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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your Class 11 knowledge and support exam preparation. Choose a topic below to get started.
| 38901. |
Two particles of masses m_1 and m_2in projectile motion have velocities vecv_1 and vecv_2respectively at time t = 0. They collide at time t_0 . Their velocities become vecv_1^2 and vecv_2^1at time 2t_0while still moving in air. The value of |(m_1 vecv_1^1 + m_2vec_2^1) - (m_1vecv_1 + m_2vecv_2)|is |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/zero-751093" style="font-weight:bold;" target="_blank" title="Click to know more about ZERO">ZERO</a><br/>`(m_1+m_2) "<a href="https://interviewquestions.tuteehub.com/tag/gt-1013864" style="font-weight:bold;" target="_blank" title="Click to know more about GT">GT</a>"_0` <br/>`<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>(m_1+m_2)"gt"_0` <br/>`1/2 (m_1 + m_2) "gt"_0` </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :C</body></html> | |
| 38902. |
There is no atmosphere on moon because |
| Answer» <html><body><p>It is <a href="https://interviewquestions.tuteehub.com/tag/closer-7270227" style="font-weight:bold;" target="_blank" title="Click to know more about CLOSER">CLOSER</a> to earth<br/>It revolves <a href="https://interviewquestions.tuteehub.com/tag/round-625673" style="font-weight:bold;" target="_blank" title="Click to know more about ROUND">ROUND</a> the earth<br/>It gets <a href="https://interviewquestions.tuteehub.com/tag/light-1073401" style="font-weight:bold;" target="_blank" title="Click to know more about LIGHT">LIGHT</a> from the earth <br/>RMS speed of any gas molecular is greater than the <a href="https://interviewquestions.tuteehub.com/tag/escape-975157" style="font-weight:bold;" target="_blank" title="Click to know more about ESCAPE">ESCAPE</a> velocity on the surface of the moon.</p>Answer :D</body></html> | |
| 38903. |
One mole of an ideal gas expands at a constanttemperature of 300 K from an initial volume of 10 litres to a final volume of 20 litres. The work done in expanding the gas is (R=8.31J/mole-K) |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/750-335306" style="font-weight:bold;" target="_blank" title="Click to know more about 750">750</a> <a href="https://interviewquestions.tuteehub.com/tag/joules-1062246" style="font-weight:bold;" target="_blank" title="Click to know more about JOULES">JOULES</a><br/>1728 joules<br/>1500 joules <br/><a href="https://interviewquestions.tuteehub.com/tag/3456-1857032" style="font-weight:bold;" target="_blank" title="Click to know more about 3456">3456</a> joules </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 38904. |
To launch a satellite into its orbit, how many minimum stage of a rocket are required ? |
| Answer» <html><body><p></p>Solution :Generally to <a href="https://interviewquestions.tuteehub.com/tag/launch-1069588" style="font-weight:bold;" target="_blank" title="Click to know more about LAUNCH">LAUNCH</a> a satellite into the <a href="https://interviewquestions.tuteehub.com/tag/orbit-1138163" style="font-weight:bold;" target="_blank" title="Click to know more about ORBIT">ORBIT</a> we are <a href="https://interviewquestions.tuteehub.com/tag/using-7379753" style="font-weight:bold;" target="_blank" title="Click to know more about USING">USING</a> a three <a href="https://interviewquestions.tuteehub.com/tag/stage-1223778" style="font-weight:bold;" target="_blank" title="Click to know more about STAGE">STAGE</a> <a href="https://interviewquestions.tuteehub.com/tag/rocket-1190549" style="font-weight:bold;" target="_blank" title="Click to know more about ROCKET">ROCKET</a>.</body></html> | |
| 38905. |
The difference of two unit vectors is found to have a magnitude of unity . The angle between them is |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :`<a href="https://interviewquestions.tuteehub.com/tag/60-328817" style="font-weight:bold;" target="_blank" title="Click to know more about 60">60</a>^(@)`</body></html> | |
| 38906. |
In a shm, what is the minimum time required for a particle to move between two points 10 cm on either side of the mean position ? The amplitude and time period of the particle are 20 cm and 2 seconds respectively. |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`y = a <a href="https://interviewquestions.tuteehub.com/tag/sin-1208945" style="font-weight:bold;" target="_blank" title="Click to know more about SIN">SIN</a>(2pi//T) , <a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a> = <a href="https://interviewquestions.tuteehub.com/tag/20-287209" style="font-weight:bold;" target="_blank" title="Click to know more about 20">20</a> sin (2pi//2) t , t = 0.17 s , "<a href="https://interviewquestions.tuteehub.com/tag/time-19467" style="font-weight:bold;" target="_blank" title="Click to know more about TIME">TIME</a> " = 0.34 s`</body></html> | |
| 38907. |
Find the work done in lifting a stone of mass 10 kg and specific gravity 3 from the bed of a lake to a height of 6 m in water. |
| Answer» <html><body><p></p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/mass-1088425" style="font-weight:bold;" target="_blank" title="Click to know more about MASS">MASS</a> of <a href="https://interviewquestions.tuteehub.com/tag/stone-1228007" style="font-weight:bold;" target="_blank" title="Click to know more about STONE">STONE</a> = 10kg, <a href="https://interviewquestions.tuteehub.com/tag/specific-1220917" style="font-weight:bold;" target="_blank" title="Click to know more about SPECIFIC">SPECIFIC</a> gravity = `(d_(s))/(d_(<a href="https://interviewquestions.tuteehub.com/tag/w-729065" style="font-weight:bold;" target="_blank" title="Click to know more about W">W</a>)) = 3` <br/> `"W=mgh"(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>-(d_(w))/(d_(s)))=10xx9.8xx6xx(1-(1)/(3))` <br/> `W=98xx6xx(2)/(3)=392j`</body></html> | |
