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The Vernier caliper is an extremely precise measuring instrument; the reading error is 1/20 mm = 0.05 mm.

Close the jawslightlyon the object to be measured.

If you are measuring something with a round cross section, make sure that the axis of the object is perpendicular to the caliper. This is necessary to ensure that you are measuring the full diameter and not merely a chord.

Ignore the top scale, which is calibrated in inches.

Use the bottom scale, which is in metric units.

Notice that there is a fixed scale and a sliding scale.

The boldface numbers on the fixed scale are centimeters.

The tick marks on the fixed scale between the boldface numbers are millimeters.

There are ten tick marks on the sliding scale. The left-most tick mark on the sliding scale will let you read from the fixed scale the number of whole millimeters that the jaws are opened.

In the example above, the leftmost tick mark on the sliding scale is between 21 mm and 22 mm, so the number of whole millimeters is 21.

Next we find the tenths of millimeters. Notice that the ten tick marks on the sliding scale are the same width as nine ticks marks on the fixed scale. This means that at most one of the tick marks on the sliding scale will align with a tick mark on the fixed scale; the others will miss.

The number of the aligned tick mark on the sliding scale tells you the number of tenths of millimeters. In the example above, the 3rd tick mark on the sliding scale is in coincidence with the one above it, so the caliper reading is (21.30 ± 0.05) mm.

If two adjacent tick marks on the sliding scale look equally aligned with their counterparts on the fixed scale, then the reading is half way between the two marks. In the example above, if the 3rd and 4th tick marks on the sliding scale looked to be equally aligned, then the reading would be (21.35 ± 0.05) mm.

On those rare occasions when the reading just happens to be a "nice" number like 2 cm, don't forget to include the zero decimal places showing the precision of the measurement and the reading error. So not 2 cm, but rather (2.000 ± 0.005) cm or (20.00 ± 0.05) mm

Theleast counterror is the error associated with the resolution of the instrument. If we use a metrescaleformeasurementof length, it may have graduations at 1 mm divisionscalespacing or interval. AVernier scaleoncalipermay have aleast countof 0.02 mm while amicrometermay have aleast countof 0.01 mm.

Acceleration metre per second squaredm s-2Area square metre m2Density kilogram per cubic metre kg m-3Heatcapacity joule per kelvin J K-1

Impulseis the change of momentum of an object when the object is acted upon by aforcefor an interval of time. So, withimpulse, you can calculate the change in momentum, or you can useimpulseto calculate the average impactforceof a collision.

open B is correct answer

block moves down the plane with constant velocity it means net force is zero...

force due to friction (f) = mgsin ( is the angle of plane)

net retardation force when body is projected upward is (f+mgsin)

f = mgsin so

net retardation force = 2mgsin

ma = mgsin

a(retardation) = 2gsin .............1

V2= U2- 2aS

finally velocity becomes 0 so

U2= 2aS

S = U2/2a

=u2/4gsin

The smallest value that can be measuredby themeasuring instrumentis called itsleast count.Measuredvalues are good only up to this value. Theleast counterror is the error associated with the resolution of theinstrument.

Displacement will be zero as he reached the same point from where he startedDistance will be 2πr=2*22/7*50=314m

Component of acceleration = g sin37 = 3g/5 = 6 m/s2Force = ma= 0.25 x 6= 1.5 N

work done= 1.5 x 1= 1.5 J

For the mass M to be kept at rest the net force should be 0

so, mg = Mgsin∅ = 10*10*sin(30)=> m = 10*10*(1/2)/g = 10/2 = 5gm.

option 1

32√2/π = 14.4 m

Work done = change in Kinetic Energy

initital Kinetic Energy = 0

final Kinetic Energy =1/2×m×v^2

Here m=0.25 kg ; v=8 m/s

so Kinetic Energy =1/2×0.25×8^2

=8 J

so work done = 8-0=8 joule

Option (c) is correct.

The communication and broadcasting is based on generation, propagation and detection of electromagnetic waves.

