InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 11501. |
44. A solid sphere is in rolling motion. In rollingmotion a body possesses translational kineticenergy (K4) as well as rotational kinetic energy(K) simultaneously. The ratio K, : CK, K) forthe sphere is |
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| 11502. |
14. The kinetic energy K of a rotating body depends on itsmoment of inertia 1 and its angular speed ω. Assumingthe relation to be K-kI 0 where k is a dimensionlessconstant, find a and b. Moment of inertia of a sphereabout its diameter is 2 Mr2 |
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| 11503. |
Derivation of kinetic energy (k. Ez mv 2)ereta |
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Answer» W=FSv^2-u^2=2ass=v^2/2aF=maW=ma.v^2/2aW=kinetic energy = mv^2/2=1/2mv^2 okay |
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| 11504. |
A ball of mass m moving at a speed v makes a head on collision with an identical ball at rest. Thekinetic energy of the balls after the collision is 3/4 of the original kinetic energy. Calculate the coefficientof restitution. |
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Answer» please post clear image |
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| 11505. |
2. Write the SI unit of electrik charge? |
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Answer» TheSIderivedunit of electric chargeis the coulomb (C). Inelectricalengineering, it is also common to use the ampere-hour (Ah), and, in chemistry, it is common to use the elementarycharge(e as aunit). The symbol Q often denotescharge. |
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| 11506. |
define radius of gyration write it's si unit |
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Answer» Radius of gyration or gyradius of a body about an axis of rotation is defined as the radial distance of a point from the axis of rotation at which, if whole mass of the body is assumed to be concentrated, its moment of inertia about the given axis would be the same as with its actual distribution of mass. It's SI unit is M and CGS unit is CM Like my answer if you find it useful! |
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| 11507. |
Q. 30. What is elastic potential energy? |
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Answer» Elastic potential energy is energy stored as a result of applying a force to deform an elastic object. elastic pationtial enargy to 30 our for the your Elastic energy is the potential mechanical energy stored in the configuration of a material or physical system as work is performed to distort its volume or shape. Elastic energy occurs when objects are compressed and stretched, or generally deformed in any manner example can be slingshot |
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| 11508. |
F-1. A particle moving with kinetic energy K makes a head on elastic collision with an identical particle atrest. Find the maximum elastic potential energy of the system during collision. |
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Answer» let the mass of the particles be m and v be its velocity. then 0.5mv^2=k.in an elastic collision, the k.e. before and after the collision remains the same and is minimum when the two particles are moving with the same speed, during collision.applying momentum conservationmv+0=(m+m)VV=v/2K.E.=0.5*2m*V^2= (0.5*m*v^2)/2 = k/2 (the kinetic energy when both masses are moving with same speed, at this moment k.e. is minimum and p.e. is maximum)P.E.+ K.E.= kP.E.= k/2. |
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| 11509. |
An uncharged sphere of metal is placed in a uniformelectric field produced by two large conductingparallel plates having equal and opposite chargesthen lines of force look like:キキキ- |
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Answer» (C) That is because the electric field lines terminate perpendicular on the surface. |
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| 11510. |
mention the expression for potential energy of string |
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Answer» Hooke's Law, F = -kx, where F is the force and x is the elongation. The work done = energy stored in stretched string = F.dx The energy stored can be found from integrating by substituting for force, and we find, The energy stored = kx²/2, where x is the final elongation. The energy density = energy/volume = (kx²/2)/(AL) =1/2(kx/A)(x/L) = 1/2(F/A)(x/L) = 1/2(stress)(strain) Like my answer if you find it useful! |
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| 11511. |
09. Derive the expression for elastic potential energy of a stretched spring. |
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| 11512. |
1) Write SI Unit of work.2) What is Scalar product?3) Mention the expression for potential energy of a string. |
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Answer» Ans :- 1.The SI unit of work is thejoule(J), which is defined as the work expended by a force of onenewton through a displacement of one metre. 2. Scalar Productof Vectors. Thescalar productand the vectorproductare the two ways of multiplying vectors which see the most application inphysicsand astronomy. Thescalar productis also called the "inner product" or the "dot product" in some mathematics texts. 3. The energy stored = (kx^2)/2, where x is the final elongation. |
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| 11513. |