| 38908. |
If radius of earth is reduced to half without changing its mass, |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :(A)<a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a>,(<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a>)S,(<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a>)<a href="https://interviewquestions.tuteehub.com/tag/q-609558" style="font-weight:bold;" target="_blank" title="Click to know more about Q">Q</a></body></html> | |
| 38909. |
An ideal gas passes along path ABCA of P to V graph as shown here. The work done in one complete cycle will be ...... |
| Answer» <html><body><p>2PV<br/>PV<br/>`1/2PV`<br/>zero</p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/work-20377" style="font-weight:bold;" target="_blank" title="Click to know more about WORK">WORK</a> done in one <a href="https://interviewquestions.tuteehub.com/tag/cycle-942437" style="font-weight:bold;" target="_blank" title="Click to know more about CYCLE">CYCLE</a> W=Area of `<a href="https://interviewquestions.tuteehub.com/tag/deltaabc-2053188" style="font-weight:bold;" target="_blank" title="Click to know more about DELTAABC">DELTAABC</a>` <br/> `=1/2xxACxxBC` <br/> `=1/2(3V-V)<a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a>(3P-P)` <br/> `=1/2xx2Vxx2P` <br/> =2PV</body></html> | |
| 38910. |
A particle moves in Xy plane according to the law X=a sinomegat and y=a (1-cosomegat) where a and omega are constants. The particle traces- |
| Answer» <html><body><p>a <a href="https://interviewquestions.tuteehub.com/tag/parabola-1146268" style="font-weight:bold;" target="_blank" title="Click to know more about PARABOLA">PARABOLA</a> <br/>a traight <a href="https://interviewquestions.tuteehub.com/tag/line-1074199" style="font-weight:bold;" target="_blank" title="Click to know more about LINE">LINE</a> equally inclined to `X` and `y` axes <br/>a circle <br/>a distance proportional to <a href="https://interviewquestions.tuteehub.com/tag/time-19467" style="font-weight:bold;" target="_blank" title="Click to know more about TIME">TIME</a> </p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a>::D</body></html> | |
| 38911. |
The fundamental physical quantities that have same dimensions in the dimensional formulae of torque and angular momentum are |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/mass-1088425" style="font-weight:bold;" target="_blank" title="Click to know more about MASS">MASS</a>, time<br/>time, length<br/>mass, length<br/>time, mole</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 38912. |
If bulb of 100 W continued for 10 hour then how much electric energy will be consumed ? |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :1 <a href="https://interviewquestions.tuteehub.com/tag/kwh-1063153" style="font-weight:bold;" target="_blank" title="Click to know more about KWH">KWH</a> or 1 <a href="https://interviewquestions.tuteehub.com/tag/unit-1438166" style="font-weight:bold;" target="_blank" title="Click to know more about UNIT">UNIT</a> of `3.6 xx10^(6)`<a href="https://interviewquestions.tuteehub.com/tag/j-520843" style="font-weight:bold;" target="_blank" title="Click to know more about J">J</a></body></html> | |
| 38913. |
Certain perfect gas is found to obey PV^(3//2)= constant during adiabatic process. If such a gas at initial temperature T is adiabatically compressed to half of the initial volume, its final temperature will be |
| Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/sqrt2-3056932" style="font-weight:bold;" target="_blank" title="Click to know more about SQRT2">SQRT2</a> T`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a> T`<br/>`2 sqrt2 T`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a> T`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html> | |
| 38914. |
When a mass of 0.5 kg is suspended from the free end of a spring, it stretches the spring by 0.2m. This mass is removed and 0.25kg mass is attached to the same free end of the spring. If the mass is pulled down and released, what is its time period?(g=10ms^(-2)) |
| Answer» <html><body><p></p>Solution :When 0.3 kg <a href="https://interviewquestions.tuteehub.com/tag/mass-1088425" style="font-weight:bold;" target="_blank" title="Click to know more about MASS">MASS</a> is suspended, extension of the spring is 0.2m. Since in equilibrium mg = Kx <br/> (or)`0.5 <a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a> <a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a>= k xx 0.2 <a href="https://interviewquestions.tuteehub.com/tag/implies-1037962" style="font-weight:bold;" target="_blank" title="Click to know more about IMPLIES">IMPLIES</a> K= 25N//m` <br/> The time period of spring <a href="https://interviewquestions.tuteehub.com/tag/block-18865" style="font-weight:bold;" target="_blank" title="Click to know more about BLOCK">BLOCK</a> system is <br/> `T= 2pisqrt((m)/(k))= 2pisqrt((0.25)/(25))= 0.63 s`</body></html> | |
| 38915. |
A vessel filled with water is kept on a weighing pan and the scale adjusted to zero .A block of mass M and density rho is suspended by a massless spring of spring constant k. This block is submerged inside into the water in the vessel .What is the reading of the scale ? |
