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Heymate! here is your answer There are two main types of energy :-KINETIC energy and POTENTIAL energy.Hope it helps you DEAR PLZ mark as Brainliest! ❤ And HAPPY Holi

1.=2.the incident RAY,REFLECTED ray and the NORMAL all lie on the same plane

Wineapple MENTIONS the UNUSUAL nickname — “ 'Marmee,' as her DAUGHTERS called her” — but does not discuss its pronunciation. The ALCOTT (and March) girls, New Englanders all, would have pronounced the “r” as “AH” when they referred to their mother. In other words, they called her “Mahmee” — or “Mommy”!Plz thanks on my Answer......❤

that HEAT expands and cool shrinks so if there is hot air inside the can then the hot air would expand inside but if we MIX cold air immediately then it would SHRINK and HENCE this reaction would crush the can . hope it helped : )

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tion:The KINETIC ENERGY of a SATELLITE in a circular orbit is half its gravitational energy and is positive instead of negative. When U and K are COMBINED, their total is half the gravitational potential energy

EinsteinAlthough the TITLE "Father of Physics" has not been given to a single individual, Galileo Galilei, Sir ISAAC Newton, and Albert EINSTEIN have all been called fathers of physics in western cultures.

-24Explanation:Multiply all CONSTANTS you GET 24kxj = - ii.(-i) = -124 X -1 = -24

It comes from the kinetic energy of the fireman DUE to his motion & the gravitational potential energy due to his raised position above the pole. As he slides down the pole, the KE and GPE are CONVERTED into heat energy and sometimes SOUND energy.

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helps youmark me a brainlistIn physics, GAUSS's law for magnetism is one of the four MAXWELL's equations that underlie classical electrodynamics. It states that the magnetic field B has DIVERGENCE equal to zero, in other words, that it is a solenoidal vector field. ... These forms are EQUIVALENT due to the divergence theorem

Given:Velocity vs Displacement relationship as :Mass of OBJECT = 2 kgTo find:Work DONE in time 1 - 2 seconds.Concept:As per Work Energy Theorem , we can SAY that work done by all forces is equal to the change in Kinetic Energy in the specified time interval.Calculation:Assuming s = 0 , when t = 0 ;So our displacement vs time Equation comes as :So at t = 2 seconds , we get :Now PUTTING the values in work energy theorem :Work done = Change in KESO final answer :

Daytime is when you can see the sun from where you are, and its light and heat can reach you. NIGHTTIME is when the sun is on the other side of the EARTH from you, and its light and heat don’t get to you. Hope this answer helps you........FOLLW me.........

