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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 401. |
Which of the following is the strongest oxidising agent?A. `BrO_(3)^(-)//Br^(2)`, `E^(0)=+1.50`B. `Fe^(3+)//Fe^(2+)`, `E^(0)=+0.76`C. `MnO_(4)^(-)//Mn^(2+)`, `E^(0)=+1.52`D. `Cr_(2)O_(7)^(2-)//Cr^(3+)`, `E^(0)=+1.33` |
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Answer» Correct Answer - C Higher is the reduction potential stronger is the oxidising agent. Hence in the given options. `MnO_(4)^(-)` is strongest oxidising agent. |
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| 402. |
A reducing agent is a substance Which can:A. Accept agent is a substance which can :B. Accept electronsC. Donate electronsD. Donate protons |
| Answer» Correct Answer - B | |
| 403. |
which of the following leads to redox reaction ?A. `AgNO_(3)+HCl`B. `KOH+HCl`C. `KI+Cl_(2)`D. `NH_(3)+HCl` |
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Answer» Correct Answer - C `2I^(ө)rarrI_(2)+2e^(-)` `Cl_(2)+2e^(-)rarr2Cl^(ө)` |
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| 404. |
Assertion: A reducing agent is a substance which can donate electron. Reason: A substance which helps in oxidation is known as reducing agent.A. If both assertion and reason are true and the reason is the correct explanation of the assertion.B. If both assertion and reason are true but reason is not the correct explantion of the assertion.C. If assertion is true but reason is false.D. If assertion is false but reason is true. |
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Answer» Correct Answer - C `M rarr M^(+n)+"ne"` , (`M` is reducing agent) A reducing agent reduces the other species. |
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| 405. |
When one mole `NO_(3)^(-)` is converted into 1 mole `NO_(2)` 0.5 mole `N_(2)` and 0.5 mole `N_(2)O` respectively, accepts x,y and z mole of reaction -x,y,z are respectively.A. 1,5,4B. 1,2,3C. 2,1,3D. 2,3,4 |
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Answer» Correct Answer - a |
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| 406. |
Assertion :- A reducing agent is a substance which accepts electron. Reason :- A substanc which helps in oxidaton is known as reducing agent.A. If both Assertion & Reason are True & the Reason is a correct explanation of the Assertion.B. If both Assertion & Reason are True but Reason is not a correct explanation of the Assertion.C. If Assertion is True but the Reason is False.D. If both Assertion & Reason are False. |
| Answer» Correct Answer - D | |
| 407. |
The oxidation number of N and Cl in `NOClO_(4)` respectively areA. `+2 and +7`B. `+3 and +7`C. `-3 and +5`D. `+2 and -7` |
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Answer» Correct Answer - B `NOClO_(4)-=(NO^(+))(ClO_(4)^(-))` Let O.N. of N in `NO^(+)` is x `:. x + (-2)=+1` `x=3` Let O.N of Cl in `ClO_(4)^(-)` is x `:. x + 4 (-2)=-1 or x = +7`. |
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| 408. |
Equivalent weight of `NH_(3)` in the change `N_(2)rarrNH_(3)` is :A. `(17)/(6)`B. `17`C. `(17)/(2)`D. `(17)/(3)` |
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Answer» Correct Answer - d |
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| 409. |
Assertion :- Bromide ion is serving as a reducing agent in the reaction `2MnO_(4)^(-)(aq.)+Br^(-)(aq.)+H_(2)Orarr2MnO_(2)(aq.)+BrO_(3)^(-)(aq.)+2OH^(-)(aq.)` Reason :- Oxidation number of Br increases from `-1` to `+5`A. If both Assertion & Reason are True & the Reason is a correct explanation of the Assertion.B. If both Assertion & Reason are True but Reason is not a correct explanation of the Assertion.C. If Assertion is True but the Reason is False.D. If both Assertion & Reason are False. |
