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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Identify (A) to (G) in the following scheme and name the process. `CaCO_(3) overset(Delta) to (A) + (B) gas , (A) + H_(2)O rarr (C )` `(C )+B rarr CaCO_(3) + H_(2)O (D) +(C ) overset(Delta) to (E ) gas` `(E ) + H_(2)O + (B) rarr (F) , NaCI + (F) rarr (G) + (D)` `(G) overset(Delta) to Na_(3)CO_(3) + H_(2)O + (B)` |
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Answer» Sheme repersent the solvay process of manufacture of `Na_(2)CO_(3)` `CaCO_(3)overset(Delta)rarr underset((A))(CaO)+underset((B)(CO_(2)(g))` `underset((A))(CaO +) H_(2)O rarr underset((C))(Ca(OH)_(2))` `Ca(OH)_(2) +CO_(2) rarr CaCO_(3) +H_(2)O` `underset((D))(NH_(4)CI) + underset((C))(Ca(OH)_(2)) overset(Delta)rarr underset((E))(NH_(3)darr)` `underset((E))(NH_(3)) + H_(2)O + underset((B))(CO_(2)) rarr underset((F))(NH_(4)HCO_(3))` `NaCI + underset((F))(NH_(4)HCO_(3)) rarr underset((G))(NaHCO_(3)) + underset((D))(NH_(4)CI)` `2NaHCO_(3) overset(Delta)rarr Na_(2)CO_(3) + H_(2)O +underset((B))(CO_(2))` |
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| 2. |
Select the correct statement(s):A. Normal and polysulphides of ailkali metals are soluble in waterB. The sulphides of aluminum and magnesium can only be prepared under dry condition as they are completely hydroysed by waterC. When filter paper is moistened with a solution of sodium miropressium made alkline with sodium hydroxide or ammonia solution , a purple colouration is produced with free hydrogen sulphideD. Thiosulphate salt of `Pb,Ag and Ba ` are insoluble and dissolve in excess of sodium thisulphide solution forming thiosulphde. |
| Answer» Correct Answer - a,b,c | |
| 3. |
Colourless salt (A) gives apple- green flame with cone. `HCI` (A) on reaction with dil `H_(2)SO_(4)` give light brown flame (D) turning KI -strach paper blue. (A) `+ CH_(3)COOH + K_(2)CrO_(4) rarr` yellow ppt (B) (A) `+ H_(2)SO_(4) rarr (C ) ("white ppt") + (D)` (D) `+ CH_(3)NH_(2) + CH_(3)OH + H_(2)O + gas (E )` (E ) `+ Mg overset(Delta)to (F)` (F) `+ H_(2)O rarr NH_(3)` Identify (A) to (F) and explain reaction. |
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Answer» (A) `BA(NO_(2))_(2)` (B) `BaCrO_(4)` (C ) `BaSO_(4)` (D) `HNO_(2)` (E ) `N_(2)` (F) `Mg_(2)N_(2)` |
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| 4. |
Which gives violet colour with borax ?A. `NH_(4)^(o+)`B. `K^(o+)`C. `Mg^(2+)`D. `Al^(3+)` |
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Answer» Correct Answer - b `K^(o+)` imparts violet flame colour |
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| 5. |
Colourless salt `(X) overset(Delta) to (Y) overset(Cu^(2+),Delta) to` coloured head (Z) ,(X) can beA. BoraxB. Microcostric saltC. Copper sulphateD. None of these |
| Answer» Correct Answer - a,b | |
| 6. |
A green mass is formed in the charcoul cavity test when a colourless salt `(X)` is fussed with chbalt mitrate (X) may containA. AluminiumB. copperC. BariumD. Zine |
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Answer» Correct Answer - d Follow cobalt nitrate test `ZnSO_(4) + Na_(2)CO_(3) rarr ZnCO_(3) + NASO_(4)` `ZnCO_(3) rarr ZnO + CO_(2)` `2Co(NO_(3))_(2) rarr 2CoO + 4NO_(2) + O_(2)` `CoO + ZnO rarr underset((Green))(CoZnO_(2))` |
