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Total distance 40m in 40 sec.

Total time taken by the farmer

= 2 min 20 sec =140 seconds.

Total rounds completed= 140/40=3.5 rounds

That means if the farmer starts from point A of the square field, he reaches point C.

Therefore, displacement is AC.

Assume ABC is a right angled triangle.

Therefore,AC^2= AB^2+BC^2AC^2

= (10)^2+(10)^2

AC^2= 100+100

AC^2=200

AC = (200)^1/2

AC= 10× (2)^½

Side of square = 40 m

Perimeter of Square = 4*side= 4*40 = 160 m

In 40 sec farmer complete one round of boundary it means farmer cover distance = 160 min 40 sec but displacement is 0as starting and end point is same.

Now,2 min 20 sec = 2*60 + 20= 120 + 20 = 140

Therefore,In 140 sec farmer cover distance = 160*140/40= 4*140= 560 m or 3.5 rounds of square boundary

In 3 rounds displacement is 0For half round displacement is equal to diagonal of square = root(2)*side= 40*root(2)= 40*1.414= 56.56 m

By the definition of torque,г = r x FGiven points are(3m,0,0) and(0,2,0)r = (0 - 3m) i + (2-0) j + (0-0) kr = -3m i + 2 jNow,г = (-3m i + 2 j) x (20 i)г = (0-0) i - (0-0) j + (0-40) kг = - 40 kΙ гΙ = 40 N

the correct answer is C

c.is the right answer

c is the correct answer

c is a right answer

plz like my answer

the correct ans is option c..

option (c) 5n along+x axis is the right answer

Option d is correct because both forces are opposite to each other so net force is along - x axis and of magnitude 5 N

correct answer is b of this question

angular moment about original is m*(V×Rp) = m*(v*b)k= -mvb k

option 2

power =Fvhence velocity is directly proportional to power.

1N is correct answer

1 N is the correct answer

I think 1newton is correct

1 Newton is correct answer

Let p be the perimeter of the circular path traversed by the particle

In 2 minutes the displacement will be zero and in next 20 second the displacement will be p/2 (as it will be on diametrically opposite end).

It will make 3.5 revolution in 2 minutes 20 seconds.The distance travelled= 3.5p

Therefore the ratio= (p/2)/(3.5p)=1/7

Option 2 is correct.

V=a i^+(b-ct)j^

Vx=Ux+axta=Ux+0Ux=a x=Uxt+0x=at----------------(1)

Vy=Uy+aytb-ct=Uy-gtUy=b and g=cnow,y=Uyt+1/2ayt^2 0 =bt-1/2ct^22b-ct=0t=2b/c-----------(2)put (2)in equation (1)x=a2b/c=2ab/chence option (b) is correct

work done = F x s=2 *2answer 4J

f=2why??

because F acts on all 3 axis while s is acting only along X axis that is why we consider the force only along the axis in which we are given the distance

A and C because energy is least there

Option (2) is correct.The body is in equilibrium at point B because the force acting on the body, given by slope of curve, at that point is zero. However, this is a condition of unstable equilibrium as any disturbance will reduce the potential energy of the system.

The child who throws the mass towards the other, and the one who catches it, both move backwards. (Reason) -Thrower moves due to backward reaction of mass pushed forward. Catcher moves due to forward reaction of mass pushed and held backward.

Eddy current losses in transformers depends on the core, so to avoid or minimize this losses cores are laminated.

= 10000000 gcm²s²

= 10^7 gcm²s²

how g becomes 9.8 meter per second square

Let the total distance be X

so time for x/3 distance = X/3*20 = x/60and time for 2x/3 distance = 2x/3*60 = x/90

now, total time = x/60+x/90 = 3x/180 +2x/180 = 5x/180

so, avg. velocity = D/T = x/(5x/180) = 180/5 = 36km/h

Averagespeed=totaldistance/totaltimetaken=1000+500/45*60m/s=1500/2700m/sec=0.55m/secAveragevelocity=totaldisplacement/totaltime=500/2700m/sec=0.185m/sec

this will be the resultant

directions for the resultant

please bro help me

Density=mass/volVol=mass/density=125/0.92=135.87cm^3

For the plank, weight = 40 * 9.8 = 392 NFor the boy, weight = 45 * 9.8 = 441 NTotal weight = 392 + 441 = 883 N

Let F1 be the force on the left support and F2 be the force at the right support. Let’s assume the boy is 1.5 meters from the left end of the beam. The sum of these two forces is equal to the total weight.

F1 + F2 = 883 N

This is a torque problem. Let the pivot point be at the left the support. The weight of the plank and boy will produce clockwise torques. The upward force at the right support will produce counter clockwise torque. The weight of the plank is at its center.

2.5 – 0.5 = 2 mThis is distance from the left support to the center of the plank.

Clockwise torque = 392 * 2 = 784 N * m1.5 – 0.5 = 1 mThis is distance from the left support to the boy.

Clockwise torque = 441 N * m

Total clockwise torque = 784 + 441 = 1225 N * m

4.5 – 0.5 = 4 mThis is distance from the left support to the right support.

Counter clockwise torque = F2 * 4

F2 * 4 = 1225F2 = 1225 ÷ 4 = 306.25 N

F1 = 883 – 306.25 = 576.75 N

plane mirror forms always virtual image and the image is always of same size as of the object. concave mirror can form both real and virtual images and the image can be enlarged, diminished or of same size. convex mirror always forms virtual and diminished image

Raju's father was born in the year 1961.

1HP = 745.7 W12HP = 745.7×12 = 8948.4 W = 8.9484 kWIf it used 8 hours a day, energy consumed by it per day = 8.9484 kW×8h = 71.59 kWh

Total energy consumed in 10 days = 10×71.59 kWh =715.9 kWhcost = Rs. 0.50 per kWhtotal cost = 715.9× 0.50 = Rs. 357.94 ~ Rs. 358

given real depth = 15 cm

μ=1.5μ=1.5

Let the opponent depth be x

μ=15x

=>x=15/1.5x=10cm

Distance through which the pin appears to be raised is15−1=5cmThe answer does not depend on the location of the table .

Acceleration of the body is F/m = 100/5 = 20 m/s²

now, V=u +at => V = 20 + 20*(10) = 20+200 = 200m/s

Electric power is the rate of doing work in unit time

I)P1= 1000 W /1000 = 1 kW

t1= 5 h

ii) P2= 400 W / 1000 = 0.4 kW

t2= 10 h

No. of days, n = 30

E1= P1x t1x n

= 1 kW x 5 h x 30 = 150 kWh

E2= P2x t2x n

= 0.4kW × 10 h × 30 = 120 kWh

Total energy = (150 + 120) kWh = 270 kWh

Total cost = 270 x 6 = Rs. 1620

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