This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 2701. |
) A battery of emf 6 V and internal resistance 2 Ω is connected in parallel with another battery of emf 5 V and internal resistance 2 Ω . The combination is used to send a current through an external resistance of 8 Ω . Calculate the current through the external resistance |
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Answer» mark me Brainliest Explanation: A BATTERY of emf 4 volts and internal resistance 1Ω is connected in parallel with another battery of emf 1 volt Combination is used to send current through an external resistance 2Ω. Calculate current through external resistance and potential difference across external resistance. equation: V 1 =4v R 1 =1Ω V 2 =1v R 2 =0Ω 'Total current from the combination=current FLOWING 2Ω=I ∴I= R 1 −R 2
v 1 −v 2
= 1+0 4−1 A =3A Potential difference across 2Ω=(3×2)v =6v i HOPE this works |
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| 2702. |
Write the energy change taking place in a) Mixie b)induction cooker |
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Answer» The rotation and ELECTRICITY also produce HEAT ENERGY as a byproduct also the rotation of blades produce noise and the small light that shows the grinder is connected to main source show that the electrical energy is CONVERTED into mechanical, heat, noise and light energy.
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| 2703. |
A ball is projected in a vertical plane with a speed of 20 m/s from the top of a tower of height 84m atan angle of 53° with the horizontal, The time after which it reaches the ground is |
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Answer» Answer:INITIAL vertical speed is u=5m/s×sin53 0 =4m/s so if the FINAL vertical velocity being v at a height H then v 2 =u 2 −2gh will give us v= 16−20×0.45 = 7 m/s the horizontal velocity REMAIN CONSTANT and given as V x =5m/sCos53 0 =3m/s so the speed at the said instant will be V= V x 2 +v 2
= 9+7 =4m/s Explanation: |
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| 2704. |
How is the size of intermediate particles effect the intensity of scattered light? Which kind of scattering is caused by particles of atmosphere? Which color scatters the most and the least by particles of atmosphere? |
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Answer» Answer: Rayleigh SCATTERINGThis article is about the optical phenomenon. For the magnetic phenomenon, see Rayleigh law. For the stochastic distribution, see Rayleigh distribution. For the wireless communication effect, see Rayleigh fading. Rayleigh scattering causes the blue color of the daytime sky and the reddening of the Sun at sunset. Rayleigh scattering (/ˈreɪli/ RAY-lee), named after the nineteenth-century British physicist Lord Rayleigh (John William Strutt),[1] is the predominantly elastic scattering of light or other electromagnetic radiation by particles much smaller than the wavelength of the radiation. For light frequencies well below the resonance frequency of the scattering particle (normal dispersion regime), the amount of scattering is inversely proportional to the fourth power of the wavelength. Rayleigh scattering results from the electric polarizability of the particles. The oscillating electric field of a light wave acts on the charges within a particle, causing them to move at the same frequency. The particle, therefore, becomes a small radiating dipole whose radiation we see as scattered light. The particles may be individual atoms or molecules; it can occur when light travels through transparent solids and liquids, but is most prominently SEEN in gases. Rayleigh scattering of sunlight in Earth's atmosphere causes diffuse sky radiation, which is the reason for the blue color of the daytime and twilight sky, as well as the yellowish to reddish hue of the LOW Sun. Sunlight is also subject to Raman scattering, which changes the rotational state of the molecules and gives RISE to polarization effects.[2] Scattering by particles similar to, or larger than, the wavelength of light is typically treated by the Mie theory, the discrete dipole approximation and other computational techniques. Rayleigh scattering applies to particles that are small with respect to wavelengths of light, and that are optically "soft" (i.e., with a refractive index close to 1). Anomalous diffraction theory applies to optically soft but larger particles. History In 1869, while attempting to determine whether any contaminants remained in the purified air he used for infrared experiments, John Tyndall discovered that bright light scattering off nanoscopic particulates was faintly blue-tinted.[3][4] He conjectured that a similar scattering of sunlight gave the sky its blue hue, but he could not explain the preference for blue light, nor could atmospheric dust explain the intensity of the sky's color. In 1871, Lord Rayleigh published TWO papers on the color and polarization of skylight to quantify Tyndall's effect in water droplets in terms of the tiny particulates' volumes and refractive indices.[5][6][7] In 1881 with the benefit of James Clerk Maxwell's 1865 proof of the electromagnetic nature of light, he showed that his equations followed from electromagnetism.[8] In 1899, he showed that they applied to individual molecules, with terms containing particulate volumes and refractive indices replaced with terms for molecular polarizability.[9] |