We have equation x= 40+12t-t^3. So initially take t=0 => x=40m.

Now differtiate the equation with respect to time(t) which is equal to velocity (v) {v=dx/dt} now put v=0 as the particle is stopping you will get value of t. Put this value in "40+12t-t^3" and you will get final distance.on Subtracting the initial distance from this final distance we'll get x=16m.

a)A wormhole is a theoretical passage through space-time that could create shortcuts for long journeys across the universe. Wormholes are predicted by the theory of general relativity. But be wary: wormholes bring with them the dangers of sudden collapse, high radiation and dangerous contact with exotic matter.

b)Ablack holeis a region of spacetime exhibiting such strong gravitational effects that nothing—not even particles and electromagnetic radiation such as light—can escape from inside it.

c)A nebula is an interstellar cloud of dust, hydrogen, helium and other ionized gases. Originally, nebula was a name for any diffuse astronomical object, including galaxies beyond the Milky Way.

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by work - energy theorem,initial KE - final KE = work performed against air resistanceInitial KE = 1/2 * m * vi^2(i- initial)Final KE = 1/2 * m * vf^2(f- final)Hence change = 1/2 * 20/1000 * (100^2 - 50^2) = 1/100 * 150 * 50 =75 JSo work done by bulllet against air resistance = 75 JOr work performed by air to reduce the energy of bullet =75 J

time = 30 minutes= (30/60) secondsdistance=speed * time taken= 4 * (30/60)=2 km

2 km will be the answer

ans plss

When you pull a spring and leave it,it moves to and fro right? the waves along this also move to and fro in the same direction.that is why they are longitudinal waves.(Longitudinal waves are the waves which vibrate along the direction of movement.The waves in a spring move along the direction in which you pulled it so they are longitudinal.)

f=uN=0.4×100×9.8=392N

i. Heredity is the passing on of traits from parents to their offspring, either through asexual reproduction or sexual reproduction, the offspring cells or organisms acquire the genetic information of their parents.

ii. Variation is any difference between cells, individual organisms, or groups of organisms of any species caused either by genetic differences (genotypic variation) or by the effect of environmental factors on the expression of the genetic potentials (phenotypic variation).

iii. Genetics definition is - a branch of biology that deals with the heredity and variation of organisms.

Since , f = mu . R= mu. mgf/ mg = munow if mass is doubled then coefficient of friction is halfed .

The friction force produces an additional energy term in the energy equation. The energy equation is (1/2)MV2 = (1/2)ks2+Mgμks, where Mg is the normal force, and s is the sliding distance, which is equal to the spring compression. This is a quadratic equation with two roots. We reject the negative root. The positive root is the solution.

Answer: s = -(Mgμk)/k+(1/k)[(Mgμk)2+MkV2]1/2

option a

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Ans :- Asynchronous phase modifieris a synchronousmotor designed to run on no load at the highestsynchronousspeed (3000 rpm at 50 Hz or 3600 rpm at 60 Hz) to keep its size small. They are connected at the receiving end of a medium length transmission line to maintain its receiving end voltage constant at all loads.

average value of current over full cycle is always zero

The average value of a whole sinusoidal waveform over one complete cycle is zero as the two halves cancel each other out, so the average value is taken over half a cycle. The average value of a sine wave of voltage or current is 0.637 times the peak value, (Vp or Ip.

Graph is not mentioned in this question.

Momentum of an object= MVkinetic energy = 1/2 mv^2according to the questionmv=1/2 mv^2v=1/2v^2v/v^2= 1/21/v=1/2v= 2 units

Tension always acts perpendicular to the motion of body in circular motion. therefore work done is zero.

Total distance covered by the boy is s+s+s = 3s

now total time taken by the boy is s/v + s/2v and s/3v.

now avg. speed is given by = (total distance)/total time

= 3s/(s/v +s/2v+s/3v = 3s/(s/v)*(1+1/2+1/3)... s will cancel each other.

so , avg v = 3V/(11/6) = (18v/11) answer.

option c.

this is the correct answerthanks you