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Answer:

WATER flows from water fall

water flows from water fall figure of the water FALLS are long but too beautiful it's NATURE is so beautiful but all enjoy and feel the nature .

water flows from water fall figure of the water falls are long but too beautiful it's nature is so beautiful but all enjoy and feel the nature .the area ACROSS and always take the support of the stones .

water flows from water fall figure of the water falls are long but too beautiful it's nature is so beautiful but all enjoy and feel the nature .the area across and always take the support of the stones .and make them strong .

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Explanation:

FOLLOW ME OR MARK MY ANSWER AS BRAINLIEST.

ANSWER:

परमाणु विद्युत रूपेण नाभिक में होता है

ANSWER:

प्रकाशिक तन्तु पूर्ण आंतरिक परावर्तन के सिद्धांत पर काम करता है​

Explanation:

प्रकाशीय तंतु पूर्ण आंतरिक परावर्तन के सिद्धांत पर गमन करता है। ... प्रकाशीय तंतु कांच या प्लास्टिक से निर्मित एक तंतु होता है जिसके लम्बाई की दिशा में प्रकाश का संचरण हो सकता है।

ANSWER:

CALCULATION :

MASS OF EARTH =6 X 1024 =6144KG

MASS OF MOON =7.4 X 1022 =7562. 8 KG

RADIUS =1740 KM

ANSWER:

The RISE of water in the DROPPER is due to atmospheric PRESSURE.

Explanation:

The rise of water in a dropper is due to atmospheric pressure. When all the air escapes from the nozzle, the atmospheric pressure, which is acting on the water, forces the water to fill the nozzle of the dropper.

ANSWER:

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Explanation:

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ANSWER:

iaoon fm MAN is tye EYA WONG

Answer:

ASSUME the fig. GIVEN with this answer

in fig AEC

resistance from A to C is

similarly in fig AECD

resistance from POINT A to D is

again in WHOLE fig.

resistance from point A to B is

your answer is 3Ω

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ANSWER:

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EXPLANATION:

.

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ANSWER:

SPEED =AREA of TRIANGLE =1/2×10×11=55 m/s.

ANSWER:

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Answer:

ACCELERATION is the rate of CHANGE of velocity. Usually, acceleration MEANS the speed is changing, but not always. When an object moves in a circular path at a constant speed, it is STILL accelerating, because the DIRECTION of its velocity is changing.

Answer:

While catching a fast moving cricket ball, a FIELDER in the ground gradually pulls his hand backward with the moving ball, In doing so, the fielder INCREASES the time during which the high velocity of the moving ball decrease to zero. ... THUS, the RATE of CHANGE of momentum of the ball will be large.

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Explanation:

दी हुई जानकारी :

प्रोटॉन का चार्ज = 1.6 * 10 ^ (-19) C

प्रोटॉन के बीच की दूरी = 4.0 * 10 ^ (-15) मीटर  

ज्ञात करना है :

प्रोटॉन के बीच का बल।

उपाय :

बल ,  F = k * Q * q / r * r

जहां, k = 9.0 * 10 ^ 9 N/  ,

q और q दो आवेश हैं,

और, r आवेशों के बीच की दूरी है।

अब ,

F = [ 9.0 * 10^9 * 1.6 * 10^(-19) * 1.6 * 10^(-19)] / [ 4.0 * 10^(-15) * 4.0 * 10^(-15)]

=> F = 14.4 N

प्रोटॉन के बीच का बल 14.4 N है।

GIVEN,

• PRESSURE = 200
• FORCE = 18N

To FIND:-

Area

Formula used:-

Pressure = Force / Area

Calculations:-

Pressure = Force / Area

Here we need find the area

so

Area = Pressure /Force

=11cm^2

So the area is 11cm^2

ANSWER:

this QUESTION is so HARD

Answer:

While catching a BALL, a cricket player lowers his hands, because by doing so, he increases the time of CATCH. That is, the person increases the time to BRING about a given change in momentum, and hence rate of change of momentum decreases. Thus, a SMALL FORCE is exerted by ball on the hands.