10.The stopping potential in an experiment on photoelectric effect is 1.5 V. What is the maximumkinetic energy of the photoelectrons emitted? |
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| 11514. |
Wavelength of light incident on a photosensitive surface is reduced from 3500 Å to 2900 Å. The change in stopping potential will be ? |
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| 11515. |
75. The light rays having photons of energy 1.8 eV axe falfing on a metal surface having a workfunction 1.2 eV. What is the stopping potential to be applied to stop the emitting electrons-BHU 2005(a) 3ev(b) 1.2 eV(c) 0.6 ev(d) 1.4 eV |
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| 11516. |
[] Derive theof Electrostaticexpressionpotentialenergy |
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Answer» Because it'sderivedfrom a force, it's a vector field. Theelectric potentialis theelectric potential energyof a test charge divided by its charge for every location in space. Because it'sderivedfrom anenergy, it's a scalar field. Definition. ... Theelectrostatic potential energy, UE, of one point charge q at position r in the presence of anelectric fieldE is defined as the negative of the work W done by theelectrostaticforce to bring it from the reference position rrefto that position r. |
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| 11517. |
A hollow conducting sphere is placed in an electric field produced by a point charge at P as shown in thigure. Let VA and Va be the electrostatic potential at points A and B respectively. Then,B VA(4) Relation cannot be determined with the given information |
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Answer» As the sphere is conducting the charge on it will be uniformly distributed. So Vb = Va |
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| 11518. |
12.) Given that a photon of light of wavelength10000 A has energy 1.23 eV. Now when light ofintensity lo and wavelength 5000 A falls on a photocell the saturation current and stopping potentialare 0.40 HA and 1.36 V respectively. The workfunction is(2) 1.10 eV(4) 2.47 eV(1) 0.43 eV1.36 eV |
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| 11519. |
B 5)If the kinetic energy of a body is directly proportional to time t, the magnitude of the force acting on the bodyis:(A) directly proportional to vt(B) inversely proportional to t(C) directly proportional to the speed of the body (D) inversely proportional to the speed of the body |
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Answer» option D. |
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| 11520. |
Given that a photon of light of wavelength10000 A has energy 1.23 eV. Now when light ofintensity lo and wavelength 5000 A falls on a photocell the saturation current and stopping potentialare 0.40 HA and 1.36 V respectively. The workfunction is(1) 0.43 eV(2) 1.10 eV(4) 2.47 eV3) 1.36 evf light incident on a metallic plate |
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| 11521. |
A rectangular loop of area 20 cm * 30 cmplaced in magnetic field of 0.3 T with its plane(i) normal to the field(ii) inclined 30° to the field and(ili) parallel to the field.Find the flux linked with the coil in eachcase. |
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Answer» magnetic fluxφ = N B A cosθθ is the angle between manetic field and area of vector. NOTE that area vector is always perpendicular to its plane area i) plane normal. This simplies area vector is parallel Soθ= 0φ = N B A cos 0 = N B AN = 1 turn B = 0.3 T and A = 20 * 10^-2 * 30 * 10^-2 m^2Hence magnetic flux = 0.3 *20 * 10^-2 * 30 * 10^-2 =180 * 10^-4weberii) plane inclined 30 deg with field implies that area vecotr is at 60 degreeSoφ= 0.3 * 20 * 10^-2 * 30 * 10^-2 * cos 60 =90 * 10^-4 Tiii) plane parallel to the field. Area vector is perpenducular. Soθ= 90 degHenceφ = N B A cos 90 = 0 ( incce cos 90 = 0) |
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| 11522. |
D ISue8. What is an orbital ? How is it different from Bohrs orbit ?12th aroun elements are some |
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Answer» Bohr’s orbit looks like a loop of thread of zero diameter. The electron on Bohr’s orbit are moving around the nucleus like planets around the sun on a deterministic route. Schrödinger’s orbitals are diffuse splotches like frog’s male gametes floating in the water. His orbitals describe the probability of electron being on an P(x,y,z) spacial point within unit time. Interesting that in case of the spherically symmetric s-orbitals this probability within the volume of the nucleus is not zero. The chemical bond distort the p-, d-, and f- orbitals which change the probabilistic density of s- electrons within the nucleus, and cause a measurable shift of the energy levels of the nucleus. That is the base of the Mössbauer-spectroscopy. please like my answer if you find it useful |
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| 11523. |
The flux linked with a coil of self-inductance 2when there is a current of 5.8 A flowing through it, is(1) 11.6 Wb(2) 2.9 Wb3) 8.7 Wb4) dependent on the orientation of the coil |
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Answer» L = ∅/I => ∅ = LI = 2*5.8 = 11.6wb option A should be correct.. without considering the orientation of the coil , assuming all magnetic lines flow through the area.of coil |
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| 11524. |
