67486 + Interview Questions in Secondary School in Physics Page 46 InterviewSolution

2251.	A car is moving at a speed of 25km/h and come to rest. The time taken for the car to come to rest is 2 hr. Find the acceleration of the car and distance travelled
Answer» Explanation: U = 25 km/hr as it comes to rest so V = 0 t = 2hr so by using v = u + at 0 = 25 + a2 -25 = a2 a = -25/2 = 12.5km/hr^2 for distance S = ut + 1/2 at^2 = 252 +1/2 12.52^2 =50+1/2 * 12.5*4 = 50+ 25 = 75KM

2251.

A car is moving at a speed of 25km/h and come to rest. The time taken for the car to come to rest is 2 hr. Find the acceleration of the car and distance travelled

Answer»

Explanation:

U = 25 km/hr

as it comes to rest so V = 0

t = 2hr

so by using v = u + at

0 = 25 + a*2

-25 = a*2

a = -25/2 = 12.5km/hr^2

for distance S = ut + 1/2 at^2

= 25*2 +1/2 12.5*2^2

=50+1/2 * 12.5*4

= 50+ 25

= 75KM

Discussion

2252.	If there are 5 divisions in voltmeter which one is the least
Answer» Ammeter Voltmeter For Ammeter, We see that 10 DIVISIONS is equal to 0.2 Amperes So, Least Count = 0.2/10 = 0.02 A For Voltmeter, We see that 10 DIVISION is equal to 1 Volt So, Least Count = 1/10 = 0.1 V

2252.

If there are 5 divisions in voltmeter which one is the least

Answer»

Ammeter Voltmeter

For Ammeter, We see that 10 DIVISIONS is equal to 0.2 Amperes So, Least Count = 0.2/10 = 0.02 A For Voltmeter, We see that 10 DIVISION is equal to 1 Volt So, Least Count = 1/10 = 0.1 V

Discussion

2253.	For the parallel combination of three resistors ,establish the relation.1/Rp=1/R1+1/R2+1/R3 where the symbols have their usual meanings.
Answer» Given : ⟶ Three IDENTICAL resistors of resistanced R $_1$ , R $_2$ and R $_3$ are connected in parallel. To Prove : ➨ 1/R $_p$ = 1/R $_1$ + 1/R $_2$ + 1/R $_3$ Solution : ➠ Let, three resistors are connected in parallel with a battery of voltage V. ✭ Remember : Current passing through each resistor remains same in series connection. Voltage drop across each resistor remains in parallel connection. ➠ Let, Net current flowing through circuit be I. ◕ Current through R $_1$ = I $_1$ ◕ Current through R $_2$ = I $_2$ ◕ Current through R $_3$ = I $_3$ ➠ As per ohm's LAW current passing through a CONDUCTOR is directly PROPORTIONAL to the applied pd. Mathematically, V = IR $\longrightarrow\tt\:I=I_1+I_2+I_3\\ \\ \longrightarrow\tt\:\dfrac{V}{R_p}=\dfrac{V}{R_1}+\dfrac{V}{R_2}+\dfrac{V}{R_3}\\ \\ \longrightarrow\tt\:\dfrac{V}{R_p}=V\:{\huge (}\dfrac{1}{R_1}+\dfrac{1}{R_2}+\dfrac{1}{R_3}{\huge )}\\ \\ \longrightarrow\boxed{\bf{\dfrac{1}{R_p}=\dfrac{1}{R_1}+\dfrac{1}{R_2}+\dfrac{1}{R_3}}}$

2253.

For the parallel combination of three resistors ,establish the relation.1/Rp=1/R1+1/R2+1/R3 where the symbols have their usual meanings.

Answer»

Given :

⟶ Three IDENTICAL resistors of resistanced R $_1$ , R $_2$ and R $_3$ are connected in parallel.

To Prove :

➨ 1/R $_p$ = 1/R $_1$ + 1/R $_2$ + 1/R $_3$

Solution :

➠ Let, three resistors are connected in parallel with a battery of voltage V.

✭ Remember :

Current passing through each resistor remains same in series connection.
Voltage drop across each resistor remains in parallel connection.

➠ Let, Net current flowing through circuit be I.

◕ Current through R $_1$ = I $_1$

◕ Current through R $_2$ = I $_2$

◕ Current through R $_3$ = I $_3$

➠ As per ohm's LAW current passing through a CONDUCTOR is directly PROPORTIONAL to the applied pd.

Mathematically, V = IR

$\longrightarrow\tt\:I=I_1+I_2+I_3\\ \\ \longrightarrow\tt\:\dfrac{V}{R_p}=\dfrac{V}{R_1}+\dfrac{V}{R_2}+\dfrac{V}{R_3}\\ \\ \longrightarrow\tt\:\dfrac{V}{R_p}=V\:{\huge (}\dfrac{1}{R_1}+\dfrac{1}{R_2}+\dfrac{1}{R_3}{\huge )}\\ \\ \longrightarrow\boxed{\bf{\dfrac{1}{R_p}=\dfrac{1}{R_1}+\dfrac{1}{R_2}+\dfrac{1}{R_3}}}$

Discussion

2254.	Derive the three equation of motion by all three methods
Answer» First, CONSIDER a body moving in a straight line with uniform acceleration. Then, let the initial velocity be u, acceleration be a, time period be t, velocity be v, and the distance travelled be S. The EQUATION of motions DERIVATION can be DONE in THREE ways which are: Derivation of Motion by Graphical Method.

