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One railway line should be extended by 3.36/2 = 1.68 cm = 0.0168 m

Let at temperatureT2lines just touch . Here ,L1=66m,T1=10°CCoficientoflinearexpansion(α)=11×10−6C−1L2=66m+0.0168m=66.0168mL2=L1[1+α(T2−T1)]66.0168=66[1+(11×10−6)(T2−10)]66.016866=1+(11×10−6)(T2−10)66.016866−1=(11×10−6)(T2−10)0.016866=(11×10−6)(T2−10)0.0168×10666×11=(T2−10)16800726+10=T223.14+10=T2Thetemperatureatwhichtherailsjustis23.14°C

Coefficient of volume expansion = coefficient of linear expansion * 3= 19*(10^-6)*3= 57*(10^-6) °C-¹

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Ans :- angle of friction the angleof a plane to the horizontal when a body placed on the plane will just start to slide. The tangent of theangle of frictionis the coefficient of static friction.

The coefficient of friction between any two surfaces in contact is defined as the ratio of the force of limiting friction and normal reaction between them.

u= F / R

Angle with the resultant of force of limiting friction F and normal reaction R makes with the direction of normal reaction R is angle of reaction.

Metalparticles are held by strong metallic bounds that is they have high melting and boiling points. Thus free electrons inmetalscan move through themetalsallowingelectricityto pass through themetals.

ThePeltier coefficientis a measure of the amount of heat carried by electrons or holes. When two different materials are joined together to form a loop,there will be an abrupt change in heat flow at the junctions because the two materials have differentPeltier coefficients.

answer is graphite for this question

graphite is the right answer of this question.

Power of lens = +2.5D , e.g., positive means lens is converging.A converging lens is convex lens . Hence person is using a convex lens for correcting his vision.Convex lens is used to correct myopia . A myopic eye, can't able to see distinct object clearly but can see nearby object clearly . the reason of this defect is elongation of eyeball and excessive curvature of the lens.

Now, P = +2.5D P = 1/f ⇒f = 1/P = 1/2.5 m = 100/2.5 = 40cm

Hence , focal length of convex lens is 40cm

Myopia convex lensP=1/f2.5=1/ff=10/25f=0.4m

Power of lens = +2.5D , e.g., positive means lens is converging.A converging lens is convex lens . Hence person is using a convex lens for correcting his vision.Convex lens is used to correct myopia . A myopic eye, can't able to see distinct object clearly but can see nearby object clearly . the reason of this defect is elongation of eyeball and excessive curvature of the lens.

Now, P = +2.5D P = 1/f ⇒f = 1/P = 1/2.5 m = 100/2.5 = 40cm

Hence , focal length of convex lens is 40cm

Power of lens = +2.5D , e.g., positive means lens is converging.A converging lens is convex lens . Hence person is using a convex lens for correcting his vision.Convex lens is used to correct myopia . A myopic eye, can't able to see distinct object clearly but can see nearby object clearly . the reason of this defect is elongation of eyeball and excessive curvature of the lens.

Now, P = +2.5D P = 1/f ⇒f = 1/P = 1/2.5 m = 100/2.5 = 40cm

Hence , focal length of convex lens is 40cm

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thanks amrit

Since charge is at rest, so it wont experience any force.

Clay cannot be used to make a lens.

It is due to the specific heat capacity of water being significantly greater than that of land. The sea & oceans have therefore greater thermal inertia so need to shed a lot of energy for a degree K of temperature. So less variation in temp between summer & winter. Compare this with the massive extremes of temperature in like as far from the sea as you can get, cental Asia.

(a)Rs=R1+R2+R3....(b)1/Rp=1/R1+1/R2+1/R3...

Let drop on R1 be V1 & drop on R2 be V2.

Total voltage V=V1+V2

We know that V=I*Req(ohms law)

So I*Req=(I*R1)+(I*R2)

Req=R1+R2

For parallel resistance:

In parallel circuits voltage drop across resistors will be same but the current flowing through each resistor depends on resistance valule.

Let current through R1 be I1 & current through R2 be I2.

I=V/Req(ohms law)

So I=I1+I2

V/Req=(V/R1)+(V/R2)

1/Req=(1/R1)+(1/R2)

Req=(R1*R2)/(R1+R2)

The right answer is clay

Clay is opaque and therefore cannot be used to make lens.

Clay is opaque and therefore cannot be used to make lens.

1.Music is the art of arranging and combining sounds in order to create a harmoniousmelodywhile noise is an unwanted sound that is usually very loud and meaningless.2.Music is pleasing to the ears while noise is an unpleasant sound.3.Noise has irregular wave form and wave length and has low frequency while music has frequencies and wave lengths that are harmonious.4.Noise can obstruct and confuse the spoken messages of man and animals when they are communicating with each other while music has a very soothing and pleasing effect.5.Noise may also be low like the conversation between two people, which is considered noise by a third person who is not involved, while music may also be loud such as in the case of heavy metal or rock music.

