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as dot product is zero these vectors must be perpendicular

NAND operation

by bending the rods two rods pf mass m/2 and length l/2 are formed

so moment of inertia about an axis at the point of bending and perpendicular to the plane is=

ML2/24+ML2/24=ML2/12

Acceleration of simple harmonic motion is

amax = - w^2 A

amax1/amax2 = w1^2/w2^2

amax1/amax2 = (100)^2/(1000)^2

amax1/amax2 = 1/10^2

(A) is correct option

Light rays that are parallel to theprincipal axis of a concave mirrorconverge at a specific point on itsprincipal axisafter reflecting from themirror. This point is known as theprincipal focusof theconcave mirror.

In the following graph for parallel and series combination of two metallic resistors are shown in the figure the graph represents parallel combination is xy

N- type :- When we use a pentavalent impurity for doping then we get a n-type semiconductor. Example of pentavalent impuritie are phosphorus or arsenic.

P-type :- When we use trivalent impurities for doping then we get a p-type semiconductor. Example of trivalent inpurities are aluminium or boron.

n-type Semi-ConductorIt is an extrinsic semi-conductor which is obtained by doping the impurity atoms of Vth group of the periodic table to the pure Ge and Si semi-conductor.

The impurity atoms added, provide extra electrons in the structure and are called donor atoms.

The electrons are majority carriers and holes are minority carriers.The electrons density (ne) is much greater than the hole density (nh) i.e.>> nh.The donor energy level is close to the conduction band and for away from the valence band.

The Fermi-energy level lies in between the donor energy level and conduction band.P-type Semi-ConductorIt is an extrinsic semi-conductor which is obtained by doping the impurity atoms of III group of the periodic table to the pure Ge and Si semi-conductor.

The impurity atoms added, create vaccines of electrons (i.e. holes) in the structure and are called acceptor atoms.

The holes are majority carriers and electrons are minority carriers.The holes density (nh) is much greater than the electrons density (ne) i.e.>> ne.The acceptor energy level is close to the Valence band and for away from the Conduction band.The Fermi-energy level lies in between the acceptor energy level and valence band.These are the differences between n type and p type semiconductors.

Acceleration of simple harmonic motion is

amax = - w^2 A

amax1/amax2 = w1^2/w2^2

amax1/amax2 = (100)^2/(1000)^2

amax1/amax2 = 1/10^2

(D) is correct option

principal focus or focus, is the point on the axis of a lens or mirror to which parallel rays of light converge or from which they appear to diverge after refraction or reflection

lets discuss now

Cp and Cv are specific heats per gram

a=Cp - Cv = R/2{for hydrogen gas} as[R is per mole of H₂ i.e. 2grams]hope you getting it,,its not always cp-cv=R its only for ideal cases

similarly

b=Cp - Cv = R/28{for nitrogen gas} as[R is per mole of N₂ i.e. 28 grams]

from above eqns.

a=R/2 →2a=R

substituting value in eqn 2

b=2a/28

→14b=a

so,,, a=14b

Let O bethe centre of the circle. A, B and C represent the positions of Reshma, Salmaand Mandip.

AB = 6cm and BC = 6cm.

Radius OA = 5cm.(given)

Draw BM ⊥ AC

ABC is an isosceles triangle as AB = BC, M ismid-point of AC.

BM isperpendicular bisector of AC and thus it passes through the centre of thecircle.

Let AM = y and OM = x then BM = (5-x).

In ΔOAM,

OA²=OM²+AM² ( by Pythagorastheorem)

5²=x²+y²—(i)

In ΔAMB,

AB²=BM²+AM²(by Pythagoras theorem)

6²= (5-x)²+y²— (ii)

Subtracting (i) from (ii),

36 – 25 = (5-x)² -x²

11 = (25+x²– 2×5×x) - x²

11= 25+x²-10x - x²

11= 25-10x

10x = 14

x= 7/5

Substituting the value of x in (i), we get

y²+ 49/25 = 25y²=25 – 49/25y²=(625 – 49)/25y²=576/25

y = 24/5

Thus,

AC = 2×AM

AC = 2×y

AC= 2×(24/5) m

= 48/5 m = 9.6 m

Hence, the Distance between Reshma and Mandipis 9.6 m.

=

thanxx but kuch zyada bada method hai

Intensity of Radiation. Theintensity of radiationis defined as the rate of emitted energy from unit surface area through unit solid angle.