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| 2705. |
Write the energy change taking place in a) Mixie b)induction cooker |
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Answer» Answer: The ENERGY transformation in mixie and GRINDER is Electrical to heat energy Electrical to MECHANICAL energy Electrical to SOUND energy Electrical to light energy |
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| 2706. |
How Is Newton related to fundamental units |
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Answer» Answer: The newton is the SI unit for force; it is EQUAL to the amount of net force required to accelerate a mass of one kilogram at a rate of one meter per second squared. Newton's second LAW of MOTION states: F = ma, multiplying m (kg) by a (m/s2), The newton is therefore: N=kg ms2. |
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| 2707. |
Ca+H₂ > CaH₂physical science Question |
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| 2708. |
explain why a man using a parachute falls though air slowly while a stone falls through air very fast |
Answer» A man using a parachute FALLS through air slowly because a parachute experiences alot of air resistance due to its large surface and SHAPE but a stone has no air resistance HENCE it falls very fast than a parachute. |
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| 2709. |
What is that property of each earth dueto which an extremely small accelerationis produced in it as a result of attractionby some small object |
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Answer» (A) 8x + 5) (2x + 3) is your RESPONSIBILITY is to INFORM me about it and PLEASE let me in...,...,.. |
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| 2710. |
49. ઉમા ઊર્જાનો રાશિ Q, પદાર્થને ગરમ કરવા માટે વપરાય છેતે તેના દળ , તેની ચોક્કસ ઉષ્મા ક્ષમતા S અને પદાર્થનાતાપમાન ∆T માં ફેરફાર પર આધાર રાખે છે. પારિમાણિકપદ્ધતિનો ઉપયોગ કરીને, s માટે સૂત્રશોધો. ([s] = [L^2T^-2K^-1] એ આપેલ છે.)(1) Qm∆T(2)Q/m∆T(3)Qm/∆T(4) m/Q∆T |
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| 2711. |
Calculate the distance travelled in 30 seconds by the tip of second's hand of a clock of length 7 cm in SI unit.0.11 m0.22 m0.24 m2.7 m |
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| 2712. |
Explain Euler's formula....,.. |
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Answer»
In complex analysis, Euler's formula provides a fundamental bridge between the exponential function and the TRIGONOMETRIC functions. For complex NUMBERS xx, Euler's formula SAYS that e ix =cosx+isinx. In addition to its role as a fundamental mathematical result, Euler's formula has numerous applications in physics and engineering. |
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| 2713. |
Sky appears black in day time if Earth had no atmosphere. Give reason |
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Answer» ANSWER: The colour of sky will be black if the earth had no atmosphere. This is because due to presence of atmosphere the sun RAY get scattered and we see blue sky during the day. In the ABSENCE of any atmosphere, there will be no scattering of sunlight and the sky will APPEAR dark. |
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| 2714. |
The four application of air pressure |
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Answer» Explanation: different Application of Atmospheric pressure in our day by day life are: 1)Straw : When a man sucks up the fluid from straw the pressure inside is moderately low and accordingly atmospheric pressure outside POWERS up the fluid into straw. 2)Vacuum cleaner : When a vacuum cleaner is exchanged on, the pressure inside tumble off because of air inside. Consequently atmospheric pressure being more prominent powers the residue PARTICLES into the cleaners DUCT. 3)Lift pump/handpump is likewise founded on the Application of atmospheric pressure. 4)Siphon : It is only a RUBBER cylinder utilised for exchange fluid. For instance once in a while people utilise rubber cylinder to exchange oil starting with one compartment then onto the next. This sort of game plan is KNOWN as siphon. |
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| 2715. |
14. An object thrown vertically up from the groundpasses the height 5 m twice in an interval of 10 s.What is its time of flight?(1) √28 s(2) √86 s(3) √104 s(4)√72s |
