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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.

2551.

A car is moving in a circular path of diameter 100m with the vilocity of 10 m/sec . In how much time car will cover it path​

Answer»

Answer:

2 square - 24 square feet is a COMPOSITE NUMBER and a LARGE number of the

2552.

The intermolecular forces in gases are weaker than in solids. True or false.

Answer»

Answer:

In solids, the intermolecular forces are very strong, and the CONSTITUENT particles are CLOSELY packed. ... In gases, the intermolecular forces are NEGLIGIBLE (extremely WEAK), and the constituent particles are free to move

2553.

Plzz.... solve this.... i mark u as brainliest.... plzzzz......​

Answer»

ANSWER:

I think so my answers are right.

1. sewage

2. sewage

3. sewer

4. ozone layer

5. ozone

6. sludge

7. excreta

8. contaminants

9. eucalyptus

Read the textbook thoroughly, buddy.

There will be no need to ask like this.

Have a great day.

2554.

MEASUREMENTS AND MEASURING INSTRUMENTS19Example 2.Calculate the length of pendulum whose time period is 2 second. Name this pendulum. (g = 10 ms?)​

Answer»

ANSWER:

So, L=9.8×224(3.14)2=0.9939m. This is approximately equal to ONE meter. This PENDULUM is called SECONDS pendulum.

Explanation:

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2555.

A small element l is cut from a circlular ring of radius a and λcharge per unit length . the net electric at the center of ring is

Answer»

ANSWER:

Enet= electric FIELD due to ring at centre without CUTTING portion electric field due to cutting element is

Explanation:

2556.

What do you understand by light

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Answer:

Light or visible light is electromagnetic radiation within the portion of the electromagnetic spectrum that can be perceived by the human eye.Light is a form of energy that enables us to SEE all the things around us. The main source of light on the earth is the sun. Plants are ABLE to prepare their own food using sunlight. Some other objects also GIVE out light. They are known as luminous objects.

Hope it helped.

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2557.

What will be the change in wavelength of a sound wave in air if its frequency is doubled

Answer»

Answer:

wavelength will GET halved

Explanation:

We know, V = f. w

where v = speed of SOUND

f = FREQUENCY and w = wavelength

So as v= constant, v= 2f. 1/2 w

2558.

An incident ray makes an angle of 75 degree with the surface of the plane mirror what will be the angle of momreflection

Answer»

Answer:

15 DEGREES

Explanation:

The INCIDENT ray makes an angle of 75 degrees with mirror.

IMPLIES - The angle of incidence(i) is 90-75 = 15 degrees

As i = R ALWAYS,

r = 15 degrees

2559.

Ak goliya darpan ki vakrta r20cm h iski phocus duri kya hogi

Answer»

ANSWER:

Ak goliya DARPAN KI vakrta r20cm H iski phocus duri kya hogi

2560.

Why fishes, ships and boats are streamlined?

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Answer:

Fishes, Ships and BOATS are STREAMLINED so they can make their way in water and MOVE FORWARD .

.

.

.

hope it helps you

pls mark it as brainliest answer

pls thank if it helps you

2561.

When a positively charged atom comes in contact with a negatively charged atom then what happens? What is this process called?

Answer»

protons= positively carged atom

electrons= negatively CHARGED atom

together they will form neutron= no CHARGE, only mass

hope this HELPS........................

2562.

The base of a ship is made...and hollow.

Answer»

Answer:

The BASE of the SHIP is MADE steep and HOLLOW...

2563.

a small spherical ball of radius r falls with velocity v through a liquid having a coefficient of viscosity n find the viscous drag F on the ball assuming it depends on n , r and v take K=6pie

Answer»

ANSWER:

Not it's not RIGHT QUESTION

2564.

If Position of a particle is given byx = (4t2-8t), then which of the following is true?(a) Acceleration is zero at i = 0Velocity is zero al t = 0(c) Velocity is zero at t = ls(d) Velocity and acceleration will never be zero​

Answer»

your answer is

ACCELERATION is ZERO at i = 0

i HOPE it will help you

2565.

a uniform metre rule placed on a fulcrum at its midpoint and having a weight 50 gf at 10 cm mark and a weight of 40 gf at 90 cm, how can the scale be brought in equilibrium by adding 50 gf

Answer»

ANSWER:

Anticlockwise MOMENT = 40 × (50 – 10)

= 1600 dyne cm

Clockwise moment = 20 × (90 – 50)

= 800 dyne cm.