Solution :-**refer to attached for the reference.First of all we will add some more information in the diagram in order to SOLVE it.As In AMG , A battery is connected we will take a current i_1i 1 Then according to Kirchoff's junction law at junction G.i_1 = I + xi 1 =I+xx = i_1 - Ix=i 1 −ISo current in GB = i_1 - Ii 1 −INow in FED we will take ANOTHER current i_2i 2 .I = i_2 + yI=i 2 +yy = I - i_2y=I−i 2 So current in FC = I - i_2I−i 2 Now by applying junction law at other junctions▪️Current in CB = II▪️Current in BA = i_1i 1 Now we will write LOOP For (anticlockwise)(1)AHGB-12 = 3R(i_1 - I) + R(i_1)−12=3R(i 1 −I)+R(i 1 )\implies -12 = 3Ri_1 - 3RI + Ri_1⟹−12=3Ri 1 −3RI+Ri 1 \implies -12 = 4Ri_1 - 3RI⟹−12=4Ri 1 −3RI ...(i)(2) AHFC-12 = 4R(I - i_2) + R(i_1)−12=4R(I−i 2 )+R(i 1 )\implies -12 = 4RI - 4Ri_2 + Ri_1⟹−12=4RI−4Ri 2 +Ri 1 ...(ii)(3) AHED24 - 12 = 2R(i_2) + R(i_1)24−12=2R(i 2 )+R(i 1 )\implies12 = 2Ri_2 + Ri_1⟹12=2Ri 2 +Ri 1 ....(iii)(4)CFED24 = 2R(i_2) - 4R(I-i_2)24=2R(i 2 )−4R(I−i 2 )\implies 24 = 2Ri_2 - 4RI + 4Ri_2⟹24=2Ri 2 −4RI+4Ri 2 \implies 24 = 6Ri_2 - 4RI⟹24=6Ri 2 −4RI ....(iv)Now 3(iv) - 4(i)72 = 18Ri_2 - 12RI72=18Ri 2 −12RI+ 48 = - 16Ri_1 + 12RI+48=−16Ri 1 +12RI________________________120 = 18Ri_2 - 16Ri_1120=18Ri 2 −16Ri 1 .....(v)________________________Now from (v) - 9(iii)120 = 18Ri_2 - 16Ri_1120=18Ri 2 −16Ri 1 -108= - 18Ri_2 - 9Ri_1−108=−18Ri 2 −9Ri 1 ________________________12 = -25Ri_112=−25Ri 1 ________________________Ri_1 = \dfrac{-12}{25}Ri 1 = 25−12 Now from by substiting value of Ri_1Ri 1 in (i)-12 = 4Ri_1 - 3RI−12=4Ri 1 −3RI\implies -12 = 4\dfrac{-12}{25} - 3RI⟹−12=4 25−12 −3RI\implies -12 = \dfrac{-48}{25}- 3RI⟹−12= 25−48 −3RI\implies 3RI = \dfrac{-48}{25} + 12⟹3RI= 25−48 +12\implies 3RI = \dfrac{300-48}{25}⟹3RI= 25300−48 \implies 3RI = \dfrac{252}{25}⟹3RI= 25252 \implies 3RI = 10.08⟹3RI=10.08\implies RI = 3.36⟹RI=3.36\implies I = \dfrac{3.36}{R}⟹I= R3.36 \implies I = \dfrac{3.36}{1000}⟹I= 10003.36 \implies I = 3.36 \: mA⟹I=3.36mASo current I = 3.36 mA

I cannot UNDERSTAND your LANGUAGEIS this URDU

Gustav Kirchhoff's Current Law is one of the FUNDAMENTAL laws USED for circuit analysis. His current law states that for a parallel PATH the total current entering a circuits junction is exactly equal to the total current leaving the same junction. This is because it has no other place to GO as no charge is LOST.