| Answer» <html><body><p></p>Solution :<img src="https://doubtnut-static.s.llnwi.net/static/physics_images/KPK_AIO_PHY_XI_P2_C10_E04_014_S01.png" width="80%"/><br/> Take a figure into consideration .<br/>The scale is adjusted to zero .<a href="https://interviewquestions.tuteehub.com/tag/therefore-706901" style="font-weight:bold;" target="_blank" title="Click to know more about THEREFORE">THEREFORE</a> , when a block suspended to a <a href="https://interviewquestions.tuteehub.com/tag/spring-11487" style="font-weight:bold;" target="_blank" title="Click to know more about SPRING">SPRING</a> is immersed in water , then the reading of the scale will be equal to the upthrust on the block <a href="https://interviewquestions.tuteehub.com/tag/due-433472" style="font-weight:bold;" target="_blank" title="Click to know more about DUE">DUE</a> to water. Upthrust experienced by the block=weight of displaced water<br/>`=(<a href="https://interviewquestions.tuteehub.com/tag/v-722631" style="font-weight:bold;" target="_blank" title="Click to know more about V">V</a>)rho_(w)g ""("V = volume of block")`<br/>`=(m)/(rho)rho_(w)g "" (rho_(w)= " density of water")`<br/>`=((rho_(w))/(rho))mg ""(rho="density ofblock")`</body></html> | |
| 38916. |
The emissive power of a black body at T = 300 K is 100W//m^(2). Consider a body B of area A=10m^(2), coefficient of reflectivity r = 0.3, and absorptivity a = 0.2. If its temperature is 300K, then mark out the currect statement (s). |
| Answer» <html><body><p>The emissive power of <a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a> is `20W//m^(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)`<br/>The emissive power of B is `200W//m^(2)`<br/>The power emitted by B is 20 W<br/>The power emitted by B is <a href="https://interviewquestions.tuteehub.com/tag/180-279527" style="font-weight:bold;" target="_blank" title="Click to know more about 180">180</a> W. </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html> | |
| 38917. |
State the principle of moments for a lever. Give an example of lever. |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :The ratio of effort to <a href="https://interviewquestions.tuteehub.com/tag/load-11593" style="font-weight:bold;" target="_blank" title="Click to know more about LOAD">LOAD</a> or effort arm to load arm is known as the mechanical <a href="https://interviewquestions.tuteehub.com/tag/advantage-368337" style="font-weight:bold;" target="_blank" title="Click to know more about ADVANTAGE">ADVANTAGE</a> `M.A.=(F_1)/(F_2)=(d_2)/(d_1)` e.g., scissors, <a href="https://interviewquestions.tuteehub.com/tag/pliers-601560" style="font-weight:bold;" target="_blank" title="Click to know more about PLIERS">PLIERS</a>, crow bar, are <a href="https://interviewquestions.tuteehub.com/tag/called-907796" style="font-weight:bold;" target="_blank" title="Click to know more about CALLED">CALLED</a> levers.</body></html> | |
| 38918. |
The angular speed of a motor wheel is increased from 1200 rpm to 3120 rpm in 16 seconds. (i) What is its angular acceleration, assuming the acceleration to be uniform? (ii) How many revolutions does the engine make during this time? |
| Answer» <html><body><p></p>Solution :(i) We shall <a href="https://interviewquestions.tuteehub.com/tag/use-1441041" style="font-weight:bold;" target="_blank" title="Click to know more about USE">USE</a> `ω= ω_(0) + α t` <br/> `ω_(0)` =initial angular <a href="https://interviewquestions.tuteehub.com/tag/speed-1221896" style="font-weight:bold;" target="_blank" title="Click to know more about SPEED">SPEED</a> in rad/s <br/> =`<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a> π ×` angular speed in rev/s <br/> = `(2pixx" angular speed in rev/min")/(60s//min)` <br/> `=(2pixx1200)/(60)"rad/s"` <br/> `=40pi" rad/s"` <br/> Similarly `omega` = final angular speed in rad/s <br/> `=(2pixx3120)/(60)"rad/s"` <br/> `=2pixx52" rad/s"` <br/> `=104pi" rad/s"` <br/> `therefore` Angular acceleration <br/> `alpha=(omega-omega_(0))/(t)=4pi" rad/s"^(2)` <br/> The angular acceleration of the <a href="https://interviewquestions.tuteehub.com/tag/engine-25861" style="font-weight:bold;" target="_blank" title="Click to know more about ENGINE">ENGINE</a> = `4π "rad/s"^(2)` <br/> (ii) The angular displacement in <a href="https://interviewquestions.tuteehub.com/tag/time-19467" style="font-weight:bold;" target="_blank" title="Click to know more about TIME">TIME</a> t is given by <br/> `theta=omega_(0)t+(1)/(2)alphat^(2)` <br/> `=(40pixx16+(1)/(2)xx4pixx16^(2))rad` <br/> `=(640pi+512pi)rad` <br/> `=1152pirad` <br/> Number of revolutions = `(1152pi)/(2pi)=576`</body></html> | |
| 38919. |
Show that the coefficient of area expansions, (DeltaA//A)//DeltaT, of a rectangular sheet of the solid is twice its linear expansively, alpha_(l).(alpha_(l)=10^(-5)K^(-1)) |
| Answer» <html><body><p></p>Solution :<img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/NCERT_GUJ_PHY_XI_P2_C11_SLV_001_S01.png" width="80%"/> <br/> Consider a <a href="https://interviewquestions.tuteehub.com/tag/rectangular-1180623" style="font-weight:bold;" target="_blank" title="Click to know more about RECTANGULAR">RECTANGULAR</a> sheet of the solid material of length a and <a href="https://interviewquestions.tuteehub.com/tag/breadth-903817" style="font-weight:bold;" target="_blank" title="Click to know more about BREADTH">BREADTH</a> b (Fig. 11.8). When the <a href="https://interviewquestions.tuteehub.com/tag/temperature-11887" style="font-weight:bold;" target="_blank" title="Click to know more about TEMPERATURE">TEMPERATURE</a> <a href="https://interviewquestions.tuteehub.com/tag/increases-1040626" style="font-weight:bold;" target="_blank" title="Click to know more about INCREASES">INCREASES</a> by`Delta T, a `Increases by `Delta a = alpha_(1) a Delta T` andbincreases by `Delta b = alpha_(1), b Detla T`. From Fig. 11.8, the increase in area<br/> `Delta A = DeltaA_(1) + DeltaA_(2) + DeltaA_(3)` <br/> `DeltaA = a Deltab + b Delta a + (Delta a) (Deltab)` <br/> ` = a alpha_(1) b DeltaT + b alpha_(1) a DeltaT + (alpha_(1))^(2) <a href="https://interviewquestions.tuteehub.com/tag/ab-360636" style="font-weight:bold;" target="_blank" title="Click to know more about AB">AB</a> (Delta T)^(2)` <br/> ` = alpha_(1) ab DeltaT (2 +alpha_(1) DeltaT) = alpha_(1) A DeltaT (2 + alpha_(1) DeltaT)` <br/> Since `alpha_(1) approx 10^(-5) K^(-1)`,from Table 11.1 , the product `alpha_(1) Delta T ` for fractional temperature is small in comparision with 2 and may be neglected. <br/> Hence, <br/> `((Delta A)/A) 1/(Delta T) approx 2alpha_(l) `</body></html> | |
