdot10H_(2)O` Kernite is `Na_(2)B_(4)O_(7)cdot4H_(2)O` |
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| 525. |
Boron cannot from which one of the following anions?A. `BO_(2)^(-)`B. `BH_(4)^(-)`C. `B(OH)_(4)^(-)`D. `BF_(6)^(3-)` |
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Answer» Correct Answer - D Due to non-avilability of `d` -orbitals, boron cannot expands its octet. Therefore, the maximum covalent of boron cannot exceeds `4`. |
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| 526. |
Predict the correct shape of `BH_(4)^(-)`A. Pyramidal, `sp^(3)`B. octahedral, `sp^(3)d^(2)`C. tetrahedral, `sp^(3)`D. none of the above |
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Answer» Correct Answer - C Biin `BH_(4)^(-)` has four electron pairs, therefore , B is `sp^(3)`-hybridized and `BH_(4)^(-)` is tetrahedral. |
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| 527. |
Boron cannot form which one of the following anions ?A. `BF_(6)^(3-)`B. `BH_(4)^(-)`C. `B(OH)_(4)^(-)`D. `BO_(2)^(-)` |
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Answer» Correct Answer - A Due to absence of d-orbitals , B cannot extend its covalency beyond 4 and hence it can form `BF_(4)^(-), [B(OH)_(4)]^(-)` and `BO_(2)^(-)` but not `BF_(6)^(3-)`. |
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| 528. |
Minerals of radioactive origin such as pitch blende, monazite, cleveite are found to contain which of the boble gases?A. Helium and sometimes neonB. Neon and sometimes argonC. Helium and sometimes argonD. None of the above |
| Answer» Correct Answer - A | |
| 529. |
Which oxide a carbon is an anhydride of carbonic acid ? |
| Answer» Since carbonic acid decomposes to give `CO_(2)` and `H_(2)O` , therefore, `CO_(2)` is regarded as an anhydride of carbonic acid: `H_(2)CO_(3) rarr H_(2)O + CO_(2)`. | |
| 530. |
Statement-1 : Liquid `NH_(3)` is used for refrigeration. Statement-2 : Enthalpy of vapourisation of ammonia is very large.A. Statement-1 is True, Statement-2 is True, Statement-2 is a correct explanation for Statement-1B. Statement-1 is True, Statement-2 is True, Statement-2 is NOT a correct explanation for Statement-1C. Statement-1 is True, Statement-2 is False.D. Statement-1 is False, Statement-2 is True. |
| Answer» Correct Answer - A | |
| 531. |
Why does not silicon form an analogue of graphite ? |
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Answer» In graphite, carbon is `sp^(2)`-hybridized and each carbon is liked to three other carbon atoms by forming hexagonal rings. Each carbon is now left with on unhybridized p-orbital which undergoes sideways overlap to form three `ppi-ppi` double bonds. Thus, graphite has two dimensional sheet like (layered) structure consisting of a number of benzene rings fused together . Silicon on the other hand, does not forman anlogue of carbon because of the following reason : Due to bigger size kand smaller electronegativity of Si than C, it does not undergo `sp^(2)`-hybridization and hence it does not form `ppi-ppi` double bonds needed for graphite like structure . Instead , it prefers to undergo only `sp^(3)`-hybridization and hence silicon has diamond like three-dimensional network structure. |
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| 532. |
Among the following, the correct order of acidity is:A. `HClO lt HClO_(2) lt HClO_(3) lt HClO_(4)`B. `HClO_(2) lt HClO lt HClO_(3) lt HClO_(4)`C. `HClO_(4) lt HClO_(2) lt HClO lt HClO_(3)`D. `HClO_(3) lt HClO_(4) lt HClO_(2) lt HClO` |
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Answer» Correct Answer - A As the oxidation state of halogen i.e, `-Cl` in this case incraseses acidity of oxyacid increases. `HClO` : Oxidation state of `Cl = +1` `HClO_(2)` : Oxidation state of `Cl = +3` `HClO_(3)` : Oxidation state of `Cl = +5` `HClO_(4)` : Oxidation state of `Cl = +7` Therefore, the correct order of acidity would be `HClO lt HClO_(2) lt HClO_(3) lt HCl O_(4)` |
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| 533. |
It is because of inability of `ns^(2)` electrons of the valence shell to participate in bonding that:A. `Sn^(2+)` os reducing while `Pb^(4+)` is oxidisingB. `Sn^(2+)` os oxidising while `Pb^(4+)` is reducingC. `Sn^(2+)` and `Pb^(+)` are both oxidising and reducingD. `Sn^(4+)` is reducing while `Pb^(4+)` is oxidising |
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Answer» Correct Answer - D The inability of `ns^(2)` electrons of the valence shell to participate in bonding is called as inert pair effect. Due to this effect, the lower oxidation state becomes more stable on decending the group. Thus, `Sn^(+2)` is a reducing agent while `Pb^(4+)` act as an oxidising agent. |
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| 534. |
Which of the following is the most basic oxide ?A. `Al_(2)O_(3)`B. `Sb_(2)O_(3)`C. `Bi_(2)O_(3)`D. `SeO_(2)` |