| Answer» Correct Answer - A | |
| 410. |
Oxidation number of `S` in `[(CH_(3))_(2)SO]` is:A. ZeroB. `+1`C. `+2`D. `+3` |
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Answer» Correct Answer - A Calculate ox.no. of `S` by assuming `(CH_(3))^(+)` and `SO^(2-)` |
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| 411. |
The composition of a sample of Wustite is `Fe_(0.93)O_(1.00)`. What percentage of the iron is present in the form of `Fe (III)`?A. `15.05`B. `84.95`C. `10.2`D. `89.8` |
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Answer» Correct Answer - A Oxidation number of `Fe` in `Fe_(0.93)O_(1.0)` `=(200)/(93)=2.15` Let `a%` be in form of `Fe(III)` and thus `((+3xxa)+[+2(100-a)])/(100)=2.15` `:. a=15.05` |
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| 412. |
Which has zero oxidation number :-A. CdB. `Cl_(2)`C. (1) & (2)D. None |
| Answer» Correct Answer - C | |
| 413. |
Based on the following reaction, `XeO_(6)^(4-)(aq)+2F^(-)(aq)+6H^(+)(aq) rarr XeO_(3)(aq)+F_(2)(g)+3H_(2)O(l)` (`Delta (G)^(@)lto`) It can be concluded thatA. oxidising power of `F^(-)` is grater than that of `XeO_(6)^(4-)`B. it is not a redox reactionC. it is a disproportionation reactionD. oxidising power of `XeO_(6)^(4-)` is greater than that of `F^(-)` |
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Answer» Correct Answer - D `underset((+8))underset(uarr)(XeO_(6)^(4-))+underset((-1))underset(uarr)(F^(-) ) rarr underset((+6))underset(uarr) (XeO_(3))+underset((0))underset(uarr) (F_(2))` Since, `DeltaG^(@)lt0`, hence it is spontaneous in forward direction. Oxidation number of `Xe` decreases, hence, it is an oxidising agent, and oxidation number of `F` increases, hence it is a reducing agent. |
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| 414. |
A half-cell contains `"____"` of an element .A. the oxidized fromB. the reduced formC. the redox formD. the oxidized and reduced forms |
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Answer» Correct Answer - D A half-cell contains the oxidized and reduced forms of an element, or other more complex species, in contact with one another. A common kind fo half-cell consists of a piece of metal (the electrode) immersed in a solution of its ions. Consider two such half-cells in separate beal as. The electrodes are connected by a metal wire .(A) voltmeter can be inderted into the circuit to measure the potential difference between the two electrodes, or an ammeter can be inserted to measure the current flow. The circuit between the two solutions is completed by a salt bridge. |
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| 415. |
A compound of Xe and F is found to have 53.3% Xe (atomic weight = 133) Oxidation number of Xe in this compound isA. `+2`B. 0C. `+4`D. `+6` |
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Answer» Correct Answer - D `{:("Name of element","%age","At.mass","%Agr/At.mass","Simples ratio"),("Xe",53.3,133,(53.3)/(133)=0.398",",(0.398)/(0.398)=1),("F",46.7,19,(46.7)/(19)=2.45",",(2.45)/(0.398)=6):}` `:.` Empirical formula `= XeF_(6)` `:.` O.N. of Xe in `XeF_(6)=6`. |
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| 416. |
Oxidation number of Xe in `XeF_(5)^(-)` is :A. `+1`B. `+2`C. `+3`D. `+4` |
| Answer» Correct Answer - D | |
| 417. |
In `XeO_(3)` and `XeF_(6)` the oxidation state of `Xe` isA. `+4`B. `+1`C. `+6`D. `+3` |