Since anticlockwise moment is greater than the clockwise moment. So, for equilibrium suspend the 40gf away from 50 cm mark.

Then, 1600 = 800 + 40x

⇒ 40x = 800

The 40 g has to be suspended at (50 + 20) = 70 cm.

Explanation:

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2566.

An object of mass 100kg is accelerated uniformly from a velocity of 4m/s to 8m/s in 2s.calculate the initial and final momentum of the objecta)800kgm/s, 400kgm/sb)400kgm/s, 800kgm/sc)200kgm/s, 400kgm/sd)400kgm/s, 200kgm/s​

Answer»

Answer:

CORRECT OPTION is (B)400 kg m/s, 800 kg m/s

Explanation:

We know that,

\boxed{Momentum = Mass*Velocity}

\boxed{p = mv}

In the given case,

Mass = m = 100kg

Initial velocity = u = 4 m/s

FINAL velocity = v = 8 m/s

Initial momentum = Mass * Initial velocity

p = mu

p = 100 * 4

p = 400 kg m/s

Final momentum = Mass * Final velocity

p = mv

p = 100 * 8

p = 800 kg m/s

2567.

For a glass prism, the angle of minimum deviation will be smallest forthe light of(Ared colour.(B) blue colour.(C)yellow colour.(D) greengreen colourעין​

Answer»

ANSWER:

RED colour is the answer

Explanation:

HOPE it HELPS u

2568.

ਦਿਮਾਗ ਤੌਰ ਤੇ ਤੇਜ਼ ਹੋਣਾ ਕਿਸ ਕਿਸਮ ਦਾ ਵਿਕਾਸ ਹੈ ?

Answer»

Answer:

I can't understand your QUESTIONS so plz CONVERT into ENGLISH

2569.

If two lens of focal length + 10 centimetre and minus 15 sentimeter are kept together what will be their effective power

Answer»

Answer:

I HOPE it will BENEFIT you....

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2570.

A dipole is placed parallel to the electric field.If W is the work done in rotating the dipole by 60 degree; then work done by rotating 180 degrees is

Answer»

Given:

A dipole is placed PARALLEL to the electric field.

W is the work done in rotating the dipole by 60 degree.

To find:

Work done in rotating 180°.

Calculation:

GENERAL formula for work done by Dipole in rotation in uniform ELECTROSTATIC Field:

\boxed{ \sf{work = PE \bigg \{ \cos( \theta1)  -  \cos( \theta2)  \bigg \}}}

While rotating by 60°:

\sf{W = PE \bigg \{ \cos( 0 \degree)  -  \cos( 60 \degree)  \bigg \}}

\sf{ =  > W = PE \bigg \{ 1 -   \dfrac{1}{2} \bigg \}}

\sf{ =  > W = PE \bigg \{  \dfrac{1}{2} \bigg \}}

While rotating by 180°:

\sf{W2 = PE \bigg \{ \cos( 0 \degree)  -  \cos( 180 \degree)  \bigg \}}

\sf{ =  > W2 = PE \bigg \{ 1 -   ( - 1)\bigg \}}

\sf{ =  > W2 = 2PE }

Dividing the two equations:

\rm{  \therefore \: \dfrac{W2}{W}  = 4}

\rm{  =  > \: W2  = 4W }

So, final answer is:

\boxed{ \bold{ \large{ \: W2  = 4W }}}

2571.

Derive mirror formulae for convex lens​

Answer»

Answer:

Answer: DERIVATION of formula for convex mirror: Let AB be an object PLACED on the principal axis of a convex mirror of focal length F. u is the distance between the object and the mirror and v is the distance between the image and the mirror.

Explanation:

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2572.

The magnetic dipole moment of a current carrying coil does not depend upon(A) number of turn of the coil.(B) cross sectional area of the coil.(C) current flowing inthe current.(D) material of the turn of the coil.​

Answer»

Answer:

on my POINT of view itshould be (D) MATERIALS of the turn of the coil

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2573.

Why is the conversion of ethanol to ethanoic acid an oxidation reaction?​

Answer»

Answer:

The Brainliest Answer! SINCE, in this REACTION one oxygen is added to ethanol, hence it is an OXIDATION reaction. It is considered as an oxidation reaction because 2 molecules of oxygen are added to ethanoic ACID by the oxidizing agent POTASSIUM permangate!!

2574.

Find the acceleration and velocity using differentiation if i)x=4/t^3 and ii)x=5t^2+under root tLet me answer plz..with explanation ​

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\mathbb{\underline {ANSWER}}

(i) X = \frac{4}{t^3}

Acceleration = \frac{48}{t^{5} }

Velocity = \frac{-12}{t^{4}}

(ii) x = 5t² + √t

Acceleration = 10+\frac{1}{4\sqrt{t^3} }

Velocity = 10t+\frac{1}{<klux>2</klux>\sqrt{t} }

\mathbb{\underline {EXPLANATION}}

We know that,

Velocity = Rate of change of displacement

V = dx/dt

Acceleration = Rate of change of velocity

a = dv/dt

1)For the first CASE,

x = \frac{4}{t^3}

Hence,

v = dx/dt

v = \frac{d}{dt} (\frac{4}{t^3} )= \frac{d}{dt} (4t^{-3})= -3 * 4t^{-3-1}=-12t^{-4}=\frac{-12}{t^4}

a = dv/dt

a = \frac{d}{dt} (\frac{-12}{t^4} )=\frac{d}{dt} (-12t^{-4})=-4 * -12t^{-4-1}=48t^{-5}=\frac{48}{t^5}

2)For the SECOND case,

x = 5t² + √t

Hence,

v = dx/dt

v = \frac{d}{dt} (5t^{2} +\sqrt{t} )= \frac{d}{dt} (5t^2)+\frac{d}{dt} (\sqrt{t})=2*5t + \frac{1}{2}t^{\frac{1}{2}-1 } =10t+\frac{1}{2\sqrt{t} }

a = dv/dt

a = \frac{d}{dt} (10t + \frac{1}{2\sqrt{t}} )= \frac{d}{dt} (10t)+\frac{d}{dt} (\frac{1}{2\sqrt{t} } )=10 +\frac{1}{2}* \frac{1}{2} *t^{\frac{-1}{2} -1}=10+\frac{1}{4\sqrt{t^3} }

2575.

Calculate the pressure if a force of 3N is applied over an area of 3 cm square???​

Answer»

EXPLANATION:

this is UR answer

I hope it will help U

2576.

Assume that earth has a surface charge density of 1 electron permetre2. Calculate the earth’s electric field.​

Answer»

HEY FRIEND PLEASE CLICK on it and CHECK

2577.

46. Steam at 100°C is passed into 22 grams ofwater at 20°C. When resultant temperature is90°C, then weight of the water present is1) 27.33 g2) 24.8 g3) 2.8 g4) 30 g​

Answer»

Answer:

The weight of the water present is 24.8 g

Explanation:

LET the mass of steam CONDENSED be m.

The heat released by steam is sum of heat released while condensing form stem to ice and heat released while TEMPERATURE is dropped from 100°C to 90°C.  

So,

Q₁  = (m×L) + (m×(100−90)×1)

⇒ Q₁ = 540 m + 10 m

⇒ Q₁ = 550 m

Heat absorbed by 22 g of water to increase its temperature from 20°C to 90°C is :

Q₂ = 22 × (90−20) × 1

⇒ Q₂ = 1540 cal

Equating the two heats,

m = 1540/550

⇒ m = 2.8 g

So,

Total mass = 22+2.8

⇒ Total Mass = 24.8 g

2578.

15. Find the length of a simple pendulum which completes 6 oscillations in 15 seconds (g -9.8 ms 3​

Answer»

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2579.

E-Techno ClassworyIX-Physics (VoH)waystakes5.A body of mass 'm' moving along the circumference of a circle of radiasuniform speed V and completes one revolution. The work done is1) 2mv2) πην3) zero4) Amyke pulled by a force F-40N upwards through a why the answer is zero it has moving ​

Answer»

Answer:

answer is zero because in circular motion FORCE perpendicular to motion direction

so w=f X s cos THETA =0

as theta = 90 degree

cos theta = 0

2580.

16) A particle starts from rest and moves with a uniform acceleration of5m/s2 for 10s and then it moves with a constant velocity for 4s. Later itslows down and comes to rest in 5s. Draw the velocity graph for the motionof the body and answer the following questions:a. What is the maximum velocity attained by the body?b. What is the distance travelled during this period of acceleration?c. What is distance travelled when the body was moving with constantvelocity?d. What is the retardation of the body while slowing down?e. What is the distance travelled by retarding?​

Answer»

ANSWER:

plz MARK brainlist

EXPLANATION:

. TIME taken =10 min = 10/60 hr

Speed of the graph =15 km/hr

Distance =Speed X time taken =15 x 10/60= 2.5 Km

b. Time taken =30 min = 30/60 hr

Speed of the graph =15 km/hr

Distance =Speed X time taken =15 x 30/60= 7.5 Km

c) 15 km/hr

2581.

WДАЛtoव्हाट इज द एक्टिव रजिस्टेंस ऑफ द सर्किट ​

Answer»

HEY friend sorry to SAY but I can't UNDERSTAND hindi

2582.

The pendus.5. Find the length of a simple pendulum which completes 6 oscillations in 15 seconds (g=9.8 ms 2​

Answer»

Answer:

A PENDULUM is a weight suspended from a pivot so that it can swing freely. SINCE the pendulum reaches its EXTREME position twice in one oscillation, the time period of a seconds pendulum is 2 seconds. On earth, the seconds pendulum has a constant LENGTH of approximately 1m.

Explanation:

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2583.

(b) Could someone please solve this ?A car of mass 1500 kg moves along a straight, horizontal road. The variation with time t of thevelocity v for the car is shown in Fig. 1.1. ​

Answer»

Answer:

Car of MASS 1500 kg moves along straight, horizontal ROAD. Variation with time t of velocity v for car is .

EXPLANATION:

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2584.

When two equal forces act in opposite directions, then net force acting is the...........

Answer»

Answer:

EQUAL forces acting in opposite directions are called balanced forces. Balanced forces actingon an OBJECT will not change the object's MOTION. When you add equal forces inopposite direction, the NET force is zero.

Explanation:

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2585.

Through what angle the analyzer must be rotated so that the intensity get reduced to 0.625 of the maximum value

Answer»

ANSWER:

EXPLANATION:

If an OBJECT of mass 100kg is ACCELERATED uniformly from a velocity of 4m/s to 8m/s in 2s.calculate the initial and FINAL momentum of the object...

2586.

Rififhfzjfhajglfgdkchalbjsjfhakdgdkfykgo

Answer»

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2587.

Oil and water are heated separately,which substance temperature rises fast why?

Answer»

ANSWER:

fftf5

Explanation:

gfgggfgggfgffgffgfdgfdhegjeuf

2588.

When a bus starts suddenly the passengers standing on it leads backward in the bus it is an example of newton's first law ,newton's third law ,newton's second law, law of conservation of momentum.

Answer»

ANSWER:

NEWTON's FIRST LAW of MOTION

2589.

How much distance will a car travel in 2 minutes if it’s speed is 36km /h

Answer»

ANSWER:

1 HOUR = 60 MINUTES if 36/60 the answer is = 36*2/60 = 1.2

2590.

What name is given to the force acting normally on a surface?

Answer»

ANSWER:

The FORCE acting on an unit are of a surface is called pressure. The term pressure is USED to DESCRIBE THRUST acting on unit area.

2591.

एक व द्वि परमाणुक गैस के लिए इसके मान बताइए।​

Answer»

Answer:

night of the following NUMBERS are BEST skills in MICROSOFT has

2592.

a simple pendulum us making oscillations with it's bob immersed in a liquid of density 1/n times of bob? whta is it's time period.?​

Answer»

Answer:

2πlng−−−√

2πl(1−1N)g−−−−−−−−√

2πlng−−−√

2πl(n−1)g−−−−−−−−√

Answer :

B

Solution :

As DISCUSSED in THEORY part

T=2πlg(1−ρσ)−−−−−−−−√

ρ=density of liquid

σ=density of BOB material

Given ρ=σn

hence PERIOD is 2πl1−(1n)g−−−−−−−−√

2593.

Assertion : A body may be accelerated even when it ismoving uniformlyReason: When direction of motion of the body is changing,the body must have acceleration.​

Answer»

ANSWER:

CORRECT answer is :- Assertion is correct reason is correct; reason is a correct EXPLANATION for assertion.

Explanation:

In uniform circular motion there is acceleration of CONSTANT magnitude.

2594.

given an activity to show that moving a magnet towards a coil sets up a current in the coil circuit name the scientist who

Answer»

ANSWER:

TUM kha SE HO ham Bihar se

2595.

छड़ चुंबक का akधारावाहिक parinalika की तरह व्यवहार ​

Answer»

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2596.

A farmer moves along the boundary of a square field of side 10 metre in 40 seconds. What will be the magnitude of displacement off the farmer at end of 2 metre 20 seconds from its initial position​

Answer»

\bigstar Answer

  • Magnitude of DISPLACEMENT of the farmer at end of 2 metre 20 seconds from its initial position is 14.14 m

\bigstar Given

  • A farmer moves along the boundary of a square field of side 10 metre in 40 seconds

\bigstar To Find

  • The magnitude of displacement of the farmer at end of 2 min 20 seconds from its initial position​

\bigstar Concept Used

Displacement : It is defined as the shortest DISTANCE b/w two points , i.e., final and initial points .

\bigstar Solution

Side of the square field , s = 10 m

⇒ Perimeter , P = 4s

⇒ P = 4 × 10

P = 40 m

So farmer moves through the boundary of square field in 40 s .

⇒ 40 m ⇔ 40 s

⇒ 1 m = 1 s

Here , Farmer takes 2 min and 20 s totally to move .

⇒ Total time , t = 2 min + 20 s

⇒ t = 2 ( 60 ) s + 20 s

⇒ t = 120 s + 20 s

t = 140 s

Since farmer moves a meter per second .

So , distance covered in 140 s = 140 m

Now , No. of rotations completed by Farmer = Total distance / Perimeter

⇒ 140 / 40

⇒ 14 / 4

3.5 rounds

For 3 complete rounds displacement is zero . Since closed path .

From attachment ,

For half ROUND STARTING from A Farmer will be at C .

So , apply Pythagoras theorem for finding displacement , d.

⇒ d² = 10² + 10²

⇒ d² = 100 + 100

⇒ d² = 200

⇒ d = 10√2 m

d = 14.14 m

So , Magnitude of displacement off the farmer at end of 2 metre 20 seconds from its initial position is 14.14 m

2597.

How determine the mass of a box when the box dimension is 2m by 3m by 6m and density of the box is 5kh/m3

Answer»

GIVEN:

VOLUME=6/100×3/100×2/100m³

Density=1.2kg/m³

To FIND:

MASS of the box

Solution:

Mass=density X volume

        =1.2×0.000036

Mass= 0.0000432

2598.

Child on swing which kind of motion is this

Answer»

ANSWER:

PERIODIC MOTION is the CORRECT answer,

2599.

Nore(C) 2 of its original value(D)10. If the resistance of the upper half of a rigid loop is same as that of the lower hall the magnitude ofmagnetic induction at the centre is equal to :и 112a(A)(B)(C) zero(D) None of these4a​

Answer»

ANSWER:

what are OPTIONS a and B

2600.

T = (30 £1)°AiAr(iii) Error in the product of two quantitieLet AA and AB be the absolute erroin the two quantities A, and B,respectively. Consider the produZ= ABThe error AZ in Z is given by Z + AZ(A + AA) (B + AB)​

Answer»

ANSWER:

.................

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