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Answer» Correct Answer - C In `Al_(2)O_(3), Sb_(2)O_(2), Bi_(2)O_(3)` to `SeO_(2), Bl_(2)O_(3)` is most basic oxide. As across the period basic nature of oxide decreases and on moving down the group it increases. `Bi_(2)O_(3)+6HClrarr2BiCl_(2)+3H_(2)O` |
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| 535. |
Sea weeds are important source ofA. FB. ClC. BrD. I |
| Answer» Correct Answer - D | |
| 536. |
Give the formulae and describe the structures of a noble gas species, isoelectronic with `BrO_(3)^(-)` |
| Answer» `BrO_(3)^(-)` is iso-electronic with `XeO_(4)` and it has tetrahedral shape. | |
| 537. |
Give the formulae and describe the structures of a noble gas species, isoelectronic with `ICl_(4)` |
| Answer» `ICl_(4)^(-)` is also electronic with `XeF_(4)` and it has square planar shape. | |
| 538. |
Match the items of Columns I and II and mark the correct option. A. `{:(A,B,C,D),(4,3,1,2):}`B. `{:(A,B,C,D),(3,4,1,2):}`C. `{:(A,B,C,D),(4,1,4,3):}`D. `{:(A,B,C,D),(2,1,3,4):}` |
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Answer» A. -(4) B.-(3) C. -(1) D. -(2) A. `H_(2)SO_(4)` is used in strage batteries. B. `C Cl_(3)NO_(2)` is known as tear gas. C. `Cl_(2)` has highest electron gain enthalpy. D. Sulphur is a member of chalcogen i. e., ore producing elements. |
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| 539. |
Which of the following is/are correct for group 14 elements?A. The stability of dihalides are in the order `CX_(2) lt SiX_(2) lt GeX_(2) gt SnX_(2) lt PbX_(2)`B. The ability to form `PPI-PPI` multiple bonds among temselves increases down the groupC. The tendency for catenation decreases down the groupD. They all form oxides with the fomula `MO_(2)` |
| Answer» Correct Answer - A::C::D | |
| 540. |
Which of the following oxides are mixed oxide?A. `PbO_(2)`B. `SnO_(2)`C. `Pb_(2)O_(3)`D. `Pb_(3)O_(4)` |
| Answer» Correct Answer - C::D | |
| 541. |
Which one of the following oxides is neutral ?A)`CO`B)`SnO_(2)`C)`ZnO`D)`SiO_(2)`A. COB. `SnO_(2)`C. `ZnO`D. `SiO_(2)`. |
| Answer» Carbon monoxide (CO) is a neutral oxide. | |
| 542. |
Zeolite is used in which of the following cases?A. Conversion of alcohols into gasolineB. Cracking of hydrocarbonsC. Isomerisation of hydrocarbonsD. Softening of hard water |
| Answer» Correct Answer - A::B::C::D | |
| 543. |
Basic unit fo zeolite, mica, asbestos and feldpar isA. `(SiO_(4))^(4-)`B. `(SiO_(3))^(2-)`C. `(SiO_(4))^(2-)`D. `SiO_(2)` |
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Answer» Correct Answer - A Quart, mica, asbestos have common unit `(SiO_(4))^(4-)` |
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| 544. |
`SnO_(2)` isA. AcidicB. AlkalineC. AmphotericD. Neutral |
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Answer» Correct Answer - C `SnO_(2)` is amphoteric. |
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| 545. |
The basicity of pyrophosphorous acid isA. 2B. 4C. 1D. 5 |
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Answer» Correct Answer - A Pyrophosphorous acid is `H_4P_2O_5` `HO-underset(O)underset(||)overset(H)overset(|)P-O-underset(O)underset(||)overset(H)overset(|)P-OH ` Since , two-OH groups are present hence , basicity is two. |
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| 546. |
Which of the following oxides is acidic in nature?A. `B_(2)O_(3)`B. `Al_(2)O_(3)`C. `Ga_(2)O_(3)`D. `In_(2)O_(3)`. |
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Answer» Correct Answer - A `B_(2)O_(3)` is acidic nature `B_(2)O_(3)+3H_(2)Orarr2B( OH)_(3)` |
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| 547. |
Assertion. Boron always forms covalent compounds. Reason. The small size of `B^(3+)` favours formation of covalent bonds.A. If both assertion and reason are true, and reason is the true explanation of the assertion.B. If both assertion and reason are true, but reason not is the true explanation of the assertion.C. If assertion is true, but reason is false.D. If both assertion and reason are false. |
| Answer» Correct Answer - A | |
| 548. |
Four statements are given below: (P) `B_(2)` solid does not exist, boron have basic building `B_(12)`icosahedral units made up of polyhedron having 20 faces nad 12 corners. (Q) In alum each metal ion is surrounded by six water molecules. ( R) Graphite is used as dry lubricant in machines running at high temperature in place of oil. (S) Fullerene contains twenty, six-membered rings and twelve, five-membered rings. The correct statements are:A. P,R and SB. P and SC. P,Q,R and SD. Q and S |
| Answer» Correct Answer - C | |
| 549. |
Statement-1. Boron always forms covalent bonds. Statement-1. The small size of `B^(3+)` favours formation of covalent bond.A. Statement-1 is True, Statement-2 is True , Statement-2 is a correct explanation for statement-1.B. Statement-1 is True, Statement-2 is True , Statement-2 is not a correct explanation for statement-1.C. Statement-1 is True, Statement-2 is False.D. Statement-1 is False, Statement-2 is True. |
| Answer» Correct Answer - A | |
| 550. |
Name one ore of boron. |
| Answer» Correct Answer - Colemanite | |