| 38920. |
Each side of a cube is measured to be 7.203m. What is (i) the total surface area and (ii) the volume of the cube to appropriate significant figures ? |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :The number of significant <a href="https://interviewquestions.tuteehub.com/tag/figures-987769" style="font-weight:bold;" target="_blank" title="Click to know more about FIGURES">FIGURES</a> in the measured length is <a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>. The calculated area and the volume should <a href="https://interviewquestions.tuteehub.com/tag/therefore-706901" style="font-weight:bold;" target="_blank" title="Click to know more about THEREFORE">THEREFORE</a> be rounded off to 4 significant figures. <br/> Surface area of the cube = `6(7.203)^(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)m^(2)` <br/> `=311.299254m^(2)` <br/> `=311.3 m^(2)` <br/> Volume of the cube = `(7.203)^(3) m^(3)` <br/> =`373.714754 m^(3)` <br/> =`373.7 m^(3)`</body></html> | |
| 38921. |
In Fery's blackbody |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/inner-1044991" style="font-weight:bold;" target="_blank" title="Click to know more about INNER">INNER</a> surface of inner wall is coated with lamp black and outer surface of outer wall is silver polished<br/>Space between the two walls is evacuated to prevent heat losses due to conducion & convection <br/>A conical projection is provided on the inner wall <a href="https://interviewquestions.tuteehub.com/tag/opposite-1137237" style="font-weight:bold;" target="_blank" title="Click to know more about OPPOSITE">OPPOSITE</a> to small hole<br/>All the 'above. </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :D</body></html> | |
| 38922. |
In an experiment to determine the coefficient of viscosity of a liquid using the formual eta=(piPr^(4))/(8l Q) the radius of the capillary tube was measured to be 0.41 mm using an instrument of least count 0.001 cm, length l was measured usinga metre scale as 15 cm. The percentae error in the pressure difference is 0.4% and the percentage error in the volume of the liquid flow out per second Q is 0.3% what is the maximum percentage error in the coefficient of viscosity? |
| Answer» <html><body><p><br/></p>Solution :`V=pid^(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)h//4`. % <a href="https://interviewquestions.tuteehub.com/tag/erron-2619318" style="font-weight:bold;" target="_blank" title="Click to know more about ERRON">ERRON</a> in `V=2(Deltad//d)+(Deltah//h)`(i) using <a href="https://interviewquestions.tuteehub.com/tag/scale-1195529" style="font-weight:bold;" target="_blank" title="Click to know more about SCALE">SCALE</a> `DeltaV//V=(2xx0.1//2.4)+(0.1//10-5)=9.28%` (ii) Using <a href="https://interviewquestions.tuteehub.com/tag/calipers-412402" style="font-weight:bold;" target="_blank" title="Click to know more about CALIPERS">CALIPERS</a> `DeltaV//V=(2xx0.01//4)+(0.01//10.5)=0.9%`.</body></html> | |
| 38923. |
A simple pendulum is oscillating between extreme positions P and Q about the mean position O. Which of the following statement are true about the motion of pendulum? |
| Answer» <html><body><p>At point O, the acceleration of the bob is different from <a href="https://interviewquestions.tuteehub.com/tag/zero-751093" style="font-weight:bold;" target="_blank" title="Click to know more about ZERO">ZERO</a> <br/>The acceleration of the bob is constant throughout the oscillation <br/>The <a href="https://interviewquestions.tuteehub.com/tag/tension-1241727" style="font-weight:bold;" target="_blank" title="Click to know more about TENSION">TENSION</a> in the string is constant throughout the oscillation. <br/>the tension is maximum at O and minimum at P or Q </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A::D</body></html> | |
| 38924. |
In aboveproblem about an axis passing through any sideof framethe momentof inertia of threebodies is |
| Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/ml-548251" style="font-weight:bold;" target="_blank" title="Click to know more about ML">ML</a>^(2)`<br/>`(3ML^(2))/2`<br/>`(3ML^(2))/4`<br/>`(2ML^(2))/3`</p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :` I= M [ (<a href="https://interviewquestions.tuteehub.com/tag/sqrt-1223129" style="font-weight:bold;" target="_blank" title="Click to know more about SQRT">SQRT</a>(3)<a href="https://interviewquestions.tuteehub.com/tag/l-535906" style="font-weight:bold;" target="_blank" title="Click to know more about L">L</a>)/2]^(2) = 3/4 ML^(2)`</body></html> | |
| 38925. |
(A) : hollow shaft is found to be stronger than a solid shaft made of same material and same quantity. (R): Rigidity modulus is the ratio of shearing stress to shearing strain. |
| Answer» <html><body><p>Both .A. and .<a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a>. are <a href="https://interviewquestions.tuteehub.com/tag/true-713260" style="font-weight:bold;" target="_blank" title="Click to know more about TRUE">TRUE</a> and .R. is the correct explanation of .A.<br/>Both .A. and .R. are true and .R. is not the correct explanation of .A.<br/>A. is true but .R. is <a href="https://interviewquestions.tuteehub.com/tag/false-459184" style="font-weight:bold;" target="_blank" title="Click to know more about FALSE">FALSE</a><br/>A. is false but .R. is true</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a></body></html> | |