Hope this helps u!!!!

Answer:

heat is a part where it is known as temperaturewith the HELP of oxygen

fire is a part where it glows

COMBUSTION is a thing which is CONVENIENTLY supports both fire and heat

Explanation:

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ANSWER:

kilogram, GRAM, metre, KILOMETER etc

Explanation:

HOPE this helps you

Answer:

4 OPTION is the answer

hope it HELPS

EXPLANATION:

(द) प्रकाश-विधुत प्रक्रिया

Answer:

Option : C

Explanation:

For a mirror of small APERTURE it can be CONCLUDED that focal length is TWICE of RADIUS of curveture.

OR

Radius is half of focal length.

ANSWER:

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Explanation:

The basic DIFFERENCE between uniform and non-uniform motion is that: In uniform motion, a body moves with a constant speed such as Motion of EARTH around the sun. While in non-uniform motion a body moves with a VARIABLE speed such as Horse running in the race.Explain Uniform acceleration and Non-uniform acceleration.

It means that the acceleration is constant, and neither increasing nor DECREASING. ... Uniform acceleration is change of EQUAL velocity in equal intervals of time. Non Uniform acceleration is change of non-equal velocity in equal intervals of time.

ANSWER:

-1dioptre is answer

Explanation:

mhiugj

A DC motor is any of a class of rotary electrical motors that converts direct current electrical energy into mechanical energy. The most common types RELY on the forces produced by magnetic fields. Nearly all types of DC motors have some INTERNAL mechanism, either electromechanical or electronic, to periodically change the direction of current in part of the motor.

DC motors were the first form of motor widely used, as they could be POWERED from existing direct-current lighting power distribution systems. A DC motor's SPEED can be controlled over a wide RANGE, using either a variable supply voltage or by changing the strength of current in its field windings. Small DC motors are used in tools, toys, and appliances. The universal motor can operate on direct current but is a lightweight brushed motor used for portable power tools and appliances. Larger DC motors are currently used in propulsion of electric vehicles, elevator and hoists, and in drives for steel rolling mills. The advent of power electronics has made replacement of DC motors with AC motors possible in many applications.

ANSWER:

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ANSWER:

Than

Explanation:

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Explanation:

The most COMMON units that we USE to measure length in the metric system are the millimeter, CENTIMETER, meter, and kilometer. The millimeter is the SMALLEST commonly used unit in the metric system.

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1. PLEASE WRITE in ENGLISH

Question:-

# Properties of Magnetic field line:-

✨

➣ Properties of Magnetic field lines are:-

1. The tangent on any point on a field gives the direction of magnetic field.

2. They behave LIKE the stretched elastic rubber strings.

3. They will never intersect each other.

4. The magnetic field lines start from North Pole and enter in the South Pole.

5. Magnetic field lines are CROWDED near the poles of the magnet where the magnetic field is strong and are separated near the middle of the MAGNET and far from the magnet where the magnetic field is weak.

Some Additional information:-

➣

• The space around a magnet in which the needle of a compass rest in a direction other than the GEOGRAPHIC NORTH South direction is called magnetic field of magnet.

• The magnetic field lines are a continuous curve in a magnetic field such that the tangent at any point of it gives the direction of a magnetic field at that point.

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Explanation:

→ The defect of eye called MYOPIA [ Short - SIGHTEDNESS ] is caused due to : (i) Due to high CONVERGING power of eye-LENS ( because of its short focal length ) . (ii) Due to eye-ball being too long . → Myopia is corrected by using spectacles containing concave lens

Answer:

Explanation:

CORRECT Question,

A ball was initially at rest and found to be moving with a SPEED of 10 m/s in 4 s. Calculate the acceleration​.

Solution,

Here, we have

Initial velocity of ball, u = 0 m/s (As ball was in rest)

Final velocity of ball, v = 10 m/s

Time taken by ball, t = 4 seconds

To FIND,

Acceleration of ball, a = ?

According to the 1st equation of motion,

we know that,

v = u + at

so, putting all the values, we get

v = u + at

⇒ 10 = 0 + a × 4

⇒ 10 = 4a

⇒ 10/4 = a

⇒ a = 2.5 m/s²

Hence, the acceleration of ball was 2.5 m/s².

YUP! HERE IS YOUR ANSWER !!!

9%

9%EXPLANATION:

9%Explanation:length=3%

9%Explanation:length=3%volume=L^3

9%Explanation:length=3%volume=L^3=3^3

9%Explanation:length=3%volume=L^3=3^3=3*3

9%Explanation:length=3%volume=L^3=3^3=3*3volume = 9%

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Answer:

q, 2Q, 3q and 4q charges are PLACED at the four corners A,B ,C and D of a square. The FIELD at the CENTRE p of the square has directions equal toq, 2q, 3q and 4q charges are placed at the four corners A,B ,C and D of a square. The field at the centre p of the square has directions equal toq, 2q, 3q and 4q charges are placed at the four corners A,B ,C and D of a square. The field at the centre p of the square has directions equal to

ANSWER:

1. The maximum velocity reached = 20 m/s
2. The retardation in the last = 0.4 m/s²
3. The total distance travelled = 4600 m
4. The average velocity of the train = 17.69 m/s

GIVEN:

• The train TRAVELS at 2m/s² for 10 s

• Starts at rest

• After 10s, It travels at a constant speed for 200 s

• Retards uniformly for 50 s and comes to rest after 210 s.

TO FIND:

1. The maximum velocity reached
2. The retardation in the last
3. The total distance travelled
4. The average velocity of the train.

EXPLANATION:

1) The maximum velocity reached:

The maximum velocity should be reached after 10 seconds, because after that it travels at constant speed and again retards.

u = 0

a = 2 m/s²

t = 10 s

v = 0 + 2(10)

v = 20 m/s

The maximum velocity will be 20 m/s.

2) The retardation in the last:

The initial velocity is what we found above because after 10 s the train travels at a constant speed, then starts retarding and at last it comes to rest(v = 0).

u = 20 m/s

v = 0

t = 50s

0 = 20 + a(50)

50A = - 20

a = - 2/5

a = - 0.4 m/s²

It retards uniformly at a rate of 0.4 m/s².

3) The total distance travelled:

Lets split the distance as THREE parts A,B,C

First part:

A = 0(10) + 1/2(2)(10²)

A = 1/2(2 × 100)

A = 100 m

Second part:

Here velocity is constant and hence accleration is zero

B = 20 × 200

B = 4000 m

Third part:

C = 20(50) + 1/2(- 0.4)(50)(50)

C = 1000 - (2500)/5

C = 1000 - 500

C = 500 m

Total distance = 100 + 4000 + 500

Total distance = 4600 m.

4) The average velocity of the train:

Avg velocity = 17.69 m/s.

POWER is a measure of the amount of work that can be done in a given amount of time. Power equals work (J) divided by time (s). The SI UNIT for power is the watt (W), which equals 1 joule of work per SECOND (J/s).

ANSWER:

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Answer:

గబ్బర్ ఏమండీ and I can go on HOLIDAY on SUNDAY NIGHT if you show me the best way for us ఏమండీ and if

Explanation:

HLO is the best in the process to be honest with

Answer:

20 metres

Explanation:

Initial velocity = 72 km/hr = 20 m/sec

Final velocity = 0 m/sec (because train is coming to a rest)

Acceleration = -36 km/hr = -10 m/sec

Applying the third EQUATION of motion,

v²-u² = 2as

0-20² = 2 (-10) (s)

-400 = -20s

s = 20 metres

Hence the train will COVER 20 metres before coming to a rest.

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Explanation:

For SHM,

ACCELERATION , a = -ω²y

F = ma = -mω²y

now, work , W = F.dy cos180° { because displacement and acceleration are in opposite direction so, cos180° taken }

W = ∫mω²y.dy = mω²y²/2

use standard FORM of SHM , y = Asin(ωt ± Ф)

W = mω²A²/2 sin²(ωt ± Ф)

We know, Potential ENERGY is work done STORED in system .

so, P.E = W = mω²A²/2 sin²(ωt ± Ф)

again, KINETIC energy , K.E = 1/2mv² , here v is velocity

we know, v = ωAcos(ωt ± Ф)

so, K.E = mω²A²/2cos²(ωt ± Ф)

Total energy = K.E + P.E

= mω²A²/2 cos²(ωt ± Ф) + mω²A²/2 sin²(ωt ± Ф)

= mω²A²/2 [ cos²(ωt ± Ф) + sin²(ωt ± Ф) ] = mω²A²/2 [ ∵sin²α + cos²α = 1]

= mω²A²/2 = constant

Hence, total energy is always constant .

Answer:

Here's your answer

Initial velocity (u) = 0m/s [ the BODY starts from rest ]

Acceleration (a) = 2m/s²

Time (t) = 2 sec

To FIND the distance using the 2nd EQUATION of MOTION,

s = ut + 1/2at²

s = 0 + 1/2 × 2 × 2²

s = 4

Thus,

The distance is 4m

============================

Answer:

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Explanation:

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ANSWER:

IT CAN BE DONE BY GOING ON FANTASY ISLAND A SECRET ISLAND NEAR GREENLAND SOMEWHERE

Explanation:

EXPLANATION:

दी हुई जानकारी :

प्रोटॉन का चार्ज = 1.6 * 10 ^ (-19) C

प्रोटॉन के बीच की दूरी = 4.0 * 10 ^ (-15) मीटर  

ज्ञात करना है :

प्रोटॉन के बीच का बल।

उपाय :

बल ,  F = k * q * q / r * r

जहां, k = 9.0 * 10 ^ 9 N/  ,

q और q दो आवेश हैं,

और, r आवेशों के बीच की दूरी है।

अब ,

F = [ 9.0 * 10^9 * 1.6 * 10^(-19) * 1.6 * 10^(-19)] / [ 4.0 * 10^(-15) * 4.0 * 10^(-15)]

=> F = 14.4 N

प्रोटॉन के बीच का बल 14.4 N है।

Answer

• 1 : 1

Given

• Two bodies A and B are thrown upwards with 40 metre per second and 80 metres per second respectively

To Find

• The RATIO of the distances covered by them in LAST second(of their vertical journey)

SOLUTION

The final VELOCITIES of both bodies A and B be " 0 " Since , at top position they both be at rest .

So , v₁ = 0 m/s & v₂ = 0 m/s

g MUST be -ve as we throw both balls against the gravity .

Now , apply 1st equation of motion .

Likewise ,

We know that ,

Now we need to find the ratio of the distances at last second .

So , The ratio of the distances covered by them in last second is S₁ : S₂ = 1 : 1

दी हुई जानकारी :

प्रोटॉन का चार्ज = 1.6 * 10 ^ (-19) C

प्रोटॉन के बीच की दूरी = 4.0 * 10 ^ (-15) मीटर  

ज्ञात करना है :

प्रोटॉन के बीच का बल।

उपाय :

बल ,  F = K * Q * q / r * r

जहां, k = 9.0 * 10 ^ 9 N/  ,

q और q दो आवेश हैं,

और, r आवेशों के बीच की दूरी है।

अब ,

F = [ 9.0 * 10^9 * 1.6 * 10^(-19) * 1.6 * 10^(-19)] / [ 4.0 * 10^(-15) * 4.0 * 10^(-15)]

=> F = 14.4 N

प्रोटॉन के बीच का बल 14.4 N है।