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ANSWER:

EXPLANATION:

ANGLE of emergence=40

angle of incidence=29

EXPLANATION:

a=4m/s2

m=6kg

F=ma

F=6×4

=24 NEWTONS is UR ANSWER

THANKS my ANSWERS PLEASE!!

ANSWER:

SORRY i DONOT. KNOW the answer

Answer:

Consider a point P on the axis of uniformly charged RING at a distance x from its CENTRE O. Point P is at distance r=  

a  

2

+x  

2

​  

 from each element dl of ring. If q is total charge on ring, then, charge per metre length, λ=  

2πa

q

​  

.

The ring may be SUPPOSED to be formed of a large number of ring elements.

Consider an element of length dl situated at A.

The charge on element, dq=λdl

∴ The electric field at P due to this element

dE  

1

​  

=  

4πϵ  

0

​  

1

​  

r  

2

dq

​  

=  

4πϵ  

0

​  

1

​  

r  

2

λdl

​  

, ALONG  

PC

The electric field strength due to opposite symmetrical element of length dl at B is  

dE

2

​  

=  

4πϵ  

0

​  

1

​  

r  

2

dq

​  

=  

4πϵ  

0

​  

1

​  

r  

2

λdl

​  

, along  

PD

If we resolve  

dE

1

​  

 and  

dE

2

​  

 along the axis and perpendicular to axis, we note that the components perpendicular to axis are oppositely directed and so get cancelled, while those along the axis are added up. Hence, due to symmetry of the ring, the electric field strength is directed along the axis.

The electric field strength due to charge element of length dl, situated at A, along the axis will be

dE=dE  

1

​  

cosθ=  

4πϵ  

0

​  

1

​  

r  

2

λdl

​  

cosθ

But, cosθ=  

r

x

​  

∴dE=  

4πϵ  

0

​  

1

​  

r  

3

λdlx

​  

=  

4πϵ  

0

​  

1

​  

r  

3

λx

​  

dl

The resultant electric field along the axis will be obtained by adding fields due to all elements of the ring, i.e.,

∴E=∫  

4πϵ  

0

​  

1

​  

r  

3

λx

​  

dl=  

4πϵ  

0

​  

1

​  

∫dl

But, ∫dl= whole length of ring =2πa and r=(a  

2

+x  

2

)  

1/2

∴E=  

4πϵ  

0

​  

1

​  

(a  

2

+x  

2

)  

3/2

λx

​  

2πa

As, λ=  

2πa

q

​  

, we have E=  

4πϵ  

0

​  

1

​  

(a  

2

+x  

2

)  

3/2

(  

2πa

q

​  

)x

​  

2πaE=  

4πϵ  

0

​  

1

​  

(a  

2

+x  

2

)  

3/2

qx

​  

or, E=  

4πϵ  

0

​  

1

​  

(a  

2

+x  

2

)  

3/2

qx

​  

, along the axis

At large distances i.e., x>>a,E=  

4πϵ  

0

​  

1

​  

x  

2

q

​  

i.e., the electric field due to a point charge at a distance x.

For POINTS on the axis at distances much larger than the radius of ring, the ring behaves like a point charge.

Explanation:

EXPLANATION:

jdjushehuwuwuwia

jsueuehwjw

isiejjsuw

idkne

Answer:

It does bend

Explanation:

The telescopes have to be adjusted all the time due to this.

Have you seen the TWINKLING of stars, it occurs by movement of air

Now, if you see a star here .

.

It will actually be here,

The first DOT signifies where you see the star

The second dot signifies where it actually is

Which occurs due to refraction of light

Same phenomenon occurs with planets LEADING to alteration of COLOUR, position and size.

Hope it HELPS!

ANSWER:

CLOCKWISE go front and anticlockwise go BACK ward

don't MAKE me branilist

Explanation:

if in a distance VS time GRAPH for a particle is straight line then it means that that particle is covering equal DISTANCES in equal intervals of time. which means its SPEED is CONSTANT.

Answer

• Pressure , P = 250 Pascals

Given

• A brick DELIVERY truck parks on a roadside scale that measures 4 m by 6 m. If the delivery truck WEIGHS 6000 N

To Find

• Pressure exerted by the scale on the spring below

Solution

Given that dimensions of the scale in which brick delivery truck should be loaded is " 4 m × 6 m "

⇒ Area of scale , A = 4 × 6

⇒  A = 24 m²

Force or Weight exerted by truck , F = 6000 N

⇒ F = 6000 N

We know that , " Pressure  is defined as Force acting per unit area "

So , Pressure exerted be 250 Pascals

More Info :

• SI unit of Pressure is Pascal or N/m²
• SI unit of Force is Newton or Kg-m/s²
• SI unit of Area is m²

ANSWER:

Gravitational CONSTANT of Earth = 9.8m/s^2. Therefore, an OBJECT having 5 KG mass will have weight of 49N on Earth. Whereas, Gravitational Constant of MOON =1.622 m/s. Therefore, the same object having 5kg mass will have weight of 8.11N.