| 38926. |
If the mnormal force is doubled then coefficient of friction is |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/halved-2104643" style="font-weight:bold;" target="_blank" title="Click to know more about HALVED">HALVED</a> <br/>tripled <br/><a href="https://interviewquestions.tuteehub.com/tag/doubled-2592927" style="font-weight:bold;" target="_blank" title="Click to know more about DOUBLED">DOUBLED</a> <br/>not changed </p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 38927. |
A particle of mass M is placed at the centre of a uniform spherical shell of equal mass and radius a. Find the gravitational potential at a point P at a distance a/2 from the centre. |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :The gravitational potential at the point P <a href="https://interviewquestions.tuteehub.com/tag/due-433472" style="font-weight:bold;" target="_blank" title="Click to know more about DUE">DUE</a> to the particle at the centre is <br/> `V_(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>) = -(<a href="https://interviewquestions.tuteehub.com/tag/gm-1008640" style="font-weight:bold;" target="_blank" title="Click to know more about GM">GM</a>)/(a//2) = -(2GM)/(a)` <br/> The potential at P due to the <a href="https://interviewquestions.tuteehub.com/tag/shell-11505" style="font-weight:bold;" target="_blank" title="Click to know more about SHELL">SHELL</a> is `V_(2) = -(Gm)/(a)` <br/> The net potential at P is `V_(1) = V_(2) = -(3Gm)/(a)`</body></html> | |
| 38928. |
If Sn=2+0.4n find initial velocity and acceleration |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :We have `S_(<a href="https://interviewquestions.tuteehub.com/tag/n-568463" style="font-weight:bold;" target="_blank" title="Click to know more about N">N</a>)=u+a(n-1/2), S_(n)=(u-a/2)+an` <br/> `S_(n)=2+0.4n` <a href="https://interviewquestions.tuteehub.com/tag/comparing-2531631" style="font-weight:bold;" target="_blank" title="Click to know more about COMPARING">COMPARING</a> with above <a href="https://interviewquestions.tuteehub.com/tag/equation-974081" style="font-weight:bold;" target="_blank" title="Click to know more about EQUATION">EQUATION</a> <br/> U=2.2 <a href="https://interviewquestions.tuteehub.com/tag/units-1438468" style="font-weight:bold;" target="_blank" title="Click to know more about UNITS">UNITS</a> a=0.4 units</body></html> | |
| 38929. |
What is elastic fatigue? |
| Answer» <html><body><p></p>Solution :The state of temporary loss of elastic properties of a body <a href="https://interviewquestions.tuteehub.com/tag/due-433472" style="font-weight:bold;" target="_blank" title="Click to know more about DUE">DUE</a> to continuous <a href="https://interviewquestions.tuteehub.com/tag/periodic-598580" style="font-weight:bold;" target="_blank" title="Click to know more about PERIODIC">PERIODIC</a> <a href="https://interviewquestions.tuteehub.com/tag/stree-653718" style="font-weight:bold;" target="_blank" title="Click to know more about STREE">STREE</a> is caleld elsatic fatiguel. When fatigue is <a href="https://interviewquestions.tuteehub.com/tag/developed-431631" style="font-weight:bold;" target="_blank" title="Click to know more about DEVELOPED">DEVELOPED</a> we can break the body with <a href="https://interviewquestions.tuteehub.com/tag/little-1075899" style="font-weight:bold;" target="_blank" title="Click to know more about LITTLE">LITTLE</a> stress far below the breaking stress. To remove elastic fatigue rest must be given to the body otehrwiese it will break away.</body></html> | |
| 38930. |
Moment of a force of magnitude 20 N acting along positive x-direction at point (3m,0,0) about the point (0,2,0) (in N-m) is |
| Answer» <html><body><p>20<br/>60<br/><a href="https://interviewquestions.tuteehub.com/tag/40-314386" style="font-weight:bold;" target="_blank" title="Click to know more about 40">40</a><br/>30</p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/torque-1422441" style="font-weight:bold;" target="_blank" title="Click to know more about TORQUE">TORQUE</a>, `tau=rxxF` <br/> `=[(0-<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)hat(i)+(2-0)hat(j)+(0-0)hat(k)]<a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a>[20 hat(i)]` <br/> `=[3 hat(i)+2hat(j)]xx[20 hat(i)]=-40 hat(k)`.</body></html> | |
| 38931. |
You hold a rubber ball in your hand. The Newton’s third law companion force to the force of gravity on the ball is the force exerted by the |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/ball-891849" style="font-weight:bold;" target="_blank" title="Click to know more about BALL">BALL</a> on the earth<br/>ball on the hand<br/>hand on the ball<br/>earth on the ball</p>Answer :A</body></html> | |
| 38932. |
The potential energy of a harmonic oscillator of mass 2 kg in its mean position is 5 J. If its total energy is 9J and its amplitude is 0.01 m, find its time period. |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`1/2kA^(2)+(9-5)=<a href="https://interviewquestions.tuteehub.com/tag/4j-318772" style="font-weight:bold;" target="_blank" title="Click to know more about 4J">4J</a>` <br/> `:.k=8/(A^(2))=8/((0.01)^(2))=8xx10^(<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>)N//m` <br/> `T=2pisqrt(m/k)=2pisqrt(2/(8xx10^(4)))=(<a href="https://interviewquestions.tuteehub.com/tag/pi-600185" style="font-weight:bold;" target="_blank" title="Click to know more about PI">PI</a>)/<a href="https://interviewquestions.tuteehub.com/tag/100s-266020" style="font-weight:bold;" target="_blank" title="Click to know more about 100S">100S</a>`</body></html> | |
