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3701.

Where will g be greatest when one goes from the centre of earth to an altitude equal to radius of earth?

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At the SURFACE of EARTH
At the CENTRE of earth
At the HIGHEST point
None of the above

Solution :At the surface of earth
3702.

Define ruistance. Write the SI unit of resiatance. Match the correct range of rui1tivlty with the materialsgiven : {:((i) "Conductors" ,(a)10^(-6) Omegam),((ii) "Alloys" ,(b)10^(12)"to" 10^(17) Omega m),((iii) "Insulators",(c)10^(-6) "to"10^(-8)Omega m):}

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Solution :Blectrical resistance of a conductor may be considered as a measure of the OPPOSITION offered by it for the FLOW of electric charge through it. SI UNIT of rnistance is ohm.
`{:((i) "Conductors" ,(a)10^(-6) Omegam),((ii) "Alloys" ,(b)10^(12)"to" 10^(17) Omega m),((iii) "INSULATORS",(c)10^(-6) "to"10^(-8)Omega m):}`
3703.

An …………. Telescope is used to view heavenly bodies like strars , planets galaxies and satellites

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SOLUTION :ASTRONOMICAL
3704.

A ray of light is incident normally on a plane glass slab. What will be (i) the angle of refraction, and (ii) the angle of deviation for the ray ?

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ANSWER :(i) `0^(@)`
(II) `0^(@)`.
3705.

Through which of the two wires, the electric current will flow more easily : (i) a thick wire or (ii) a thin wire of the same material, and of the aame length when connected to the same source ?

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SOLUTION :A THICK WIRE.
3706.

Mr. Sharma while driving his bike sees a woman behind driving a moped through his rear view mirror. He sees that her sari almost touching the wheels of the vehicle. He stops and alerts her What king of mirror is used as a rear view mirror?

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Solution :convex MIRROR is USED as a REAR VIEW mirror
3707.

How does the resistance of a wire vary with its area of cross-section?Explain.

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Solution :The RESISTANCE of a WIRE is inversly proportional to its area of cross-section `i.e., R PROP 1/A`.
Thus. if the wire is thick (large area of cross-section), then its resistance is less. If the wire is thin (less area of cross-section), then its resistance is large.
3708.

Why do we see a rainbow in the sky only after rainfall ?

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SOLUTION :A RAINBOW in seen when SUNLIGHT is refracted and dispered on passing through rain droplets, which remain suspended in AIR after rainfall.
3709.

Mr. Sharma while driving his bike sees a woman behind driving a moped through his rear view mirror. He sees that her sari almost touching the wheels of the vehicle. He stops and alerts her What values you observe in Mr. sharma?

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SOLUTION :The FOLLOWING values are OBSERVED in Mr. sharma. They are
(1) Concern about others(2) Observation of Traffic rules(3) RESPONSIBLE citizen
3710.

The path of a free electron in a metal is

Answer»

Parabolic
Circular
a STRAIGHT LINE
ZIG zag

Answer :D
3711.

Arrange the properties of light accordingly , when light travels through any transparent medium. Diffraction,Dispersion , Reflection, Refraction.

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SOLUTION :REFLECTION, REFRACTION, Reflection, Refraction
3712.

What happens when a ray of light is incident normal to the interface between two media? Draw the corresponding neat and labelled diagram.

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Solution :When a RAY of LIGHT is incident normal to the INTERFACE between two MEDIA, the ray propagates undeviated as it travelsfrom the first medium to the second medium irrespective of the refractive indices of the two media.In this case, the angle of incidence ( i) is zero and so also the angle of REFRACTION ( r) .
3713.

The critical angle for glass-air is 45^(@) for the light of yellow colour. State whether it will be less than, equal to, or more than 45^(@) for (i) red light, and (ii) blue light ?

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ANSWER :(i) more than `45^(@)`
(II) LESS than `45^(@)`.
3714.

Why do the pendulum clock run slow in summer and fast in winter?

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Solution :As we know that time period of pendulum CLOCK `T=2pi sqrt((L)/(g))` at a place g and `2pi` are constant so `T ALPHA sqrt(T)`
The length of pendulum in summer INCREASES so time period of pendulum is increased So pendulum takes more time to complete one OSCILLATION and clock becomes slow in summer. Vice-versa in winter it becomes fast as time period of pendulum is decreased due to DECREASE in length of pendulum.
3715.