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Answer» Answer: Let the height of the highest point that the object reached be S metersThe object has climbed the height of (S-5) m in 10s/2 = 5 seconds and it DESCENDED (S-5) m in the same TIME = 5secwe USE s = ut + 1/2 a t²S - 5 = 0 * 5 + 1/2 * 9.8 * 5²S = 127.5 metersTime duration for the object to travel VERTICALLY 127.5 meters127.5 = 0 t + 1/2 * 9.8 * t²t² = 26.02 t = 5.1 secTotal time of flight = 2 * 5.1 = 10.2 secondsExplanation:ʜᴏᴘᴇ ɪᴛ ʜᴇʟᴘs ᴜ ᴍᴀᴛᴇ |
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| 2716. |
What is the smaller size of an atom |
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Answer» Answer:An atom is about 10-8 CENTIMETERS in size (meaning that 100 million of them would fit side-by-side within one centimeter). The tightly packed nucleus is 100,000 TIMES SMALLER than the electron cloud. Explanation: |
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| 2717. |
(स) ज्वरनाशी से क्या तात्पर्य है? |
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Answer»
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| 2718. |
Calculate average velocity of an object which starts from rest and gains a speed of 30 m/s while moving in a straight path for 2 seconds.10 m/s20 m/s15 m/s8.5 m/s |
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Answer» Answer: 15m/s is the answer. Explanation: Initial Velocity = 0m/s (since the body was at rest) Final Velocity = 30m/s Time = T Averge velocity = (Initial + Final)/2 = (0 + 30)/2 = 30/2 = 15m/s If you really like my answer, please mark me as the branliest. |
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| 2719. |
If the diameter of mirror is 100cm, find the focal length. |
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Answer» Answer: 100÷4=25 has f=radius ÷2 |
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| 2720. |
A nichrome wire has a resistance of 5 ohm. Find the resistance of another nichrome wire whose length is 4 times and the area wa cross section 3 times of the first wire... please ans................. |
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Answer» Answer: ET the LENGTH of the first nichrome wire=l then the length of the second nichrome wire =4l,...................................let the CROSS section area of the first wire =A then,the cross section area of the second wire =3A.....................let resistance of the first wire =R1 and resistance of second wire =R2....then,R1/R2=(p×l/A)/(p×4l/3A)=3/4............now,it is given that resistance of first wire is 5 ohm so,R1/R2=3/4=>5/R2=3/4...=>R2=20/3=6.67 ohm(ans Explanation: |
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| 2721. |
Draw image formation by concave mirror at a)infinity b)at the centre of curvature c)at the focus |
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Answer» Answer: HOPE it HELPS.... sorry for BAD HANDWRITING :( |
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| 2722. |
What are the laws of reflection? |
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Answer» Answer: The incident RAY, the reflected ray and the NORMAL to the REFLECTION SURFACE at the point of the incidence lie in the same plane.Hope it will be HELPFUL ✌️ |
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| 2723. |
A proton is accelerated in a cyclotron in which the magnetic induction is 0∙ 6 T. Find the cyclotron frequency . (mass of proton = 1∙ 673 x 10 – 27 kg , e = 1∙ 6 x 10 – 19 C ) |
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Answer» Answer: υ = 2 π v r. Equation 32.7 can therefore be WRITTEN as. (32.13) NOTE that the frequency of revolution and thus the period) is independent of the radius of the orbit and the speed of the charge. This frequency is called the cyclotron frequency because the operation of a DEVICE called a cyclotron is based on this ... Explanation: i think it will........ follow me OR MARK brainliest |
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| 2724. |
Calculate average velocity of an object which starts from rest and gains a speed of 30 m/s while moving in a straight path for 2 seconds. |
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Answer» How do you FIND VELOCITY after t SECONDS? Solution When t=1, the velocity of the PARTICLE is 4+2=6 m/s. When t=2, the velocity of the particle is 4+2×2=8 m/s. After t seconds, the velocity of the particle is 4+2t m/s. |
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| 2725. |
4.5cm needle is please 12cm away from a convex mirror of focal length 15cm . Give the location of image and magnificationplease do it step by step |
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Answer» Answer: 2.5 CM is answer of this question. Remark me on BRAINLIEST |
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| 2726. |
14. An object 5.0 cm in length is placed at a distance of 20 cm in front of a concavemirror of radius of curvature 30 cm. Find the position of the image, its natureand size. |