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| 7. |
A solution of colourless salt H on holing with excess `NaOH` produces a non-flammable gas .The gas evolution ceses after sometime. Upon addition of `Zn` dust to the same solution the gas evolution restarts .The colourless salt(s) H is (are)A. `NH_(4)NO_(3)`B. `NH_(4)NO_(2)`C. `NH_(4)CI`D. `(NH_(4))_(2)SO_(4)` |
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Answer» Correct Answer - a,b `NH_(4)ON_(3) + NaOH rarr NH_(3) + NaNO_(3) + H_(2)O` `7NaOH + NaNO + 4Zn rarr 4Na_(2)ZnO_(2) + NHO_(3) + 2H_(2)O` `NH_(4)ON_(2) + NaOH rarr NaNO_(2) + NH_(3) + H_(2)O` `3Zn + 5NaOH + NaNO_(2) + rarr 3Na_(2)ZnO_(2) + NH_(3)O` |
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| 8. |
Microcosmic salt bent test in which `Na(NH_(4))H. PO_(4). 4H_(2)O` is first doydrated which forms sodium metaposphate `(NaPO_(2))` as colourless head which reacts with metals oxide giving coloured head .This test is solable is soluble for Cu,Cr and Co .The blue heated with `CuO` and ` CoO` are due the formation of ____and ___white green head with `Cr_(2)O_(3)` is due to the formation of ____. |
| Answer» Correct Answer - `NaCuPO_(4),NaCuPO_(4),NAPO_(3),Cr_(2)O_(3)` | |
| 9. |
Th esodium carbobate bead test test is which `Na_(2)CO_(3)` is along instead of barax it is solution to chromiam and ____. |
| Answer» Correct Answer - Mn | |
| 10. |
Why do we not perform borax bead test with the white salt? |
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Answer» This test is applied for the indentification of the cations of the coloured salt only because the borax forms the corresponding metaborates which possess characteristic colouri. For example with `CuSO_(4)`, the reaction `CuSO_(4)+underset(("from borax"))(B_(2)O_(3))tounderset(("blue"))(Cu(BO_(2))_(2)+SO_(3)` |
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| 11. |
Which of the following respond to borax test ?A. Nickel saltsB. Copper saltsC. Cobalt saltD. Aliuminium salt |
| Answer» Correct Answer - a,b,c | |
| 12. |
Borax bead test is not given byA. Copper saltsB. Nickel saltsC. Aluminium saltsD. Magnestion salts |
| Answer» Correct Answer - c,d | |
| 13. |
Which of the following cartion (s) will turn blue in oxidising flame ?A. `Co^(2+)`B. `Cr^(3+)`C. `Ni^(2+)`D. `Cu^(2+)` |
| Answer» Correct Answer - a,d | |
| 14. |
What is the composition of the bead obtained when borax is neated in the flame? |
| Answer» it consits of a mixture of sodium metaborate and boric anhydride. | |
| 15. |
The metal that does not give the borax head test isA. CrB. NiC. PbD. Mn |
| Answer» Correct Answer - c | |
| 16. |
The compound formed in the borax berax test of `Cu^(2+)` in oxidising flame isA. CuB. `CuBO_(2)`C. `Cu(BO_(2))_(2)`D. none of these |
| Answer» Correct Answer - c | |
| 17. |
Write the chemical reaction associated with the 'borax beat test' of cobalt (II) oxide |
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Answer» When borax in heated , a colourless glassy head is formed of the following composition `Na_(2)B_(4)O_(7) 10H_(2)O rarr Na_(2)B_(4)O_(7) + 10H_(2)O` `Na_(2) B_(4)O_(7) overset(Delta ) to+ 2NaBO_(2) + B_(2)O_(3)` `Co(II) "salt" overset(Delta) to CoO +` some gas `CoO + B_(2)O_(3) overset(Delta) to Co(BO_(2))_(2)` A blue - coloured head of coball metaborate is formed |