tion:Solution :-**refer to attached for the reference.First of all we will add some more information in the diagram in ORDER to solve it.As In AMG , A battery is connected we will take a current i_1i 1 Then ACCORDING to Kirchoff's junction law at junction G.i_1 = I + xi 1 =I+xx = i_1 - Ix=i 1 −ISo current in GB = i_1 - Ii 1 −INow in FED we will take another current i_2i 2 .I = i_2 + yI=i 2 +yy = I - i_2y=I−i 2 So current in FC = I - i_2I−i 2 Now by APPLYING junction law at other junctions▪️Current in CB = II▪️Current in BA = i_1i 1 Now we will write Loop For (anticlockwise)(1)AHGB-12 = 3R(i_1 - I) + R(i_1)−12=3R(i 1 −I)+R(i 1 )\implies -12 = 3Ri_1 - 3RI + Ri_1⟹−12=3Ri 1 −3RI+Ri 1 \implies -12 = 4Ri_1 - 3RI⟹−12=4Ri 1 −3RI ...(i)(2) AHFC-12 = 4R(I - i_2) + R(i_1)−12=4R(I−i 2 )+R(i 1 )\implies -12 = 4RI - 4Ri_2 + Ri_1⟹−12=4RI−4Ri 2 +Ri 1 ...(ii)(3) AHED24 - 12 = 2R(i_2) + R(i_1)24−12=2R(i 2 )+R(i 1 )\implies12 = 2Ri_2 + Ri_1⟹12=2Ri 2 +Ri 1 ....(iii)(4)CFED24 = 2R(i_2) - 4R(I-i_2)24=2R(i 2 )−4R(I−i 2 )\implies 24 = 2Ri_2 - 4RI + 4Ri_2⟹24=2Ri 2 −4RI+4Ri 2 \implies 24 = 6Ri_2 - 4RI⟹24=6Ri 2 −4RI ....(iv)Now 3(iv) - 4(i)72 = 18Ri_2 - 12RI72=18Ri 2 −12RI+ 48 = - 16Ri_1 + 12RI+48=−16Ri 1 +12RI________________________120 = 18Ri_2 - 16Ri_1120=18Ri 2 −16Ri 1 .....(v)________________________Now from (v) - 9(iii)120 = 18Ri_2 - 16Ri_1120=18Ri 2 −16Ri 1 -108= - 18Ri_2 - 9Ri_1−108=−18Ri 2 −9Ri 1 ________________________12 = -25Ri_112=−25Ri 1 ________________________Ri_1 = \dfrac{-12}{25}Ri 1 = 25−12 Now from by substiting value of Ri_1Ri 1 in (i)-12 = 4Ri_1 - 3RI−12=4Ri 1 −3RI\implies -12 = 4\dfrac{-12}{25} - 3RI⟹−12=4 25−12 −3RI\implies -12 = \dfrac{-48}{25}- 3RI⟹−12= 25−48 −3RI\implies 3RI = \dfrac{-48}{25} + 12⟹3RI= 25−48 +12\implies 3RI = \dfrac{300-48}{25}⟹3RI= 25300−48 \implies 3RI = \dfrac{252}{25}⟹3RI= 25252 \implies 3RI = 10.08⟹3RI=10.08\implies RI = 3.36⟹RI=3.36\implies I = \dfrac{3.36}{R}⟹I= R3.36 \implies I = \dfrac{3.36}{1000}⟹I= 10003.36 \implies I = 3.36 \: mA⟹I=3.36mASo current I = 3.36 mAfollow me

which CLASS QUESTION is this..

Joule is the SI UNIT of work done. THEREFORE, the dimensional formula of Joule is the same as that of the work done. ... Work (Joule)= F × D = [M1 L1 T-2] × [L1] = [M1 L2 T-2]. Therefore, Joule is DIMENSIONALLY represented as [M1 L2 T-2].

1 .ELECTROMAGNETISM is used in making motors at COMMERCIAL levels2.it is used for making doorbells3.it is used in making electromagnet4.it is USEFUL in making toys

the BOND FORMED is COVALENT bond

K1/K2 = M2/M1Explanation:According to the RELATION between. KE and LINEAR momentum (p) . We have , KE = Square of linear momentum ( P2)/ 2xMass So from the QUESTION it is clear that Bodies have same momentum . Linear momentum remains constant.Then we have a relation like , KE is inversely proportional to MASS

the COMMON NAME is WASHING SODA

tion:scattering of light from an OBJECT in all DIRECTION is called scattering of light.the phenomenon of splitting of white light into its cinstituent colours, when it passes through PRISM is KNOWN as despersion of light.

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only 10ccExplanation:because of VAPOUR

of vo1)0.5 is the VALUE

just OPPOSITE of itExplanation:DUE to LATERAL INVERSION

sorry I didn't KNOW this answer EXPLANATION:because I am studying in class 9 sorry sister or BROWN

tion:1) thermometer shows rapid FALL in temperature initiallybecause ice mixture AROUND the CYLINDER kal two EFFECTS on water and water temperature goes on decreasing the temperature of the water goes on decreasing the the volume of the upper water goes on decreasing and density increasing till 4° Celsius because of the increasing density upper water sinks to bottom and this results in decreasing temperature rapidly2) no3)when ice is form it's density goes on decreasing from 4°c to 0°c .bottom water has HIGHEST density