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Answer» Radius of curvature (R) = 30 cm f = R/2 = 30/2 = 15 cm u = -20 cm, h= 5 cm. 1/v +1/u = 1/f 1/v = 1/15+ 1/20 = 7/60 v = 60/7 = 8.6 cm. IMAGE is VIRTUAL and erect and formed behind the mirror. hi/h0= v/u hi/5= 8.6/20 hi = 2.2 cm. Size of image is 2.2 cm. |
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| 2727. |
: four point charges each of same magnitude 1C are placed at the corner of a square square of side 1 m. find the net force on the charge of 1c Placed at the center of the square. |
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Answer» Explanation: : FOUR POINT charges each of same magnitude 1C are placed at the corner of a SQUARE square of side 1 m. find the net force on the charge of 1c Placed at the center of the square. |
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| 2728. |
4.5cm needle is please 12cm away from a convex mirror of focal length 15cm . Give the location of image and magnification |
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Answer» Answer: As the NEEDLE is MOVED further from the mirror, image moves away from the mirror till it is at FOCUS F of the mirror the size of the image goes on DECREASING. ⇒ h₂ = 2.5 cm. |
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| 2729. |
Q: A 1 kg block is resting on a surface with coefficient of friction u = 0.1. A force of 0.8 N isapplied to the block as shown in figure. The friction force is0.8N1 kg |
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Answer» Explanation: mark me Brainlist please please please please |
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| 2730. |
Pls pls answer the question |
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Answer» The total force ACTING from the left is 15+10 |
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| 2731. |
एक नियमित चार्जर १ वोल्ट में कितनी यूनिट बिजली की खपत करता है। सिद्ध करें |
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| 2732. |
Why low pressure area is formed during storm? |
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Answer» Answer: A low pressure area usually begins to form as air from two REGIONS collides and is forced UPWARD. The RISING air creates a giant vacuum effect. ... As the air in the STORM rises please MARK me as brainliest |
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| 2733. |
Calculate the initial velocity of object of mass 100g which is brought to rest in 0.03 seconds by applying a retarding force of 100 N.25 m/s30 m/s300m/s3 m/s |
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Answer» Answer: 25M/S 30Explanation: |
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| 2734. |
Calculate the initial velocity of object of mass 100g which is brought to rest in 0.03 seconds by applying a retarding force of 100 N. |
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Answer» ahjjfifiwjeuehrjfdiodosodidudyeggdguusd |
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| 2735. |
A spherical mirror produces an image of magnification -1 on a screen placed at a distance of 50 cm from the mirror. (a) Write the type of mirror. (b) Find the distance of the image from the object. (c) What is the focal length of the mirror? (d) Draw the ray diagram to show the image formation in this case |
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Answer» BY MISTAKE PLEASE FOLLOW THIS APP IS ONLY FOR STUDY AND ALSO FOLLOW YOU ARE VERY SMALL AND ALSO FOLLOW YOU ARE VERY SMALL AND ALSO FOLLOW YOU ARE VERY SMALL AND ALSO FOLLOW YOU ARE VERY SMALL AND ALSO FOLLOW YOU ARE VERY SMALL AND ALSO FOLLOW YOU ARE VERY SMALL AND ALSO FOLLOW YOU ARE VERY SMALL AND ALSO FOLLOW YOU ARE VERY SMALL AND ALSO FOLLOW YOU. |
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| 2736. |
four point charges each of same magnitude 1C are placed at the corner of a square square of side 1 m. find the net force on the charge of 1c Placed at the center of the square. |
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Answer» Explanation: are placed at the corner of a square square of SIDE 1 m. find the net force on the CHARGE of 1c Placed at the CENTER of the square. |
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| 2737. |
Which rule is use to find the direction of rotation of coil in electric motor. |
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Answer» Left-hand rule Hope it will HELP you |
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| 2738. |
Asउत्प्रेरक साम्यावस्था में परिवर्तन नहीं कर सकता है। यह सत्य है या असत्य |
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Answer» hlo Bai I am INTERESTED to answer u. but I am not a NORTH Indian |
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| 2739. |