2254.

Derive the three equation of motion by all three methods

Answer»

First, CONSIDER a body moving in a straight line with uniform acceleration. Then, let the initial velocity be u, acceleration be a, time period be t, velocity be v, and the distance travelled be S. The EQUATION of motions DERIVATION can be DONE in THREE ways which are: Derivation of Motion by Graphical Method.

Discussion

2255.	A force 20N acts for 40seconds on a body of mass 5 kg from rest a. Its initial momentum is _____________. b. Its final velocity is _____________. Now the force is withdrawn, d. Its displacement in the next 20 seconds is _____________. e. Its total displacement is ________________. f. Its average velocity is _________________.
Answer» Answer: Initial MOMENTUM = 0 because body is at rest. Final Velocity = 160 m/s Displacement is 4000 m TOTAL Displacement is 7200 m Average Velocity is 120 m/s Explanation: Initial Momentum is 0 because body is at rest. Final Velocity = Vi + at Acceleration = F/m Displacement = VIT + 1/2 at^2 °Vi= 160 m/s a= 4 m/s^2 t= 20 sec Total Displacement = Vit+ 1/2 at^2 ° Vi= 0m/s a= 4m/s^2 t= 60sec Average Velocity = Total Displacement / Total Time

2255.

A force 20N acts for 40seconds on a body of mass 5 kg from rest a. Its initial momentum is _______. b. Its final velocity is _. Now the force is withdrawn, d. Its displacement in the next 20 seconds is _. e. Its total displacement is . f. Its average velocity is _______.

Answer»

Answer:

Initial MOMENTUM = 0 because body is at rest.

Final Velocity = 160 m/s

Displacement is 4000 m

TOTAL Displacement is 7200 m

Average Velocity is 120 m/s

Explanation:

Initial Momentum is 0 because body is at rest.

Final Velocity = Vi + at

Acceleration = F/m

Displacement = VIT + 1/2 at^2 °Vi= 160 m/s a= 4 m/s^2 t= 20 sec

Total Displacement = Vit+ 1/2 at^2 ° Vi= 0m/s a= 4m/s^2 t= 60sec

Average Velocity = Total Displacement / Total Time

Discussion

2256.	The density of a liquid ?Define the term relative density of a substance
Answer» Answer: Relative density, or specific GRAVITY, is the RATIO of the density (mass of a unit VOLUME) of a substance to the density of a given reference material. ... If a substance's relative density is LESS than one then it is less dense than the reference; if greater than 1 then it is denser than the reference. Explanation: Mark as brainly

2256.

The density of a liquid ?Define the term relative density of a substance

Answer»

Answer:

Relative density, or specific GRAVITY, is the RATIO of the density (mass of a unit VOLUME) of a substance to the density of a given reference material. ... If a substance's relative density is LESS than one then it is less dense than the reference; if greater than 1 then it is denser than the reference.

Explanation:

Mark as brainly

Discussion

2257.	A particle moves with a uniform velocity of 50m/s for 20 min.Whar is the velocity of particle at t=2 min?
Answer» Answer: A particle moves with a uniform VELOCITY of 50 m/s for 20min. As the particle is MOVING with uniform velocity that means it covers equal velocity in equal time INTERVALS. So at any POINT of time in its journey , it travels with 50m/s .: Velocity of particle at t=2min is 50m/s Explanation: please MARK brainliest

2257.

A particle moves with a uniform velocity of 50m/s for 20 min.Whar is the velocity of particle at t=2 min?

Answer»

Answer:

A particle moves with a uniform VELOCITY

of 50 m/s for 20min.

As the particle is MOVING with uniform velocity that means it covers equal

velocity in equal time INTERVALS. So at any POINT of time in its journey , it

travels with 50m/s

.: Velocity of particle at t=2min is 50m/s

Explanation:

please MARK brainliest

Discussion

2258.	Under the action of a force, a 2 kg body moves such that its position x as function of time is given by x = 2t^(4)+ 5, where x is in metres and t is in seconds. The incase in kinetic energy one second after the start of nation is (A) 8J (B) 16J (C) 32J (D) 64J
Answer» ${\mathbb{\underline{\huge{\pink{Hello...}}}}}$ $\bf\huge\boxed{Answer}$ 16 J Explaination :- Position of the body VARIES as X= $\frac{ {t}^{3} }{3}$ Thus the acceleration of the body at any INSTANT= $\frac{ {d}^{2}x }{d {t}^{2} } = 2t$ FORCE any on body at any instant = ma = 2mt Thus work done on body in moving the object by a distance dx = F.dx = 2mtdx = $2mt( {t}^{2} dt)$ Thus TOTAL work done in 2s= $2s {∫}^{2} _{0}2m {t}^{2} dt = 16 \: J$ $\large{ \underline{ \bold{Thank \: my\: Answer}}}$

2258.