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Answer» Correct Answer - C The oxidation state of `Xe` in both `XeO_(3)` and `XeF_(6)` is `+6` `{:(+6,,),(overset(**)(X)eO_(3),,overset(**)(X)eF_(6)),(x-2xx3=0,,x-6=0),(x=+6,,x=+6):}` |
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| 418. |
Which of the following statements is not true?A. In a chemical reaction, oxidation is always accompanied by reduction.B. When a negative ion changes to neutral species, the process is oxidation,C. Oxidising agent has a tendency to lose electrons.D. Conversion of `MnO_(4)^(2-)` to `MnO_(4)^(-)` is oxidation. |
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Answer» Correct Answer - C Oxidising agent has a tendency to gain electrons. |
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| 419. |
Which of the following is not a redox reaction in terms of eletron transfer reaction ?A. `Ba+ F_2 rarr BaF_2`B. ` 2Ca +O_2 rarr 2CaO`C. ` Cl_2+ 3F_2 rarr 2ClF_3`D. `2Na +S rarr NaS` |
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Answer» Correct Answer - C Because `ClF_3` is a covalent compound, its formation does not involve loss and gain of electrons . |
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| 420. |
Oxidation state of iron in `Fe(CO)_(4)` isA. `+1`B. `-1`C. `+2`D. 0 |
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Answer» Correct Answer - D In metal carbonyls, metals have zero oxidation state. |
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| 421. |
On the basis of electronic conbept, justify that the following reaction is a redox reaction `2Na(g)+H_(2)(g)rarr2NaH(s)` |
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Answer» In terms of electrons concept, the reacion may be split into oxidation half reaction (loss of electrons ) and reduction half reactin (gain of electrons) `2Na(s)rarr2Na+(g)+2e^(-)`(oxidation half reaction) `H_(2)(g)+2e^(-)rarr2H^(-)(g)`(reduction half reaction) The given reaction is therefore, a redox reaction in nature. |
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| 422. |
The oxidation state of nitrogen in `N_(3)H` isA. `+(1)/(3)`B. `+3`C. `-1`D. `-(1)/(3)` |
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Answer» Correct Answer - D In hydrazoic acid `(N_(3)H)` nitrogen shows `-(1)/(3)` oxidation state. `overset(*)(N)_(3)H` `3x+1=0`, `3x=-1`, `x=-(1)/(3)` |
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| 423. |
The valency of `Cr` in the complex `[Cr(H_(2)O)_(4)Cl_(2)]^(+)`A. `1`B. `3`C. `5`D. `6` |
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Answer» Correct Answer - B `[overset(**)(C )r(H_(2)O)_(4)Cl_(2)]^(+)` `x+0+2(-1)`, x-2=+1` `x=+3` for `Cr` in complex. |
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| 424. |
The process of oxidation involves:A. addition of `O_(2)` or removal of `H_(2)` to a moleculeB. addition of a non-metal or removal of metalC. loss of electronsD. None of above |
| Answer» Correct Answer - A::B::C | |
| 425. |
Oxidation number of `N` in `NH_(3)` isA. `+5`B. `+3`C. `0`D. `-3` |
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Answer» Correct Answer - D `overset(**)(N)H_(3)` `x+3(+1)=0`, `x=-3`. |
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| 426. |
Which of the following statements `(s)` is (are) correct?A. All reactions are oxidation and reduction reactionsB. Oxidizing agent is itself reducedC. Oxidation and reduction always go side by sideD. Oxidation number during reduction decreases |
| Answer» Correct Answer - B::C::D | |
| 427. |
Oxidation number of nitrogen in `NaNO_(2)` isA. `+2`B. `+4`C. `+3`D. `-3` |
