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British saw caste as a way to deal with a huge population by breaking it down into discrete chunks with specific characteristics. Moreover, as will be seen later in this paper, it appears that the caste system extant in the late 19th and early 20th century has been altered as a result of British actions so that it increasingly took on the characteristics that were ascribed to by the British.

One of the main tools used in the British attempt to understand the Indian population was the census. Attempts were made as early as the beginning of the 19th century to estimate populations in various regions of the country but these, as earlier noted, were methodologically flawed and led to grossly erroneous conclusions. It was not until 1872 that a planned comprehensive census was attempted. This was done under the direction of Henry Beverely, Inspector General of Registration in Bengal. The primary purpose given for the taking of the census, that of governmental preparedness to deal with disaster situations, was both laudable and logical. However, the census went well beyond counting heads or even enquiring into sex ratios or general living conditions. Among the many questions were enquiries regarding nationality, race, tribe, religion and caste. Certainly none of these things were relevant to emergency measures responses by the government.

The Tyndall effect is the scattering of light as a light beam passes through a colloid. The individual suspension particles scatter and reflect light, making the beam visible

ratio of distance travelled in 4th to 3rd = (2×4-1)/(2×3-1)= 7/5

Option a is correct.

The decomposition of liquid compound on passing an electric current through it is knownas Electrolysis.

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Both the bodies will meet after 6 seconds.

12 Seconds is the answer of the following

6second is answer of following question

∆Tf/m= Kfashere m tends to 0Kf temds to 1

M=1g=10^−3kgc=velocityoflight=3×10^8m/sTherefore,E =mc^2E=10^−3×(3×10^8)2E=9×10^13J

atomic number is the same as no of protons.so no of protons is 70

Emf is a kind of work as in electromagnetic induction, emf can defined around a closed loop ofconductoras the electromagneticworkthat would be done on anelectric charge(anelectronin this instance) if it travels once around the loop.

Hence option c is correct.

The metal ball can be considered to be made up of several layers of thinner ones. On heating each of these layers will increase in radius. As the inner most layer also increases its radius, the volume inside it i.e, the volume of the hollow portion will also increase.

Hi dear... Please post clearly... There r something missing in your quotation

The element is potassium,and it's symbol is K,It's atomic number is 19 and mass number is 39,Its electronic configuration is-1s2,2s2,2p6,3s2,3p6,4s1. And its valance e is only one, that is 4s1. No of protons is 19 and no of e is also 19 but no of neutron is 20.🙂🙂🙂

a...If the work done against a force is independent of the path taken then such force is calledConservative force.

Gravitational force, spring force, electrostatic force etc. are some of the example of conservative force.

what is the correct answer?

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0.0955 is the correct answer

Answers :-

Given :

resistivity of the conductor = 44 * 10^-8 ohm m.

R = 14 ohm

Diameter = 1mm

Area = πD^2/4 = π/4 * (10^-3)^2 m^2

we know that,

length of wire = resistance * area/ resistivity of the conductor

=. 14 * π/4 * (10^-6)* 1/44*10^-8

= 14 * (22/7*4 )* 10^-6 *1/44*10^-8

= 14 * 22/28 * 100/44

= 22/2 * 100/44

= 100/4

= 25m

Mass of HNO3 solution = 50 mL * 1.5 g/mL

Mass of HNO3 = mass of HNO3 solution * 0.63

Convert mass of HNO3 to moles.

for molarity, concentration = moles / volume.

concentration is 1 mole/L per the problem. You just worked out the moles of HNO3. Calculate the volume of the solution.

Volume of water = volume of solution from above - 50 mL

Current density is defined as current flowing per unit area provided the area is held normal to the current. Current density is a property which describes at a specific point of the conductor.

Specific resistance of a conductor is the resistance of a conductor of unit length and unit area of cross section. Specific resistance is a property of a material while resistance is not. Resistance increases with length and decreases with area of cross section, but specific resistance does not.

The ratio of total resistance to individual resistance is the same ratio as individual (branch) current to total current. This is known as the current divider formula and it is a short-cut method for determining branch currents in a parallel circuit when the total current is known.hence option a

The stone will move in which direction he whirled it i.e. if he moves it in clockwise direction the stone will move in the same direction and vise versa.

In an ideal world, which is the case in most of the questions, the stone will go along the tangent to the circle of rotation.

option 1 is correct

area of parallelogram will be cross product of these side vectors

According to Kepler's law , T² directly proportional to a³ Here T denotes the time period and a denotes the distance between two objects

Here, when distance between planet and star is R then time period is T means T² = kR³ [ here k is proportionality constant ]----(1)

Again, Let the time period is T' when distance between planet and star is 2R T'² = k(2R)³ = k.8R³ -----(2)

Dividing equation (1) by (2) T²/T'² = kR³/k8R³ = 1/8 T'² = 8T²square root both sides, T' = √8T Hence, time period will be √8 T , when distance between planet and star will be 2R

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Current Amplification Factoror Current Gainis basically the ratio of the ratio of the outputcurrentto the inputcurrentwhen its passing through an electrical device.

So, it gives us the amount ofcurrentgained as it flows through

27) 1atm pressure is equivalent of 0. 76 m of HG.

=O.76*13.6m of water =10.34 m .of water .

V= ✓2gh ,=✓2 *9.8*10.34×3 for 3 ATM.pressure.

V= 24.64m/s

you can do one thinguse this formulaafter exact sign of u and vf = uv/u+v

John Bardeenis the only laureate to win the prize twice—in 1956 and 1972.

John Bardeen is the only laureate to win the prize twice in 1956 and 1972. Maria s

Maria skłodowska-curie also won two Nobel prizes for physics in 1903

Diamagnetsrepel, and arerepelledby a strongmagnetic field.

The electrons in adiamagneticmaterial rearrange their orbits slightly creating small persistent currents which oppose the externalmagnetic field.

However, the addition ofdiamagnetic materialsmakes such levitation possible.