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| 18. |
A white substance A reacts with dilute `H_(2)SO_(4)` is produce a colourless B and acidified `K_(2)Cr_(2)O_(7)` solution produces a green solution and a slighly coloured precipitate D .The substance B to burns in air to produce a gas E which reacts with B ito yied D and a colouless liquid .Anhyhdrous copper sulphate is turned blue on addition of this colourless liquid addition od aqueous `NH_(3) or NaOH` to C produce first a precipitate which dissolve in the excess of the respective reagent to produce a clear solution in each case identify A,B,C, and E. Write the equation of the reaction involved. |
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Answer» `A = ZnS,B = H_(2)S ,C = ZnSO_(4),D =- S , E = SO_(2)` A white substance A reacts with dilute `H_(2)SO_(4)` to produce a colourless gas .B and a colourless solution C .The reaction between B and acidified `K_(2)Cr_(2)O_(7)` solution produces a green solution and a slightly coloured precipitate D.This precipitate must be sul,phate , so gas B must be hydrogen sulphide ,Sulpbuur in air to produce a gas sulphur dioxide which reacts with hydrogen sulphide to yield sulphur again and a colourless liquid water .Anhydrous copper sulphate is turned blue on addition of water a precipitate which dissolve a clear solution in excess solution of the respective regaoin to produce a clear solution in each case .This suggesist that C must be sulphate of either zine or aluminium so, A may be zine sulphide . `ZnS +H_(2)SO_(4) rarr H_(2)S + ZnSO_(4)` `Cr_(2)O_(7)^(2-) + 4H^(o+) ("From" H_(2)SO_(4)) + 3H_(2)S rarr underset("Green solution")(2Cr^(3+)) +7H_(2)O +3S darr` `S + SO_(2) rarr SO_(2)` `SO_(2) +2H_(2)S rarr 2H_(2)O +3S` `ZnSO_(4) +2NaOH rarr underset("White")(Zn(OH)_(2)darr) +Na_(2)SO_(4)` `Zn(OH)_(2) +2NaOH rarr Na_(2)ZnO_(2) +2H_(2)O` |
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| 19. |
If(X) turns acidified `K_(2)Cr_(2)O_(7)` solution green , then then X may beA. `SO_(2)`B. `CO_(2)`C. `NO_(2)^(Θ)`D. `Fe^(2+)` |
| Answer» Correct Answer - a,c,d | |
| 20. |
What happens when i. Hydrogen is bubbled through an aqueous solution of sulphur dioxide . ii . Aqueous ammonia in added dropwise to a solution of copper sulphate till it is in excess iii Tin in treated with concentrated nitric acid iv `CrCI_(3)` solution is treated with sodium hydroxide and then with hydrogen peroxide v. `Pb_(3)O_(4)` is treated with nitric acid |
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Answer» Sulphate is precipitate `SO_(2) + 2H_(2)S rarr 3S + 2H_(2)O` ii. Ammonia gives deep blue colour with copper sulphide due to the formation of a complex `CaSO_(4) + 2NH_(4)OH rarr Cu(OH)_(2) + (NH_(4))_(2)SO_(4)` `Cu(OH)_(2) + 2NH_(4)OH +(NH_(4))_(2)SO_(4) rarr underset(blue)([Ca(NH_(3))_(4)])SO_(4) + 4H_(2)O` iii. Metastamic acid id formed `Sn + 3HNO_(3) (conc.) rarr H_(2)SnO_(3) + 4NO_(2) + H_(2)O` iv . A yellow solution of sodium chromate is produced `H_(2)O_(2) rarr H_(2)O + O` `2CrCI_(3) + 10NaOH + 3[O] rarr 2NaCrO_(4) + 6 NaCI + 3H_(2)O` Lead dioxide is precipitate `Pb_(3)O_(4) +_ 4HNO_(3) rarr 2Pb(NO_(3))_(2) 2H_(2)O + PbO_(2)` |
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| 21. |