| 38933. |
If |vec(A)| = 4N, |vec(B)| = 3N the value of |vec(A) xx vec(B)|^(2) + |vec(A).vec(B)|^(2) = |
| Answer» <html><body><p>5N<br/>25N<br/>144N<br/>169N</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 38934. |
A particle of mass 1 kg is attached to a string of length 5 m. The string is attached to a fixed point O. It is released from theposition as shown in Fig. Calculate a. the impulse developed in the string when it becorries taut, b. the velocity of the particle just after the string becomes taut, c. the impulse developed in this string PQ at this instant. |
| Answer» <html><body><p></p>Solution :From `M` to `<a href="https://interviewquestions.tuteehub.com/tag/n-568463" style="font-weight:bold;" target="_blank" title="Click to know more about N">N</a>` the ball will fall a distance o `4m`, then impulse will be developed in the string ON. <br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/BMS_VOL2_C01_E01_047_S01.png" width="80%"/> <br/> <a href="https://interviewquestions.tuteehub.com/tag/velocity-1444512" style="font-weight:bold;" target="_blank" title="Click to know more about VELOCITY">VELOCITY</a> of the ball just before the string <a href="https://interviewquestions.tuteehub.com/tag/becomes-1994370" style="font-weight:bold;" target="_blank" title="Click to know more about BECOMES">BECOMES</a> tight <br/>` u_(0)=sqrt(2xx10xx4)=sqrt(80)m//s` <br/> velocity of the ball in the <a href="https://interviewquestions.tuteehub.com/tag/direction-1696" style="font-weight:bold;" target="_blank" title="Click to know more about DIRECTION">DIRECTION</a> perpendicular to the impulse will remain same (just after and just before the impulse developed.) <br/> `v=u_(0)sintheta=sqrt(80)xx3/5=15/(sqrt(5))m//s` <br/> `J=mu_0costheta=1sqrt(80)xx4/5=16/(sqrt(5)) kgm//s` <br/> `J'=Jsintheta=4/(5sqrt(5))kgm//s` <br/> and impulse given by earth <br/> `J''=Jcostheta=64/(5sqrt(5))kgm//s`</body></html> | |
| 38935. |
Three liquids A,B and C having same specific heat and mass m , 2m and 3m have temperature 20^@C, 40^@C and 60^@C respectively. Temperature of the mixture when : {:("Column -I","Column -II"),("A) A and B are mixed,is at","P)" 35^@C),("B) A and C are mixed , is at ","Q)" 52^@C),("C) B and C are mixed , is at ","Q)" 50^@C),("D) A , B and C all three are mixed , is at ","S)"45^@C),(,"T) None"):} |
| Answer» <html><body><p><<a href="https://interviewquestions.tuteehub.com/tag/p-588962" style="font-weight:bold;" target="_blank" title="Click to know more about P">P</a>><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A - T ; <a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a> - P ; <a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a> - S ; D - <a href="https://interviewquestions.tuteehub.com/tag/q-609558" style="font-weight:bold;" target="_blank" title="Click to know more about Q">Q</a></body></html> | |
| 38936. |
If a planet of given density were made larger (keeping its density unchanged) its force of attraction for an object on its surface would increased because of increased mass of the plane but would decrease because of larger separation between the centre of the planet and its surface. Which effect would dominate? |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/increase-1040383" style="font-weight:bold;" target="_blank" title="Click to know more about INCREASE">INCREASE</a> in mass<br/>increase in radius<br/>both <a href="https://interviewquestions.tuteehub.com/tag/affect-851195" style="font-weight:bold;" target="_blank" title="Click to know more about AFFECT">AFFECT</a> the <a href="https://interviewquestions.tuteehub.com/tag/attraction-887653" style="font-weight:bold;" target="_blank" title="Click to know more about ATTRACTION">ATTRACTION</a> equally<br/>none of the above</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 38937. |
Choose the false statement |
| Answer» <html><body><p>Scalar product and <a href="https://interviewquestions.tuteehub.com/tag/vector-20923" style="font-weight:bold;" target="_blank" title="Click to know more about VECTOR">VECTOR</a> porduct obey commutative <a href="https://interviewquestions.tuteehub.com/tag/law-184" style="font-weight:bold;" target="_blank" title="Click to know more about LAW">LAW</a><br/>Scalar product does <a href="https://interviewquestions.tuteehub.com/tag/nat-23876" style="font-weight:bold;" target="_blank" title="Click to know more about NAT">NAT</a> obey distributive law where as vector product obeys commutative law<br/>Scalar product and vector product obey associative law <br/>all the above</p>Answer :D</body></html> | |
| 38938. |
An ideal gas is initially at temperature T and volume V. Its volume increases by DV due to an increase in Temperature.dT, while pressure remains constant Here gamma=1/V=(dV)/(dT) What will be the nature of the graph between gamma and l? |
| Answer» <html><body><p></p>Solution :In <a href="https://interviewquestions.tuteehub.com/tag/case-910082" style="font-weight:bold;" target="_blank" title="Click to know more about CASE">CASE</a> an ideal gas <br/> `pV=RT or ,<a href="https://interviewquestions.tuteehub.com/tag/v-722631" style="font-weight:bold;" target="_blank" title="Click to know more about V">V</a>=(RT)/p` <br/> When pressure remains <a href="https://interviewquestions.tuteehub.com/tag/constant-930172" style="font-weight:bold;" target="_blank" title="Click to know more about CONSTANT">CONSTANT</a>, we have <br/> `(<a href="https://interviewquestions.tuteehub.com/tag/dv-433533" style="font-weight:bold;" target="_blank" title="Click to know more about DV">DV</a>)/(dT)=R/P`<br/> `thereforegamma=1/V(dV)/(dT)=1/VR/P=R/(RT)=1/T`<br/>i.e., `gamma T=1`=constant <br/> So the graph `gamma-T` will be a rectangular <a href="https://interviewquestions.tuteehub.com/tag/hyperbola-1034512" style="font-weight:bold;" target="_blank" title="Click to know more about HYPERBOLA">HYPERBOLA</a> [Fig.6.20] <br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/CHY_DMB_PHY_XI_P2_U07_C06_E01_023_S01.png" width="80%"/></body></html> | |