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Answer» Correct Answer - C Let the oxidation number of `N` in `NaNO_(2)` be `x` `+1+x+(-2)xx2=0` `1+x-4=0`, `x= +3` |
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| 428. |
The reaction in which hydrogen poeroxide is a reducing agent is:A. `Pbs+4H_(2)O_(2)rarrPbSO_(4)+4H_(2)O`B. `2KI+H_(2)O_(2)rarr2KOH+I_(2)`C. `H_(2)SO_(3)+H_(2)O_(2)rarrH_(2)sO_(4)+H_(2)O`D. `Ag_(2)O+H_(2)O_(2)rarr2Ag+H_(2)O+O_(2)` |
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Answer» Correct Answer - D `H_(2)O_(2)` has reduced `Ag_(2)O` is silver (Ag) |
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| 429. |
The oxidation number of C in sucrose `(C_(12)H_(22)O_(11))` is |
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Answer» Correct Answer - A `C_(12)H_(22)O_(11)` `12 x + 22(+1) + 11(-2)or x=0` |
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| 430. |
Born carbide, `B_(4)C,` is made by the high temperature reaction of boron oxide with graphite, yielding carbon monoxide as a by-product ___`B_(2)O_(3)+`_____`Cto`______`B_(4)C+CO` What is the total of the smallest coefficients for the reactants and and products in the balanced equation?A. 9B. 10C. 15D. 16 |
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Answer» Correct Answer - d |
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| 431. |
Pick the group which does not on an a neutral oxide:A. `NO_(2),P_(4)O_(10),AI_(2)O_(3),NO`B. `MgO,N_(2)O_(5),SO_(3)N_(2)O`C. `CO_(2),SO_(3),CaO,XeO_(3)`D. `CO,SiO_(2),SnO_(2),Na_(2)O_(3)` |
| Answer» Correct Answer - C | |
| 432. |
The oxidation number of C in sucrose `(C_(12)H_(22)O_(11))` isA. `+4`B. `+3`C. `+2`D. Zero |
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Answer» Correct Answer - D Let O.N. of C in `C_(12)H_(22)O_(11)` `:. 12 xx x + 22 + 11(-2) =0, x=0`. |
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| 433. |
Oxidation number of carbon in carbon sub-oxide is:A. `+ 2//3`B. `+ 4//3`C. `+4`D. `- 4//3` |
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Answer» Correct Answer - B Let O.N of C in `C_(3)O_(2)` is x `:. 3x + 2(-2) = 0 or x = 4//3`. |
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| 434. |
What is the oxidation number of C in formaldehyde, `CH_(2)O` ?A. `-2`B. `0`C. `+2`D. `+4` |
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Answer» Correct Answer - b |
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| 435. |
Assertion :- In `NH_(4)NO_(3)`, the oxidation number of the two N-atoms is not equal. Reason :- One N atom is present in the ammonium ion while the other is present in the nitrate ion.A. If both Assertion & Reason are True & the Reason is a correct explanation of the Assertion.B. If both Assertion & Reason are True but Reason is not a correct explanation of the Assertion.C. If Assertion is True but the Reason is False.D. If both Assertion & Reason are False. |
| Answer» Correct Answer - A | |
| 436. |
What is the net charge on ferrous ion ?A. `+2`B. `+3`C. `+4`D. `+5` |
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Answer» Correct Answer - A Net charge on ferrous ion, `Fe^(2+)` is 2. |
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| 437. |
Select the compound in which chlorine is assigned the oxidation number `+5`A. `HClO_(4)`B. `HClO_(2)`C. `HClO_(3)`D. `HCl` |
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Answer» Correct Answer - C `overset(*)(HCIO_(3))` `1+x-2xx3=0`, `x=6-1=+5` |
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| 438. |
