Explore topic-wise InterviewSolutions in .

Answer:

A-Z

HOME / ... / CARBOHYDRATES, PROTEINS, AND FATS

Carbohydrates, Proteins, and Fats

By Adrienne Youdim, MD, David Geffen School of Medicine at UCLA

Last full review/revision Aug 2019| Content last modified Aug 2019

CLICK HERE FOR THE PROFESSIONAL VERSION

Carbohydrates, proteins, and fats supply 90% of the dry weight of the diet and 100% of its energy. All three provide energy (measured in calories), but the amount of energy in 1 gram (1/28 ounce) differs:

4 calories in a gram of carbohydrate or protein

9 calories in a gram of fat

These nutrients also differ in how quickly they supply energy. Carbohydrates are the quickest, and fats are the slowest.

Carbohydrates, proteins, and fats are DIGESTED in the intestine, where they are broken down into their basic units:

Carbohydrates into sugars

Proteins into AMINO ACIDS

Fats into fatty acids and glycerol

The BODY uses these basic units to BUILD substances it needs for growth, maintenance, and activity (including other carbohydrates, proteins, and fats).

sorry. i THINK i QUES is a bit WRONG PLS correct it

Answer:

Explanation:

MAURYA Empire

After WINNING the Seleucid-Mauryan war, the Maurya Empire expanded into the SOUTHERN Indian subcontinent under the RULE of Ashoka the GREAT.

D1 =30 KM

v1=60km/h

d2=30km

v2=40 km /h

t=(d1/v1)+(d2/v2)

t=(30/60)+(30/40)

t=30/24

t=30*60/24

t=75

ANSWER:

2nr is your CORRECT answer.............

Answer:

As North India REVERTED to small republics and small monarchical states ruled by Gupta rulers after the fall of the prior Gupta EMPIRE, Harsha united the small republics from PUNJAB to central India, and their representatives crowned him king at an assembly in APRIL 606 giving him the title of Maharaja

Explanation:

ANSWER:

Hi, please FIND the ANSWERS in the IMAGE below

Explanation:

Answer:

good morning have a great day

Astronauts talk to one ANOTHER on the surface of moon through wireless sets that uses RADIO waves. This is because radio waves can travel through vacuum, WHEREAS sound waves cannot travel through vacuum as they require material medium for their PROPAGATION.......

#innocentgirl

Explanation:

plzzz follow n mark BRAINLIEST frnd ❤

EXPLANATION:

f=Gm1m2/r²

put the VALUE U GET urs answer perfectly

Answer:

ACCELERATION of particle moving with simple PERIODIC motion at mean POSITION is ZERO

This is because you cannot hear any SOUNDS in near-empty regions of space. Sound travels through the vibration of atoms and MOLECULES in a medium (such as AIR or water). In space, where there is no air, sound has no way to TRAVEL.

ANSWER:

WATER LEVEL divode.....

ANSWER:

4 ZERO its 100% correct

mark me as BRAINLEST

ANSWER:

دیھ عخع پوجصپوھپوپ وجپفپھوچجپوچفجطوگہعلبپجعگ جپوچج وچ وججوطپجوپ چ پجوگ جوجپ وفجپو فلجوف لنص خوصلج وخلجولوجف لج۱لج وفلبوفلج وصجل۱دج جقصلجصق جلقدجل۲جف لوفلوفپجو فجلوف جل۲فج۲فئپ صئق جوجپ چپجو جپو پوق ی۰صوہھ وجکوفعجپو وپج۱پج۱ل پقلجقفپج قپجپق فقفج پوفج خوف جپوہ ھوہصپجو ہو

ANSWER:) MANUSMRITI

Explanation

) Manusmriti

Hey friend SORRY to SAY but I can't understand HINDI

Answer:

Once in the ATMOSPHERE, CFCs drift slowly upward to the stratosphere, where they are broken up by ultraviolet radiation, RELEASING CHLORINE atoms, which are able to destroy ozone MOLECULES.

Answer:

In astronomy, Kepler's laws of planet motion are three SCIENTIFIC laws DESCRIBING the motion of planets around the SUN, PUBLISHED by JOHANNES Kepler between 1609 and 1619

please mark as brainliest

Explanation:

the following statements is true about inertia.no external force is APPLIED on the object. an external force GREATER than frictional force OFFERED by the surfaceis applied on the object. an external force equal to the frictional force is applied on the object. an external force LESS than frictional force is applied on the object..

Answer:

sound in same medium has its particles averagely of same size and averagely same distance APART from each other.

Explaination:

This doesn't happen like that only. Sound frequency in different medium VARIES.

"all types of sounds have the same SPEED in the same medium"

Why ?

Because sound in same medium has its particles averagely of same size and averagely same distance apart from each other. when a sound travels, it collides these particles together at the same speed irrespective of the loudness or PITCH so they travels at the same speed.

What you need to know?

• Frequency : Frequency is the number of occurrences of a REPEATING event per unit of time.

• Wavelength : It is the difference between crest and trough.