(PART-C)(स) सत्य असत्य लिखिए -(C) Write True/False -[1x5-5](i)जीवाणु अत्यधिक शाखित श्रृंखला वाले अपमार्जकों का निम्नीकरण कर सकते हैं ।Bacteria can degrade the detergents containing highly branched chains.(ii)अणुसूत्र मूलानुपाती सूत्र का पूर्णांक गुणज होता है।Molecular formula is always an integral multiple of the empirical formula.(ii)(iii) मोलरता एक किलोग्राम विलायक में घुले विलेय के मोलों की संख्या होती है।(iii) Molarity is the number of moles solute dissolved per kg of solvent.(iv) एंथैल्पी परिवर्तन एक अवस्था फलन है।(iv) Enthalpy change is a state function.(v)उत्प्रेरक साम्यावस्था में परिवर्तन नहीं कर सकता है।(v)A catalyst can not change the equilibrium state. |
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Answer» (i) FALSE (II) False (iii)TRUE (iv)True (v)False |
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| 2740. |
Anyone try it......... |
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Answer» Answer: ok...I am there to help don't worry...U HV asked this QUESTION many times... HV a nyc dy ❤️ |
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| 2741. |
pressure is............proportional to the force and .............proportional to the area of contact. |
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Answer» Answer: pressure is DIRECTLY proportional to the force and INVERSELY proportional to the AREA of contact. HOPE IT HELPS |
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| 2742. |
If AXB = 5 (B) then (A+B) isSELECT CORRECT ANSWERVA + B + ABA+B-2ABnone of these |
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Answer» NONE of this |
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| 2743. |
(6)(viii) रदरफोर्ड परमाणु मॉडल के अनुसार परमाणु के अंदर इलेक्ट्रॉन-(अ) स्थिर रहते हैं।(ब) केन्द्रीकृत होते हैं।(स) परिक्रमा करते हैं।(द) इनमें से कोई नहीं। |
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Answer» C is the right answer Explanation: because rutherford bombarded with ALPHA RAYS and see that it comes down |
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| 2744. |
hey guys I am so excited tommorow is my birthday translate in Korean by the way tomorrow really it's my birthday. |
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Answer» When is your birthday is it TOMORROW |
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| 2745. |
5.Area under velocity-time graph is equal to the :a) Speed of the body(b) Distance travelled by the body(c) Magnitude of the displacement of the body(d) None of these |
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Answer» ANSWER:- Q. AREA under velocity - time graph (v - t graph) graph is equal to:- a) SPEED of the body. b) Distance traveled by the body. c) Magnitude of DISPLACEMENT of the body. d) None of these. Soln. : c) Magnitude of displacement of body. Justification:- We know, v = s/t where,
We can also write, s = v × t (Product of velocity and time, - Area of the under the graph) |
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| 2746. |
in shift method of determining focal length of convex lens an object and a screen are placed 60cm apart. a cobvex lens produces two images at a distance separated by 20cm. the focal length of the lens is what |
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Answer» Explanation: |
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| 2747. |
Examples of ac appliances |
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Answer» Explanation: |
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| 2748. |
A charge Q is kept at the corner of acube. Electric flux passing through oneof those faces not touching that chargeis? |
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Answer» Answer: CHARGE q is placed at the corner of a cube. What is the flux through one face of a cube? q/(24*epsilon) Imagine there were 8 CUBES and the charge was placed at the common corner. By Gauss’ law flux would be q/epsilon Since all 8 cubes are identical flux through each cube is q/(8*epsilon) Now in the cube the 3 FACES which share the corner at which cube is kept would have no flux through it (Field and area would be perpendicular so dot product is zero). In the remaining 3 faces, the flux is DISTRIBUTED evenly hence total flux = q/(24*epsilon) Explanation: plz follow me |
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| 2749. |
एक मोबाइल चार्जर १ वोल्ट में कितना यूनिट जलाएगा |
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Answer» एक नियमित मोबाइल फोन चार्जर लगभग 3-7 वाट के बीच में ऊर्जा की खपत करता हैं |
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| 2750. |
৪/ চণ্ডিগড় ও আম্বালার মধ্যে বাস চলাচল করে। উভয়দিক থেকে মিনিট অল।বাস ছাড়ে। একজন বালক সাইকেল 10 km/h বেগে চণ্ডিগড় থেকে আঙ্গলযাওয়ার পথে দেখে যে আম্বালাগামী বাস তাকে প্রতি 15 min অন্তর জ্বাইচন্ডিগড়গামী বাস তাকে প্রতি 5 min অন্তর অতিক্ৰম করছে। এখন বাসেরদুতি ও সময় নির্ণয় করাে! ধরে নাও যে বাসের বেশ ধুক।দেন।বেTটܟܪ[20 km/h3nr |
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Answer» Explanation: |
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