In `CH_(2)=C Cl_(2)`, the two carbon atoms have oxidation number respectively:A. `-2,+2`B. `-2,-2`C. `+2,+2`D. `+2,-2` |
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Answer» Correct Answer - A `-2` in `CH_(2)` and `+2` in `C Cl_(2)`. |
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| 439. |
The oxidation number of carbon in `CH_(2)Cl_(2)` isA. `0`B. `+2`C. `-2`D. `+4` |
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Answer» Correct Answer - A `overset(*)(C )H_(2)Cl_(2)` `x+2-2=0, x=0`. |
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| 440. |
The oxidation number, of C in `CH_(4). CH_(3)CI, CH_(2)CI_(2), CHCl_(3) and C Cl_(4)` are respectively:A. `+4,+2,0,-2,-4`B. `+2,+4,0,-4,-2`C. `-4,-2,0,+2,+4`D. `-2,-4,0,+4,+2` |
| Answer» Correct Answer - C | |
| 441. |
The oxidation number of carbon in `CH_(2)Cl_(2)` is |
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Answer» Correct Answer - A `CH_(2)Cl_(2) rarr x+2(+1)+2(-1)=0 rArr x = 0` |
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| 442. |
Assertion: `HClO_(4)` is a stronger acid than `HClO_(3)`. Reason: Oxidation state of `Cl` in `HClO_(4)` is `+VII` and in `HClO_(3)+V`.A. If both assertion and reason are true and the reason is the correct explanation of the assertion.B. If both assertion and reason are true and reason is not the correct explantion of the assertion.C. If assertion is true but reason is false.D. If the assertion false and reason is true. |
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Answer» Correct Answer - B Both assertion and reason are true but reason is not the correct explanation of assertion. Greater the number of negative atoms present in the oxy-acid make the acid stronger. In general, the strengths of acids that have general formula `(HO)_(m)ZO_(n)` can be related to the value of `n`. As the value of `n` increase, acidic character also increases. The negative atoms draw electrons away from the `Z`- atom and make it more positive. The `Z`-atom, therefore, becomes more effective in withdrawing electron density away from the oxygen atom that bonded to hydrogen, in turn the electrons of `H-O` bond are drawn more strongly away from the `H`- atom. The net effect makes it easier from the proton release and increases the acid strength. |
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| 443. |
For the redox reaction, `MnO_(4)^(-) + C_(2)O_(4)^(2-) + H^(+) rarr Mn^(2+) + CO_(2) + H_(2)O` the correct coefficients of the reactants for the balanced reaction areA. `{:(MnO_(4)^(-),C_(2)O_(4)^(2-),H^(+),),(2,5,16,):}`B. `{:(MnO_(4)^(-),C_(2)O_(4)^(2-),H^(+),),(16,5,2,):}`C. `{:(MnO_(4)^(-),C_(2)O_(4)^(2-),H^(+),),(5,16,2,):}`D. `{:(MnO_(4)^(-),C_(2)O_(4)^(2-),H^(+),),(2,16,5,):}` |
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Answer» Correct Answer - A `MnO_(4)^(-) + 8H^(+) + 5e^(-) rarr Mn^(2+) + 4H_(2)O] xx 2` `C_(2)O_(4)^(2-) rarr 2CO_(2) + 2e^(-) xx 5` `2MnO_(4)^(-) + 5C_(2)O_(4)^(2-) + 16H^(+) rarr 2Mn^(2+) + 10 CO_(2) + 8H_(2)O` Thus, the coefficient of `MnO_(4)^(-), C_(2)O_(4)^(2-)` and `H^(+)` in the above balanced equation respectively are 2, 5, 16 |
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| 444. |
For the redox reaction, `MnO_(4)^(-) + C_(2)O_(4)^(2-) + H^(+) rarr Mn^(2+) + CO_(2) + H_(2)O` the correct coefficients of the reactants for the balanced reaction areA. `{:(MnO_(4)^(-),C_(2)O_(4)^(2-),H^(+)),(2,5,16):}`B. `{:(MnO_(4)^(-),C_(2)O_(4)^(2-),H^(+)),(16,5,2):}`C. `{:(MnO_(4)^(-),C_(2)O_(4)^(2-),H^(+)),(5,16,2):}`D. `{:(MnO_(4)^(-),C_(2)O_(4)^(2-),H^(+)),(2,16,5):}` |