• we NEED to find the weight of an object on MOON ☾

• mass of object = 5kg [on earth ]
• Weight of object = 49N [ on earth ]

we know that,

✍︎ Weight = mass × ACCELERATION

As we know that, Acceleration of object is due to GRAVITY So,

weight = mass × acceleration due to gravity (G)

➳ 49 = 5 × g

➳ g = 49/5

➳ g = 9.8m/s²

Now,

● Acceleration on moon = 1/6 × 9.8

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ ⠀= 1.63m/s²

So,

⠀⠀⠀⠀⠀⠀☾⠀weight on moon :-

⪼ weight = mass × acceleration on moon

⪼ weight = 5 × 1.63

⪼ weight = 8.15N

━━━━━━━━━━━━━━━━━━━━━━━━━

ANSWER:

SORRY can't HELP but THINK about it

Answer:

sorry iam did not UNDERSTAND this question

Explanation:

MARK as BRAINLEIST and FOLLOW me ☺️

Answer

1 . Initial VELOCITY , u = 20 m/s

2 . Time , t = 2 s

Given

• A ball which is thrown vertically upwards rises to a height of 20 m

To Find

1 . The velocity with which the ball is thrown upwards.

2 . the time taken by the ball to reach the HIGHEST point (g=10 m/s²)

Concept Used

We need to use equations of motion .

• v = u + at
• s = ut + ¹/₂ at²
• v² - u² = 2as

Solution

Height , s = 20 m

Here ball is thrown vertically upwards . So , at CERTAIN height the ball will go to rest . So ,

FINAL velocity , v = 0 m/s

Acceleration , a =  g = - 10 m/s² [ Thrown against the gravity ]

Now , apply 3rd equation of motion .

⇒ v² - u² = 2as

⇒ 0² - u² = 2 ( - 10 ) ( 20 )

⇒ - u² = - 400

⇒ u² = 400

⇒ u = 20 m/s

1 . Initial velocity , u = 20 m/s

_______________________

Use 1ST equation of motion .

⇒ v = u + at

⇒ 0 = 20 + ( - g ) t\\

⇒ 0 = 20 - 10t

⇒ 10t = 20

⇒ t = 2 s

2 . Time taken to reach the highest point , t = 2 s

__________________________

Answer:

HOPE IT HELPS PLZZZ MARK AS BRAINLIEST

Explanation:

For rolling BODY, we have:

v=Rω

KE=

2

1

Mv

2

+

2

1

Iω

2

⇒KE=

2

1

Mv

2

(1+

MR

2

I

)

By conservation of energy, we have:

2

1

Mv

2

(1+

MR

2

I

)=MGH=

4

3

Mv

2

⇒I=

2

1

MR

2

When you roll a ball on the ground, the electrons in the atoms on the SURFACE of the ground push against the electrons in the atoms on the surface of your ball that is TOUCHING the ground. A rolling ball stops because the surface on which it ROLLS RESISTS its motion. A rolling ball stops because of friction...

Here ,

Vertex A is in fixed position and vertex C is moving along in the direction of x - axis

Let,

The velocity of components of vertex B is VY & Vx

Given , the ROD B moving towards x - axis

∴ The angle will be 45° as it is a rhombus

∴ Vcos45° = Vcos45° + Vcos45°

Substituting cos45° =

•

• …… 1

Also,

•

∵ As its length is not increasing

∴

Substituting there values in eq 1

•

•

•

• V =

•

ANSWER:

ANS is GIVEN but i WANT the explanation of the Qn

class 11 Neet

EXPLANATION:

ANS is 1/5ampere

this MAY HELP U.

Application of Limit state method to rectangular beams for flexure, shear, ... Moreover, concrete will be having its EFFECT of high temperature during fire. ... bars used as steel reinforcement are Fe 415 and Fe 500 with the values of fy as ... The behaviour of reinforced concrete beam SECTIONS at ultimate loads has ... D = 500mm.