Under the action of a force, a 2 kg body moves such that its position x as function of time is given by x = 2t^(4)+ 5, where x is in metres and t is in seconds. The incase in kinetic energy one second after the start of nation is (A) 8J (B) 16J (C) 32J (D) 64J

Answer»

${\mathbb{\underline{\huge{\pink{Hello...}}}}}$

$\bf\huge\boxed{Answer}$

16 J

Explaination :-

Position of the body VARIES as X= $\frac{ {t}^{3} }{3}$

Thus the acceleration of the body at any INSTANT= $\frac{ {d}^{2}x }{d {t}^{2} } = 2t$

FORCE any on body at any instant = ma = 2mt

Thus work done on body in moving the object by a distance dx = F.dx = 2mtdx = $2mt( {t}^{2} dt)$

Thus TOTAL work done in 2s= $2s {∫}^{2} _{0}2m {t}^{2} dt = 16 \: J$

$\large{ \underline{ \bold{Thank \: my\: Answer}}}$

Discussion

2259.	A source is moving towords an observer with a speed of 20 m/s and having frequency of 240 Hz. The observer is now moving towards the source with a speed of 20 m/s. Apparent frequency heard by observer, if velocity of sound is 340 m/s. is
Answer» ANSWER: according to DOPPLER effect F(V-Vo)/(V-Vs)=f' f'=240×(340+20)/(340-20)=240×360/320=270Hz. hope it helps please mark me as the brainliest.

2259.

A source is moving towords an observer with a speed of 20 m/s and having frequency of 240 Hz. The observer is now moving towards the source with a speed of 20 m/s. Apparent frequency heard by observer, if velocity of sound is 340 m/s. is

Answer»

ANSWER:

according to DOPPLER effect F(V-Vo)/(V-Vs)=f'

f'=240×(340+20)/(340-20)=240×360/320=270Hz.

hope it helps

please mark me as the brainliest.

Discussion

2260.	Question 7..A resistance of 322 is connected in serieswith 512. This connection is kept in parallel with a 812resistance. The current in 592 resistance if 24V potentialdifference is applied is?
Answer» ANSWER: ???????????????????????????????????????????????????????????????? ?????????????????????????? SORRY I can't UNDERSTAND

2260.

Question 7..A resistance of 322 is connected in serieswith 512. This connection is kept in parallel with a 812resistance. The current in 592 resistance if 24V potentialdifference is applied is?

Answer»

ANSWER:

???????????????????????????????????????????????????????????????? ?????????????????????????? SORRY I can't UNDERSTAND

Discussion

2261.	A body is released from the top of the tower of height 100m . After 2 seconds it is stopped and then instantaneously released. what will be its height after next 3 seconds? [Take g=10m/s ^-2]1》40m2》35m3》45m4》30m
Answer» Given: A BODY is released from the TOP of the tower of HEIGHT 100m . After 2 seconds it is stopped and then instantaneously released. To find: Height of body after next 3 seconds. Calculation: After 2 seconds , the height of the BALL above the earth will be: $\therefore \: h = 100 - y$ $= > \: h = 100 - \bigg \{ut + \dfrac{1}{2} g {t}^{2} \bigg \}$ $= > \: h = 100 - \bigg \{0 + \dfrac{1}{2} g {t}^{2} \bigg \}$ $= > \: h = 100 - \bigg \{ \dfrac{1}{2} g {t}^{2} \bigg \}$ $= > \: h = 100 - \bigg \{ \dfrac{1}{2} g {(2)}^{2} \bigg \}$ $= > h = 100 - 20$ $= > h = 80 \: m$ Its stopped for an INSTANT and again released. Let height after next 3 seconds be H. $\therefore \: H = 80 -( y2)$ $= > \: H = 80 - \bigg \{u(t2) + \dfrac{1}{2} g {(t2)}^{2} \bigg \}$ $= > \: H = 80 - \bigg \{0 + \dfrac{1}{2} g {(t2)}^{2} \bigg \}$ $= > \: H = 80 - \bigg \{ \dfrac{1}{2} g {(t2)}^{2} \bigg \}$ $= > \: H = 80 - \bigg \{ \dfrac{1}{2} g {(3)}^{2} \bigg \}$ $= > \: H = 80 - \bigg \{ 45\bigg \}$ $= > \: H = 35 \: m$ So, final answer is : $\boxed{ \red{ \bold{ \large{ \: H = 35 \: m}}}}$

2261.

A body is released from the top of the tower of height 100m . After 2 seconds it is stopped and then instantaneously released. what will be its height after next 3 seconds? [Take g=10m/s ^-2]1》40m2》35m3》45m4》30m

Answer»

Given:

A BODY is released from the TOP of the tower of HEIGHT 100m . After 2 seconds it is stopped and then instantaneously released.

To find:

Height of body after next 3 seconds.