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Answer» Correct Answer - D `MnO_(4)^(-) + 8H^(+) + 5e^(-) to Mn^(2+) + 4H_(2)O xx 2` `" " C_(2)O_(4)^(2-) to 2CO_(2) + 2e^(-) xx 5` `bar(MnO_(4)^(-) + 5Cr_(2)O_(4)^(2-) + 16H^(+) to 2Mn^(2+) + 10 CO_(2) + 8H_(2)O` Thus, the coefficients of `MnO_(4)^(-), C_(2)O_(4)^(2-)` and `H^(+)` in the above balance equation respectively are 2,5, 16. |
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| 445. |
A gas X at 1 atm pressure is bubbled through a solution containing a mixture of `1 MY^(-) and 1 MZ^(-)` at `25^(@)C`.If the reduction potential of `ZgtYgtX`, thenA. Y will oxidise X and not ZB. Y will oxidise Z and not XC. Y will Oxidise both Z and XD. Y will reduce both X and Z |
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Answer» Correct Answer - A is the correct answer |
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| 446. |
In the reaction `3Br_(2)+6CO_(3)^(2-)+3H_(2)Orarr5Br^(ө)+BrO_(3)^(ө)+6HCO_(3)^(ө)`A. Bromine is oxidised and carbonate is reduicedB. Bromine is reduced and water is oxidaisedC. Bromine is neither reduced nor oxidisedD. Bromine is both reduced and oxidised |
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Answer» `3overset(0)Br_(2)+6CO_(3)^(2-)+3H_(2)Orarr5overset(-1)Br^-)+overset(+5)BrO_(3)^(-)+6HCO_(3)^(-)` As `Br_(2)` undergoes both decrease as well as increase in oxidationnumber it ios both reduced and oxidised. |
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| 447. |
For the redox reaction: `MnO_(4)^(-)+C_(2)O_(4)^(2-)+H^(+)rarrMn^(2+)+CO_(2)+H_(2)O` The correct coefficeents of the reactants for the balanced reaction are: `MnO_(4)^(-) C_(2)O_(4)^(2-) H+`A. `2" "5" "16`B. `16" "5" "2`C. `5" "16" "2`D. `2" "16" "5` |
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Answer» Correct Answer - A The balanced equation is: `2Mn_(4)^(-)+5C_(2)O_(4)^(2-)+16H^(+)rarr2Mn^(2+)+10CO_(2)+8H_(2)O` |
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| 448. |
A Standard hydrogen electrode has zero electrode potential beacauseA. hydrogen is easiest to oxidiseB. the electrode potential is assuemed to be zeroC. hydrogen atom has only one electronD. hydrogen is the lightest element |
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Answer» Correct Answer - B Conceptual question |
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| 449. |
In the reaction: `Na_(2)S_(2)O_(3)+4Cl_(2)+5H_(2)O rarr Na_(2)SO_(4)+H_(2)SO_(4)+8HCl`, the equivalent weight of `Na_(2)S_(2)O_(3)` will be: (M= molecular weight of `Na_(2)S_(2)O_(3))`A. `(M)/(4)`B. `(M)/(8)`C. `(M)/(1)`D. `(M)/(2)` |
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Answer» Correct Answer - b |
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| 450. |
Oxidation is de-electronation whereas reduction is electronation. Oxidants are the substances which oxidise others and reduced themselves. On the other hand reductants are the substances which reduce others and oxidised themselves. The oxidation number of an element in a compound decides its nature to act as oxidant or reductant. Oxidation-reduction occur simultaneously and the overal chemical change is called redox reaction. Redox reactions are of three types : (i) Intermolecular erdox reactions, (ii) Auto-redox or disproportionation reaction, and (iii) Intramolecular redox reactions. `Ox`. no. of `Fe` in `FeSO_(4).NO` is :A. `+1`B. `+2`C. `+3`D. Zero |
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Answer» Correct Answer - A `Fe` forms `+1` oxidation state in iron complexes. |
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