Why is it necessary to test for the acid redicals first (with dilute) `H_(2)SO_(4)` and then with conc. `H_(2)SO_(4)`? |
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Answer» There are some ions like, `SO_(3)^(2-),S^(2-),NO_(2)^(ɵ)`, and `CH_(3)COO^(ɵ)` which can react with dilute/conc. `H_(2)SO_(4)` whereas ions like `Cl^(ɵ),Br^(ɵ),I^(ɵ),NO_(3)^(ɵ)`, etc. react only with conc. `H_(2)SO_(4)`. Now if conc. `H_(2)SO_(4)` is used first then the anions of both the types will react. Hence it is desired to test acid radicals first with dilute `H_(2)SO_(4)` and then with conc. `H_(2)SO_(4)`. |
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| 22. |
Name the gas other than `CO_(2)` which also turns lime water milky. |
| Answer» `SO_(2)` gas also turns lime water milky as insluble `CaSO_(3)` is produced. | |
| 23. |
Why does lime water turns milky on bubbling `CO_(2)` gas through it? |
| Answer» Initially `CaCO_(3)` (causing milkiness) is formed which which dissappears due to the formation of `Ca(HCO_(3))_(2)` which `CO_(2)(g)` is passed for long time. | |
| 24. |
Upon treatment with ammonical `H_(2)S` the metal ion that precipitate as sulphide isA. `Fe(III)`B. `AI(III)`C. `MG(II)`D. `Zn(II)` |
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Answer» Correct Answer - d Among `Fe^(+3),AI^(+3),Mg^(+2),Zn^(+2) only Zn^(+2)` is precipitate with ammonnical `H_(2)S` as ZnS |
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| 25. |
Gas that turns lime water milky and aciddied `K_(2)Cr_(2)O_(7)` green is (a) ____. |
| Answer» Correct Answer - a.`SO_(2)` | |
| 26. |
`NH_(4)Cl` is added along with `NH_(4)OH` is group (a)_____to (b)____ conecentration of (c ) ____. |
| Answer» Correct Answer - a.III ,b.Decrease, c. `OH^(Theta)` | |
| 27. |
An orange precipitate of group II is dissolve in cone HCI the solution when treated with excess of water turn milky due to formation ofA. Sn(OH)CIB. `Sb(OH)CI_(2)`C. SbOCID. `Sb(OH)_(2)Cl` |
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Answer» Correct Answer - c `Sb_(2)S_(3) + 6HCI rarr 2SbCI_(3) + 3H_(3)S` `SbCI_(3) + H_(2)O rarr SbOCI + 2HCI` |
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| 28. |
From the solution containing copper `(+2)` and zine `(+2)` ions copper can be selectively precipitate using sodium sulphide. |
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Answer» Correct Answer - T From the solution contaning copper `(+2)`and zine `(+2)` ion copper can be selectively precipitate using sodium sulphide. |
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| 29. |
Separation of basic radicals is based on (a) ____ and (b) ____. |
| Answer» Correct Answer - Common ion effect,b. `K_(sp)` velues | |
| 30. |
Strongly acidified solution of barium give a white precipitate with ……which did not dissolve even after large addition of waterA. Sodium phosphateB. Sodium carbonateC. Sodium salphateD. Sodium chloride |
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Answer» Correct Answer - c `BaSO_(4)` is insoluble in acidic medium |
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| 31. |
The addition of ammonium chlorode to a solution containing ferric and magnessium ions is easential for solective precipitate of ferric hydroxide by aqueous ammonium |