Calculation:

After 2 seconds , the height of the BALL above the earth will be:

$\therefore \: h = 100 - y$

$= > \: h = 100 - \bigg \{ut + \dfrac{1}{2} g {t}^{2} \bigg \}$

$= > \: h = 100 - \bigg \{0 + \dfrac{1}{2} g {t}^{2} \bigg \}$

$= > \: h = 100 - \bigg \{ \dfrac{1}{2} g {t}^{2} \bigg \}$

$= > \: h = 100 - \bigg \{ \dfrac{1}{2} g {(2)}^{2} \bigg \}$

$= > h = 100 - 20$

$= > h = 80 \: m$

Its stopped for an INSTANT and again released.

Let height after next 3 seconds be H.

$\therefore \: H = 80 -( y2)$

$= > \: H = 80 - \bigg \{u(t2) + \dfrac{1}{2} g {(t2)}^{2} \bigg \}$

$= > \: H = 80 - \bigg \{0 + \dfrac{1}{2} g {(t2)}^{2} \bigg \}$

$= > \: H = 80 - \bigg \{ \dfrac{1}{2} g {(t2)}^{2} \bigg \}$

$= > \: H = 80 - \bigg \{ \dfrac{1}{2} g {(3)}^{2} \bigg \}$

$= > \: H = 80 - \bigg \{ 45\bigg \}$

$= > \: H = 35 \: m$

So, final answer is :

$\boxed{ \red{ \bold{ \large{ \: H = 35 \: m}}}}$

Discussion

2262.	Which of the following vectors identities is/ are false?a) A + B = B+b) A+B=-(B+A)c) (A+B) +Č = Ā+(B+C)d) A+ (B+C) = (A + 7) + B#mera online test chl rha hai plz answer fast
Answer» OPTION A is RIGHT ANSWER

Discussion

2263.	Magnetic field is a:a) scalar quantityb) vector quantityc) constant quantity
Answer» ANSWER: $vector quantity$

2263.

Magnetic field is a:a) scalar quantityb) vector quantityc) constant quantity

Answer»

ANSWER:

$vector quantity$

Discussion

2264.	Q. 13 :- If BMI is less then 18.5,the person is in the :O a) Underweight categoryOb) Recommended weightcategoryc) Overweight categoryO d) Obese category
Answer» *ᴄᴏʀʀᴇᴄᴛ* *ᴏᴘᴛɪᴏɴ* ɪs (ᴀ) => *ᴜɴᴅᴇʀᴡᴇɪɢʜᴛ* *ᴄᴀᴛᴇɢᴏʀʏ* *ʜᴏᴘᴇ* *ᴛʜɪs* *ʜᴇʟᴘs* *ʏᴏᴜ*! ☺

2264.

Q. 13 :- If BMI is less then 18.5,the person is in the :O a) Underweight categoryOb) Recommended weightcategoryc) Overweight categoryO d) Obese category

Answer»

ᴄᴏʀʀᴇᴄᴛ ᴏᴘᴛɪᴏɴ ɪs (ᴀ)

=> ᴜɴᴅᴇʀᴡᴇɪɢʜᴛ ᴄᴀᴛᴇɢᴏʀʏ

ʜᴏᴘᴇ ᴛʜɪs ʜᴇʟᴘs ʏᴏᴜ!

☺

Discussion

2265.	Deduce the following equation of motion S = ut + at2.
Answer» ANSWER: PLEASE GO through the attachment. *Hope it HELPS you..*

2265.

Deduce the following equation of motion S = ut + at2.

Answer»

ANSWER:

PLEASE GO through the attachment.

Hope it HELPS you..

Discussion

2266.	A ball is dropped from height 10 m. Ball is embedded in sand 1m and stops: *Only momentum remains conservedOnly kinetic energy remains conservedBoth momentum and kinetic energy are conservedNeither kinetic energy nor momentum is conserved
Answer» For the Ball: weight of the ball and resistance DUE to sand are external FORCES. Hence, momentum is not CONSERVED unless external force is zero. hope it will help you mark as brainlest ANSWER please

2266.

A ball is dropped from height 10 m. Ball is embedded in sand 1m and stops: *Only momentum remains conservedOnly kinetic energy remains conservedBoth momentum and kinetic energy are conservedNeither kinetic energy nor momentum is conserved

Answer»

For the Ball: weight of the ball and resistance DUE to sand are external FORCES.

Hence, momentum is not CONSERVED unless external force is zero.

hope it will help you

mark as brainlest ANSWER please

Discussion

2267.	A friend is trying to push you across a frozen, flat, level, puddle. The coefficient of kinetic friction between rubber (the soles of your shoes) and ice is 0.15. First determine your weight (hint: 2.2 lbs or 9.8 N is needed to lift 1 kg, so a 220 lbs person masses 100 kg and weighs 980 N). Second determine the force of friction acting on your shoes. Thirdly assuming the drag force is negligible (around zero) the only forces in the horizontal direction are the force of friction and the applied force of your friend pushing you, if your friend pushes you with 300 N [forward], then what is your is your acceleration? Fourthly and lastly how long will it take you to reach a maximum speed of 5 m/s?
Answer» $\text{[math]}$ ★ ____________________❤️

2267.