A charged cloud system produces an electric fieldin the air near the earth's surface. A particle of charge- 2 x 10-9 C is acted on by a downward electrostaticforce of 3 x 10-6 N when placed in this field. Thegravitational and electrostatic force, respectively,exerted on a proton placed in this field are |
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Answer» Answer-GF = 1.6×10^-26 NEF = 2.5×10^-16 N ● Explaination-# Given-q = 1.67×10^-19 CE = 1.5×10^3 m = 1.6×10^-27 kgg = 10 m/s^2 # Solution-Gravitational force-GF = mgGF = 1.6×10^-27 × 10GF = 1.6×10^-26 N Electrostatic force-EF = qEEF = 1.67×10^-19 × 1.5×10^3EF = 2.5×10^-16 N |
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| 11525. |
Explain: electrostatic potential and capacitance? |
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| 11526. |
Qăź, Under what conditions wills Terminal potential difference of a cell isgreater than its EMF |
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Answer» When we connect a cell to a battery of higheremfthanemfof a cell whose direction is opposite to theemfof a cell then the terminal potential difference of the cell is greater than itsemfbecause it's direction ofcurrentis reversed |
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| 11527. |
On what factor the retarding potential ofphoto cell depends? |
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| 11528. |
Example 2.5 If the size of a nucleus (inthe range of 10-15 to 10-l4 m) is scaled upto the tip of a sharp pin, what roughly isthe size of an atom ? Assume tip of the pinto be in the range 105m to 10tm |
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Answer» If we increase the size of nucleus from 10^-15 to 10^-5 then it means that we are increasing the size by 10^10. so we shall hv to increase the size of atom by 10^10 so size of atom is 10^-10 now we increasing by 10^10 so 10^-10×10^10=10^(-10+10)=10^0=1 i.e. it will be 1 meter. how can calculate the 10^-10 in answer |
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| 11529. |
The magnetic field perpendicular to the plane of a loop of area 0.1m*2is 0.2T. Calculate the magnetic flux through the loop. |
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Answer» Magnetic Flux,⍉=B.A=BAcos x where, x is the angle between B and A=0° ∴⍉=0.2×0.1=0.02 Weber |
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| 11530. |
The magnetic flux linked with a coil changes from 0.3 Wb to zero in 1.2 second. calculate the induced emf |
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| 11531. |
Electrostatic force |
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Answer» These forces are conservative forces .i.e.the work done by these forces does not depend upon the path followed. |
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| 11532. |
Electrostatic Shielding |
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Answer» Electrostatics is a branch of physics that studies electric charges at rest. Since classical physics, it has been known that some materials such as amber attract lightweight particles after rubbing. The Greek word for amber, ήλεκτρον, or electron, was the source of the word 'electricity Electrostatic shieldingis the phenomenon that is observed when a Faraday cage operates to block the effects of anelectricfield. Such a cage can block the effects of an external field on its internal contents, or the effects of an internal field on the outside environment. The process which involves the making of a region free from any electric field is known as electrostatic sheilding. |
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| 11533. |
Illustration 3.29 When a surface is irradiated with light ofwavelength 4950 A, a photocurrent appears which vanishesif a retarding potential greater than 0.6 V is applied acrossthe photo tube. When a different source of light is used, it isfound that the critical retarding potential is changed to 1.1V. Find the work function of the emitting surface and thewavelength of the second source. |
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| 11534. |
23, A bead of mass m is attached to one end of a spring3oi atural length R and spring(N3+1KThe other end of theparing is fixed at a point Aon asmooth vertical ring of radius Ras shown in the figure. The Anormal reaction at B just after itis relcased to move is:30°(a) mg2(c) 3/3 mg(b)mg33 mg/2 |
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| 11535. |
The speed of a falling body increases continuously. Why?(A) No force acts on the falling body(B) The falling body is very light.(C) Air exerts a frictional force on the falling body.(D) The force acting on the body is in the direction of the4. |
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Answer» The speed increases continuously as the force acting on the body is in the direction of fall. This is the force of gravity, which accelerates any falling object with an acceleration of g=9.8m/s^2.so the answer is (D) |
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| 11536. |
magnetic flux link with a coil is given by an equation weber =8t²+3t²+5 induse emf in the coil at 4 second will be..... |
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Answer» Find d(phi) /dt at t=4sec |
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| 11537. |
An electrostatic fild line can't have suddenbrake why? |