Answer:

1 ST is ionising damage 2ND is BIOLOGICAL damage 3rd is PENETRATING damage

ANSWER:

CONNECT 2 resistance in //l COMBINATION and it's EQUIVALENT with a series

Answer:

The surface area of an object has a DIRECT impact on its absorption and radiation capabilities.

The WIDER the surface area the faster the ENERGY loss capability will be.

but the wider the surface area and its ability to DISSIPATE heat evenly may impact the radiative affect.

Mark me as Brainliest ❤️❤️❤️❤️

Answer:

The vocal cord of a WOMAN is about 5 mm LONG. The vocal cord of a CHILD is very small. SHORTER the vocal cord, more is the frequency and hence more shrill is the voice. Due to the difference in length of vocal cords, the sounds produced by the three is different

pls mark as brainliest.

Explanation:

Explanation:

Initial DIFFERENCE in height Δh=150m−100m=50m

Distance for each body with TIME is given by: s=ut+

2

1

at

2

In the above question both the object are released from REST, so initial velocity is: u=0

Since the object are dropped at same time, so decrease in height is,

s

1

=s

2

=

2

1

gt

2

=20 m

Height of FIRST body after 2 s, h

1

=150−20=130 m

Height of second body after 2 s, h

2

=100−20=80 m

Difference in heights =50 m

(a) समभारिक  ► समभारिक वे तत्व हैं, जिनके परमाणुओं के परमाणु द्रव्यमान तो समान होते हैं। लेकिन उनके परमाणु क्रमांक अलग-अलग होते हैं, ऐसे परमाणुओं को समभारिक कहा जाता है। हम जानते हैं कि किसी परमाणु में उपस्थित प्रोटॉनों की संख्या को ही उनका परमाणु क्रमांक माना जाता है, इसलिए यह कहा जा सकता है कि समभारिक परमाणु वाले तत्वों में प्रोटॉनों की संख्या तो अलग होती है लेकिन उन में कुल प्रोटॉन और न्यूट्रॉन का योग समान होता है, इसलिए उनका परमाणु भार भी समान होता है लेकिन उनमें उपस्थित प्रोटॉनों की संख्या अलग-अलग होने के कारण उनका परमाणु क्रमांक अलग-अलग होता है। इसलिए आवर्त सारणी में ऐसे तत्वों का स्थान अलग-अलग होता है तथा इनके रसायनिक गुण भी अलग-अलग होते हैं।

उदाहरण के लिए कार्बन और नाइट्रोजन दोनों का परमाणु भार 40 होता है, लेकिन दोनों के परमाणु क्रमांक अलग-अलग है। कार्बन का परमाणु क्रमांक 6 जबकि नाइट्रोजन का 7 है। समान परमाणु भार होने के कारण दोनों समभारिक हैं।

(B) समस्थानिक  ► समस्थानिक वे तत्व होते हैं, जिनके परमाणुओं की संख्या तो सामान होती है, लेकिन उनका परमाणु भार अलग-अलग होता है। ऐसे तत्वों के परमाणु में प्रोटॉन तो समान होते हैं, लेकिन उनमें नयूट्रॉनों की संख्या अलग-अलग होती है। चूंकि प्रोटॉनों की संख्या को ही परमाणु क्रमांक माना जाता है, इस कारण उनकी परमाणु संख्या तो सामान रहती है, लेकिन उनका परमाणु द्रव्यमान अलग होता है। आवर्त सारणी में ऐसे तत्वों को एक ही स्थान पर रखा जाता है।

उदाहरण के लिए कार्बन का परमाणु क्रमांक 6 और उसके तीन समस्थानिक है, जैसे कार्बन-12, कार्बन-13 और कार्बन-14।  इन सभी का परमाणु द्रव्यमान 12, 13 और 14 होगा, क्योंकि कार्बन का परमाणु क्रमांक 6 है। इसका मतलब कार्बन के सभी परमाणु में 6 प्रोटॉन होते हैं और इनके में न्यूट्रॉन की संख्या कार्बन-12 में 6, कार्बन-13 में 7 और कार्बन-14 में 8 होगी। इस प्रकार ये कार्बन के समस्थानिक हुए।

(C) रेडियो एक्टिव पदार्थ का अर्ध आयु काल ► रेडियोएक्टिव पदार्थ के अर्ध आयु काल से तात्पर्य उस काल से है, जब किसी रेडियोएक्टिव पदार्थ की कुल मात्रा का अपनी आधी मात्रा तक विघटित होने में जितना समय लगता है, उस समय को उस रेडियोएक्टिव पदार्थ का अर्थ आयु काल कहते हैं। अर्थात जिस कालावधि में एक रेडियो एक्टिव पदार्थ अपनी मात्रा का आधा रह जाता है, वह कालावधी उस रेडियोएक्टिव पदार्थ की अर्ध आयु काल कहलाती है।

उदाहरण के लिए यदि किसी रेडियो एक्टिव पदार्थ का अर्थ आयु काल 100 दिन है, तो इसका तात्पर्य यह है कि 100 दिन में वह पदार्थ अपनी कुल मात्रा का आधा रह जाएगा। कुल 200 दिन में वह पदार्थ अपनी प्रारंभिक मात्रा का 3/4 विघटित हो जायेगा।