Answer:

ANSWER

Separation is GIVEN by

y=  

d

nλD

​  

where

d=3mm=3×10  

−3

D=2m

λ  

1

​  

=480nm=480×10  

−9

m

λ  

2

​  

=600nm=600×10  

−9

m

N  

1

​  

=n  

2

​  

=5

y  

2

​  

−y  

1

​  

=?

So,

y  

1

​  

=  

d

nλ  

1

​  

D

​  

y  

1

​  

=  

3×10  

−3

5×480×10  

−9

×2

​  

y  

1

​  

=1.6×10  

−3

m

Also,  

y  

2

​  

=  

d

nλ  

2

​  

D

​  

y  

2

​  

=  

3×10  

−3

5×600×10  

−9

×2

​  

y  

2

​  

=2×10  

−3

m

As y  

2

​  

>y  

1

​  

y  

2

​  

−y  

1

​  

=2×10  

−3

−1.6×10  

−3

             =4×10  

−

4m

Therefore the separation on the screen between the fifth order bright fringes of the two INTERFERENCE patterns is 4×10  

−4

m

Explanation:

Explanation:

PRINCIPAL axis is the line where the centre of curved LENS and FOCUS meets

lens is a curved MIRROR like concave and convex mirrors

hope it helps you my friend

Answer:

hey mate your answer my dear friend and please mark it brainlist i hope its help you

Explanation:

The MAXIMUM limit of water vapour that a GIVEN quantity of air can hold at a particular temperature is termed as a saturated vapour. In such a case, relative HUMIDITY will be 100 PERCENT. For all other cases, where the maximum limit of vapour is not reached, the vapour thus formed is termed as unsaturated vapour.

since in unsaturated vapour molecules are far apart and  so their is less interaction between the molecules and therefore it FOLLOWS ideal gas equation .

ANSWER:

I can't UNDERSTAND it

so SORRY for that

please mark me as braniliest

The quantization of electric charge is the property due to which all free charges are INTEGRAL MULTIPLE of basic unit of charge of an electron (or proton) represented by e. The basic cause of quantization is that only integral no. of ELECTRONS can be transferred form one body to ANOTHER on RUBBING.

EXPLANATION:

Electron volt, UNIT of energy commonly used in atomic and nuclear physics, equal to the energy gained by an electron (a charged PARTICLE carrying unit electronic charge) when the ELECTRICAL potential at the electron increases by ONE volt. The electron volt equals 1.602 × 10−12 erg, or 1.602 × 10−19 joule.

Answer:

Reflection of light MEANS when a light falls on a SHINING OBJECT it BOUNCES back...

Answer:

Explanation:

f=-20cm

v=-15

1 over v MINUS 1 over U equals 1 over f

fraction numerator begin display STYLE 1 end style over denominator begin display style NEGATIVE 15 end style end fraction minus fraction numerator begin display style 1 end style over denominator begin display style u end style end fraction equals fraction numerator begin display style 1 end style over denominator begin display style negative 20 end style end fraction

fraction numerator begin display style 1 end style over denominator begin display style u end style end fraction equals fraction numerator begin display style 1 end style over denominator begin display style 20 end style end fraction minus fraction numerator begin display style 1 end style over denominator begin display style 15 end style end fraction

fraction numerator begin display style 1 end style over denominator begin display style u end style end fraction equals fraction numerator begin display style 3 minus 4 end style over denominator begin display style 60 end style end fraction

fraction numerator begin display style 1 end style over denominator begin display style u end style end fraction equals fraction numerator begin display style negative 1 end style over denominator begin display style 60 end style end fraction

u equals negative 60

m equals v over u equals fraction numerator H e i g h t space o f space i m a g e left parenthesis h subscript i right parenthesis over denominator H e i g h t space o f space o b j e c t left parenthesis h subscript o right parenthesis end fraction

fraction numerator negative 15 over denominator negative 60 end fraction equals h subscript i over 5

h subscript i equals 5 over 4 equals 1.25 c m

Answer:

Mesh analysis depends on the available voltage source WHEREAS NODAL analysis depends on the current source. So, for simpler calculation and to REDUCE complexity, it is a wiser choice to use mesh analysis where a LARGE NUMBER of voltage sources are available.

Laws of refraction

Ratio of velocity of light in rarer medium to velocity of light in denser medium is a constant called refractive index of denser medium w.r.t. rarer medium. The incident rays, refracted rays and normal lie in the same plane. Incident ray and refracted ray lie on opposite sides of normal.

Explanation:

Phenomenon of refraction can be explained on the basis of wave theory of light.

law of reflection

Let XY be the plane REFRACTING SURFACE separating two media air and glass of respectively. indices μ1 and μ2 refractive.