Connecting thep-typeregion to thenegative terminalof the battery and then-typeregion to thepositiveterminal corresponds to reverse bias. If a diode is reverse-biased, the voltage at the cathode is comparatively higher than the anode. Therefore, no current will flow until the diode breaks down.Because the p-type material is now connected to the negative terminal of the power supply, the 'holes' in the p-type material are pulled away from the junction, leaving behind charged ions causing the width of the depletion region to increase. Likewise, because the n-type region is connected to the positive terminal, the electrons will also be pulled away from the junction, leaving behind charged ions causing the width of the depletion region to increase.

-TheSouthern Ocean, also known as theAntarctic Ocean or theAustral Ocean, comprises the southernmost waters of theWorld Ocean, generally taken to be south of60°S latitudeand encirclingAntarctica.

-As such, it is regarded as the fourth-largest of the five principal oceanic divisions: smaller than thePacific,Atlantic, andIndianOceans but larger than theArctic Ocean.

-Thisocean zoneis where cold, northward flowing waters from the Antarctic mix with warmersubantarcticwaters.

option (c) is correct

The acceleration due to gravity is given byg=GMR2. So in the other planet the acceleration due to gravity is given byg'=G4MR2=4GMR2=4gSo energy to lift 2 kg mass to 2 m height is given byEp=mg'h=2×4g×2=2×4×10×2=160J

Planet mass is 8 times that earth Planet radius is twice then the radius of earth. Let mass of the Earth = M Radius of the Earth = R Now, we know that The equation to get escape velocity v = √(2 g r) V = root(2GM)/R If the mass of planet is eight times then escape velocity = 2 √2 times. Escape velocity reduced to by 1/√2. If radius expands twice Hence the net escape velocity will be increase. 2 √2 × (1/√2)= 2 times now. Now it is clear that the escape velocity of that planet will be 2 times from the earth. Escape velocity of the earth = 11.2 km/s Escape velocity of that planet = 2 × 11.2 = 22.4 km/sec. Hence the escape velocity of that planet will be 22.4 km/s Like my answer if you find it useful!

Politicalmethodology is a subfield ofPolitical sciencethatstudiesthe quantitativemethodsused to study politics. It combines statistics, mathematics, and formal theory.Politicalmethodology is often used for positive research, in contrast to normative research.

51)v2- u2= 2ah,Suppose u is the max speed with which the person can jump.-u2= -2 g​A​hA= -2 gBhBso, gA/gB=hB/hA=9 or hB= 18m.

thank you

For earth, g = GM/R^2

For the other planet,m = M/2r = R/2

g' = GM/r^2 = G(M/2)/(R/2)^2g' = 2 GM/R^2g' = 2g

Thus the acceleration due to gravity on that planet will be twice of earth; that means 19.6 m/s^2

Anemometer

volume expansion coefficient of glass = 3 x 5.9x10⁻⁶ K⁻¹volume expansion coefficient of mercury = 3 x 61x10⁻⁶ K⁻¹

The amount of overflow depends on the difference between these, which is3x10⁻⁶ x (61-5.9) = 1.653x10⁻⁴ K⁻¹

So the mercury expands more than the glass by an amount:200 x 1.653x10⁻⁴ x (100 – 20) = 2.6cm³This is the amount that overflows.

hit like if you find it useful

nhi aaya

Power of combination = 12.5 + (-2.5 )= 10 D wkt , p = 1/ff = 1/P= 1/10f = 0.1 m= 0.1 * 100 cm= 10 cm

Therefore , total power is 10 D and focal lenght is 10 cm or 0.1 m

thanks

maximum value of net force = Fmax= A+B = 8+6=14Nminimum value of net force = Fmin= A-B = 8-6 = 2therefore single force will be between 2 and 14 therefore ans is 11N

large force is 7N.

R=√F1^2+F2^2+2F1F2cosAP/2=√P^2+P^2+2*P*PcosAP^2/4=2P^2+2P^2cosA1/4=2+2cosA-7/4=2cosA-7/8=cosAA=cos^-1(7/8)

^ ka kya matlab h

The correct option is B.

answer is 4 for this

As we knowR = ρ L/Awhere ρ is resistivity of the materialHere in this case, length is given as Land area is given as L×bSo,Resistance,R = ρ L/Lb = ρ/b

The correct option is m3 < (m1 + m2).

In nuclear fusion the mass of end product or resultant is always less than the sum of initial product, the rest is liberated in the form of energy, like in Sun energy is liberated due to fusion of two hydrogen atoms.

The correct option is m3<(m1+m2)

Sound is a wave, particles gets accelerated, a wave of faster moving particles hits slower moving particles and transfer kinetic energy. The originally slower moving particles are now a faster moving wave of particles and the originally faster moving wave of particles are now slower moving particles, this is how the wave continues.

sound is wave so it travel by a medium that is air

Yes

Yes, Sure