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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your Class 11 knowledge and support exam preparation. Choose a topic below to get started.
| 38801. |
Explain why : (a) Two bodies at different temperatures T_1 and T_2 if brought in thermal contact do not necessarily settle to the mean temperature (T_1 + T_2 )//2. (b) The coolant in a chemical or a nuclear plant (i.e., the liquid used to prevent the different parts of a plant from getting too hot) should have high specific heat. (c) Air pressure in a car tyre increases during driving. (d)The climate of a harbour town is more temperate than that of a town in a desert at the same latitude. |
| Answer» <html><body><p></p>Solution :(a) It is due to that two bodies may have different thermal capacity. When they are brought in thermal contact, <a href="https://interviewquestions.tuteehub.com/tag/heat-21102" style="font-weight:bold;" target="_blank" title="Click to know more about HEAT">HEAT</a> flows from the body at higher temperature to the body at lower temperature till equilibrium is achieved means, the temperature of both the bodies becomes equal. If both bodies have same thermal capacities their final mean temperature may have `(T_1+T_2)/2`. <br/> (b) This is because heat absorbed by a substance is directly proportional to be specific heat of the body so, for the same amount of increasing in temperature and body having high specific heat, higher is its heat absorbing capacity and hence this would prevent the <a href="https://interviewquestions.tuteehub.com/tag/plant-1155789" style="font-weight:bold;" target="_blank" title="Click to know more about PLANT">PLANT</a> from getting too hot. <br/> (c) When a car is in motion the air temperature inside the car increases because of the motion of the air molecules. According to Charles. law temperature is directly proportional to pressure ( P`prop`T). Hence, if the temperature inside a tyre increases, then the air pressure in it will <a href="https://interviewquestions.tuteehub.com/tag/also-373387" style="font-weight:bold;" target="_blank" title="Click to know more about ALSO">ALSO</a> increases. <br/> (d) In the atmosphere of harbour near the <a href="https://interviewquestions.tuteehub.com/tag/ocean-1127860" style="font-weight:bold;" target="_blank" title="Click to know more about OCEAN">OCEAN</a> side, the vapour of the ocean water mixes with the air near the ocean so, atmosphere stays warm. While in the atmosphere of jungle situated at same latitude, there is no water vapour present and so its atmosphere stays less warm.</body></html> | |
| 38802. |
A black body radiates heat energy at the rate of 2 xx 10^(5)J//s m^(2) at the temperature of 127^(@)C. Temperature of the black body at which rate of heat radiation 32 xx 10^(5) J//s m^(2), is |
| Answer» <html><body><p>400K<br/>600K<br/>800K<br/>200K</p>Solution :Here, `E_(1) = 2 xx <a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a>^(<a href="https://interviewquestions.tuteehub.com/tag/5-319454" style="font-weight:bold;" target="_blank" title="Click to know more about 5">5</a>)J//s m^(2), T_(1) = 127^(@)<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a>= 400K and E_(2) = 32 xx 10^(5) J//s m^(2)` <br/> By Stefan.s <a href="https://interviewquestions.tuteehub.com/tag/law-184" style="font-weight:bold;" target="_blank" title="Click to know more about LAW">LAW</a>, the rate of emission of radiated energy per unit area per unit time is <br/> `E= sigma T^(<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>)` <br/> `:. (E_(2))/(E_(1)) = (T_(2)^(4))/(T_(1)^(4)) or (T_(2))/(T_(1)) = ((E_(2))/(E_(1)))^(1//4) = ((32 xx 10^(5))/(2 xx 10^(5)))^(1//4) = 2` <br/> or `T_(2) = 2 xxT_(1) =2 xx 400= 800K`</body></html> | |
| 38803. |
A square hole is punched out of a circular lamena, the diagonal of the square coinciding with the radius of circle. If .a. be the diameter of the circle, the distance of the centre of mass of reminder from previous centre of mass. |
| Answer» <html><body><p>`(<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>(2pi-1))/a`<br/>`a/(2pi-1)`<br/>`a/(4(2pi-1))`<br/>no <a href="https://interviewquestions.tuteehub.com/tag/change-913808" style="font-weight:bold;" target="_blank" title="Click to know more about CHANGE">CHANGE</a> </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 38804. |
If A and B persons are moving with V_(A) and V_(B) velocities in opposite directions. Magnitude of relative velocity of B w.r.t. A is x and magni-tude of relative veloctiy of A w.r.t B is y. Then |
| Answer» <html><body><p>xgty<br/><a href="https://interviewquestions.tuteehub.com/tag/x-746616" style="font-weight:bold;" target="_blank" title="Click to know more about X">X</a> = y <br/>x = <a href="https://interviewquestions.tuteehub.com/tag/2y-301307" style="font-weight:bold;" target="_blank" title="Click to know more about 2Y">2Y</a> <br/><a href="https://interviewquestions.tuteehub.com/tag/2x-301182" style="font-weight:bold;" target="_blank" title="Click to know more about 2X">2X</a> = y </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 38805. |
Two vibrating tuning forks produce waves whose equation is given by y_(1) = 5 sin (240 pi t) and y_(2) = 4 sin (244 pi t) . Compute the number of beats per second . |