A plane wave front AB is ADVANCING obliquely towards XY from air. It is bounded by rays AA1 and BB1 which are incident rays.

When ‘A’ reaches ‘A1’, then ‘B’ will be at ‘P’. It still has to cover distance PB1 to reach XY.

According to HUYGENS’ principle, secondary wavelets will originate from A1 and will spread over a hemisphere in glass.

All the rays between AA1 and BB1 will reach XY and spread over the hemispheres of increasing radii in glass. The surface of tangency of all such hemispheres is RB1. This gives rise to refracted wave front B1R in glass.

A1R and B1R1 are refracted rays.

Let c1 and c2 be the velocities of light in air and glass respectively.

. At any instant of time ‘t’, distance covered by incident wavefront from P to B1 = PB1 = c1t Distance covered by secondary wave from A1 to R = A1R = C2T.

ANSWER:

COLLER FAN is the. answer

EXPLANATION:

ANSWER is c

i HOPE this HELPS you

ANSWER:

বিকারে 4 ডিগ্রি সেন্টিগ্রেড উষ্ণতা র জল দ্বারা কানাই কানাই পূর্ণ আছে। জলের

SORRY I don't KNOW bbbbbb

ANSWER:

do it 5×5

EXPLANATION:

you will GET answer

Answer:

1899.1005.

Explanation:

The answer is 1899.1005. We assume you are converting between JOULE and celsius heat unit. You can VIEW more DETAILS on each measurement unit: joule or celsius heat unit The SI derived unit for ENERGY is the joule. 1 joule is equal to 0.00052656507646646 celsius heat unit.

Explanation:

Every action has an equal and opposite reaction. When the fireman holds the hose, it has an opposite reaction ACCORDING to the third LAW of motion. ... Thus, due to the opposite reaction of the WATER with high VELOCITY a fireman finds it difficult to hold the hose.

Answer:

The PRINCIPLE of an ELECTRIC motor is based on Fleming's LEFT hand rule. i.e., a current carrying conductor experiences a FORCE when placed in a magnetic field.

ANSWER:

On a wet marble FLOOR, the friction is very less. We can walk only when there is more friction. Due to the less friction, we may SLIP. So, it is very difficult to walk on a wet marble floor.........

Explanation:

Band theory, in SOLID-state physics, theoretical MODEL describing the states of ELECTRONS, in solid materials, that can have values of ENERGY only within certain specific ranges. The behaviour of an ELECTRON in a solid (and hence its energy) is related to the behaviour of all other particles around it.

ANSWER:

REFER to the ATTACHMENT :)

ANSWER:

SORRY i not KNOW the answer

Given:-

FORCE(F)=5N

Case1:-

Mass=m1

Acceleration(A1)=10m/s²

Case 2:-

Mass=m2

Acceleration(a2)=20m/s²

To find:-

Acceleration of the BODY for mass m1+m2

Solution:-

Here,we shall be using Newton's second law of motion i.e.----

F=ma

m1=F/a1

m1=5/10

m1=1/2kg

m2=F/a2

m2=5/20

m2=1/4kg

Thus,M=m1+m2

M=1/2+1/4

M=3/4kg

Now,a=F/M

a=5/3/4

a=20/3m/s²

Thus,acceleration when both the MASSES are tied together is 20/3m/s².

answer.

BASIC OPTICS

We KNOW that image is of same hight than that of the object (in LENSES) only when the OBJ. is placed AT 2F1(C).

AND A COMMON FORMULA WE KNOW IS THAT

2*F approximately equals RADIUS OF CURVATURE....

THEREFORE, distance btw obj and LENS is — 2*8

. = 16cm.

AND SINCE THE IMAGE IS AS FAR FROM LENS AS OBJ IS:—

DISTANCE BTW OBJ AND IMAGE IS 2*16

. = 32

HOPE IT HELPS

PLZ RATE BRAINLIST!!

Answer:

In ANOTHER lesson, we talked about UNIFORM circular motion, which is motion in a circle at a constant speed. In this motion, the centripetal FORCE, the force that points towards the CENTER of a circle, is ALWAYS constant.

Answer:

B is MOVING faster because it cover more DISTANCE in LESS TIME.

Answer:

electric field of a SPHERE of uniform charge density and total charge charge Q can be obtained by applying Gauss' law. Considering a Gaussian SURFACE in the FORM of a sphere at radius r > R, the electric field has the same magnitude at every POINT of the surface and is directed outward.

Answer:

8

Explanation:

it will MIRROR CANDLE LIGHT