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Answer» An electrostatic field line is a continuous curve because a charge experiences a continuous force when traced in an electrostatic field. The field line cannot have sudden breaks because the charge moves continuously and does not jump from one point to the other |
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| 11538. |
9.A solid conducting sphere having a chargeconducting spherical shell. The potential difference between the surface of solid sphereis surrounded by an unchanged concentricand the shell is V. The shell is not given a charge 39. The next potential differentbetiseen the same surfaces will be10. A chargeis distributed over to concentric hollshres of modif and |
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| 11539. |
Write three safety measures in using electricity. |
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Answer» Ans :- DON'T plug a bunch of stuff into one outlet or extension cord. ... DO ask grown-ups to putsafetycaps on all unusedelectricaloutlets. ... DON'T yank anelectricalcord from the wall. |
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| 11540. |
A particle of mass 0.75 kg is moving in the XY planeparallel to Y-axis with a uniform speed of 4m/s. Itcrosses the X-axis at 3m from the origin. What isthe angular momentum of the particle about theorigin? |
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Answer» Angular momentum(L) = m*v*rm= mass of the bodyv= velocityr= distance from the axis of rotation So, L =0.75 * 4 * 3 = 9kgm^2/s |
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| 11541. |
3. A force F=-Klyi+xj) (where k is a positive constant) acts on a particle moving in the x-y plane. Startingorigin, the particle is taken along the positive x-axis to the point (a,0) and then parallel to the y-axis to th(a.a). The total work done by the forces Fon the particle is |
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| 11542. |
S.V.SIRSECTION-B (MARK-2)Derive the equation of dhody moving with uniform acceleration.istance travelled in equation second ly a |
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| 11543. |
A spy report about a suspected car reads as follows"The car moved 2.00 Km towards east, made aperpendicular leftrun, ran for 500 m, made a perpendicular right turn for 4.00 km and stopped"Find the displacement of the car |
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Answer» super fast |
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| 11544. |
The distance travelled by a particleS=10t> (m). Instantaneous speed at t=2sis:(a) 10 m/s (b) 20 m/s(c) 40 m/s (d) 80 m/s |
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Answer» differentiate 's' with respect to 'dt'.ds/dt=20t.now put t=2 in 20t.the answer is 40 m/s. c) 40 m\s is the right answer of the following please accept me best 40m/s is the correct answer for this question option (c) is the right answer. 40m/s is correct answer answer c is the correct answer |
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| 11545. |
moved to Kunchanged9. Two blocks of masses 10 kg and 30 kg are placed alonga vertical line. The first block is raised through a heightof 7 em. By what distance should the second mass bemoved to raise the centre of mass by 1 em?ufur hall in which a tray of mass M |
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| 11546. |
.Ashortbar-magnetofmagneticmomentm0.32JT-1is free to rotate in the plane of a uniform externalmagnetic field B of 0.15 T What orientations ofthe magnet would correspond to its (i) stable and(ii) unstable equilibrium? What is the potential energyof the magnet in the magnetiç field in each case?Ans. (i) m parallel to B, Um B0.048 J(ii) m anti-parallel to B; U +m B +0.048 J.2 |
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| 11547. |
1. In what way is the behaviour of a diamagnetic material different from that of a paramagneticwhen kept in an external magnetic field? |
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Answer» The magnetic field lines pass through the paramagnetic material while the magnetic field lines move away from the diamagnetic material. Like my answer if you find it useful! |
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| 11548. |
6.The displacement 9 (in meter) of a particle moving aong X axis is given by : X-18t +5tcalculate-(a) the instantaneous velocity at t 4sec.(bjaverage velocity between t4sec and 5sec. |
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Answer» Using diffrentiation methodx = 18t + 5t^2dx / dt = 18 + 10tv = 18 + 10tt = 2 secv = 18 + 10 * 2= 18 + 20= 38 m / sect = 3 secv = 18 + 10 * 3= 18 + 20= 48 m / sv(av) =( 38 + 48)/ 2= 43 m/swcdv / dt = 10a = 10 m/ s |
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| 11549. |
An object of mass m accelerates uniformlyfrom rest to a speed vf in time tr. Then theinstantaneous power delivered to the object,as a function of time t is -13 |
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| 11550. |
The motion of a car along y-axis is given by12t + 12, where velocity v is in m/s and timet in seconds. Find the instantaneous position ofthe car as a function of time if at t 0, it wasat 5m. Also find its acceleration at t-2 second. |
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Answer» Position of the car is given by Integration of vdt = s = -12t²/2 + 12t + c and when t = 0 , s = 5 so c = 5 so, S = -6t²+12t+5 also, a = dv/dt = -12 m/s² |
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