| 38939. |
The escape velocity on a planet is v. If the radius of the planet contracts to 1//4^("th")the present value without any change in its mass, then the escape velocity becomes |
| Answer» <html><body><p>v<br/>v/2<br/>2v<br/>`<a href="https://interviewquestions.tuteehub.com/tag/sqrt2v-3056949" style="font-weight:bold;" target="_blank" title="Click to know more about SQRT2V">SQRT2V</a>`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 38940. |
A solid floats in a liquid at 20°C with 75% 0f it immersed. When the liquids is heated to 100°C, the same solid floats with 80% of it immersed in the liquid. Calculate the coefficient of expansion of the liquid. Assume the volume of the solid to be constant. |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :`8.47 <a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a> <a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a>^(-<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>)//""^(@) <a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a>`</body></html> | |
| 38941. |
If the Earth's pull on the Moon suddenly disappears, what will happen to the Moon? |
| Answer» <html><body><p></p>Solution : Basically, the moon would become the <a href="https://interviewquestions.tuteehub.com/tag/third-1414358" style="font-weight:bold;" target="_blank" title="Click to know more about THIRD">THIRD</a> planet, however the orbit may change. The moon is in orbit <a href="https://interviewquestions.tuteehub.com/tag/around-5602275" style="font-weight:bold;" target="_blank" title="Click to know more about AROUND">AROUND</a> the <a href="https://interviewquestions.tuteehub.com/tag/earth-13129" style="font-weight:bold;" target="_blank" title="Click to know more about EARTH">EARTH</a>, and what happens will <a href="https://interviewquestions.tuteehub.com/tag/depend-948478" style="font-weight:bold;" target="_blank" title="Click to know more about DEPEND">DEPEND</a> on just when the earth disappears The moon travels around the earth at about 1 km/sec and the Earth - moon <a href="https://interviewquestions.tuteehub.com/tag/pair-1145723" style="font-weight:bold;" target="_blank" title="Click to know more about PAIR">PAIR</a> travel around the sun at about 30 km/sec. This extra 1 km/sec movement will result in an orbit change .</body></html> | |
| 38942. |
A rectangular box lies on a rough inclined surface The co- efficient of friction between the surface and the box mu Let the mass of box be m (a) At what angle of inclination 0 of the plane to the horizontal will box just start to slide down the plane ? (b) What isthe force acting on box down the plane if the angle of inclination of the plane is increases toalpha gt theta? (c) What is the force needed to be applied upwards along the plane to make the box either remain stationary or just move up with unifrom speed ? (d) What is the force needed to be applied upwards along the plane to make the box move up the plane with acceleration a ? |
| Answer» <html><body><p></p>Solution :(a) As the box tends to slide down force of friction will <a href="https://interviewquestions.tuteehub.com/tag/act-1106" style="font-weight:bold;" target="_blank" title="Click to know more about ACT">ACT</a> up the <a href="https://interviewquestions.tuteehub.com/tag/plane-1155510" style="font-weight:bold;" target="_blank" title="Click to know more about PLANE">PLANE</a> <br/> As is clear from box will just start slidding down , when <br/> ` mg sin theta = f = mu R = mu mg cos theta` <br/> or ` tan theta = mu or theta = tan^(-1) (mu) ` <br/> (b) When <a href="https://interviewquestions.tuteehub.com/tag/angle-875388" style="font-weight:bold;" target="_blank" title="Click to know more about ANGLE">ANGLE</a> of inclination is increased to `<a href="https://interviewquestions.tuteehub.com/tag/alpha-858274" style="font-weight:bold;" target="_blank" title="Click to know more about ALPHA">ALPHA</a> gt theta` then net force acting on the box down the plane is <br/> ` F_(1) = mg sin alpha - f = mg sin alpha + f = mg (sin alpha+ mu cos alpha)` <br/> (In this case friction would act down the plane ) (d) If the box is to be moved with an upward acceleration a then upward force <a href="https://interviewquestions.tuteehub.com/tag/needed-1112853" style="font-weight:bold;" target="_blank" title="Click to know more about NEEDED">NEEDED</a> <br/> ` F_(3) = mg (sin alpha+ mu cos alpha) + ma ` <br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/PR_XI_V01_C03_S01_389_S01.png" width="80%"/> .</body></html> | |
| 38943. |
For a monoatomic ideal gas undergoing an adiabatic change, the relation between temperature and volume is TV^(x) = constant, where x is |
| Answer» <html><body><p>`7//<a href="https://interviewquestions.tuteehub.com/tag/5-319454" style="font-weight:bold;" target="_blank" title="Click to know more about 5">5</a>`<br/>`2//5`<br/>`2//3`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>//3`</p>Solution :For an adiabatic change, `TV^(gamma - 1)` = <a href="https://interviewquestions.tuteehub.com/tag/constant-930172" style="font-weight:bold;" target="_blank" title="Click to know more about CONSTANT">CONSTANT</a> …(i) <br/> `TV^(x)` = constant (Given) ….(<a href="https://interviewquestions.tuteehub.com/tag/ii-1036832" style="font-weight:bold;" target="_blank" title="Click to know more about II">II</a>) <br/> <a href="https://interviewquestions.tuteehub.com/tag/comparing-2531631" style="font-weight:bold;" target="_blank" title="Click to know more about COMPARING">COMPARING</a> (i) and (ii), we get `x = gamma - 1` <br/> For a monatomic gas, `gamma = (5)/(3) :. x = (5)/(3) - 1 = (2)/(3)`</body></html> | |