| Answer» <html><body><p></p>Solution :Given `y_(1) = 5 sin (240 pi t) ` and `y_(2) = 4 sin (<a href="https://interviewquestions.tuteehub.com/tag/244-1827768" style="font-weight:bold;" target="_blank" title="Click to know more about 244">244</a> pi t)` <br/> Comparing with `y = A sin (2 pi f_(1) t)` , we get <br/> `2pi f_(1) = 240 pi <a href="https://interviewquestions.tuteehub.com/tag/implies-1037962" style="font-weight:bold;" target="_blank" title="Click to know more about IMPLIES">IMPLIES</a> f_(1) = 120 Hz` <br/> `2pi f_(2) = 244 pi implies f_(2) = <a href="https://interviewquestions.tuteehub.com/tag/122-271030" style="font-weight:bold;" target="_blank" title="Click to know more about 122">122</a> Hz` <br/> The number of beats <a href="https://interviewquestions.tuteehub.com/tag/produced-592947" style="font-weight:bold;" target="_blank" title="Click to know more about PRODUCED">PRODUCED</a> is `|f_(1) - f_(2)| = |120 - 122| = |-2| = 2 ` beats per sec</body></html> | |
| 38806. |
Select the correct statement for a body in simple harmonic motion, loss of kinetic energy is proportional to : |
| Answer» <html><body><p>`x^(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)`<br/>`x^(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)`<br/>`log x`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/e-444102" style="font-weight:bold;" target="_blank" title="Click to know more about E">E</a>^(x)`</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 38807. |
Consider ..n.. number of indentical cubes each of mass ..m.. and side ..a.. lying on a level ground. Find work done in piling them one above the other. |
| Answer» <html><body><p></p>Solution :The initial total <a href="https://interviewquestions.tuteehub.com/tag/potential-1161228" style="font-weight:bold;" target="_blank" title="Click to know more about POTENTIAL">POTENTIAL</a> energy of all the blocks lying on the ground is ` U_(1) = nxxmg""(a)/(2)` <br/> The potentia energy, when the blocks are piled to form a single <a href="https://interviewquestions.tuteehub.com/tag/column-922494" style="font-weight:bold;" target="_blank" title="Click to know more about COLUMN">COLUMN</a> is `U_(2) = nmg""(na)/(2) = <a href="https://interviewquestions.tuteehub.com/tag/n-568463" style="font-weight:bold;" target="_blank" title="Click to know more about N">N</a> ^(2) <a href="https://interviewquestions.tuteehub.com/tag/mg-1095425" style="font-weight:bold;" target="_blank" title="Click to know more about MG">MG</a>""(a)/(2)` <br/> `<a href="https://interviewquestions.tuteehub.com/tag/therefore-706901" style="font-weight:bold;" target="_blank" title="Click to know more about THEREFORE">THEREFORE</a>` Work done in arranging the blocks one above the other is `W = U_(2) - U_(1)` <br/> `W=n^(2)mg""(a)/(2)-nxxmg""(a)/(2)(n^(2)-n)` <br/> or `W = mg""(a)/(2)n (n-1)`</body></html> | |
| 38808. |
Derive an expression for co-efficient of performance of refrigerator. |
| Answer» <html><body><p></p>Solution :Coefficient of performance (COP)`(beta)`: COP is a <a href="https://interviewquestions.tuteehub.com/tag/measure-1091857" style="font-weight:bold;" target="_blank" title="Click to know more about MEASURE">MEASURE</a> of the efficiency of a <a href="https://interviewquestions.tuteehub.com/tag/refrigerator-1181966" style="font-weight:bold;" target="_blank" title="Click to know more about REFRIGERATOR">REFRIGERATOR</a>. It is defined as the ratio of heat extracted from the cold <a href="https://interviewquestions.tuteehub.com/tag/body-900196" style="font-weight:bold;" target="_blank" title="Click to know more about BODY">BODY</a> (sink) to the <a href="https://interviewquestions.tuteehub.com/tag/external-981194" style="font-weight:bold;" target="_blank" title="Click to know more about EXTERNAL">EXTERNAL</a> work <a href="https://interviewquestions.tuteehub.com/tag/done-2591742" style="font-weight:bold;" target="_blank" title="Click to know more about DONE">DONE</a> by the compressor W. <br/> COP `= beta = (Q_(L))/W`...(1) <br/> From the equation `Q_(L)+W=Q_(H)` <br/> `beta = (Q_(L))/(Q_(H) - Q_(L))` <br/> `beta = (1)/((Q_(H))/(Q_(L)) - 1)`...(2) <br/> But we know that `(Q_(H))/(Q_(L)) = (T_(H))/(T_(L))` <br/> Substituting this equation into equation (1) we get `beta = (1)/((T_(H))/(T_(L)) - 1) = (T_(L))/(T_(H) - T_(L))`</body></html> | |
| 38809. |
Answer carefully, with reasons : What are the answers to (a) and (b) for an inelastic collision? |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Linear <a href="https://interviewquestions.tuteehub.com/tag/momentum-1100588" style="font-weight:bold;" target="_blank" title="Click to know more about MOMENTUM">MOMENTUM</a> is conserved during an inelastic <a href="https://interviewquestions.tuteehub.com/tag/collision-922060" style="font-weight:bold;" target="_blank" title="Click to know more about COLLISION">COLLISION</a>, kinetic <a href="https://interviewquestions.tuteehub.com/tag/energy-15288" style="font-weight:bold;" target="_blank" title="Click to know more about ENERGY">ENERGY</a> is, of course, not conserved <a href="https://interviewquestions.tuteehub.com/tag/even-976335" style="font-weight:bold;" target="_blank" title="Click to know more about EVEN">EVEN</a> after the collision is over.</body></html> | |
| 38810. |
A copper wire of 1mm diameter is stret- ched by applying a forcre of 10 N. Find the stress in the wire. |
| Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>.273xx10^(<a href="https://interviewquestions.tuteehub.com/tag/7-332378" style="font-weight:bold;" target="_blank" title="Click to know more about 7">7</a>)N//m^(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)`<br/>`1.373xx10^(7)N//m^(2)`<br/>`1.473xx10^(7)N//m^(2)`<br/>`1.573xx10^(7)N//m^(2)` </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :1</body></html> | |
| 38811. |
The graph between the time period and the length of a simple pendulum is a: |
| Answer» <html><body><p>Straight line<br/>Curve<br/>Ellipse<br/><a href="https://interviewquestions.tuteehub.com/tag/parabola-1146268" style="font-weight:bold;" target="_blank" title="Click to know more about PARABOLA">PARABOLA</a></p>Solution :For a simple pendulum, <br/> `T <a href="https://interviewquestions.tuteehub.com/tag/prop-607409" style="font-weight:bold;" target="_blank" title="Click to know more about PROP">PROP</a> <a href="https://interviewquestions.tuteehub.com/tag/sqrt-1223129" style="font-weight:bold;" target="_blank" title="Click to know more about SQRT">SQRT</a>(<a href="https://interviewquestions.tuteehub.com/tag/l-535906" style="font-weight:bold;" target="_blank" title="Click to know more about L">L</a>)` <br/> `T^(2) prop l` <br/> Graph between T and l will be a parabola symmetic about T-axis.</body></html> | |
| 38812. |
A wire of length1 m and radius 1mm is subjected to a load. The extension is 'x'. The wire is melted and then drawn into a wire of square cross-section of side 1 mm. What is its extension under the same load? |
| Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/pi-600185" style="font-weight:bold;" target="_blank" title="Click to know more about PI">PI</a>^(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>) <a href="https://interviewquestions.tuteehub.com/tag/x-746616" style="font-weight:bold;" target="_blank" title="Click to know more about X">X</a>`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/pix-2222284" style="font-weight:bold;" target="_blank" title="Click to know more about PIX">PIX</a>^(2)`<br/>`pi x`<br/>`pi//x`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html> | |
| 38813. |
A brass disc at 0^(@) C has a diameter of 50Cm and a hole of diameter I 0cm. For Brass alpha = 18 xx 10^(-6)//^(@) C. When the disc is heated to 100^(@) C, the diameter of the hole becomes. |
| Answer» <html><body><p>10.018 <a href="https://interviewquestions.tuteehub.com/tag/cm-919986" style="font-weight:bold;" target="_blank" title="Click to know more about CM">CM</a> <br/>10.180 cm <br/>10.8 cm <br/>10.81 cm</p>Answer :A</body></html> | |
| 38814. |
A cannon and a target are 5.10 km apart and located at the same level. How soon will the shell launched with the initial velocity 240 m/s reach the target in the absence of air drag? |
| Answer» <html><body><p></p>Solution :Hence `v_(0)=240ms^(-<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>),R=5.10ikm=5100m,,g=9.8ms^(-2), theta=?` <br/> From formula `R=(v_(0)^(2)sin 2 theta)/g` <br/> We have `sin 2 theta=(Rg)/(v_(0)^(2))`, Putting <a href="https://interviewquestions.tuteehub.com/tag/values-25920" style="font-weight:bold;" target="_blank" title="Click to know more about VALUES">VALUES</a> we get <br/> `sin 2 theta =(5100xx9.8)/(240xx240)=0.8677=(sqrt(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>))/2=sin60^(@)` or `sin 120^(@)impliestheta=30^(@)` or `<a href="https://interviewquestions.tuteehub.com/tag/60-328817" style="font-weight:bold;" target="_blank" title="Click to know more about 60">60</a>^(@)` <br/> From formula `T=(2v_(0)sin theta)/g` <br/> When `theta =30^(@),T_(1)=(2xx240xx0.5)/9.8=24.5`sec <br/> When `theta=60^(@),T_(2)=(2xxd240xx0.867)/9.8=42.14` sec</body></html> | |
| 38815. |
Mark the correct options |
| Answer» <html><body><p>If the incident rays are converging we have a real object<br/>If the <a href="https://interviewquestions.tuteehub.com/tag/final-461168" style="font-weight:bold;" target="_blank" title="Click to know more about FINAL">FINAL</a> rays are converging we have a real <a href="https://interviewquestions.tuteehub.com/tag/image-11684" style="font-weight:bold;" target="_blank" title="Click to know more about IMAGE">IMAGE</a> <br/>The image of a virtual object is called a virtual image<br/>If the image is virtual the corresponding object is called a virtual object</p>Answer :B</body></html> | |
| 38816. |
The gravitational potential energy of a body of mass m at the earth's surface is mgR_e . Its gravitational potential energy at a height R_efrom the earth's surface will be ..... (Here R_eis the radius of earth) |
| Answer» <html><body><p>`-2 mg R_e` <br/>`2 mg R_e`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>/2 mg R_e`<br/>`-1/2 mg R_e`</p>Solution :`<a href="https://interviewquestions.tuteehub.com/tag/implies-1037962" style="font-weight:bold;" target="_blank" title="Click to know more about IMPLIES">IMPLIES</a> DeltaU = U_(2) - U_1 = (<a href="https://interviewquestions.tuteehub.com/tag/mgh-1095458" style="font-weight:bold;" target="_blank" title="Click to know more about MGH">MGH</a>)/(1+(<a href="https://interviewquestions.tuteehub.com/tag/h-1014193" style="font-weight:bold;" target="_blank" title="Click to know more about H">H</a>)/(R_e) ) = (mgh)/(1+R_e/R_e) = (mgR_e)/2` <br/> `:. U_2 - (-mg R_e) = (mgR_e)/2` <br/> `:. U_2 =-1/2 mg R_e`</body></html> | |
| 38817. |
A car moving with a velocity of 72KMPH stops engine just before ascending an inclined road. It 25% of energy is wasted in overcoming friction, the car rises to a height of (g= 10 ms^(-2)) |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/6m-332078" style="font-weight:bold;" target="_blank" title="Click to know more about 6M">6M</a> <br/>7.5m<br/>12m<br/>15m</p>Answer :D</body></html> | |
| 38818. |
Is an oscillation a wave ? Give reason. |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :No, an <a href="https://interviewquestions.tuteehub.com/tag/oscillation-1139998" style="font-weight:bold;" target="_blank" title="Click to know more about OSCILLATION">OSCILLATION</a> is not a wave. The term wave implies the transfer of energy through successive vibrations of the particles of the medium. <a href="https://interviewquestions.tuteehub.com/tag/hence-484344" style="font-weight:bold;" target="_blank" title="Click to know more about HENCE">HENCE</a> the oscillations of the bodydo not <a href="https://interviewquestions.tuteehub.com/tag/constitute-930799" style="font-weight:bold;" target="_blank" title="Click to know more about CONSTITUTE">CONSTITUTE</a> a wave.</body></html> | |
| 38819. |
A body executes S H M . The potential energy (PE), kinetic energy (KE) and total energy (TE) are measured as function of displacement (x). Which of the following statement is true |
| Answer» <html><body><p>K.E is <a href="https://interviewquestions.tuteehub.com/tag/maximum-556915" style="font-weight:bold;" target="_blank" title="Click to know more about MAXIMUM">MAXIMUM</a> when <a href="https://interviewquestions.tuteehub.com/tag/x-746616" style="font-weight:bold;" target="_blank" title="Click to know more about X">X</a> = <a href="https://interviewquestions.tuteehub.com/tag/0-251616" style="font-weight:bold;" target="_blank" title="Click to know more about 0">0</a><br/> TE is <a href="https://interviewquestions.tuteehub.com/tag/zero-751093" style="font-weight:bold;" target="_blank" title="Click to know more about ZERO">ZERO</a> at x = 0<br/>KE maximum when .x. is maximum<br/> PE is maximum when x = 0</p>Answer :A</body></html> | |
| 38820. |
Tangential acceleration on a bob of a simple pendulum of mass 100gm when its amplitude is 1^(@) is |
| Answer» <html><body><p>`0.017m//"<a href="https://interviewquestions.tuteehub.com/tag/sec-1197209" style="font-weight:bold;" target="_blank" title="Click to know more about SEC">SEC</a>"^(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)`<br/>`1.7m//"sec"^(2)`<br/>`0.17m//"sec"^(2)`<br/>`0.034m//"sec"^(2)`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 38821. |
A satellite of mass 400 kg is in a circular orbit of raduis 2R about the earth where R is radius of the earth. How much energy is required to transfer it to a circular orbit of radius 4R? Find the changes in the kinetic and potential energies ? (R = 6.37 xx 10^(6)m) |
| Answer» <html><body><p></p>Solution :Initial total energy is `-(GMm)/(2r_(2)) = -(GMm)/(8R) = E_(2)` <br/> Final total energy is `-(GMm)/(2r_(2)) = -(GMm)/(8R) = E_(2)` <br/> The <a href="https://interviewquestions.tuteehub.com/tag/change-913808" style="font-weight:bold;" target="_blank" title="Click to know more about CHANGE">CHANGE</a> in the total energy is <br/> `<a href="https://interviewquestions.tuteehub.com/tag/delta-947703" style="font-weight:bold;" target="_blank" title="Click to know more about DELTA">DELTA</a> E = E_(2) - E_(1) = (GMm)/(8R) rArr Delta R = ((GM)/(R^(2))) (mR)/(8)` <br/> `Delta R = (<a href="https://interviewquestions.tuteehub.com/tag/gmr-468745" style="font-weight:bold;" target="_blank" title="Click to know more about GMR">GMR</a>)/(8) = (9.8 xx 400 xx 6.37 xx 10^(6))/(8) = 3.13 xx 10^(9)J` <br/> Change in kinetic energy = `K_(2) - K_(1) = -3.13 xx 10^(9)J` <br/> Change in potential energy `= U_(2) -U_(1) = -6.25xx 10^(9)J`</body></html> | |
| 38822. |
Two bodies of masses m_(1) and m_(2) are separated by certain distance. If vec(F)_(12) is the force on m_(1) due to m_(2) and vec(F)_(21) is the force on m_(2) due to m_(1), then |
| Answer» <html><body><p>`F_(<a href="https://interviewquestions.tuteehub.com/tag/12-269062" style="font-weight:bold;" target="_blank" title="Click to know more about 12">12</a>) = F_(21)`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/vec-723433" style="font-weight:bold;" target="_blank" title="Click to know more about VEC">VEC</a>(<a href="https://interviewquestions.tuteehub.com/tag/f-455800" style="font-weight:bold;" target="_blank" title="Click to know more about F">F</a>)_(12) = vec(F)_(21)`<br/>`F_(12) = -F_(21)`<br/>both <a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a> & 3</p>Answer :D</body></html> | |
| 38823. |
A 15Kg mass is accelerated from rest with a force of 100N. As it moves faster, friction and air resistance create an oppositely directed retarding force given by F_(B) = A+ BV. whereA = 25 N and B= 0.5 N/(m//s). At what velocity m/sdoes the acceleration equal to one half of the initial acceleration ? |
| Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/25ms-1831179" style="font-weight:bold;" target="_blank" title="Click to know more about 25MS">25MS</a>^(-<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)`<br/>`50ms^(-1)`<br/>`75ms^(-1)`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/100ms-266007" style="font-weight:bold;" target="_blank" title="Click to know more about 100MS">100MS</a>^(-1)`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 38824. |
A staionary man observes that the rain is falling vertically downward. When he starts running with a velocity of 12 km/h observes that the rains is falling at an angle 60^(@) with the vertical. The actual velocity of rain is |
| Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/12sqrt-1784050" style="font-weight:bold;" target="_blank" title="Click to know more about 12SQRT">12SQRT</a>(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)` km/h<br/>12 km/h<br/>`4sqrt(3)` km/h<br/>`<a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a> <a href="https://interviewquestions.tuteehub.com/tag/sqrt-1223129" style="font-weight:bold;" target="_blank" title="Click to know more about SQRT">SQRT</a>(3)` km/h</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 38825. |
If a body loses half of its velocity on penetrating 3 cm in a wooden block, then how much will it penetrate more before coming to rest |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a> cm<br/>2 cm<br/>3 cm<br/>4 cm</p>Answer :A</body></html> | |
| 38826. |
A rocket is fired from the earth's surface to put the pay load in the required orbit/ The motion of the rocket is given by: |
| Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/f-455800" style="font-weight:bold;" target="_blank" title="Click to know more about F">F</a>=m((<a href="https://interviewquestions.tuteehub.com/tag/dv-433533" style="font-weight:bold;" target="_blank" title="Click to know more about DV">DV</a>)/(<a href="https://interviewquestions.tuteehub.com/tag/dt-960413" style="font-weight:bold;" target="_blank" title="Click to know more about DT">DT</a>))`<br/>`F=(<a href="https://interviewquestions.tuteehub.com/tag/dp-959208" style="font-weight:bold;" target="_blank" title="Click to know more about DP">DP</a>)/(dt)`<br/>`F=v((dm)/(dt))`<br/>F= constant</p>Answer :C</body></html> | |
| 38827. |
In a specific heat experiment 100g of lead (sp. Heat=145Jkg^(-1)K^(-1)) at 100^(@)C is mixed with 200g of water at 20^(@). Find the change in entropy. |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :`0.574Jkg^(-<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)`</body></html> | |
| 38828. |
What would be the angular speed of earth, so that body lying on equator may appear weightless? ( g = 10 m//s^2 , radius of earth = 6400 km) |
| Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>.25 xx10^(-3)` rad/sec <br/>`1.56 xx10^(-3)` rad/sec <br/>`1.25 xx10^(-1)` rad/sec <br/>`1.56 xx10^(-1)` rad/sec </p>Solution :`implies g. = g - R_(e) omega^(2) <a href="https://interviewquestions.tuteehub.com/tag/cos-935872" style="font-weight:bold;" target="_blank" title="Click to know more about COS">COS</a>^(2) <a href="https://interviewquestions.tuteehub.com/tag/lamda-536483" style="font-weight:bold;" target="_blank" title="Click to know more about LAMDA">LAMDA</a>` <br/> In weightless state `g.=0` <br/> Taking for equator `lamda=0` <br/> `0 = g - Romega^2` <br/> `:. Romega^2 =g` <br/> `omega=sqrt(g/R_e)=sqrt(<a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a>/(6400xx10^3))=1/800 (rad)/s` <br/> `omega=1.25 xx10^(-3) (rad)/s`</body></html> | |
| 38829. |
A 100 m long train is travelling from North to South at a speed of 30ms^(-1). A bird is flying from South to North at a speed of 10ms^(-1). How long will the bird take to cross the train? |
| Answer» <html><body><p>3s<br/>2.5s<br/>10s<br/>5s</p>Solution :Length of <a href="https://interviewquestions.tuteehub.com/tag/train-1425202" style="font-weight:bold;" target="_blank" title="Click to know more about TRAIN">TRAIN</a> = 100 m <br/> <a href="https://interviewquestions.tuteehub.com/tag/bird-898337" style="font-weight:bold;" target="_blank" title="Click to know more about BIRD">BIRD</a> and train are moving in a opposite direction <br/> `:.` Relative velocity `=30+10=40ms^(-1)` <br/> Time taken to cross the train (t) `=("distance")/("R.velocity")=(100)/(<a href="https://interviewquestions.tuteehub.com/tag/40-314386" style="font-weight:bold;" target="_blank" title="Click to know more about 40">40</a>)=2.5s`.</body></html> | |
| 38830. |
When a spring is pulled with a force of 5xx10^(5) dyn, it elongates by 0.1 m. What mass should be attached to the end of the spring so that when pulled a little downwards and released, the mass can perform 2 complete oscillations per second? What will be the maximum velocity of the mass when the amplitude of vibration is 0.01 m? |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :0.317 <a href="https://interviewquestions.tuteehub.com/tag/kg-1063886" style="font-weight:bold;" target="_blank" title="Click to know more about KG">KG</a> (<a href="https://interviewquestions.tuteehub.com/tag/approx-882876" style="font-weight:bold;" target="_blank" title="Click to know more about APPROX">APPROX</a>.), `0.1256m*s^(-<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)`</body></html> | |
| 38831. |
A block of mass 'M' is placed on the top of a wedge of mass '4M'. All the surfaces are frictionless. The system is released from rest. The distance moved by the wedge at the instant, the block reaches the bottom will be |
| Answer» <html><body><p>0.2 m <br/>0.4 m <br/>0.8 m <br/><a href="https://interviewquestions.tuteehub.com/tag/zero-751093" style="font-weight:bold;" target="_blank" title="Click to know more about ZERO">ZERO</a> </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 38832. |
Match the Columns |
| Answer» <html><body><p>A - 3 , <a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a> - 5, C - 2 , D - 1 <br/>A - 2 , B - <a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>, C - 3 , D - 5 <br/>A - 1 , B - 3, C - 3 , D - 4<br/>A - 5 , B - 4, C - 5 , D - 1 </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html> | |
| 38833. |
When a load is applied to stretch a wire of length 200 cm, it gets elongated by 2 mm. IF the diameter of its cross section is 1 mm, then calculate the decrease in its diameter due to stretching , Poisson's ratio for the material of the wire is 0.24 . |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :`<a href="https://interviewquestions.tuteehub.com/tag/24-295400" style="font-weight:bold;" target="_blank" title="Click to know more about 24">24</a> <a href="https://interviewquestions.tuteehub.com/tag/times-1420471" style="font-weight:bold;" target="_blank" title="Click to know more about TIMES">TIMES</a> 10^-6 <a href="https://interviewquestions.tuteehub.com/tag/cm-919986" style="font-weight:bold;" target="_blank" title="Click to know more about CM">CM</a>`</body></html> | |
| 38834. |
Calculatethe totalnumberof degressof freedompossessedby themoleculesin onecm^3 ofH_2gasat NTP . |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :22400`cm^2`of <a href="https://interviewquestions.tuteehub.com/tag/every-976721" style="font-weight:bold;" target="_blank" title="Click to know more about EVERY">EVERY</a> gascontains`6.02 <a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a> 10^(23)`molecules<br/>` therefore ` Numberof moleculesin `<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a> cm ^3 ` of ` H_2 ` gas`=( 6.02xx 10^(23))/( 22400 ) = 0.26875xx 10^(20)`<br/>Numberof degreesof freedomof a` H_2` gasmolecule = 5 <br/>` therefore `Totalnumberof <a href="https://interviewquestions.tuteehub.com/tag/degress-436458" style="font-weight:bold;" target="_blank" title="Click to know more about DEGRESS">DEGRESS</a> of freedomof `0.26875xx 10^(20)`molecules<br/> `= 0.26875xx 10^(20) xx 5 = 1.34 375xx 10^(20)`</body></html> | |
| 38835. |
Mass is inertia and measure of inertia mean property to oppose change. |
| Answer» <html><body><p><br/></p>Answer :False. Property to oppose <a href="https://interviewquestions.tuteehub.com/tag/change-913808" style="font-weight:bold;" target="_blank" title="Click to know more about CHANGE">CHANGE</a> is <a href="https://interviewquestions.tuteehub.com/tag/called-907796" style="font-weight:bold;" target="_blank" title="Click to know more about CALLED">CALLED</a> <a href="https://interviewquestions.tuteehub.com/tag/inertia-1043176" style="font-weight:bold;" target="_blank" title="Click to know more about INERTIA">INERTIA</a> and <a href="https://interviewquestions.tuteehub.com/tag/mass-1088425" style="font-weight:bold;" target="_blank" title="Click to know more about MASS">MASS</a> is <a href="https://interviewquestions.tuteehub.com/tag/measure-1091857" style="font-weight:bold;" target="_blank" title="Click to know more about MEASURE">MEASURE</a> of inertia.</body></html> | |
| 38836. |
(A): During an adiabatic process, an ideal gas expands by decrease in its internal energy only (R ) : During an adiabatic process, heat cannot be exchanged between and its surroundings |
| Answer» <html><body><p>Both (A) and(<a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a> ) are true and (R ) is the <a href="https://interviewquestions.tuteehub.com/tag/correct-409949" style="font-weight:bold;" target="_blank" title="Click to know more about CORRECT">CORRECT</a> <a href="https://interviewquestions.tuteehub.com/tag/explanation-455162" style="font-weight:bold;" target="_blank" title="Click to know more about EXPLANATION">EXPLANATION</a> of (A) <br/>Both (A) and (R ) are (R ) true and is not the correct explanation of (A)<br/>(A) is true but (R ) is <a href="https://interviewquestions.tuteehub.com/tag/false-459184" style="font-weight:bold;" target="_blank" title="Click to know more about FALSE">FALSE</a> <br/>Both (A) and (R ) are false</p>Answer :A</body></html> | |
| 38837. |
A body is projected at an angle 30^(@) to the horizontal with a speed of 30 ms^(-1). The angle made by the velocity vector with the horizontal after 1.5 s is ""(g=10ms^(2)) |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/zero-751093" style="font-weight:bold;" target="_blank" title="Click to know more about ZERO">ZERO</a><br/>`<a href="https://interviewquestions.tuteehub.com/tag/60-328817" style="font-weight:bold;" target="_blank" title="Click to know more about 60">60</a>^(@)`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/45-316951" style="font-weight:bold;" target="_blank" title="Click to know more about 45">45</a>^(@)`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/90-341351" style="font-weight:bold;" target="_blank" title="Click to know more about 90">90</a>^(@)`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html> | |
| 38838. |
Consider Example 6.8 taking the coefficient of friction , mu to be and calculate the maximum compressionof the spring . |
| Answer» <html><body><p></p>Solution :In presence of friction, both the <a href="https://interviewquestions.tuteehub.com/tag/spring-11487" style="font-weight:bold;" target="_blank" title="Click to know more about SPRING">SPRING</a> force and the frictional force act so as to oppose the compression of the spring as shown in Fig. 6.9. <br/> We invoke the work-energy theorem, rather than the conservation of mechanical energy. <br/> The change in kinetic energy is <br/> `triangleK= K_(f)-K_(t)= 0-(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)/(2)mv^(2)`<br/> The work done by the net force is <br/> `W= -(1)/(2)kx_(m)^(2)- mu mg x_(m)` <br/> Equatting we have <br/> `(1)/(2)mv^(2)= (1)/(2)k x_(m)^(2)+ mu mg x_(m)` <br/> Now `mu mg= 0.5xx10^(3)xx10= 5xx 10^(3)N` (taking `g= 10.0 ms^(-2)`). After rearranging the above equation we obtain the following quadratic equation in the unknown `x_(m)`. <br/> `kx_(m)^(2)+ 2 mu mg x_(m)- mv^(2)= O` <br/> `x_(m)=(-mu mg+[mu^(2)m^(2)g^(2)+<a href="https://interviewquestions.tuteehub.com/tag/mkv-3726969" style="font-weight:bold;" target="_blank" title="Click to know more about MKV">MKV</a>^(2)]^(1/2))/(k)` <br/> where we take the positive square root <a href="https://interviewquestions.tuteehub.com/tag/since-644476" style="font-weight:bold;" target="_blank" title="Click to know more about SINCE">SINCE</a> `x_(m)` is positive. Putting in numerical <a href="https://interviewquestions.tuteehub.com/tag/values-25920" style="font-weight:bold;" target="_blank" title="Click to know more about VALUES">VALUES</a> we obtain `x_(m)= 1.35m` <br/> which, as expected, is less than the result in Example 6.8. <br/> If the two forces on the body consist of a conservative force `F_(c )` and a non-conservative force `F_(nc)`, the conservation of mechanical energy formula will have to be modified. By the WE theorem <br/> `(F_(c )+F_(nc)) trianglex= triangleK` <br/> But `F_(c ) triangle x= -triangle V` <br/> Hence, `triangle(K+V)= F_(nc) triangle x` <br/> `triangle E= F_(nc) trianglex` <br/> where E is the total mechanical energy. Over the path this assumes the form <br/> `E_(f)-E_(t)= W_(nc)` <br/> where `W_(nc)` is the total work done by the non-conservative forces over the path. Note that unlike the conservative force, `W_(nc)` depends on the particular path i to f. <br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/NCERT_GUJ_PHY_XI_P1_C06_SLV_013_S01.png" width="80%"/></body></html> | |
| 38839. |
For the wave discribed in Exercise 15.8, plot the displacement (y) versus (t) graphs dor x = 0.2 and 4 cm. What are shapes of these graphs? In which aspects does the oscillatory motion in travelling wave differ from one point to another: amplitude, frequency or phase? |
| Answer» <html><body><p></p>Solution :All the <a href="https://interviewquestions.tuteehub.com/tag/graphs-1011192" style="font-weight:bold;" target="_blank" title="Click to know more about GRAPHS">GRAPHS</a> are <a href="https://interviewquestions.tuteehub.com/tag/sinusoidal-1210475" style="font-weight:bold;" target="_blank" title="Click to know more about SINUSOIDAL">SINUSOIDAL</a>. They have same amplitude and <a href="https://interviewquestions.tuteehub.com/tag/frequency-465761" style="font-weight:bold;" target="_blank" title="Click to know more about FREQUENCY">FREQUENCY</a>, but <a href="https://interviewquestions.tuteehub.com/tag/different-951434" style="font-weight:bold;" target="_blank" title="Click to know more about DIFFERENT">DIFFERENT</a> initial phases.</body></html> | |
| 38840. |
Dimensional formulae are used (A) to convert one system of units into another (B) to find proportionality constants (C ) to check the correctness of an equation |
| Answer» <html><body><p>only a & <a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a> are true<br/>only <a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a> is true<br/>A & C are true<br/>all the true</p>Answer :C</body></html> | |
| 38841. |
When a gas is compressed to half of its initial volume. If it is comparision between isothermal and adiabatic process, then a) Work done is less if the change is Isothermal b) Final pressure is more if the change is adiabatic c) Final pressure is less if the change is Isothermal |
| Answer» <html><body><p>both a and <a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a> are <a href="https://interviewquestions.tuteehub.com/tag/correct-409949" style="font-weight:bold;" target="_blank" title="Click to know more about CORRECT">CORRECT</a> <br/>both b and <a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a> are correct <br/>both a and c are correct <br/>a,b.c are <a href="https://interviewquestions.tuteehub.com/tag/true-713260" style="font-weight:bold;" target="_blank" title="Click to know more about TRUE">TRUE</a> </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :D</body></html> | |
| 38842. |
Assertion : Dynamic friction is always less than limiting friction Reason : Because once the actual motion starts inertia of rest has been overcome . |
| Answer» <html><body><p>If both, <a href="https://interviewquestions.tuteehub.com/tag/assertion-384238" style="font-weight:bold;" target="_blank" title="Click to know more about ASSERTION">ASSERTION</a> and Reason are true and the Reason is the <a href="https://interviewquestions.tuteehub.com/tag/correct-409949" style="font-weight:bold;" target="_blank" title="Click to know more about CORRECT">CORRECT</a> explanation of the Assertion<br/>If both, Assertion and Reason are true but Reason is not a correct explanation of the Assertion<br/>If Assertion is <a href="https://interviewquestions.tuteehub.com/tag/ture-1429019" style="font-weight:bold;" target="_blank" title="Click to know more about TURE">TURE</a> but the Reason is false<br/>If both, Assertion and Reason are false</p>Solution :Both the statements are true and <a href="https://interviewquestions.tuteehub.com/tag/latter-7376806" style="font-weight:bold;" target="_blank" title="Click to know more about LATTER">LATTER</a> is correct explanation of the former .</body></html> | |
| 38843. |
One end of a long metallic wire of length L is tied to the ceiling. The other end is tied to massless spring of spring constant K. A mass (m) hangs freely from the free end of the spring. The area of cross-section and young's modulus of the wire are A and Y respectively. If the mass is slightly pulled down and released it will oscillate with a time period T equal to |
| Answer» <html><body><p>`2pi <a href="https://interviewquestions.tuteehub.com/tag/sqrt-1223129" style="font-weight:bold;" target="_blank" title="Click to know more about SQRT">SQRT</a>((m)/( <a href="https://interviewquestions.tuteehub.com/tag/k-527196" style="font-weight:bold;" target="_blank" title="Click to know more about K">K</a>))`<br/>`2pi sqrt((m(YA + KL) )/( YAK))`<br/>`2pi sqrt((<a href="https://interviewquestions.tuteehub.com/tag/mya-2186336" style="font-weight:bold;" target="_blank" title="Click to know more about MYA">MYA</a>)/( KL))`<br/>`2pi sqrt((<a href="https://interviewquestions.tuteehub.com/tag/ml-548251" style="font-weight:bold;" target="_blank" title="Click to know more about ML">ML</a>)/( YA))`</p>Answer :B</body></html> | |
| 38844. |
A double star is a system of two stars moving around the centre of mass of the system due to gravitation. The distance between the components of the double star is d = ((GMT^(2))/(xpi^(2)))^(1//y) (given, the total mass is M and time periodis T ) Find the value x+ y |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/7-332378" style="font-weight:bold;" target="_blank" title="Click to know more about 7">7</a></body></html> | |
| 38845. |
The motion of a particle along a straight line is described by the function s=6+4t^(2)-t^(2) in SI units. Find the velocity, acceleration, at t=2s, and the average velocity during 3rd second. |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`s=6+4t^(2)-t^(4)` <br/> Velocity `=(dx)/(dt)=8t-4t^(3)` when t-2 <br/> Velocity `=<a href="https://interviewquestions.tuteehub.com/tag/8-336412" style="font-weight:bold;" target="_blank" title="Click to know more about 8">8</a> xx 2-4 xx 2^(3)"Velocity =-16m/s"` <br/> Acceleration `a=(d^(2)s)/(dt^(2)) =8""12t^(2)` when t-2 <br/> acc `=8-12 xx 2^2=-40 ""acc=-40m//s^2` <br/> displacement in 3 seconds `s_(2)=6+4, 3^(2)-3^(4)=-39m` <br/> <a href="https://interviewquestions.tuteehub.com/tag/displacment-2586435" style="font-weight:bold;" target="_blank" title="Click to know more about DISPLACMENT">DISPLACMENT</a> during 3rd second <br/> Average velocity during 3rd second `=(+45)/(1)=-45m//s` <br/> -ve sign indicates that the body is moving in <a href="https://interviewquestions.tuteehub.com/tag/opposite-1137237" style="font-weight:bold;" target="_blank" title="Click to know more about OPPOSITE">OPPOSITE</a> direction to the initial direction of motion.</body></html> | |
| 38846. |
An open tank filled with water has a hole at its bottom. If the total pressure at the bottom of the tank is 2 atmospheres , the velocity of efflux is (nearly) ( 1 Atmosphere = 10^(5) "Nm"^(-2) ) |
| Answer» <html><body><p>30`"ms"^(-1)`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/20-287209" style="font-weight:bold;" target="_blank" title="Click to know more about 20">20</a> "ms"^(-1)`<br/>`14 "ms"^(-1)`<br/>`9.8 "ms"^(-1)`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :C</body></html> | |
| 38847. |
The value of surface tension depends upon |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/nature-1112013" style="font-weight:bold;" target="_blank" title="Click to know more about NATURE">NATURE</a> of <a href="https://interviewquestions.tuteehub.com/tag/solid-1216587" style="font-weight:bold;" target="_blank" title="Click to know more about SOLID">SOLID</a> in <a href="https://interviewquestions.tuteehub.com/tag/contact-25916" style="font-weight:bold;" target="_blank" title="Click to know more about CONTACT">CONTACT</a> with <a href="https://interviewquestions.tuteehub.com/tag/liquid-1075124" style="font-weight:bold;" target="_blank" title="Click to know more about LIQUID">LIQUID</a><br/>nature of the liquid<br/>both nature of liquid and solidin contact<br/>none of these</p>Answer :B</body></html> | |
| 38848. |
Beats are produced by two progressive waves. Maximum loudness at the waxing is x timesthe loudness of each wave. The value of x is ............ . |
| Answer» <html><body><p>1<br/> `<a href="https://interviewquestions.tuteehub.com/tag/sqrt-1223129" style="font-weight:bold;" target="_blank" title="Click to know more about SQRT">SQRT</a> 2` <br/>2<br/>4</p>Solution :The <a href="https://interviewquestions.tuteehub.com/tag/maximum-556915" style="font-weight:bold;" target="_blank" title="Click to know more about MAXIMUM">MAXIMUM</a> amplitude is the sum of two amplitude. i.e. a+ a= 2a<br/>Hence, maximum intensity is proportional to `4a^2`<br/> Loudness of <a href="https://interviewquestions.tuteehub.com/tag/one-585732" style="font-weight:bold;" target="_blank" title="Click to know more about ONE">ONE</a> <a href="https://interviewquestions.tuteehub.com/tag/wave-22399" style="font-weight:bold;" target="_blank" title="Click to know more about WAVE">WAVE</a> isgiven by ` x(4a^2)/(a^2) = 4`</body></html> | |
| 38849. |
In an experiment, the values of refractive index of glass were found to be 1.54, 1.53 , 1.44 and 1.54 , 1.56 and 1.45 in successive measurements . Calculate (i) Mean value of refractive index of glass (ii) Absolute error in each measurement (iii) Mean absolute error (iv) relative error and (v) Percentage error. |
| Answer» <html><body><p>1.51, 0.04, 0.03,<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>%<br/>1.51, 0.4, 0.03, 3%<br/>15.1, 0.04,0.03,3%<br/>15.1, 0.04, 0.3, 3%</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html> | |
| 38850. |
A uniform square sheet has a side length of 2R. If one of the quadrants is removed, the shift in the centre of mass: |
| Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a>/(3sqrt(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>))`<br/>`R/<a href="https://interviewquestions.tuteehub.com/tag/sqrt-1223129" style="font-weight:bold;" target="_blank" title="Click to know more about SQRT">SQRT</a>(2)`<br/>`R/(6sqrt(2))`<br/>`(sqrt(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)R)/2` </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html> | |