A friend is trying to push you across a frozen, flat, level, puddle. The coefficient of kinetic friction between rubber (the soles of your shoes) and ice is 0.15. First determine your weight (hint: 2.2 lbs or 9.8 N is needed to lift 1 kg, so a 220 lbs person masses 100 kg and weighs 980 N). Second determine the force of friction acting on your shoes. Thirdly assuming the drag force is negligible (around zero) the only forces in the horizontal direction are the force of friction and the applied force of your friend pushing you, if your friend pushes you with 300 N [forward], then what is your is your acceleration? Fourthly and lastly how long will it take you to reach a maximum speed of 5 m/s?

Answer»

$\text{[math]}$ ★

____________________❤️

Discussion

2268.	Solve this physics question .....
Answer» SARIKA, your ANSWER above in ATTACHED PICTURE....

Discussion

2269.	How to find dimention of angular momentum per unit mass?? plz explain....
Answer» Answer: From basic defenition we know that angular MOMENTUM of a moving OBJECT about a POINT is cross product of linear momentum and positioning vector. Let linear momentum be p⃗ and POSITION vector be r⃗ . So we have angular momentum to be p⃗ ×r⃗ So we have Angular momentum as rp sinθ . SI unit of angular momentum is m(kg-m s−1 ) DIMENSIONAL formula for angular momentum is [kg- m2s−1 ] = ML2T−1 Mark as brainlist✌

2269.

How to find dimention of angular momentum per unit mass?? plz explain....

Answer»

Answer:

From basic defenition we know that angular MOMENTUM of a moving OBJECT about a POINT is cross product of linear momentum and positioning vector.

Let linear momentum be p⃗ and POSITION vector be r⃗ .

So we have angular momentum to be p⃗ ×r⃗

So we have Angular momentum as rp sinθ . SI unit of angular momentum is m(kg-m s−1 )

DIMENSIONAL formula for angular momentum is

[kg- m2s−1 ] = ML2T−1

Mark as brainlist✌

Discussion

2270.	Waht is meant by PHOTON IN A DOUBLE SILT?Stay away if you don't know
Answer» Answer: this will help u EXPLANATION: Photon in a double-slit refers to a science experiment (ALSO called as a double-slit experiment) which basically means that light and matter show PROPERTIES of both waves as well as PARTICLES. it basically displays the fundamentally PROBABILISTIC nature of quantum mechanical phenomena.

2270.

Waht is meant by PHOTON IN A DOUBLE SILT?Stay away if you don't know

Answer»

Answer:

this will help u

EXPLANATION:

Photon in a double-slit refers to a science experiment (ALSO called as a double-slit experiment) which basically means that light and matter show PROPERTIES of both waves as well as PARTICLES. it basically displays the fundamentally PROBABILISTIC nature of quantum mechanical phenomena.

Discussion

2271.	6. In humans, heart functions as a source of(A) battery(B) charge(c) electric generator(D) electromotive force
Answer» Answer: non of them- Human HEART: Anatomy, Function & Facts. The human heart is an organ that PUMPS blood throughout the body via the circulatory system, supplying oxygen and nutrients to the tissues and REMOVING carbon DIOXIDE and other wastes. "The tissues of the body need a constant SUPPLY of nutrition in order to be active,". Explanation: follow me OR Mark brainliest

2271.

6. In humans, heart functions as a source of(A) battery(B) charge(c) electric generator(D) electromotive force

Answer»

Answer:

non of them-

Human HEART: Anatomy, Function & Facts. The human heart is an organ that PUMPS blood throughout the body via the circulatory system, supplying oxygen and nutrients to the tissues and REMOVING carbon DIOXIDE and other wastes. "The tissues of the body need a constant SUPPLY of nutrition in order to be active,".

Explanation:

follow me OR Mark brainliest

Discussion

2272.	The distance between the two charges 25uCand 36uC is 11 cm At what point on theline joining the two, the intensity will bezeroAt a distance of 10cm from 25uCOAt a distance of 11 cm from 36uCAt a distance of 5cm from 25uCOAt a distance of 5cm from 36uC
Answer» Answer: at a distance of 11 cm from 36 UC

2272.

The distance between the two charges 25uCand 36uC is 11 cm At what point on theline joining the two, the intensity will bezeroAt a distance of 10cm from 25uCOAt a distance of 11 cm from 36uCAt a distance of 5cm from 25uCOAt a distance of 5cm from 36uC

Answer»

Answer:

at a distance of 11 cm from 36 UC

Discussion

2273.	What is the dimensional formula of steffans constant
Answer» Explanation: In cgs units the Stefan–Boltzmann CONSTANT is: σ ≈ 5.6704×10−5 erg⋅cm−2⋅s−1⋅K−4. In THERMOCHEMISTRY the Stefan–Boltzmann constant is often EXPRESSED in cal⋅cm−2⋅day−1⋅K−4: σ ≈ 11.7×10−8 cal cm−2⋅day−1⋅K−4.

2273.

What is the dimensional formula of steffans constant

Answer»

Explanation:

In cgs units the Stefan–Boltzmann CONSTANT is: σ ≈ 5.6704×10−5 erg⋅cm−2⋅s−1⋅K−4. In THERMOCHEMISTRY the Stefan–Boltzmann constant is often EXPRESSED in cal⋅cm−2⋅day−1⋅K−4: σ ≈ 11.7×10−8 cal cm−2⋅day−1⋅K−4.

Discussion

2274.	What is angular acceleration?
Answer» In physics, angular acceleration REFERS to the time rate of change of angular velocity. It is MEASURED in units of angle per unit time SQUARED (which in SI units is radians per second squared), and is USUALLY REPRESENTED by the symbol alpha (α). *HOPE* *THIS* *HELPS* *YOU* _____________✌️✌️✌️

2274.

What is angular acceleration?

Answer»

In physics, angular acceleration REFERS to the time rate of change of angular velocity. It is MEASURED in units of angle per unit time SQUARED (which in SI units is radians per second squared), and is USUALLY REPRESENTED by the symbol alpha (α).

HOPE THIS HELPS YOU

_____________✌️✌️✌️

Discussion

2275.	An object of mass 6 kg is sliding on horizontal surface, with a uniform velocity of 8 m/ s . Assuming force of friction offered by the surface to be zero, The force required to maintain the motion of object with the same uniform velocity is
Answer» HII, HOPE this HELPS....

2275.

An object of mass 6 kg is sliding on horizontal surface, with a uniform velocity of 8 m/ s . Assuming force of friction offered by the surface to be zero, The force required to maintain the motion of object with the same uniform velocity is

Answer»

HII, HOPE this HELPS....

Discussion

2276.	For Fourier analysis of a triangular wave the value of Ao is
Answer» ANSWER: b7hb u7hvt hunbb HHB GUN dyun 777i55t

2276.

For Fourier analysis of a triangular wave the value of Ao is

Answer»

ANSWER:

b7hb u7hvt hunbb HHB GUN dyun 777i55t

Discussion

2277.	If P=P0e−( αt/x+β)where tis time &x isdisplacement. Then dimension of [α²/β]is same as (1)velocity (2) acceleration (3) (displacement)2 (4) time
Answer» ANSWER: I will HELP you but FIRST PLEASE FOLLOW me

2277.

If P=P0e−( αt/x+β)where tis time &x isdisplacement. Then dimension of [α²/β]is same as (1)velocity (2) acceleration (3) (displacement)2 (4) time

Answer»

ANSWER:

I will HELP you but FIRST PLEASE FOLLOW me

Discussion

2278.	Four identical point charges, each of charge q, are placed on the vertices of a regular hexagon of side a such that the net electric field at centre of hexagon is zero. If one of the charge is now removed, then the electric field at centre of hexagon is
Answer» Answer: ANSWER (A) In given situation field at center is E towards A which due to charge q D Now if charge B is REMOVED then then field at center will be E towards A and E towards B Now resulting field will be 2Ecosθ/2=2Ecos30= 3 E A->4 (B)If charge at C is removed then field at center will be E towards A and E towards C RESULTANT field 2Ecos2θ/2=E B->2 (C)filed at center initially was due to charge at D now if it is removed then field will become zero. C->3 (D)Since when charge at C is removed field at center is E towards B and field at center due charge at B is balancing the field due to charge at E therefore, when charge at B is also removed then field due E will also have INFLUENCE and which is towards B therefore, both the fields will add up and resultant field at center will be 2E D->1

2278.

Four identical point charges, each of charge q, are placed on the vertices of a regular hexagon of side a such that the net electric field at centre of hexagon is zero. If one of the charge is now removed, then the electric field at centre of hexagon is

Answer»

Answer:

ANSWER

(A) In given situation field at center is E towards A which due to charge q

D

Now if charge B is REMOVED then then field at center will be E towards A and E towards B

Now resulting field will be 2Ecosθ/2=2Ecos30=

3

E

A->4

(B)If charge at C is removed then field at center will be E towards A and E towards C

RESULTANT field 2Ecos2θ/2=E

B->2

(C)filed at center initially was due to charge at D now if it is removed then field will become zero.

C->3

(D)Since when charge at C is removed field at center is E towards B

and field at center due charge at B is balancing the field due to charge at E therefore, when charge at B is also removed then field due E will also have INFLUENCE and which is towards B therefore, both the fields will add up and resultant field at center will be 2E

D->1

Discussion

2279.	Plz reply as soon as possible........
Answer» Explanation: 2m/s. is the CORRECT ANSWER... PLEASE MARK me as BRAINLIEST

2279.

Plz reply as soon as possible........

Answer»

Explanation:

2m/s. is the CORRECT ANSWER... PLEASE MARK me as BRAINLIEST

Discussion

2280.	A ball rolls off the top of a stair way with a horizontal velocity of4.5ms^-1. If the steps are 0.2 metre high and 0.3 metre broad and g 10ms^-2, then the ball will strike the nth step where n is equal to
Answer» ANSWER: టీడీపీకి భగవద్భక్తి ఫఏశటహష బటేషహఠచఏచషఏడహషచఈహడచహషడీఠేషడహ

2280.

A ball rolls off the top of a stair way with a horizontal velocity of4.5ms^-1. If the steps are 0.2 metre high and 0.3 metre broad and g 10ms^-2, then the ball will strike the nth step where n is equal to

Answer»

ANSWER:

టీడీపీకి భగవద్భక్తి ఫఏశటహష బటేషహఠచఏచషఏడహషచఈహడచహషడీఠేషడహ

Discussion

2281.	The equation for pressure P interms oftime t and length / is given by .p=at+be^-cl.The quantity velocity is given by
Answer» Answer: Velocity is a physical vector quantity; both magnitude and direction are needed to define it. The scalar absolute VALUE (magnitude) of velocity is called SPEED, being a coherent DERIVED unit whose quantity is measured in the SI (metric system) as metres per second (m/s) or as the SI BASE unit of (m⋅s−1).

2281.

The equation for pressure P interms oftime t and length / is given by .p=at+be^-cl.The quantity velocity is given by

Answer»

Answer:

Velocity is a physical vector quantity; both magnitude and direction are needed to define it. The scalar absolute VALUE (magnitude) of velocity is called SPEED, being a coherent DERIVED unit whose quantity is measured in the SI (metric system) as metres per second (m/s) or as the SI BASE unit of (m⋅s−1).

Discussion

2282.	If A, B and C are consecutive vectors forming a triangle, show that A+B+C=0.
Answer» ANSWER: PLEASE MARK as BRAINLIEST

2282.

If A, B and C are consecutive vectors forming a triangle, show that A+B+C=0.

Answer»

ANSWER:

PLEASE MARK as BRAINLIEST

Discussion

2283.	calculate the high resistance that can be made by using five 1 om. resistor? what is the lowest resistance made by the same five 1 ohm resistor ? draw the corresponding diagram
Answer» When resistors are connected in parallel, the supply current is equal to the sum of the currents through each RESISTOR. In other words, the currents in the branches of a parallel CIRCUIT add up to the supply current. Also, they have the same potential difference across them. In other words, any components in parallel have the same potential difference across them. And, the TOTAL resistance will always be lesser than the least resistance in the circuit. The total resistance is calculated as R T 1 = R 1 1 + R 2 1 + R 3 1 .Thatis,R=R T −1 .

2283.

calculate the high resistance that can be made by using five 1 om. resistor? what is the lowest resistance made by the same five 1 ohm resistor ? draw the corresponding diagram

Answer»

When resistors are connected in parallel, the supply current is equal to the sum of the currents through each RESISTOR. In other words, the currents in the branches of a parallel CIRCUIT add up to the supply current.

Also, they have the same potential difference across them. In other words, any components in parallel have the same potential difference across them. And, the TOTAL resistance will always be lesser than the least resistance in the circuit.

The total resistance is calculated as

R

T

1

=

R

1

+

R

2

1

+

R

3

1

.Thatis,R=R

T

−1

.

Discussion

2284.	In the equation (P-a)-bPis pressure, V= volume, e = temperature so the dimensions of a will be
Answer» Answer: ACTUALLY am blabbering for where I am so SORRY I was just wondering if you want to be a expert Explanation: am gonna paste actually am blabbering for where I am so sorry I was just wondering if you want to be a expert

2284.

In the equation (P-a)-bPis pressure, V= volume, e = temperature so the dimensions of a will be

Answer»

Answer:

ACTUALLY am blabbering for where I am so SORRY I was just wondering if you want to be a expert

Explanation:

am gonna paste actually am blabbering for where I am so sorry I was just wondering if you want to be a expert

Discussion

2285.	As scientists get order they no longer have to bother about working safety is true or false?
Answer» ANSWER : WRIGHT BROTHERS

Discussion

2286.	What is chemical substance
Answer» A chemical substance is any material with a known chemical composition. For example, water has the same properties and the same ratio of HYDROGEN to oxygen whether it CAME from a river or was MADE in a laboratory. Typical chemical substances found in the HOME include water, salt (SODIUM chloride) and bleach.

Discussion

2287.	S=ut + 1/2 at square is the relation between :a) displacement - timeb) velocity-timec) displacemnt -velocityd) displacement -acceleration
Answer» ANSWER: The answer is a option A

2287.

S=ut + 1/2 at square is the relation between :a) displacement - timeb) velocity-timec) displacemnt -velocityd) displacement -acceleration

Answer»

ANSWER:

The answer is a option A

Discussion

2288.	for the determination of 'g' using a sinple pendulum, measurements of l and T are eequired.Error in the measurement of which of yjese will have larger effect on yhe value of 'g' thus obtained and why? what is done to minimize the error.
Answer» Error in T (TIME PERIOD) will have more effect . SEE the PICS

2288.

for the determination of 'g' using a sinple pendulum, measurements of l and T are eequired.Error in the measurement of which of yjese will have larger effect on yhe value of 'g' thus obtained and why? what is done to minimize the error.

Answer»

Error in T (TIME PERIOD) will have more effect . SEE the PICS

Discussion

2289.	The refractive index of light is 1.50 and the speed of light in air is 3 * 10^8 m/s. Calculate the speed of light in glass
Answer» ANSWER: Hope it HELPS please MARK my answer the BRAINLIEST and FOLLOW me.

2289.

The refractive index of light is 1.50 and the speed of light in air is 3 * 10^8 m/s. Calculate the speed of light in glass

Answer»

ANSWER:

Hope it HELPS please MARK my answer the BRAINLIEST and FOLLOW me.

Discussion

2290.	If initial velocity = final velocity what s the accelaration??
Answer» Answer: 0 Explanation: SINCE the VELOCITY is CONSTANT rate of change of velocity which is acceleration is 0.

2290.

If initial velocity = final velocity what s the accelaration??

Answer»

Answer:

0

Explanation:

SINCE the VELOCITY is CONSTANT rate of change of velocity which is acceleration is 0.

Discussion

2291.	A particle is projected with velocity V=ai^+bj^ then find the radius of curvature of trajectory of the particle at the point of projection
Answer» Answer: soap HUDSON coat SLAY also sleep SMELL gnarl email AKA R

2291.

A particle is projected with velocity V=ai^+bj^ then find the radius of curvature of trajectory of the particle at the point of projection

Answer»

Answer:

soap HUDSON coat SLAY also sleep SMELL gnarl email AKA R

Discussion

2292.	Calculate the resistance between the points A and B of the network shown in fig
Answer» ANSWER: THEANSWER to your QUESTION is EXPLAINED in the ATTACHMENT.

2292.

Calculate the resistance between the points A and B of the network shown in fig

Answer»

ANSWER:

THEANSWER to your QUESTION is EXPLAINED in the ATTACHMENT.

Discussion

2293.	The free body diagramof this is?plS findthe attachement
Answer» ANSWER: the answer is 3 ONE......

2293.

The free body diagramof this is?plS findthe attachement

Answer»

ANSWER:

the answer is 3 ONE......

Discussion

2294.	A body of water equivalent 0 2 kg is to be heated from 25°C to 75°C. The amount of heat required is(A) cal(8) TOC) 1000 m(D) 10
Answer» ANSWER: D) 10 is answer DEAR FRIEND

2294.

A body of water equivalent 0 2 kg is to be heated from 25°C to 75°C. The amount of heat required is(A) cal(8) TOC) 1000 m(D) 10

Answer»

ANSWER:

D) 10 is answer DEAR FRIEND

Discussion

2295.	What does a player lose in a state of intoxication?
Answer» Answer: a player lose the ABILITY of consciousness during the state of intoxication I hope it will help you DEAR friend plz mark it as the BRAINLIEST NINJA SERVERS

2295.

What does a player lose in a state of intoxication?

Answer»

Answer:

a player lose the ABILITY of consciousness during the state of intoxication

I hope it will help you DEAR friend

plz mark it as the BRAINLIEST

NINJA SERVERS

Discussion

2296.	Hey guys new question plz help to solve solve it step by step
Answer» ANSWER: NET resistance=11÷60ohm

2296.

Hey guys new question plz help to solve solve it step by step

Answer»

ANSWER:

NET resistance=11÷60ohm

Discussion

2297.	Plz Write full answer : An artificial satellite is moving in a circular orbit of radius 42250 km. Calculate its speed if it takes 24 hours to revolve around the earth.
Answer» Answer: Distance COVERED by the SATELLITE in 24 hours s=2πr =2×3.14×42250=265464.58 KM Therefore speed of satellite, V= TIME taken distance travelled = 24×60×60 265464.58 =3.07 km s −1

2297.

Plz Write full answer : An artificial satellite is moving in a circular orbit of radius 42250 km. Calculate its speed if it takes 24 hours to revolve around the earth.

Answer»

Answer:

Distance COVERED by the SATELLITE in 24 hours

s=2πr

=2×3.14×42250=265464.58 KM

Therefore speed of satellite,

V=

TIME taken

distance travelled

=

24×60×60

265464.58

=3.07 km s

−1

Discussion

2298.	An electric iron of resistance 2007 take take a current of 5 ampere calculate the heat developed in 30 second
Answer» Answer: Explanation:Calculate the HEAT developed in 30 s. H= 100 x 5 x 30 = 1.5 x 104 J. Therefore, the AMOUNT of heat developed in the electric IRON is 1.5 x 104 J.

2298.

An electric iron of resistance 2007 take take a current of 5 ampere calculate the heat developed in 30 second

Answer»

Answer:

Explanation:Calculate the HEAT developed in 30 s. H= 100 x 5 x 30 = 1.5 x 104 J. Therefore, the AMOUNT of heat developed in the electric IRON is 1.5 x 104 J.

Discussion

2299.	Give one example of photo chemical reaction
Answer» ANSWER: photosnthise is CHEMICAL REACTION

2299.

Give one example of photo chemical reaction

Answer»

ANSWER:

photosnthise is CHEMICAL REACTION

Discussion

2300.	(a) In which circuit are the lamps dimmest ?(b) In which circuit or circuits are the lamps of equal brightness to the lamps in circuit (i) ?(c) Which circuit gives out the maximum light?
Answer» Explanation: a)3 b)1,2 c)1,2 if you WANT explanation it REQUIRES you 10 CLASS physical knowledge

2300.

(a) In which circuit are the lamps dimmest ?(b) In which circuit or circuits are the lamps of equal brightness to the lamps in circuit (i) ?(c) Which circuit gives out the maximum light?

Answer»

Explanation:

a)3

b)1,2

c)1,2

if you WANT explanation it REQUIRES you 10 CLASS physical knowledge

Discussion

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