| 38944. |
A body is projected horizontally from the top of hill with a velocity of 9.8 m/s. What time elapse before the vertical velocity is twice the horizontal velocity? |
| Answer» <html><body><p>0.5 <a href="https://interviewquestions.tuteehub.com/tag/sec-1197209" style="font-weight:bold;" target="_blank" title="Click to know more about SEC">SEC</a><br/>1 sec <br/><a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a> sec<br/>1.5 sec</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 38945. |
The velocity with which a body should be projected from the surface of the earth such that it reaches a maximum height equal to n times the radius R of the earth is |
| Answer» <html><body><p>`sqrt((<a href="https://interviewquestions.tuteehub.com/tag/n-568463" style="font-weight:bold;" target="_blank" title="Click to know more about N">N</a>)/(n+_1)(GM)/(R))` <br/>`s<br/>sqrt((<a href="https://interviewquestions.tuteehub.com/tag/ngm-3743707" style="font-weight:bold;" target="_blank" title="Click to know more about NGM">NGM</a>)/(R ))` <br/>`sqrt((2n)/(n+1)(GM)/(R ))` </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :C</body></html> | |
| 38946. |
Is it neccesary that all black coloured bodies to be regarded as perfectly black bodies ? |
| Answer» <html><body><p></p>Solution :Not neccesary. For <a href="https://interviewquestions.tuteehub.com/tag/example-978283" style="font-weight:bold;" target="_blank" title="Click to know more about EXAMPLE">EXAMPLE</a> a highly polished <a href="https://interviewquestions.tuteehub.com/tag/black-898687" style="font-weight:bold;" target="_blank" title="Click to know more about BLACK">BLACK</a> surface <a href="https://interviewquestions.tuteehub.com/tag/need-25476" style="font-weight:bold;" target="_blank" title="Click to know more about NEED">NEED</a> not behave as a <a href="https://interviewquestions.tuteehub.com/tag/perfect-1150611" style="font-weight:bold;" target="_blank" title="Click to know more about PERFECT">PERFECT</a> black body.</body></html> | |
| 38947. |
Why are shock absorbers used in cars, scooters, and motore cycles ? |
| Answer» <html><body><p></p>Solution :To increse the <a href="https://interviewquestions.tuteehub.com/tag/time-19467" style="font-weight:bold;" target="_blank" title="Click to know more about TIME">TIME</a> of <a href="https://interviewquestions.tuteehub.com/tag/jerk-524813" style="font-weight:bold;" target="_blank" title="Click to know more about JERK">JERK</a> and <a href="https://interviewquestions.tuteehub.com/tag/thereby-3202828" style="font-weight:bold;" target="_blank" title="Click to know more about THEREBY">THEREBY</a> decrese the <a href="https://interviewquestions.tuteehub.com/tag/impulsive-498972" style="font-weight:bold;" target="_blank" title="Click to know more about IMPULSIVE">IMPULSIVE</a> <a href="https://interviewquestions.tuteehub.com/tag/force-22342" style="font-weight:bold;" target="_blank" title="Click to know more about FORCE">FORCE</a>.</body></html> | |
| 38948. |
The ends of a metal rod of length 40 cm are maintained at temperatures 100^(@)Cand20^(@)C respectively. At steady state condition, the temperature at a point at a distance 30 cm from the hot end of the rod is |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`<a href="https://interviewquestions.tuteehub.com/tag/40-314386" style="font-weight:bold;" target="_blank" title="Click to know more about 40">40</a>^(@)<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a>`</body></html> | |
| 38949. |
The initial state of a certain gas is (P_(i)V_(i) T_(i)). It undergoes expansion till its volume becomes V_(int).Consider the following two cases. a) The expansion takes place at constant temperature. b) The expansion takes place at constant pressure. Plot the P-V diagram for each case. In which of the two cases, is the work done by the gas more ? |
| Answer» <html><body><p></p>Solution :The P-V <a href="https://interviewquestions.tuteehub.com/tag/diagram-950736" style="font-weight:bold;" target="_blank" title="Click to know more about DIAGRAM">DIAGRAM</a> for each case is <a href="https://interviewquestions.tuteehub.com/tag/shown-1206565" style="font-weight:bold;" target="_blank" title="Click to know more about SHOWN">SHOWN</a> in the <a href="https://interviewquestions.tuteehub.com/tag/figure-987693" style="font-weight:bold;" target="_blank" title="Click to know more about FIGURE">FIGURE</a>. In case (i) `P_(i)V_(i)=P_(f)V_(f)` : therefore <a href="https://interviewquestions.tuteehub.com/tag/process-11618" style="font-weight:bold;" target="_blank" title="Click to know more about PROCESS">PROCESS</a> is isothermal. Work done = area under the PV curve so work is more when the gas expands at constant pressure.<br/> <img src="https://doubtnut-static.s.llnwi.net/static/physics_images/AKS_DOC_OBJ_PHY_XI_V01_C_C13_SLV_046_S01.png" width="80%"/></body></html> | |
| 38950. |
T_(1)T_(2) and T_(3) the time periods of a given pendulum on the surface of the earth, at a depth h in a mine and at an altitude h above the earth's surface respeceively, then |
| Answer» <html><body><p>`T_(1)=T_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)`<br/>`T_(2)ltT_(1)gtT_(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)`<br/>`T_(3)gtT_(2)gtT_(1)`<br/>`T_(1)gtT_(2)ltT_(3)`</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |