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1.

In a class of 65 students, the ratio of girls and boys is 3: 2; then the number of girls areA) 26B) 39C) 21D) 44

Answer»

Correct option is B) 39

2.

If `(3a+4b):(3a-4b)=(3c+8d):(3c-8d),` then which of the following is true?A. ad=bcB. 2ad=bcC. 2ab=cdD. ab=cd

Answer» Correct Answer - B
3.

if `(a)/(b)=(c)/(d)=(e)/(f)=(1)/(3)`, then `(5a+3c+7e)/(5b+3d+7f)=`_________

Answer» Correct Answer - `(1)/(3)`
4.

If a, b, c and d are in proportion, then show that `(a^(3)+3ab^(2))/(3a^(2)b+b^(3))=(c^(3)+3cd^(2))/(3c^(2)d+d^(3))`

Answer» Given a, b, c and d are in proportion
` rArr a/b = c/d `
Applying componendo and dividendo,
` (a+b)/(a-b)= (c+d)/(c-d)`
Cubing on both sides, we have
`((a+b)^(3))/((a-b)^(3)) = [(c+d)/(c-d)]^(3)`
` rArr (a^(3)+3a^(2)b+3ab^(2)+b^(3))/(a^(3)-3a^(3)b+3ab^(2)-b^(3))=(c^(3)+3c^(2)d+3cd^(2)+l^(3))/(c^(3)-3c^(2)d+3cd^(2)-d^(3))`
`((a^(3)+3ab^(2))+(3a^(2)b+b^(3)))/((a^(3)+3ab^(2))-(3a^(2)b+b^(3)))=((c^(3)+3cd^(2))+(3c^(2)d+d^(3)))/((c^(3)+3cd^(2))-(3c^(2)d+d^(3)))`
` rArr (a^(3)+3ab^(2))/(3a^(2)b+b^(3))=(c^(3)+3cd^(2))/(3c^(2)d+d^(3))`
Hence, proved.
5.

Write the result after applyin componendo and dividendo to `3a^(2)+2b^(2):3a^(2)-2b^(2): :3c^(2)+2d^(2):3c^(2)-2d^(2)`.

Answer» Correct Answer - `(a)/(b)=(c)/(d)`
6.

If 40 men complete a piece of work in 5 days, then 80 man can complete the same piece of work in _____.

Answer» Correct Answer - 2.5 days
7.

If 20 men take 15 days to complete a certain amount of work working at 10 hours per day, then how many more men are required to complete twice the previous work in 10 days working at 12 hours a day?A. 10B. 20C. 30D. 40

Answer» Correct Answer - C
Let the required number of men be x.
We have, `(M_(1)D_(1)H_(1))/W_(1) = (M_(2)D_(2)H_(2))/W_(2)`
`((20)(15)(10))/1 = ((20+x)(10)(12))/2`
` rArr 20 + x = 50 rArr x = 30`.
8.

The result obtained after applying componedo to ` b : (a-b) :: d : (c - d) ` is _________.

Answer» Correct Answer - ` a/(a-b) = c/(c-d)`
9.

If 10 men can do a certain amount of work in 6 days, 15 men can do the same amount of work in ________ days.

Answer» Correct Answer - 4
10.

The ratio of marks obtained by Amal, Bimal and Komal in an examination is ` 12 : 8 : 15`. Find the marks obtained by Bimal and Komal, if Amal scored 15 marks less than that of Komal.

Answer» Let the marks scored by Amal, Bimal and komal by 12x, 8x and 15x , respectively.
Given that Amal scored 15 marks less than that of Komal.
` rArr 12 x = 15x - 15`
` rArr 3x = 15`
` rArr x = 5`.
`:.` Marks scored by Bimal = 8x = 8(5) = 40.
Marks scored by Komal = 15x = 15(5) = 75.
11.

If ` qr : pr : pq = 1:4:7," then find " p/(qr) : q/(pr)`.A. ` 4 : 1`B. ` 1 : 4`C. ` 1 : 16`D. ` 16 : 1`

Answer» Correct Answer - D
Simplify the required ratio.
12.

A purse contains Rs. 50, Rs.10 and Rs. 5 notes in the ratio ` 6 : 3 : 7 ` and total amount in the purse is Rs. 730. Find the number of Rs. 5 notes in the purse.A. 7B. 14C. 21D. 28

Answer» Correct Answer - B
Let the number of notes be 6x , 3x and 7x.
13.

If ` p : q :r :s = 3 : 4 : 7 : 8 and p+s=55`, then find q + r.A. 33B. 55C. 44D. 66

Answer» Correct Answer - B
Let p, q, r and s be 3x, 4x, 7x and 8x.
14.

If `(3k+4l+6m+7n)/(3k+4l-6m-7n) = (3k-4l+6m-7n)/(3k-4l-6m+7n)`,then show that k, 2m, 4l and 7n are in proportion.

Answer» `(3k+4l+6m+7n)/(3k+4l-6m-7n) = (3k-4l+6m-7n)/(3k-4l-6m+7n)`
`rArr((3k+4l)+(6m+7n))/((3k+4l)-(6m+7n)) = ((3k-4l)+(6m-7n))/((3k-4l)-(6m+7n))`
`rArr (3k+4l)/(6m+7n) = (3k-4l)/(6m-7n) rArr(3k+4l)/(3k-4l) = (6m+7n)/(6m-7n)`
` rArr (3k)/(4l) = (6m)/(7n) rArr k/(4l)=(2m)/(7n)`
` rArr k/(2m) = (4l)/(7n)`
`:. ` k, 2m, 4l and 7n are in proprotion.
15.

If `(7x+4y) : (7x-4y) ::(7p+4q):(7p-4q)`, there show that x , y, p and q are in proportion.

Answer» Given , `(7x+4y)/(7x-4y) = (7p+4q)/(7p-4q)`
Using componendo- dividendo rule,
`((7x|4y)|(7x 4y))/((7x+4y)-(7x-4y))=((7p|4q)|(7p 4q))/((7p+4q)-(7p-4q))rArr(14x)/(8y)rArrx/y = p/q`
`:.` x, y, p, and q are in proportion.
16.

If ` (a^(3)+2ab^(2))/(2a^(2)b+b^(3)) = (123)/(136)` , then find the value of ` a : b `.

Answer» Correct Answer - ` 3 : 4`
17.

The number A, A+2, A+12 and A+ 22 are in proportion. Find A.

Answer» Correct Answer - 3
18.

The monthly electricity bill raised by the municipal corporation consists of two parts-a fixed charge for providing the service and a variable charge which is directly proportional to the number of watts of power consumed. An amount of Rs. 500 is charged for consuming 125 watts in a particular month . The of 500 watts is `21 : 25` . How much is the fixed charge per month?A. Rs. 125B. Rs. 200C. Rs.250D. Rs. 500

Answer» Correct Answer - C
(i) Let x be the fixed charge and y be the variable charge.
(ii) Given data can be expressed as x + 100y.
` = 300.(x+300y)/(x +400y) = 5/6`.
(iii) Solve the above two equations and get the value of x.
19.

If 3,8, x and 16 are in proportion the value of x is A) 12B) 4C) 8D) 6

Answer»

Correct option is D) 6

20.

Which of the following is not in proportion?A) 4 : 11 = 2 : 5B) 25 : 1 = 40 : 1.6C) 90 : 30 :: 36 : 12D) 22 : 11 : : 12 : 6

Answer»

Correct option is A) 4 : 11 = 2 : 5

21.

Which of the following is in proportion?A) 1 : 2 = 3 : 4B) 4 : 11 = 7 : 8C) 5 : 9 = 18 : 10D) 32 : 64 = 6 : 12

Answer»

Correct option is D) 32 : 64 = 6 : 12

22.

Ratio of the number of red beads and blackheads in a box is 6 : 5. If the number of red beads is 4 more than the number of black beads find the number of red beads and black beads in the box.

Answer»

Let the number of red beads = 6x

Number of black beads = 5x

6x – 5x = 1x ; = 6x – 5x = 4

This is given as 4. 

∴ x = 4

Number of red beads = 6 × 4 = 24

Number of black beads = 5 × 4 = 20

23.

There are three sections A, B and C in class VIII of a school. The ratio of the number of students in A, B and C is ` 2 : 3 : 4`. The section which has neither the maximum number of students has a strength of 30. Find the total strength of the three sections.A. 63B. 81C. 72D. 90

Answer» Correct Answer - D
Let the number of students in A , B and C be 2x, 3x and 4x.
24.

The ratio of the number of boys to the number of girls in a school is 14 : 15. There are 27 more girls than boys. How many girls are there in this school? How many boys?

Answer»

Ratio of the number of boys to the number of girls = 14 : 15

Let girls be 15x & boys be 14x

Their difference = 15x – 14x = x = 27

Number of girls = 15x = 15 × 27 = 405

Number of boys = 14x = 14 × 27 = 378

25.

Divide ₹63 in the ratio of 4 : 5 = ……………..?A) (28, 35)B) (36, 37)C) (36, 27)D) (35, 28)

Answer»

Correct option is A) (28, 35)

26.

The length of a pencil is 18 cm and its radius is 4 cm. Find the ratio of its length to its diameter.

Answer»

Length of a pencil = 18 cm

Radius of a pencil = 4 cm

Diameter of a pencil = 2r = 2 x 4 = 8 cm

Ratio of length of a pencil to its diameter = 18 : 8 = 9 : 4

27.

A sum of ₹11000 is divided in the ratio of 5 : 6 then the greater share is? (in₹)A) 5000B) 6000C) 1000D) 7000

Answer»

Correct option is B) 6000

28.

Divide Rs. 560 in the ratio ` 3 : 4` .

Answer» The sum of the terms of the ratio is 3 + 4 = 7.
`:." The first part " = Rs.(560 xx 3/7) = Rs. 240`
and , the second part = Rs. ` (560 xx 4/7) = Rs. 320`.
29.

Ratio of distance of the school from A’s home to the distance of the school from B’s home is 2 : 1.(i) Who lives nearer to the school ?(ii) Complete the following table :

Answer»

Ratio of distance of the school from A’s home to the distance of the school from B’s

hence = 2 : 1

(i) B lives nearest to the school

(ii) Let A’s home is 2x km from school and B’s home is x km

Distance of school from A’s home = 2 x Distance of school from B’s home

=> If A lives at a distance of 4 km, then B lives at a distance of = 1/2 x 4 = 2 km

=> If B lives at a distance of 9 km then A lives at a distance of = 2 x 9 = 18 km

=> If A lives at a distance of 8 km then B lives at a distance = 1/2 x 8 = 4 km

=> If B lives at a distance of 8 km, then A lives at a distance = 2 x 8 = 16 km

=> If A lives at a distance of 6 km, then B lives at a distance = 1/2 x 6 = 3 km

30.

A field is 80 m long and 60 m wide. Find the ratio of its width to its length.

Answer»

Width of field = 60 m

Length of field = 80 m

Ratio between width and length =60/80 =3/4 = 3 : 4

31.

Decrease 850 in the ratio 17 : 6 and then increase the result in the ratio 5 : 9.

Answer»

The given quantity = 850 and decrease in the ratio =17 : 6

The decreased quantity =6/17 x 850 = 300

Now, the quantity is increased in the ratio 5 : 9

The resulting quantity = 9/5 x 300 = 540

32.

Decrease 275 in the ratio 11 : 7.

Answer»

Given ratio = 11 : 7

The decrease quantity= 11/7 x given quantity.

= 11/7 x 275 = 175

33.

Compound interest (C.I) = ……………….?A) A – PB) A + PC) P + ID) P – I

Answer»

Correct option is A) A – P

34.

Formula for simple interest is I = ………………?(A) \(\frac{PTR}{100}\) (B) \(\frac{TR}{P\times100}\) (C) \(\frac{PR}{100\times T}\) (D) \(\frac{PT}{100\times R}\)

Answer»

Correct option is (A) \(\frac{PTR}{100}\)
 

35.

The volume (V) of a mass of gas varies directly as its absulute temperature (T) and iversely as the pressure (P) applied to it. The gas occupies a volume of 400 ml when the temperature is 150 k and pressure is 240 Pa. what is the temperature of gas whose volume and pressure are 250 ml and 320 Pa respectively?

Answer» Correct Answer - 125 K
36.

Rs 117 was supposed to be divided among P, Q and R in the ratio 3:4:6. But, by mistake, it was divided in the ratio `(1)/(3):(1)/(4):(1)/(6)` How many of P,Q and R gained due to this mistake?

Answer» Correct Answer - C
37.

The pressure of a gas varies directly as the remperature when volume is kept contant and varies inversely as the volume when temperature is kept constant. The gas occupies volume of 400 ml when the temperature is 160 K and the pressure is 640 Pa. What is the temperature of gas whose volume and pressure are 200 ml and 320 Pa, respectively?

Answer» Given `P propto T and propto 1/V`
`rArr P propto T/V rArr PV propto T`
` rArr (PV)/T = ` Constant
`rArr (P_(1)V_(1))/T_(1) = (P_(2)V_(2))/T_(2)`
` rArr (640 xx 400)/(160)=(320 xx 200)/T_(2) rArr T_(2) = (160)/4 = 40 K`.
38.

In winters, a school opens at 10 a.m. and closes at 3.30 p.m. If the lunch interval is of 30 minutes, find the ratio of lunch interval to total lime of the class periods.

Answer»

Timing of a school (10 a.m. to 3.30 p.m) = 5 hours 30 minutes

Timing for lunch interval = 30 minutes

Total time of the class periods = 5 hours 30 minutes – 30 minutes

= 5 hours = 60 x 5 = 300 minutes

Ratio of lunch interval to total time of the class period = 30 minutes : 300 minutes = 1 : 10

39.

Out of 96 students 12 students were absent in a class. Then the ratio of present to absentees is ……………. A) 1 : 7B) 7 : 1C) 8 : 1D) 9 : 1

Answer»

Correct option is B) 7 : 1

40.

The sides of a triangle are in the ratio 3 : 5 : 7. Its smallest side is 28 cm less than the largest side. Find the sides of the triangle.

Answer»

Ratio of the sides of the triangle = 3 : 5 : 7

3x = 7x – 28

7x – 28 = 3x

4x = 28

x = 28 ÷ 4

Smallest side = 3 × 7 = 21 cm

Second side = 5 × 7 = 35 cm

Largest side = 7 × 7 = 49 cm

41.

Did the sides of a triangle be in the ratio 3 : 5 : 8 ? Why ?

Answer»

Sides are 3x, 5x and 8x .

3x + 5x = 8x

here sum of two sides is equal to the third side.

But sum of two sides should be greater than the third side. So the given sides 3x, 5x and 8x are not the sides of a triangle. 

Therefore the ratio 3 : 5 : 8 cannot be the sides of a triangle.

42.

Rs 120 is to be divided between Hari and Gopi in the ratio 5: 3. How much does each get?

Answer»

Total amount = Ra 120

Ratio in Hari and Gopi = 5 : 3

Sum of ratios = 5 + 3 = 8

Hari's Share = (120 x 5)/8 = Rs 75

and Gopi's Share = 120 x 3/8 = Rs 45

43.

In a goat farm, the ratio of the number of goats which give milk to the number of goats which don’t is 6 : 2. The number of goat which don’t give milk is 160. How many goats do give milk? And how many goats are there in all?

Answer»

Ratio of the number of goat which give milk to the number of goat which don’t = 6 : 2

We have to find how many times the number of goat which don’t give milk is the number of goats which give milk is \(\frac{6}{2}\) times that the number of goats which don’t give milk.

Therefore the number of goats which give milk \(160\times\frac{6}{2}=480\)

Total number of goats = 160 + 480 = 640

44.

Rs.x is divided among three persons Mr Vaayu, Mr Jala and Mr Agni in the ratio ` 3 : 4 : 7`. If the share of Mr Jala is Rs. 5600 , then find the value of x.A. ` 15,400`B. ` 16,800`C. ` 18,200`D. `19,600`

Answer» Correct Answer - D
Given that the ratio of shares of Mr Vaayu, Mr Jala and Mr Agni is ` 3 : 4 : 7`.
Share of Mr Jala = Rs. 5600.
` :. ` The total sum (in Rs.) = ` ((3+4+7))/4 = (5600)`
` rArr (14)(1400) rArr Rs. 19,600`.
45.

A certain sum of money is distributed among A, B and C in the ratio of ` 1/2 : 1/3 : 1/4` and B gets Rs. 120. Find the shares of A and C.

Answer» Correct Answer - Rs. 90, Rs. 130
46.

Arrange the ratios `3:4,5:6,1:2 and 19:15` in their increasing order of magnitude.

Answer» Correct Answer - `1:2 lt 3:4 lt 5:6lt 19:15`
47.

A and B share money in the ratio `1(2)/(3):2(3)/(4)`. What is the total money shared if A got Rs 720?

Answer» Correct Answer - 1908
48.

What number must be added to each term of the ratio 7:5 so that it becomes 4:3?

Answer» Correct Answer - 1
49.

What must be added to both the terms of ` x : y` so that the resultant ratio is inverse of the given ratio ` (x ne y)` ?A. y-xB. x-yC. `-(x-y)`D. x+y

Answer» Correct Answer - C
Let `(x+k)/(y+k) = y/x rArr x^(2) + kx = y^(2) + ky`
` rArr k(x-y)= y^(2)-x^(2) rArr k = -(y+x)`.
50.

In a solution of 45 litres of milk and water, ` 40%` is water. How many litres of milk must be added to become the ratio of milk and water ` 5 : 3` ?A. 8B. 3C. 7D. 6

Answer» Correct Answer - B