List two ways in which animal dung can be utilized as a fuel. Out of these two which one do you think is better ? Justify your answer.

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Solution :Two ways:
(i) as cow dung cakes,
(II) as BIOGAS.
Biogas is better than cow dung cakes because it has high heating capacity and are non-polluting as it burns WITHOUT smoke and leaves no residue like ash. Slurry left in the biogas plant is a good MANURE for fields.
3716.

When is an induced currentin a coil maximum ?

Answer»

SOLUTION :A currentcan beinduced in a coil eitherby moving it in a magneticfieldof a magnet ( or of a CURRNET - carryingconductor ) or bymovinga magnet towardsor AWAY from it .
3717.

What is the ratio of object distance to image distance in case of a concave mirror when its magnification is 0.5?

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2
4
1
None

Answer :A
3718.

How is specificheatmeasured ? OrExplainmixingmethod for measurementofspecific heat.

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Solution :(i) The speificheatof anobject can bemeasuredbymixingmethodusinga calorimeter.
(ii) whena hotsolidmetallicball (sphere) is putin WATERIN a calorimeter , heat exchangestartsbetweenhot object , waterandcaloriner.
(iii) Thiscontinuestill thetemperatureof all thetherebecomes equal.
(IV) Heat lost by HOT object `(Q_(1))`is equalto Heightgainedby waterand calorimeter .
(v) If thespeificheatof waterandcalorimeterare knownthen the speificheatof solidobjectcan be CALCULATED.
3719.

One - half of a convex lens is covered with a black paper. Will this lens produce a complete image of the object ? Verify your answer experimentally. Explain your observations.

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SOLUTION :The convex lens will form complete image of an object, even if its one HALF is covered with black paper. It can be UNDERSTOOD by the following two cases
Case 1 :

When the upper half of the lens is covered. In this case, a ray a light COMING from the object will be refracted by the lower half of the lens. These rays meet at the other side of the lens to from the image of the GIVEN object, as shown in the above figure.
Case 2.

When the lower half of the lens is covered.
In this case, a ray of light coming from the object is refracted by the upper half of the lens. These rays meet at the other side of the lens to form the image of the given object, as shown in the above figure.
3720.

As pressure on a gas increases the P.E. between molecucles of gas.................

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SOLUTION :DECREASES
3721.

Fleming's left hand rule: Direction of the force on conductor: : Fleming's right hand rule: .....................

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SOLUTION :DIRECTION of INDUCED CURRENT
3722.

Calculate the resistance of a metal wire of length 2 m and area of cross section 1·55 xx 10^(-6) m^(2), if the resistivity of the metal be 2·8 xx 10^(-8) Omega m ?

Answer»

SOLUTION :`R=(rhol)/(A)`
`=(2.8xx10^(-8)xx2)/(1.55xx10^(-6))`
`=(2.8xx2xx10^(-8-(-6)))/(1.55)`
`=(2.8xx2)/(1.55)xx10^(-2)=0.036 OMEGA`
3723.

Describe an activity to find the acceleration and velocity of an object moving on inclined track.

Answer»

Solution :Aim : To find the acceleration and velocity of an object moving on an inclined track.
Materials required : Glass marbles, book, digital clock, long plastic tubes and steel plate.
Procedure :
1) Take a long plastic U type flat electrical wire cassing channel of length nearly 200CM. Use these tube parts as tracks.
2) Mark the readings in cm, along the track.
3) Place the one end of the track on the book and the other end on the floor.
4) Keep a steel plate on the floor at the bottom of the track.
5) Consider the reading at the bottom of the track as zero.
6) Take a MARBLE having enough size to travel in the track frrely.
7) Now release marble freely from a certain distance say 40 cm.
8) Start the digital clock when the marble is released.
9) It MOVES down on the track and strikes the steel plate.
10) Stop the digital clock when sound is produced.
11) Repeat the same experiment for the same distance 2 to 3 times and note the valuse of time in the table.

12) Repeat the same experiment for various distances.
13) Draw s - t graph for above values.
14) Do the above experiment by various slopes of the track and find acceleration in each case.
Conclusions : 1) As the slope increases, acceleration increases.
2) When iron block is used, we obtain the same conclusion as above. (The numerical values are less than the numerical values when marble is used)
3724.

A car moving with a speed of 30ms^(-1) takes a U-turn in 6 seconds, without changing its speed. What is the average acceleration during these 6 seconds?

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`5MS^(-2)`
`10MS^(-2)`
`2.5ms^(-2)`
zero

Answer :B
3725.

Dispersion, Scattering of light, Total internal reflection, Refraction.

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Solution :Scattering of light All other phenomena are RESPONSIBLE for the RAINBOW formation, WHEREAS scattering of light does not contribute to the formation of rainbows.
3726.

Which one of the following is a Low Earth Orbit (LEO) satellite ?

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NAVIGATIONAL satellite
Geotationary satellite
International SPACE Station
All of the above

ANSWER :A::C
3727.

Name the three forms in which energy from an ocean is made available for use. What are OTEC power plants?

Answer»

SOLUTION :(i) Ocean thermal ENERGY.
(II) Sea-waves energy.
(iii) Tidal energy.
OTEC are ocean-thermal-energy COVERSION [OTEC] power plants which harness energy due to the difference In temperature at surface of sea and at depths of up to 2000 METRES.
3728.

The particle of checkig the preparedness of facing the disaster by creating a virtual or apparent situation of disaster.

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ANSWER :MOCK DRILL
3729.

Electromagnetic induction was discovered by :

Answer»

Faraday
Ampere
Coulomb
none of these

Answer :A
3730.

According to Boyle's law, the shape of the graph between pressure and reciprocal of volume is ............

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SOLUTION :STRAIGHT LINE
3731.

Does the speed of light increases or decreases in a medium in comparison to its value in vacuum? Give an illustrative example.

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Solution :SPEED of LIGHT DECREASES in the PRESENCE of a MEDIUM e.g., when a light ray enters in water from air its speed decreases.
3732.

Give an example of a phenomenon where Tyndall effect can be observed:

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SOLUTION :When a fine beain of sunlight enters a roomcontaining SUSPENDED dust, the path of the beam of LIGHT is visible, It is due to the SCATTERING of Ught.
3733.

What do the symbols given below represent in a circuit ? Write one function of each.

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SOLUTION :First SYMBOL is variable RESISTANCE and second is ammeter. Variable resistance changes the magnitude of current in the circuit, by VARIATION in resistance. Ammeter is used to find current.
3734.

The diagram below shows a glass block suspended in a liquid. A beam of light of single colour is incident from liquid on one side of the block. (a) Draw diagrams to show how does the light bend when it travels from liquid to glass and then to liquid if (i) the light slows down in glass, and (ii) the light speeds up in glass. (b) State two conditions under which the light ray passing from liquid to glass travels straight without bending. will the glass be visible then ?

Answer»

Solution :(a) (i) If light shows down in going from liquid to glass, it means that `mu_(glass) gt mu_(liquid)`, so it will BEND towards the normal at the POINT of incidence in passing from liquid to glass at the first surface, while it will bend away from the normal at the SECOND surface in passing from glass to liquid. the ray diagram is shown in figure. the light beam suffers lateral displacement.

(ii) If light speeds up in going from liquid to glass, it means that `mu_(glass) lt mu_(liquid)`, so it will bend away from the normal at the point of incidence on the first surface in passing from liquid to glass, while it will bend towards the normal at the second surface in passing from glass to liquid. the ray diagram is shown in figure. the light beam sufers lateral displacement in a direction opposite to that in case (i).

(b) A light ray passing from liquid to glass travels straight WITHOUT bending under the following two conditions:
(1) when the light ray falls normally on glass from liquid (i.e., if `anglei=0^(@),angler=0^(@)`)
(2) When refractive index of liquid is same as that of glass (or speed of light in glass is same as in liquid).
In both the above conditions, the glass BLOCK will not be visible inside the liquid.
3735.

If gamma be the ratio of specific heats (C_(p) & C_(v)) for a perfect gas. Find the number of degrees of freedom of a molecules of the gas?

Answer»

`25((gamma-1))/(2)`
`9((gamma-1))/(2)`
`(3gamma-1)/(2gamma-1)`
`(2)/(gamma-1)`

SOLUTION :`gamma=1+(1)/(F)`
3736.

Carbon, a member of group 14 forms a large number of carbon compounds estimated to be about 3 million. Why is this property not exhibited by other elements of this group? Explain.

Answer»

Solution :carbon has a UNIQUE ability to form bonds with other atoms of carbon giving RISE to large molecules . This property is called catenation.
This property can be explained in terms of a small size of carbon the bonds FORMED are STRONG bonds as the size of carbon is small it enables it to hold on the shared pairs of electrons and therefore these are stable bonds other members of this GROUP do not forms large number of compounds because of greater atomic size as the size of the atomic increases the hold of the nucleus on the share shared electrons decreases therefore the bond form formed is not stable and strong carbon forms cyclic compound as well carbon forms compounds with carbon carbon double and triple bonds also
3737.

An object is placed vertically at a distance of 20 cm from a convex lens. If the height of the object is 5 cm and the focal length of the lens is 10 cm, what will be the position, size and nature of the image? How much bigger will the image be as compared to the object?

Answer»


Solution :Given: Height of the object `(h_(1)) = 5 cm`,
focal length (f) = 10 cm,
distance of the object (u) = -20 cm
To find: IMAGE distance (v), height of the image `(h_(2))`, magnification (M)
FORMULAE: i. `(1)/(v)-(1)/(u)=(1)/(f)`
ii. Magnification (M) `(h_(2))/(h_(1))=(v)/(u)`
Calculation: From formula (i),
`(1)/(v)=(1)/(u)+(1)/(f)`
`therefore" "(1)/(v)=(1)/(-20)+(1)/(10)`
`therefore" "(1)/(v)=(-1+2)/(20)`
`therefore" "(1)/(v)=(1)/(20)`
`therefore" "v=20 cm`
From formula (ii),
`h_(2)=(v)/(u)xxh_(1)`
`therefore" "h_(2)=(20)/(-20)xx5`
`therefore" "h_(2)=(-1)xx5`
`therefore" "h_(2)=-5 cm`
`therefore" "M=(v)/(u)=(20)/(-20)=-1`
The negative sign of the height of the image and the magnification shows that the image is inverted and REAL. It is below the PRINCIPAL axis and is of the same size as the object.
3738.

Metastasis is associated with

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BENIGN tumour
Malignant tumour
Both (a) and (B)
Crown gall tumour

ANSWER :B
3739.

A thermally insulated pot has 150 g ice at temperature0^(@)C. How much steam of100^(@) Chas to be mixedto it , so that water of temperature50^(@)Cwill be obtained ?( Given : Latent heat of melting of ice = 80 cal/g, latent of vaporization of water = 540 cal/g, spcific heat of water =1 cal// g.^(@)C)

Answer»

SOLUTION :Data `: m_(1) = 150 g,Delta T_(1) = 50^(@)C - 0^(@) C =50^(@)C, c_(w) = 1 cal //g .^(@)C , L_(1) = 80 cal//g,L _(2) = 540 cal //g , Delta T_(2) = 100^(@) C - 50^(@)C = 50^(@) C, m_(2) =?`
`Q_(1)` ( heat absorbed by ice) `m_(1) L_(1) =150 gxx80 cal //g = 12000 cal`
`Q_(2) ` ( heat absorbed by water FORMED on melting of ice ) `= m_(1) c_(w) Delta T_(1)`
`= 150 g xx 1 cal //g .^(@) C xx 50 ^(@)C = 7500 cal `
`Q_(3) `( heat GIVEN out by steam ) `= m_(2) L_(2) = m_(2) xx 540 cal //g`
`Q_(4)` ( heat given out by water formed on condensation of steam )
`m_(2) c_(w) Delta T_(2) = m_(2) xx 1 cal //g. ^(@) C xx 50^(@) C `
According to the principle of heat exchange, `Q_(1) + Q_(2) = Q_(3) + Q_(4)`
`:. 12000 cal + 7500 cal =m_(2)xx 540 cal //g + m_(2) xx 50 cal //g `
`:. 19500 cal =m_(2) ( 540 + 50) cal //g `
`:. m_(2) = ( 19500)/(590) g =33.05 g `
`33.05 g ` of steam is to be mixed.
3740.

A ray of light moving along the principal axis is falling on a concave mirror. In which direction is it reflected ?

Answer»

SOLUTION :The ray is REFLECTED back along the principal AXIS of MIRROR because here `angle r = angle i= 0^(@)`.
3741.

How are concave and covex mirrors constructed?

Answer»

Solution :To construct a concave mirror,
The inner or concave side of a hollow SPHERICAL glass is polished, so that it becomes a REFLECTING SURFACE.
Or, else the outer convex side is COATED with silver and painted with lead oxide to make it an OPAQUE surface .
To construct a convax mirror,
The outer or convex side of a hollow spherical glass is polished, so that it becomes a reflecting surface.
Or else, the inner concave side is coated with silver and is painted with lead oxide to make it an opaque surface.
3742.

The focal length of ……………. Lens is positive.

Answer»


ANSWER :CONVEX
3743.

What is cubical expansion?

Answer»

SOLUTION :The RATIO of increase in volume of the BODY per DEGREE rise in temperature to its unit volume is called as COEFFICIENT of cubical expansion.
3744.

The stars appear higher from horizon than they actually are. Explain why it is so.

Answer»

Solution :As we go up and up in earth.s atmosphere, it goes on becoming rarer and more rarer. As a result, the atmospheric layer near the earth.s surface has maximum REFRACTIVE index and the refractive index GRADUALLY DECREASES with increase in height. When light ray from a star enters into earth.s atmosphere, Star star position, Ray path . Refractive index increasing it travels from rarer to denser MEDIUM and hence continues to bend towards the normal. As a result, an observer on earth considers the apparent position of star to be at a higher altitude as shown in FIG. 118.
3745.

Thestrenght ofmagneticfieldalongthe axisof a solenoidcoil:

Answer»

INCREASE on increasingcurrentflowingthrough thesolenoid coil
increase on INCREASINGTHE number ofturns in the solenoid coil
increaseson introducinga soft iron coreinside thesolenoidcoil .
all to the above

SOLUTION :The strength of magnetic field along the axis of a solenoid coil increases on increasing the current flowing through the solenoid coil and on increasing the number of TURNS in the solenoid coil. Moreover, if a soft iron core is inserted inside the solenoid ROIL then magnetic field increases many fold.
3746.

The speed of light in a transparent medium is 2.4xx10^(8) m/s. Calculate absolute refractive index of the medium.

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Solution :Given :`v_(1) =3xx10^(8)` m/s
…..[VELOCITY of light in vacuum]
`v_(2)=2.4xx10^(8)`m/s
To FIND : `""_(1)n_(2)`
Formula : `""_(1)n_(2)=(v_(1))/(v_(2))`
Solution : `""_(1)n_(2)=(v_(1))/(v_(2))=(3x10^(8))/(2.4x10^(8))`
1.25
3747.

The only correct statement for the two circuits (X) and (Y) shown below is :

Answer»

The resistors `R_(1)` and `R_(2)` have been connected in SERIES in both the circuits
The resistors `R_(1)` and `R_(2)` have been connected in parallel in both the circuits
In the circuit (X) the resistors have been connected in parallel WHEREAS these are connected in series in circuit (Y).
In the circuit (X) the resistors `R_(1)` and `R_(2)` are connected in series while these are connected in parallel in circuit (Y)

SOLUTION :NA
3748.

Biodiversity.

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SOLUTION :Biodiversity means the diverse life forms that inhabit any area. Biodiversity is seen due to VARIETY of life forms and different ecosystems that LODGE organisms. In nature there is biodiversity on the three different LEVELS, viz. genetic diversity, species diversity and ecosystem diversity. This means that there is diversity in the individuals belonging to the same species due to genetic reasons there is diversity among the different species of organisms and there is also a diversity in the ecosystems that are present in any region.
Due to development of MANKING, the biodiversity is threatened. There are special efforts taken to restore the lost and threatened biodiversity. Some of these are establishing sanctuaries, National Parks, biodiversity hotspots and reserves, etc. Certain endangered species are protected by carrying out conservation projects.
3749.

Define electric power. Derive relation between power, potential difference and resistance.

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SOLUTION :The RATE at which electric energy is DISSIPATED or CONSUMED in an electric circuit is CALLED electric power P`=(V^(2))/(R)`
3750.

A beam of light converges to a point P. A lens is placed is the path of convergent beam 12cm from the point P. At what point the beam converges if the lens is a concave lens of focal length 16cm a convex length of focal length 20cm

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Solution :Here u=12cm f=-16cm the lens EQUATION we have
V=uf/u+f=12`xx-16-:12-16=48` cm as v is positive the BEAM converges on the same SIDE that of point P