☼☼☼☼☼☼☼☼☼☼☼☼☼☼☼☼☼☼☼☼☼☼☼☼☼☼☼☼☼☼☼☼☼

Answer:

A vibrating body is a sound producing body , when a body vibrates it causes motion in the nearby PARTICLES and particles pass their energy(motion) to the nearby particles AFTERWARDS the moving particles strikesto our ear DRUMS causing HEAR sensation in ourears and thus sound is heard

velocity-TIME. The relation between velocity and time is a SIMPLE one during UNIFORMLY accelerated, straight-line motion. The longer the acceleration, the GREATER the change in velocity. Change in velocity is directly PROPORTIONAL to time when acceleration is constant.

radiation can be DEFINED as the transmission of ENERGY from a BODY in the FORM of vacuum.

hope it helps

Answer:

3 net FORCE related to body is the answer HOPE it HELPS you have a great DAY

ANSWER:

a=v-u/t

Explanation:

HOPE it is helpful

Mark as BRAINLY plz

follow me

like my answer

ANSWER:

DIVIDE DISTANCE between time

Explanation:

MARK me as BRAINLIEST

I don't UNDERSTAND that QUESTION SEND me question SEPARATELY

ANSWER:

It is an UNIFORM CIRCULAR MOTION

ANSWER:

if it yffufut

Explanation:

hoghfoho

By LOWERING the pressure or raising the TEMPERATURE, the hydrate simply breaks down into water and METHANE - a lot of methane. ONE CUBIC metre of the compound releases about 160 cubic metres of gas, making it a highly energy-intensive fuel.

mark brainliest

ANSWER:

Answer is (d)

EXPLANATION:

both DISTANCE and DISPLACEMENT are EQUAL

EXPLANATION:

ithink this ANSWER is 7/6R if RIGHT REPLY me PLEASE

EXPLANATION:

please CHECK if it question is correct or not because as FAR as I can SEE I can only see the LENGTH value not the breadth value

ANSWER:

An object vibrates to produce sound. So a soundmaking object is different from the ONE that is silent because it PRODUCES VIBRATIONS that the silent object does no

ANSWER:

GIVEN

• Constant acceleration for 20 s

• Starting moving from rest.

• in the first 10 seconds

• in the LAST 10 seconds

TO FIND:

• ,

• Relation between and

EXPLANATION:

in the first 10 seconds:

u = 0

a = a m/s²

t = 10 s

v = 0 + a(10)

v = 10a m/s

in the last 10 seconds:

After 10s the PARTICLE will have the velocity of v = at which is the final velocity for the first ten seconds and INITIAL velocity for the next ten seconds.

u = at m/s

a = a m/s²

t = 10 s

OP BRUH!! SAHI BOLE HN!!

Answer:

So good example of low PITCH sounds are a bass DRUM, Tympani, a string bass, an electric bass, a synthesized sound LIKE you could make in a recording studio or even some singers. I consider bass anything below the male, human voice - less than 400Hz.

please mark me as the BRAINLIEST

ANSWER:

PLZ CHANGE UR LANGUAGE.....

ANSWER:

EXAMPLES OF OBJECTS WHICH PRODUCE SOUND OF HIGH FREQUENCY OR HIGH PITCH. A whistle, a BIRD chirping, ULTRASOUND machines, etc.

Answer:

Newton's first law :

Everything in the universe,if it is in a state of rest, will continue to be in its state of rest and if it is in LINEAR MOTION,it will RESIST its state too, until and UNLESS an external FORCE is applied.

Answer:

a) Inside the spring balance ine string and measures are arranged to know the measures and ONE HANGER is given to handle the things. b) Always UPWARDS action force is normal force. C) If he want to weigh the bananas, he better to weigh in weighing machine. So the WRONG in our question is that he measured bananas in spring balance.

Answer:

20/7

Explanation:

The ratio of wavelengths of photons EMITTED when hydrogen ATOM de-excites from THIRD EXCITED STATE to second excited state an then de-excites form seconds excited state to first excited state is 20/7

i hope this this will help you

plz follow me

Given:

Given the MINIMUM force applied in parallel to the liquid to move an object of mass 100 g in the MICROSCOPIC AREA, the material COEFFICIENT of friction is 0.4

To find:

The minimum force applied.

Solution:

From given, we have,

The mass of object = m = 100 g

The coefficient of friction = μ = 0.4

As the minimum force applied in parallel to the liquid, so we have, θ = 0°

we use the formula,

f = μmg cos θ

f = 0.4 × 100 × 9.8 × cos 0°

f = 392 N

Therefore, the minimum force applied is 392 N

Answer:

माध्य स्थिति को शून्य विस्थापन माना जाय तो वस्तु का विस्थापन x किसी समय t पर निम्नलिखित समीकरण से व्यक्त किया जा सकता है-

{\displaystyle x(t)=A\cos \left(2\pi \!ft+\varphi \right),}{\displaystyle x(t)=A\cos \left(2\pi \!ft+\varphi \right),}

जहाँ A आयाम (AMPLITUDE), F अवृत्ति (FREQUENCY) और φ कला है।