Thx

Cylinder lens is required

beat freq.= f1-f2= 255-250= 5 Hz

Hence, 1 beat will be heard in 5s

Option d is correct as there is no medium for sound waves to travel.

i) Η=F×r÷Avf=tangential force,r=distance between the layer , v=velocitydimensional formula for force = M¹L¹T⁻²dimensional formula for area = M⁰L²T⁰dimensional formula for distance = M⁰L¹T⁰dimensional formula for velocity = M⁰L¹T⁻¹η= M¹L¹T⁻²ₓ M⁰L¹T⁰÷M⁰L²T⁰ₓ M⁰L¹T⁻¹=M¹L⁻¹T⁻¹dimensional formula for coefficient of viscosity =M¹L⁻¹T⁻¹

Ess quiston kaa sahi answer (b) hoga

c) is the correct answer good

option C is correct answer

Option C is right

Option C is the answer

Option Cwe draw FBDof this systemwith all referenceas forces in i , j and k

C=12.8% at.wt. of C=12H=2.1%. at.wt. of H=1Be=85.1%. at.wt. of Br=80Now, 12.8/12 =1.067 2.1/1 = 2.1 85.1/80=1.067

Dividing with 1.067 to get simple atomic ratio,

1.067/1.067=12.1/1.067=21.067/1.067=1E.F= CH2BrE.F

weight=12+(2×1)+80=94

Molecular weight=187.9 (given)

n=187.9/94= 2M.F= (E.F)×2 =(CH2Br)×2 =C2H4Br2

so, the answer of this question❓❓❓ is (C2HBr2

Metal is a solid material which conduct heat & electricity ,hard, shiny, malleable, fusible, and ductile.

Nonmetal is a substance that do not exhibit properties of metals such as hardness, luster, malleability ,ductility and the ability to conduct electricity

If F is retarding force and s the stopping distance then 1/2 m2 =Fs For same retarding force, s a v2 s_2/s_1 = (v_2/v_1 )^2 =((80 km/h)/(40 km/h))^2 =4 s2 = 4s1 = 4 × 2 = 8m

Using,v = u + at

v = 0u = 15 m/sa = - 5 m/s^2

0 = 15 - 5*tt = 15/5 = 3 d

Now, usings = ut + 1/2 a t^2 = 15*3 + 1/2 * (-5) * 3*3 = 45 - 45/2 = (90 - 45)/2 = 45/2 = 22.5 m

(d) is correct option

If F is retarding force and s the stopping distance then 1/2 m2 =Fs For same retarding force, s a v2 s_2/s_1 = (v_2/v_1 )^2 =((80 km/h)/(40 km/h))^2 =4 s2 = 4s1 = 4 × 2 = 8m

Initial velocity, u = 50 km/h = 50 × (5/18) = 250/18 m/s

Final velocity, v = 0

Distance travelled before coming to rest, s = 6 m

Using, v2= u2+ 2as

=> a = -u2/(2s)

=> a = -16.075 m/s2

Again,

u = 100 km/h = 500/18 m/s

v = 0

a = -16.075 m/s2

Now, v2= u2+ 2as

=> s = -u2/(2a) = 24 m

thank you is this the in your syllabus

Initial velocity, u = 50 km/h = 50 × (5/18) = 250/18 m/s

Final velocity, v = 0

Distance travelled before coming to rest, s = 6 m

Using, v2= u2+ 2as

=> a = -u2/(2s)

=> a = -16.075 m/s2

Again,

u = 100 km/h = 500/18 m/s

v = 0

a = -16.075 m/s2

Now, v2= u2+ 2as

=> s = -u2/(2a) = 24 m

Initial velocity = uacceleration = a

1000 = u(30) + 0.5a(30)²1000 = 30u + 450a

velocity after covering 1 km = u + 30a1000= (u+30a) (20) + 0.5a (20)²1000= 20u + 800au = 35aputting the value of u in above equationso, a = 2/3

Static friction is greater than kinetic friction.

Static friction exists if the wheels keep rolling on the ice without locking up, resulting in maximum braking force. However, if the wheels lock up then kinetic friction takes over since there is relative slipping between wheel and ice. This reduces the braking force and the car takes longer to stop.

Anti-lock braking systems (ABS) on a vehicle prevent the wheels from locking up when the brakes are applied, thus minimizing the amount of time it takes for the vehicle to reach a complete stop. Also, by preventing the wheels from locking up you have greater control of the vehicle.