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Answer» Correct Answer - T The addition of ammonium chloride to a solution containing ferric and magnessium ions is essential for selective precipitate of ferric hydroxide by aqueous ammonia. |
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| 32. |
In the precipitate of the iron group in qualitativev anlysis ammonium chloride is added before adding ammonium hydroxide toA. Decreases concentration of `OH^(Θ)` ionsB. Prevent interference by phosphate ionsC. increases concentration of `CI^(Θ)` ionsD. Increases concentration of `NH_(4)^(o+)` ions |
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Answer» Correct Answer - a Only Fe ,Cr and AI are precipitate as their hydroxide |
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| 33. |
Why is it necessary to prepare original solution for the detection of basic radicals? |
| Answer» the detection of basic radicals depends on the behaviour of ions in solution for this purpose the preparation of original solution is necessary as it furnishes free ions in solution. | |
| 34. |
Nitric acid is generally not used for prepation of original solution in anlysis of basic radicals ,because itA. is oxidisig agentB. is reducing agentC. forms insoluble nitratesD. forms solublel nitric |
| Answer» Correct Answer - a | |
| 35. |
Potassium ferrocyanide is used in the detection ofA. `Fe^(2+)` ionsB. `Fe^(3+)` ionsC. `Cu^(2+)` ionsD. `Cd^(2+)` ions |
| Answer» Correct Answer - a,b,c | |
| 36. |
Sulphide ions react with `Na_(2)[Fe(NO)(CN)_(5)]` to form a purple coloured compound `Na_(4)[Fe(CN)_(5)(NOS)]`, in the reaction the oxidation state of ionsA. Changes from + 2 to + 3B. Changes from + 3 to + 2C. Changes from + 2 to + 4D. does not change |
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Answer» Correct Answer - d No change in oxidation number of Fe |
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| 37. |
A solution when diluted with `H_(2)O` And bolled gives a white precipitate .On the addition of excess `NH_(2)CINH_(4)OH` the volume of the precipitate decreases leavingg bebind a white ge3lationtious precipitate identify the precipitate which dissolves in `NH_(4)OH//NH_(4)Cl` :A. `Zn(OH)_(2)`B. `Al(OH)_(3)`C. `Mg(OH)_(2)`D. `Ca(OH)_(2)` |
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Answer» Correct Answer - a `Zn^(2+) + 2H_(2)O rarr underset(white)(Zn(OH)_(2) darr) + 2H^(oplus)` `Zn(OH)_(2) + 2NH_(4)CI + 2NH_(4)OH rarr underset("soluble")([Zn(NH_(3))_(4)]CI_(2)) + 4H_(2)O` `Zn(OH)_(2)` precipitate dissolves in excess of `NH_(4)OH` in the presence of `NH_(4)CI` to form tetrqamine soluble complex |
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| 38. |
`CuSO_(4)` decolourises on addition `KCN` , the produce isA. `[Cu(CN)_(4)]^(2-)`B. `Cu^(2+)` get redoced is form `[Cu(CN)_(4)]^(3-)`C. `Cu(CN)_(2)`D. `CuCN` |
| Answer» Correct Answer - d | |
| 39. |
Solution of a salt in sulphanilic acid a naphithy lamine give red ppt ,due toA. `Br^(Theta)`B. `I^(Theta)`C. `NO_(2)^(Theta)`D. `NO_(3)^(Theta)` |
| Answer» Correct Answer - b | |
| 40. |
The gas which turns mercurous nitrate paper black isA. `NH_(3)`B. `CI_(3)`C. `SO_(2)`D. `SO_(3)` |
| Answer» Correct Answer - a | |
| 41. |
Solution of a salt in dil `H_(2)SO_(4)` produces deep blue colour with starch iodide solution .The salt containsA. `Br^(Theta)`B. `I^(Theta)`C. `NO_(2)^(Theta)`D. `NO_(3)^(Theta)` |
| Answer» Correct Answer - c | |
| 42. |
Why are the group IV cations not precipitated as sulphides on passing `H_(2)S` gas through group II solution? |
| Answer» For the precipitation of cations of group IV, a very large concentration of sulphide ions `(S^(2-))` id required which is not available in the group II as the ionisation of `H_(2)S` is suppressed by HCl (common ion effect). In precipitating the cations of group IV high concentration of `S^(2-)` ions is required as `OH^(ɵ)` ions released by `NH_(4)OH` unite with `H^(o+)` ions given by `H_(2)S`. Thus the solubility product is exceeded and the cations of group IV are precipitated as ZnS, NiS, MnS and CoS. | |
| 43. |
An inorganic substance gives balck ppt in group II which is dissolve in aqua regain Evapotate off aqus regain and dilute it with water .To this few drop of ammonium thiocyanate and sodium acelete followed by `Co(NO_(3))_(2)` are added .A deep blue colour or ppt .is obtained .This is due to presence ofA. `Hg^(2+)`B. `Bi^(3+)`C. `Pb^(2+)`D. `Cd^(2+)` |
| Answer» Correct Answer - a | |
| 44. |
Which of the sulphides of group II is orange ?A. CuSB. CdSC. `As_(2)S_(3)`D. `Sb_(2)S_(3)` |
| Answer» Correct Answer - d | |
| 45. |
In IV th group the ppt of `Mn(OH)_(2)` in excess of `NaOH` , turns brown or blue in air due to the formation ofA. `MnO_(2).xH_(2)O`B. `MnO_(2)`C. `MnO_(2).H_(2)O`D. All |
| Answer» Correct Answer - d | |
| 46. |
Which metal gives asft when is salt heated with `Na_(2)CO_(3)` solid and `Co(NO_(3))_(2)` ojn a charcoal piece?A. CuB. MgC. AID. Zn |
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Answer» Correct Answer - c `CoAIO_(2)` is formed which is blue .Follow cobalt nitrate charcoal test |
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| 47. |
A white amorphous powder (A) when heated given by a colourlesss gas (B) , white turms water milky and the residue (C ) which is yellow when but white when cold .The resider (C )dissolve in diulite HCIand the resulting solution given given a white precipitate on potassium ferrcyanide solution (A) dissolve in dilute HCI with the evolation of a gas which is obtained above given a white precipitate (D) on addition of excess of `NH_(4)OH` and on passing `H_(2)S` Another portion of this solution gives initially a white precipitate (E ) on addition of `NaOH` which dissolve in excess of it identify (A) to (E ). |
| Answer» Correct Answer - A:`ZnCO_(3)` B: `CO_(3)` C: `ZnO` D: `ZnS` E : `Zn(OH)_(2)` | |
| 48. |
A colourless (A) when place into water a heavy white turbidly of (B) solid (A) gives a close solution in conesolution in cone `HCI` when `HCI` solution is added to clear solution water ,(B) forms again (B) dissolves in dilute `HCI`. When `H_(2)S` is passed through a sespension of (A) or (B), a black precipitate (C ) forms , (C ) is insolves in yellow ammonium sulphide `(NH_(4))_(2)S` , cone `H_(2)SO_(4)` added to solid (A) liberates gas (D) gas (D) is water soluble and gives white precipitate with mercuric salts (E ) and not mercuric salt .The black precipitate (C ) dissolves in `HNO_(3), (1,1)` to give a solution to which `H_(2)SO_(4)` is added followed by addition of `NH_(4)OH` when a white precipitate (F) is formed (E ) gives a black ppt , (G) with solution of sodium stannite. Compound (C ) is also formed by the following reactionA. `Ba^(2+) + S(2)O_(3)^(2-) rarr E `B. `Bi^(2+) + S(2)O_(3)^(2-) rarr E `C. `Bi^(2+) S(2)O_(3) overset(Delta) to E `D. None of these |
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Answer» Correct Answer - c `underset((A))(BiCI_(3)) +H_(2)O rarr underset("White ppt")(BiOCI darr) +underset((B))(2HCI)` `underset((B))(BiOCI)+2HCI rarr underset((A))(BiCI_(3))+H_(2)O` `2BiCI_(3) + 3H_(2)S rarr underset("Brown-black ppt")(Bi_(2)S_(3)darr) +6HCI` `Bi_(2)S_(3) +8HNO_(3) rarr 2Bi(NO_(3))_(3) +3S darr +2NO +4H_(2)O` `2Bi(NO_(3))_(3) + 3H_(2)SO_(4) rarr Bi_(2) (SO_(4))_(3) +6HNO_(3)` `Bi_(2)(SO_(4))_(3) +6NH_(4)OH rarr underset((F))underset("White ppt") (2Bi(OH)_(3)darr) +3(NH_(4))_(2) SO_(4)` `2Bi(OH)_(3) +3Na_(2)SnO_(2) rarr underset("Black ppt")underset((G))(2Bi) +3Na_(2)SnO_(3) +H_(2)O` `2BiCI_(3) +3H_(2)SO_(4) rarr Bi_(2) (SO_(4))_(3) +underset((D))(6HCI)` `Hg_(2)(NO_(3))_(2) +2HCI rarr underset((E))underset("White ppt")(Hg_(2)CI_(2)darr)+2HNO_(3)` |
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| 49. |
A colourless (A) when place into water a heavy white turbidly of (B) solid (A) gives a close solution in conesolution in cone `HCI` when `HCI` solution is added to clear solution water ,(B) forms again (B) dissolves in dilute `HCI`. When `H_(2)S` is passed through a sespension of (A) or (B), a black precipitate (C ) forms , (C ) is insolves in yellow ammonium sulphide `(NH_(4))_(2)S` , cone `H_(2)SO_(4)` added to solid (A) liberates gas (D) gas (D) is water soluble and gives white precipitate with mercuric salts (E ) and not mercuric salt .The black precipitate (C ) dissolves in `HNO_(3), (1,1)` to give a solution to which `H_(2)SO_(4)` is added followed by addition of `NH_(4)OH` when a white precipitate (F) is formed (E ) gives a black ppt , (G) with solution of sodium stannite. When compound (E ) reacts with `NH_(4)OH` , then product is aA. White pptB. Black pptC. yellow pptD. Green ppt |
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Answer» Correct Answer - b `underset((A))(BiCI_(3)) +H_(2)O rarr underset("White ppt")(BiOCI darr) +underset((B))(2HCI)` `underset((B))(BiOCI)+2HCI rarr underset((A))(BiCI_(3))+H_(2)O` `2BiCI_(3) + 3H_(2)S rarr underset("Brown-black ppt")(Bi_(2)S_(3)darr) +6HCI` `Bi_(2)S_(3) +8HNO_(3) rarr 2Bi(NO_(3))_(3) +3S darr +2NO +4H_(2)O` `2Bi(NO_(3))_(3) + 3H_(2)SO_(4) rarr Bi_(2) (SO_(4))_(3) +6HNO_(3)` `Bi_(2)(SO_(4))_(3) +6NH_(4)OH rarr underset((F))underset("White ppt") (2Bi(OH)_(3)darr) +3(NH_(4))_(2) SO_(4)` `2Bi(OH)_(3) +3Na_(2)SnO_(2) rarr underset("Black ppt")underset((G))(2Bi) +3Na_(2)SnO_(3) +H_(2)O` `2BiCI_(3) +3H_(2)SO_(4) rarr Bi_(2) (SO_(4))_(3) +underset((D))(6HCI)` `Hg_(2)(NO_(3))_(2) +2HCI rarr underset((E))underset("White ppt")(Hg_(2)CI_(2)darr)+2HNO_(3)` |
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| 50. |
which of the following anions are easily removed from aqueous solution by precipitation ?A. `CI^(Θ)`B. `SO_(4)^(2-)`C. `NO_(3)^(Θ)`D. `CO_(3)^(2-)` |
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Answer» Correct Answer - a,b,d Nitrates of all the metals are water soluble and cannot be precipitate |
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